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A small stone is dropped from top of a long tower. The ratio of distance travelled by the particle between t = 5 s to t = 10 s and t = 15 s to t = 20 s is |
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Answer» After time t, distance covered by first stone is s= 21 gt 2 After time (t-1), distance travelled by second stone is s=u(t−1)+ 21 g(t−1) 2 =20t−20+ 21 g(t−1) 2 These distance must be EQUAL at the time of OVERTAKING,Thus, 21 gt 2 =20t−20+ 21 g(t−1) 2 or, 0=20t−20+ 21 g(1−2t)which gives, 20t−20+5−10t=0 (putting g=10)or t=1.5Put this t in equation for distance to get s= 21 gt 2 = 21 10(1.5) 2 =11.25mhope it helps you |
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