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To prove that action and reaction forces are acting on TWO DIFFERENT objects. Procedure: -->Take a test tube and put small amount of water in it. ... --->Heat the test tube with a Bunsen BURNER until water vaporizes and cork blows out.Explanation:ANS is (A)

The velocity of an OBJECT is the rate of change of its POSITION with respect to a frame of reference, and is a function of time. ... Velocity is a physical vector quantity; both magnitude and DIRECTION are NEEDED to define it.maybe her or his NAME is devroy

The GRAVITATIONAL interaction between the earth and an object near the earth's surface OVERWHELMS the other gravitational interactions experienced by the object (in the reference FRAME of the earth). The gravitational force exerted on an object near the earth's surface is called the object's WEIGHT.

The velocity of light in water =2.205\times 10^8\dfrac{m}{s}=2.205×10 8 SM Given,The absolute refractive INDEX of water = 1.36 andvelocity of light in vacuum= 3\times 10^8 \dfrac{m}{s}3×10 8 sm To find, the velocity of light in water = ?We know that,The velocity of light in water =\dfrac{velocity of light in vacuum}{The absolute refractive index of water} Theabsoluterefractiveindexofwatervelocityoflightinvacuum =\dfrac{3\times 10^8 \dfrac{m}{s}}{1.36}= 1.363×10 8 sm =2.205\times 10^8\dfrac{m}{s}=2.205×10 8 sm The velocity of light in water =2.205\times 10^8\dfrac{m}{s}=2.205×10 8 sm Hence, the velocity of light in water =2.205\times 10^8\dfrac{m}{s}=2.205×10 8 sm Explanation:Given,The absolute refractive index of water = 1.36 andvelocity of light in vacuum= 3\times 10^8 \dfrac{m}{s}3×10 8 sm To find, the velocity of light in water = ?We know that,The velocity of light in water =\dfrac{velocity of light in vacuum}{The absolute refractive index of water} Theabsoluterefractiveindexofwatervelocityoflightinvacuum =\dfrac{3\times 10^8 \dfrac{m}{s}}{1.36}= 1.363×10 8 sm=2.205\times 10^8\dfrac{m}{s}=2.205×10 8 sm =2.205\times 10^8\dfrac{m}{s}=2.205×10 8 sm The velocity of light in water =2.205\times 10^8\dfrac{m}{s}=2.205×10 8please like my answer and mark as brainlest and FOLLOW me

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tion:The ANSWER is (d) 1 650 763.73This question relates to a definition of the meter that was in effect from 1960 until 1986, and stated that one meter was equal to the total length of 1 650 763.73 WAVELENGTHS of the orange-red emission line in the electromagnetic spectrum of the krypton-86.This question relates to a definition of the meter that was in effect from 1960 until 1986, and stated that one meter was equal to the total length of 1 650 763.73 wavelengths of the orange-red emission line in the electromagnetic spectrum of the krypton-86.(It has since been REPLACED by a definition based on the SPEED of light.)

♧ᴠᴏʟᴛᴍᴇᴛᴇʀ ᴍᴇᴀꜱᴜʀɪɴɢ ᴠᴏʟᴛᴀɢᴇ ᴡɪᴛʜ ᴀ ᴠᴏʟᴛᴍᴇᴛᴇʀ ᴀ ᴠᴏʟᴛᴍᴇᴛᴇʀ ɪꜱ ᴄᴏɴɴᴇᴄᴛᴇᴅ ɪɴ ᴘᴀʀᴀʟʟᴇʟ ᴡɪᴛʜ ᴡʜᴀᴛᴇᴠᴇʀ ᴅᴇᴠɪᴄᴇ ɪᴛ ɪꜱ ᴍᴇᴀꜱᴜʀɪɴɢ. ᴀ ᴘᴀʀᴀʟʟᴇʟ ᴄᴏɴɴᴇᴄᴛɪᴏɴ ɪꜱ ᴜꜱᴇᴅ ʙᴇᴄᴀᴜꜱᴇ ᴏʙᴊᴇᴄᴛꜱ ɪɴ ᴘᴀʀᴀʟʟᴇʟ ᴇxᴘᴇʀɪᴇɴᴄᴇ ᴛʜᴇ ꜱᴀᴍᴇ ᴘᴏᴛᴇɴᴛɪᴀʟ ᴅɪꜰꜰᴇʀᴇɴᴄᴇ.♧Hope This HELPS You♧

