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[(Tan60°) ^2+4cossqare45°+4cosecsqare60°+2secsqare90°]/[2cosec30°+3sec60°-7/3cotsqare30° |
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Answer» VALUE of tan60= sqrt3 cos45 = 1/sqrt2 cosec45=sqrt2 sec90=INFINITY =Tan60°) ^2+4cossqare45°+4cosecsqare60°+2secsqare90°]/[2cosec30°+3sec60°-7/3cotsqare30 =Tan60°) ^2+4cossqare45°+4cosecsqare60°+infinity]/[2cosec30°+3sec60°-7/3cotsqare30 =infinity In the given QUESTION there is sec90 whose value is INFINITE so the and become infinity . |
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