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Two friends start at the same time from cities P and Q towards cities to Q and P respectively. After meeting at some point between P and Q,they reach their destination in 54 and 24 minutes respectively. In what time did the one who moved from Q to P complete his journey?need explained ans |
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Answer» N will take 60 mins to complete the entire journey from Q to P. Step-by-step explanation: Let the two friends be “M” who will be TRAVELLING from P to Q and “N” who will be travelling from Q to P. Let us CONSIDER the speed of M be “x” and the speed of N be “y”. Also, let them meet after “t” minutes. Case 1: Before M & N meets each other Distance travelled by M = x * t Distance travelled by N = y * t Case 2: After M & N crosses each other Distance travelled by M = x * 54 Distance travelled by N = y * 24 Now, (Distance travelled by M & N before meeting each other) = (Distance travelled by M & N after CROSSING each other) ∴ x * t = x * 54 ….. (i) And, y * t = y * 24 …. (ii) Multiplying equation (i) & (ii), we get xy * t² = xy * 54 * 24 or, t² = 1296 or, t = 36 Since we are required to find the time taken by N to travel the entire journey from city Q to P, therefore, N WOULD take 36 + 24 = 60 minutes to complete his entire journey. |
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