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Explanation:50 √2  m is the displacement of the player at the end of 11  MINUTES 40 seconds Explanation: Square GROUND of 50 m  sides => perimeter = 4 * 50 = 200 m one round is completed in 200 Sec => Hence speed = 1 m/s DISTANCE Covered in 11 min 40 secs = 700 sec    = 700 m 700 = 200 + 200 + 200 + 100 Hence he has moved 100 m from initial position 50 m on one SIDE  and 50 m at right angle Hence Distance of final position from initial position =  √50² + 50² = 50√2 50 √2  m is the displacement of the player at the end of 11  minutes 40 seconds Learn more: A car travels from stop A to stop B with a speed of 30 km/h and then moves

Motion between tectonic PLATES can be divergent ... These models show 6 main TYPES of PLATE tectonic boundaries. ... Label the landmasses of each CONTINENT

Here INITIAL velocity (u) = 58.8 m/sFinal velocity (V) = 0 (as it comes to rest on TOUCHING the ground)Time (t) = 6 secondsWe KNOW v = u - at0 = 58.8 - a × 6⇒6a=58.8⇒a= 658.8 ∴a=9.8m/s 2 ∴ The value of acceleration due to GRAVITY = 9.8 m/s 2

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nitial Velocity u=0Initial Velocity u=0Fianl velocity V=?Initial Velocity u=0Fianl velocity v=?HEIGHT, s=19.6mInitial Velocity u=0Fianl velocity v=?Height, s=19.6mBy third EQUATION of motionInitial Velocity u=0Fianl velocity v=?Height, s=19.6mBy third equation of motionv Initial Velocity u=0Fianl velocity v=?Height, s=19.6mBy third equation of motionv 2Initial Velocity u=0Fianl velocity v=?Height, s=19.6mBy third equation of motionv 2 =u Initial Velocity u=0Fianl velocity v=?Height, s=19.6mBy third equation of motionv 2 =u 2Initial Velocity u=0Fianl velocity v=?Height, s=19.6mBy third equation of motionv 2 =u 2 +2gsInitial Velocity u=0Fianl velocity v=?Height, s=19.6mBy third equation of motionv 2 =u 2 +2gsv Initial Velocity u=0Fianl velocity v=?Height, s=19.6mBy third equation of motionv 2 =u 2 +2gsv 2Initial Velocity u=0Fianl velocity v=?Height, s=19.6mBy third equation of motionv 2 =u 2 +2gsv 2 =0+2×9.8×19.6Initial Velocity u=0Fianl velocity v=?Height, s=19.6mBy third equation of motionv 2 =u 2 +2gsv 2 =0+2×9.8×19.6v Initial Velocity u=0Fianl velocity v=?Height, s=19.6mBy third equation of motionv 2 =u 2 +2gsv 2 =0+2×9.8×19.6v 2Initial Velocity u=0Fianl velocity v=?Height, s=19.6mBy third equation of motionv 2 =u 2 +2gsv 2 =0+2×9.8×19.6v 2 =384.16Initial Velocity u=0Fianl velocity v=?Height, s=19.6mBy third equation of motionv 2 =u 2 +2gsv 2 =0+2×9.8×19.6v 2 =384.16⇒v=19.6m/sMark me as Brainlist

it's PHYSICS but it's about physics

tion:(a) The resistivity of copper wire is very low. The connections are made of thick copper wires to minimize the resistance of CONNECTING wires. Because the connection resistance have not been accounted in the FORMULA, (v Resistance is inversely PROPORTIONAL to cross-sectional area, so thick wire has low resistance).(b) The balance point is obtained in the middle of the meter bridge wire so as to increase the SENSITIVITY of the meter bridge and there by no deflection in the galvanometer.(c) Alloys, such as manganin or constantan are used for making meter bridge wire due to their low temperature coefficient of resistance and high resistivity. Due to which the resistance of the wire does not change with increase in temperature of the wire due to flow of current.Given: A resistance ofRΩ draws current from a potentiometer. The potentiometer has a total resistance R 0 Ω. A voltage V is supplied to the potentiometer.To find an expression for the voltage across R when the sliding contact is in the middle of the potentiometer.Solution:Total resistance is given by,

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the CAR controled by MOBILE I THINK so....

