This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 2. |
If (a - b) is 6 more than (c + d) and (a + b) is 3 lessthan (c - d), then the value of (a - c) is |
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Answer» a-c =3/2 Step-by-step EXPLANATION: SIMPLY ADD both the EQUATIONS. 2a=2c+3 so a-c= 3/2 |
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| 3. |
What total do you get if you add up the numbers in the Hindi saying "Nau Do Gyarah Hona"?[A] 9[B] 22[C] 11[D] 13 |
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Answer» [B]22 Step-by-step explanation: 9+2+11=22 that is your answer |
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| 4. |
0/0=2Prove this by any method of mathematics. |
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Answer» it is POSSIBLE because in MULTIPLY or division by 0 always GIVE 0 |
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| 5. |
A shopkeeper bought 50 kg of sugar he sold 1/4 of the sugar. find the weight of the sugar that was left. |
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Answer» Step-by-step explanation: TOTAL sugar bought by shopkeeper is = 50kg; 1/4 of the 50kg sugar was SOLD = 1/4*(50) = 12.5 KG of sugar was sold out; Total weight of sugar was LEFT = 50-12.5 = 37.5 kg |
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| 6. |
Find the acute angle theta such that 2 cos squared theta is equal to 3 sin theta |
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Answer» Answer: 30 deg Step-by-step explanation: sin alpha LIES between -1 & 1 |
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| 7. |
The area of a triangular park is 240m. If two sides are 78,and 50m, find the length of the perpendicular on the side of length 50 m from the opposite vertex.Please answer |
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Answer» Answer: PERIMETER of triangular PARK = 240m LENGTH of two SIDE are- 1) 78m 2) 50m let 3rd side be = X meter 78+50+x = perimeter of triangle 78+50+x = 240m 128+x = 240m x = 240-128 x = 112m therefore, the length of third side is 112m . |
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| 8. |
3(2x+1)-4(x-2)=0 pls... it's very urgent ... |
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Answer» 6x+3-4x+8=0 6x-4x+3+8=0 2x+11=0 2x=0-11 2x=11 x=11/2 therefore the ANSWER is x=11/2 |
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| 9. |
If 6(x÷2-5)=120,then x= |
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Answer» Step-by-step explanation: 6(x÷2-5)=120 6x÷12-30=120 6x÷12=150 6x=150*12 6x=12.5 x=2.0834 |
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| 10. |
Two friends start at the same time from cities P and Q towards cities to Q and P respectively. After meeting at some point between P and Q,they reach their destination in 54 and 24 minutes respectively. In what time did the one who moved from Q to P complete his journey?need explained ans |
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Answer» N will take 60 mins to complete the entire journey from Q to P. Step-by-step explanation: Let the two friends be “M” who will be TRAVELLING from P to Q and “N” who will be travelling from Q to P. Let us CONSIDER the speed of M be “x” and the speed of N be “y”. Also, let them meet after “t” minutes. Case 1: Before M & N meets each other Distance travelled by M = x * t Distance travelled by N = y * t Case 2: After M & N crosses each other Distance travelled by M = x * 54 Distance travelled by N = y * 24 Now, (Distance travelled by M & N before meeting each other) = (Distance travelled by M & N after CROSSING each other) ∴ x * t = x * 54 ….. (i) And, y * t = y * 24 …. (ii) Multiplying equation (i) & (ii), we get xy * t² = xy * 54 * 24 or, t² = 1296 or, t = 36 Since we are required to find the time taken by N to travel the entire journey from city Q to P, therefore, N WOULD take 36 + 24 = 60 minutes to complete his entire journey. |
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| 11. |
1. Prove that the sum of three angles of a triangle is 180° |
