The velocity of light in water =2.205\times 10^8\dfrac{m}{s}=2.205×10 8 SM Given,The absolute refractive INDEX of water = 1.36 andvelocity of light in vacuum= 3\times 10^8 \dfrac{m}{s}3×10 8 sm To find, the velocity of light in water = ?We know that,The velocity of light in water =\dfrac{velocity of light in vacuum}{The absolute refractive index of water} Theabsoluterefractiveindexofwatervelocityoflightinvacuum =\dfrac{3\times 10^8 \dfrac{m}{s}}{1.36}= 1.363×10 8 sm =2.205\times 10^8\dfrac{m}{s}=2.205×10 8 sm The velocity of light in water =2.205\times 10^8\dfrac{m}{s}=2.205×10 8 sm Hence, the velocity of light in water =2.205\times 10^8\dfrac{m}{s}=2.205×10 8 sm Explanation:Given,The absolute refractive index of water = 1.36 andvelocity of light in vacuum= 3\times 10^8 \dfrac{m}{s}3×10 8 sm To find, the velocity of light in water = ?We know that,The velocity of light in water =\dfrac{velocity of light in vacuum}{The absolute refractive index of water} Theabsoluterefractiveindexofwatervelocityoflightinvacuum =\dfrac{3\times 10^8 \dfrac{m}{s}}{1.36}= 1.363×10 8 sm=2.205\times 10^8\dfrac{m}{s}=2.205×10 8 sm =2.205\times 10^8\dfrac{m}{s}=2.205×10 8 sm The velocity of light in water =2.205\times 10^8\dfrac{m}{s}=2.205×10 8please like my answer and mark as brainlest and FOLLOW me