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Find the port done in moving an object alongthe applied force is F = (21 +33 +7k) |
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Answer» Force, F =4 i^ −3 J^ +2 k^ Displacement vector is s =(2−3) i^ +(−1−2) j^ +(4+1) k^ =− i^ −3 j^ +5 k^ Hence, WORK done W= F ⋅ s =(4 i^ −3 j^ +2 k^ )⋅(− i^ −3 j^ +5 k^ )=−4+9+10=15units |
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