-Laws of Limiting Friction:The limiting friction hinges upon the material, the nature of the surfaces INTERACTING, and their EVENNESS. So long as the normal reaction is the same, the magnitude of limiting friction is free of the SHAPE or the area of the surfaces in contact, for any two given surfaces.hope this help u if yes then,Plz mark my answer BRAINEST answer...

tion:zero GRAVITATIONAL field due to spherical SPHERE A point INSIDE spherical cylender R

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The ANSWER was the a TRANSLATION

It is ALSO CALLED as SUDDEN errors.mark me BRAINLIEST

HiExplanation:

m = 30/9.8 = 3.06 kgExplanation:Mass will remain the same everywhere, as it is a property of MATTER. It is not effected by the VALUE of ACCELERATION due to GRAVITY anywhere

is Y203.a. State the VALENCY of YB. Is Y a metal or non metalc. WRITE the FORMULA of 'Y' with chloride

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I hope it's help you ( ◜‿◝ )♡Explanation:Skis create a large CONTACT AREA between the skier and the SNOW. Therefore, the weight of the skier—or how much GRAVITY pulls on him—is spread out over a larger area. The skier presses less on each square INCH of snow, and instead of sinking into it he or she can glide over it.

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tion:ACCORDING to the Kepler's THIRD law T 2 ∝R 3 ∴ T 2 T 1 =( R 2 R 1 3/2 ) or R 2 =(R 1 )( T 1 T 2 ) 3/2 =(R 1 )( 216 ) 2/3 =4R 1 =4R (given R 1 =R) ....(i)Orbital velocity, V o = RGM ∴ v o1 v o2 = R 2 R 1 = 4R 1 R 1 = 21 ....(using (i))or v o2 = 21 v o1 = 21 v o

0.1kgm/s because PRODUCT of MASS and Velocity is linear mamentum or SIMPLY MOMENTUM.

k done in bringing twocharges (Q) at a DISTANCE a' fromeach other is 2mJ. THREE chargesq, -q and q are assembled at thethree CORNERS of an equilateraltriangle. The work done will be(A)zero (B)-2mJ(C)4mJ

Since N is even number, ( 28 +1) th term i.e., 5th term is the middle term in (2X + 3Y) 8 .T 5 =T 4+1 = 8 C 4 (2x) 8−4 (3y) 4 = 8 C 4 (2x) 4 (3x) 4

Force, F =4 i^ −3 J^ +2 k^ Displacement vector is s =(2−3) i^ +(−1−2) j^ +(4+1) k^ =− i^ −3 j^ +5 k^ Hence, WORK done W= F ⋅ s =(4 i^ −3 j^ +2 k^ )⋅(− i^ −3 j^ +5 k^ )=−4+9+10=15units

From POINT A to BDistance covered=300mDisplacement=300mTime taken=2 MIN 30 SEC=(2×60)+30=150 secAverage speed=TimetakenDistance covered=150300=2 m/secAverage velocity=TimetakenDisplacement=150300=2 m/secFrom point A to CDISTANCE covered=300+100=400mDisplacement=300−100=200mTime taken=3 min 30 sec=(3×60)+30=210 secAverage speed=Distance covered/timetaken=210400=1.90 m/secAverage velocity=Displacement/time taken=210200=0.95 m/sec

When an object perform TWO or more TYPES of motion at the same time, then the motion of the object is CALLED as multiple motion. ... If the circular motion is uniform, it is periodic also.When an object perform two or more types of motion at the same time, then the motion of the object is called as multiple motion. ... If the circular motion is uniform, it is periodic also.When an object perform two or more types of motion at the same time, then the motion of the object is called as multiple motion. ... If the circular motion is uniform, it is periodic also.

tion:Answer8.3Explanation:25 and X 4 metre and DIVIDE 12 metre then is ANSWER is 8.3 BA of the persons are CORRECT answer for requirement SPRING require load PER Kitna load