1.

If the percentage error in the measurement of radius 'R' of a sphere is 2%,then what is the percentage error in it's volume​

Answer» 6%Explanation:Percentage ERROR in radius is given as 2% i.e. rΔr ×100=2 %Volume of sphere V= 34π r 3 Percentage error in volume VΔV ×100=3× rΔr ×100=3×2=6 %


Discussion

No Comment Found

Related InterviewSolutions