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Answer» angles of triangle = 180 degrees so all the SIDES of the triangle will be xcm => x+x+x=180 =>3x=180 =>x=180/3 =>x=60 degrees so now if we will add 60 three times then the sum will be 180 degrees |
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| 12. |
Answer the question,First correct one will be 100% brainlist |
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Answer» PLEASE SEE the ATTACHMENT |
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| 13. |
If cos A+cos²A=1 then sin²A+sin²A |
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Answer» Answer: 2cosA Step-by-step EXPLANATION: cosA=1-cos^2A =sin^2A Sin^2A+sin^2A=2cosA |
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| 14. |
Find the value of cos(2π/7) + cos(4π/7) + cos(6π/7) ? |
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Answer» Step-by-step explanation: Hello...This is a streamlined version of the PROOF I posted earlier. The trig identities used are: [a] sin (π-X) = sin x ----used in step 9 [b] sin (π+x) = -sin x ----used in step 8 [c] sin (-x) = -sin x ----used in step 6 (TWICE) [d] sin 2X = 2 sin x cos x ----used in step 4 [e] sin x cos y = (1/2)sin(x+y) + (1/2)sin(x-y) ----used in step 5 (twice) 1. cos(2π/7) + cos(4π/7) + cos(6π/7) = 2. 2sin(2π/7)[(cos(2π/7) + cos(4π/7) + cos(6π/7)] / 2sin(2π/7) = 3. [2sin(2π/7)cos(2π/7) + 2sin(2π/7)cos(4π/7) + 2sin(2π/7)cos(6π/7)] / 2sin(2π/7) = 4. [sin(4π/7) + 2sin(2π/7)cos(4π/7) + 2sin(2π/7)cos(6π/7)] / 2sin(2π/7) = 5. [sin(4π/7) + sin(6π/7) + sin(-2π/7) + sin(8π/7) + sin(-4π/7)] / 2sin(2π/7) = 6. [sin(4π/7) + sin(6π/7) - sin(2π/7) + sin(8π/7) - sin(4π/7)] / 2sin(2π/7) = 7. [sin(6π/7) - sin(2π/7) + sin(8π/7)] / 2sin(2π/7) = 8. [sin(6π/7) - sin(2π/7) - sin(π/7)] / 2sin(2π/7) = 9. [sin(π/7) - sin(2π/7) - sin(π/7)] / 2sin(2π/7) = 10. -sin(2π/7) / 2sin(2π/7) = 11. -1/2 @hardikrakholiya21❤️. |
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| 17. |
If 6(x÷2 - 5)=120, then x = |
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Answer» Answer: X = 50 Step-by-step explanation: 6(x÷2 - 5)=120 3x - 30 = 120 3x = 150 x = 50 |
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| 18. |
Hi can someone pls solve this |
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Answer» answer is (7)^-2 Step-by-step EXPLANATION: here.., =3√(343)^-2 =3√1/343×343 =3√1/7×7×7×7×7×7 ={1/(7^6)}^1/3 =(1/7^2) =7^-2 |
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| 19. |
2 Two numbers are in the ratio 7:9. If the sum of thenumbers is 272, find the numbers. |
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Answer» Answer: Now, 7x + 9x = 272 16x = 272 X =272/ 16 = 17 Now, 17 × 7 = 119 119 × 9 = 1071 |
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| 20. |
Find the number of digits in the square root of 225 |
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Answer» |
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| 21. |
a sum of rs 190 is divided into two parts. if the smaller part is rs 5 less than half of the greater part, find the parts of the sum. |
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| 22. |
Which number in each of the following pairs is smaller? 2,5 |
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Answer» Answer: 1 Step-by-step EXPLANATION: |
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| 23. |
FIND THE SUM OF ALL TWO DIIT NATURAL NUMBER WHICH ARE DIVISIBLE BY 9 |
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Answer» Answer: 18+27+36+45+54+63+72+81=396 |
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| 24. |
1) . there are 4225 trees in 25 rows. How many trees are there in 34 such rows .2) if it takes 72 minutes to fill 9 buckets of water how long with it take to fill 12 buckets? |
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| 25. |
I) The denominator of a common fraction exceedsthe numerator by 7. If 3 is deducted fromthe numerator as well as the denominator,the fraction is obtained. Find the originalcommon fraction.Viti bouche |
