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| 1. |
If the percentage error in the measurement of radius 'R' of a sphere is 2%,then what is the percentage error in it's volume |
| Answer» 6%Explanation:Percentage ERROR in radius is given as 2% i.e. rΔr ×100=2 %Volume of sphere V= 34π r 3 Percentage error in volume VΔV ×100=3× rΔr ×100=3×2=6 % | |