Given, aftar half the circle, the particle will REACH the diametrically opposite opint i.e., from point A to point B. And we KNOW DISPLACEMENT is shortest path between initial and final point. HENCE, the displacement aftar half circle is 2r.Hope it helps you............

जब दो या दो से अधिक प्रतिरोधों को इस प्रकार से संयोजित किया जाए की प्रत्येक प्रतिरोध में विद्युत धारा का मान एकसमान हो तो इस प्रकार के प्रतिरोधों के संयोजन को श्रेणी क्रम संयोजन कहते है।इस प्रकार के संयोजन में प्रतिरोध का दूसरा सिरा अगले प्रतिरोध के पहले सिरे से जुड़ा रहता है और इसी प्रकार दूसरे प्रतिरोध का दूसरा सिरा तीसरे प्रतिरोध के पहले सिरे से जुड़ा रहता है जैसा चित्र में दिखाया गया है।चित्रानुसार 3 प्रतिरोध R1 , R2 , R3 है ये तीनो श्रेणीक्रम में जुड़े हुए है , तीनो प्रतिरोधों में समान मान की धारा I प्रवाहित हो रही है , तीनो प्रतिरोधों पर विभवांतर V1 , V2 , V3 है। V1 , V2 , V3 का मान ओम के नियम से निकाल सकते है।V1 = IR1V2 = IR2V3 = IR3चूँकि परिपथ में आरोपित कुल विभवांतर Vs है।Vs = V1 + V2 + V3V1 , V2 , V3 का मान रखने परVs = IR1 + IR2 + IR3Vs = I (R1 + R2 + R3)चूँकि हम जानते है की Vs = I RVS का मान ऊपर समीकरण में रखने परI R = I (R1 + R2 + R3)अतःR = R1 + R2 + R3यहाँ R को श्रेणी क्रम में प्रतिरोधों का तुल्य या कुल प्रतिरोध कहते है , यहाँ हमने देखा की श्रेणीक्रम में तुल्य प्रतिरोध का मान सभी प्रतिरोधों के योग के बराबर प्राप्त होता है।नोट : हमने 3 प्रतिरोध लेकर इसको समझा है , लेकिन 3 से अधिक प्रतिरोध होने पर भी ये ही निष्कर्ष इसी प्रकार निकाला जा सकता है।

8.6 ± 0.1 °CExplanation:FALL of TEMP. = INITIAL temp. - FINAL temp. = 76.3-67.7 ± 0.4-0.3 °C = 8.6 ± 0.1 °C

tion:12thPhysicsWave OpticsYoung's Double Slit ExperimentIn a double slit EXPERIMENT...PHYSICSIn a double slit experiment, the two slits are 1 mm apart and the screen is place 1 m away. A monochromatic light of wavelength 500 NM is used. What will be the WIDTH of each slit for obtaining ten maxima of double slit WITHIN the central maxima of single slit pattern?MEDIUMShareStudy laterVIDEO EXPLANATIONANSWERd=10 −3 mD=1mλ=500×10 −9 mThe width of central maxima in a single slit diffraction: a2λD Fringe width in double slit pattern: β= dλD Given,10β= a2λD ⇒10 dλD = a2λD ⇒a= 5d mm=0.2mm

78.4 m ...Explanation:100% SURE ANS

1) A pulley is a simple machine that CONSISTS of a rope wrapped around a grooved WHEEL. Pulleys are generally used to lift a load.2) There are three types of pulleys: fixed pulleys, moveable pulleys, and COMPOUND pulleys. Compound pulleys consist of TWO or more fixed and moveable pulleys.3) The ideal mechanical advantage of a pulley equals the number of rope segments pulling up on the load.