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| 26. |
Ramesh sold an article at a certain profit. Had he purchased the article for 12% less and sold it for 24% more, his profit percentage would have been 2.5 times his actual profit percentage. Find his actual profit percentage. |
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Answer» Dear Student, ◆ Answer - Profit % = 28.57 % ● Explanation - Suppose RAMESH SOLD an article of cost price P at a profit of x %. If he had purchased it for 12 % LESS and sold it to 24 % more, profit % would have been 2.5 % more. SP × 124/100 - CP × 88/100 = 2.5 (SP-CP) 1.24SP - 0.88CP = 2.5SP - 2.5CP 2.5CP - 0.88CP = 2.5SP - 1.24CP 1.62CP = 1.26SP SP = 1.62CP/1.26 SP = 1.2857CP Profit percentage is calculated as - Profit % = (SP/CP - 1) × 100 Profit % = (1.2857CP/CP - 1) × 100 Profit % = (1.2857 - 1) 100 Profit % = 28.57 % Hope that's all... |
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| 27. |
99999999999999999999999999999999999999999999999999999999999999×12 |
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Answer» Cannot be POSSIBLE on CALCULATOR ALSO |
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| 28. |
(ii) If a number is increased by 23 and the sum ismultiplied by 7, the product is 364. Find theAnumber. |
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Answer» (A+23)*7=364 So A+23=364/7=52 So A=52-23=29 ANS |
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| 29. |
531* या संख्येला 13 ने पूर्ण भाग जातो तर * = ?1.92.8 3.3. 4.7 |
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| 30. |
[(Tan60°) ^2+4cossqare45°+4cosecsqare60°+2secsqare90°]/[2cosec30°+3sec60°-7/3cotsqare30° |
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Answer» VALUE of tan60= sqrt3 cos45 = 1/sqrt2 cosec45=sqrt2 sec90=INFINITY =Tan60°) ^2+4cossqare45°+4cosecsqare60°+2secsqare90°]/[2cosec30°+3sec60°-7/3cotsqare30 =Tan60°) ^2+4cossqare45°+4cosecsqare60°+infinity]/[2cosec30°+3sec60°-7/3cotsqare30 =infinity In the given QUESTION there is sec90 whose value is INFINITE so the and become infinity . |
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| 31. |
नौ पिंंजरे है और 22 कबूतर है तो 22कबूतर कैसे बेठैगे |
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| 32. |
Pls Tell me important question of height nd distance |
Answer» QUESTIONS FORM NCERT book are very very IMPORTANT for EVERY EXAM... |
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| 33. |
The area of a triangle ABC is 8cm square in which AB=AC =4cm And angle A is 90 degree |
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Answer» AREA of triangle ABC = 1/2 ×BASE × HEIGHT = 1/2 × AB × AC = 1/2 × 4× 4 = 2 × 4 = 8 cm square LET AD IS PERPENDICULAR TO BC In Triangle ADB AND ADC AD = AD ( common) angle ADC = angle ADB ( each 90 degree) AB = AC (Given) Triangle ADB (congruent to). triangle ADC ( RHS criteria) BD = CD ( cpct ) in triangle ABC , BY Pythagoras THEOREM ABsquare + ACsquare = BC square 4 square +4 square = BCsquare 16 +16 = BCsquare 32 = BC square :. BC = 4√2 cm BD + CD = BC 2BD = BC (. BD = CD ) 2BD = 4√2 BD = 2√2 cm now in triangle BAD , by Pythagoras theorem ADsquare + BD square = ABsquare ADsquare + 2√2 square = 4 square ADsquare + 4×2 = 16 ADsquare + 8 = 16 ADsquare = 16- 8 ADsquare = 8 .: AD = √8 .: AD = 2√2 cm Hence length of perpendicular from A to BC = length of AD = 2√2 cm Read more on Brainly.in - brainly.in/question/2113729#readmore |
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| 34. |
Xy2+(x-1)y-l solve this sum |
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Answer» Step-by-step explanation: 2xy+(x-1)y-l 2xy+xy-y-l 3xy-y-l |
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| 35. |
A toy market at 750 is after 570 complete the rate of discount |
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Answer» The DIFFERENCE is 750-570 =180 And we have to find the percentage. 24 PERCENT |
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| 36. |
Perimeter of a parallelogram with sides 9 cm and 5cm |
