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7gr A pendulum bob is given velocity u = atV 2lowest point where r is length of the string then theminimum velocity of bob in subsequent motion isgrV=then value of P is.P |
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Answer» Using conservation of energy in vertical motion of pendulum when it reaches horizontal position, 21 MV h 2 +mgL= 21 mv B 2 Velocity at the bottom is GIVEN by,v b = 5gL v h = 3gL ------ (1)Tension at the horizontal position is =T= Lmv h 2 ----- (2) =3mg ; (Substituting v h from eqn 1 in eqn2)∴ Net force on the bob is = (3mg) 2 +(MG) 2 = 10 mg |
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