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The area of a triangle ABC is 8cm square in which AB=AC =4cm And angle A is 90 degree |
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Answer» AREA of triangle ABC = 1/2 ×BASE × HEIGHT = 1/2 × AB × AC = 1/2 × 4× 4 = 2 × 4 = 8 cm square LET AD IS PERPENDICULAR TO BC In Triangle ADB AND ADC AD = AD ( common) angle ADC = angle ADB ( each 90 degree) AB = AC (Given) Triangle ADB (congruent to). triangle ADC ( RHS criteria) BD = CD ( cpct ) in triangle ABC , BY Pythagoras THEOREM ABsquare + ACsquare = BC square 4 square +4 square = BCsquare 16 +16 = BCsquare 32 = BC square :. BC = 4√2 cm BD + CD = BC 2BD = BC (. BD = CD ) 2BD = 4√2 BD = 2√2 cm now in triangle BAD , by Pythagoras theorem ADsquare + BD square = ABsquare ADsquare + 2√2 square = 4 square ADsquare + 4×2 = 16 ADsquare + 8 = 16 ADsquare = 16- 8 ADsquare = 8 .: AD = √8 .: AD = 2√2 cm Hence length of perpendicular from A to BC = length of AD = 2√2 cm Read more on Brainly.in - brainly.in/question/2113729#readmore |
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