Length is a measure of DISTANCE. In the International SYSTEM of Quantities, length is a quantity with dimension distance. In most systems of measurement a base UNIT for length is CHOSEN, from which all other units are derived. In the International System of Units (SI) system the base unit for length is the metre.Explanation:I hope this is helpfull for you☺Follow ND like my answer✌Mark my answer Brainliest☺✌

this is your answerExplanation:the weight of a LARGE stone is greater than a small one because large stone has greater MASS then small stone.therefore,it is DIFFICULT to lift a large stone on the SURFACE of the earth but easy to lift small one. hope its helpfulall the BEST

Two persons SEATED at the two EXTREME ends of the LINE are C and B.

There are DIFFERENT types of motion: translational, ROTATIONAL, PERIODIC, and non periodic motion. A type of motion in which all parts of an object move the same distance in a GIVEN time is called translational motion.

The aqueous humour is a thin, transparent fluid similar to plasma. It's MADE up of 99.9% water – the other 0.1% consists of sugars, VITAMINS, proteins and other nutrients. This fluid nourishes the CORNEA and the lens, and GIVES the EYE its shape....

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I am not UNDERSTANDING your QUESTION what is your question about EXPLANATION:which LESSON is this

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hdjbbidhuebdjdbudbfhrbrhdbbfndbdndExplanation:nssssnnnkajkanaans

96NExplanation:Given that,Weight of body in air = 100 N Buoyant force = Weight of liquid displaced Volume of water displaced = 400 cc² DENSITY of water = 1g/cm³ In this case,ρ= m/V m=ρ×V m=1×400 m=400g. We know that,The weight of water displaced isW=m×gW= 2/5 × 9.8W=3.92NNow, weight of the OBJECT in waterW=100−3.92W=96.08W=96N.Hence, the weight of object in water is 96 N.Please MARK it as brainliest .!!!!

The anomalous behaviour of water can be studied with Hope's apparatus.In Hope's apparatus, a flat bowl is attached to a cylindrical container.There is provision to attach thermometers above and below the flat bowl on the cylindrical container.Water is filled in the mixture of ice and SALT is put in the flat bowl.Initially both temperature T1 and T2 are identical but as TIME passes, temperature T1 of water in the lower part of the cylinder decreases fast while temperature T2 of water in the upper part of the cylinder decreases comparatively SLOWLY.However, once the temperature T1 of the lower part reaches 4°C, it remains ALMOST stable at the temperature.T2 decreases slowly to 4°C.Thereafter, since T2 starts changing rapidly, it records 0°C first and after that the lower temperature T1 records 0°C temperature.The point of intersection of the TWO curves shows the temperature of maximum density.The behaviour of water between it's temperature from 0°C to 4°C is called anomalous behaviour of water.

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(C) is your ANSWER.............

In this CASE, a wire of uniform thickness with a RESISTANCE of 27 is cut into three equal pieces and they are joined in parallel. As we know that the resistance is DIRECTLY proportional to the length of the wire, R∝L, so when the wire is cut into 3, the resistance of the cut wire is reduced to one third of the total resistance. That is, the resistance of each cut wire becomes 27/3= 9 ohms.Now, when these 3 wires are connected in a parallel connection, the total resistance is given as 91+91+91=0.3331=3ohms.Hence, the total resistance is now 3 ohms only.Explanation: MARK as brainliest bro

The conductor and insulator are the TYPES of MATERIAL. One of the major difference between the conductor and insulator is that the conductor allows the energy (i.e., CURRENT or heat ) to PASS through it, whereas the insulator does not ALLOW the energy to pass through it

T is 1sExplanation:HOPE this HELPS you

r whose magnitude is unity (= 1) is called a unit VECTOR. The unit vector of vector v SHOWN in FIGURE 2 can be obtained by dividing the vector with its magnitude

's right HAND rule :The forefinger, the middle finger and the thumb of the right hand are HELD in three MUTUALLY PERPENDICULAR directions. If the forefinger points along the direction of the magnetic field and the thumb along the direction of motion of the magnetic field and the thumb along the direction of motion of the conductor, then the middle finger points in the direction of induced CURRENT.

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