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Answer» Step-by-step EXPLANATION: |
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| 37. |
The weight of two boxes is 5 3/4 kg . If the weight of one box is 2 5/6 kg. Find the weight of second box? |
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Answer» Answer: 2 11/12 Kg. Step-by-step explanation: WEIGHT of BOXES = 5 3/4 Kg = 23/4 kg. Weight of 1 box = 2 5/6 Kg = 17/6 kg. Weight of 2nd box = 23/4 - 17/6
= 69 - 34 ------------- = 35/12 = 2 11/12 Kg. 12 |
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| 38. |
Sum and products of the roots of the quadratic equation 3+1/a =10/asquare |
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| 39. |
?1 _ 2? = 34 what is the anser |
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Answer» Answer: 11+23=34 PLEASE MARK ME THE BRAINLIEST... |
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| 40. |
A/5+3=2 solve this equation |
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Answer» -5 Step-by-step EXPLANATION: a/5= 2-3 a/5= -1 a= -1×5 a = -5 |
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| 41. |
Can you tell where we use milligramme |
Answer» HeyATo measure weights SMALLER than 1 gram, we can USE MILLIGRAMS (mg) and micrograms (µg). 1000 mg = 1 g, 1000 µg = 1 mg, 1 000 000 µg = 1 g.These are USED in SCIENCE and medicine and you may find that pills and tablets for vitamins or medicines have values of contents in mg or µg. |
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| 43. |
X upon 6=y-6. 3upon 4=1+y |
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Answer» What we have to do in this QUESTION it is INCOMPLETE question |
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| 44. |
in a ∆ ABC angle a =40° ,angle B =80° and agle C = 60° .find the measurment of the angle of the triangle formed by joing the mid point of the sides of the triangle . |
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Answer» MARK AS BRAINLIEST!!!! |
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| 45. |
Saraswati College purchased a computer for their labthe discount of 10% was on the printed price of computer rate of GST charged was 18% purchase price for computer is 47790 find the printed price of computer |
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Answer» CP=SP× 100/100+profit /-LOSE% but there is LESS and more both then CP=47790×100/100+10-18 COMES= 51945 |
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| 46. |
Please answer this question tomarrow is my exam. |
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Answer» Answer: So simple Step-by-step EXPLANATION: |
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| 48. |
Why the period of elected representative has fixed for 5year , not for whole life. |
Answer» Because people choose their own representative as they NEED if they like their WORK then they give more chance if they don't like them then they can CHANGE their representative NEXT time..... |
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| 49. |
Write note on eclipse that you have seen |
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Answer» Answer: An eclipse is an astronomical event that occurs when an astronomical object is temporarily obscured, EITHER by PASSING into the shadow of ANOTHER body or by having another body pass between it and the viewer. This alignment of three celestial objects is known as a syzygy.[1] Apart from syzygy, the TERM eclipse is ALSO used when a spacecraft reaches a position where it can observe two celestial bodies so aligned. An eclipse is the result of either an occultation (completely hidden) or a transit (partially hidden). |
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| 50. |
Mark bought a pen for rupees 150 at a discount of 25% what is the Marked price of the pen |
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Answer» Step-by-step EXPLANATION: MARKED price=150 discount price=25%OF150 =25×150/100 =37.5 new marked price=150-37.5=112.5 |
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