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Joseph jogs from one end A to another end B of a straight 300 m road in 2 minutes and 30 sex and then turns around and jogs 100 m back to point C in another 1 minute. What are his average speed and velocities in jogging? a) From A to B b) From A to C? Need quality answer no spam! |
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Answer» From POINT A to BDistance covered=300mDisplacement=300mTime taken=2 MIN 30 SEC=(2×60)+30=150 secAverage speed=TimetakenDistance covered=150300=2 m/secAverage velocity=TimetakenDisplacement=150300=2 m/secFrom point A to CDISTANCE covered=300+100=400mDisplacement=300−100=200mTime taken=3 min 30 sec=(3×60)+30=210 secAverage speed=Distance covered/timetaken=210400=1.90 m/secAverage velocity=Displacement/time taken=210200=0.95 m/sec |
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