1.

[(Tan60°) ^2+4cossqare45°+4cosecsqare60°+2secsqare90°]/[2cosec30°+3sec60°-7/3cotsqare30°

Answer»

VALUE of

tan60= sqrt3

cos45 = 1/sqrt2

cosec45=sqrt2

sec90=INFINITY

=Tan60°) ^2+4cossqare45°+4cosecsqare60°+2secsqare90°]/[2cosec30°+3sec60°-7/3cotsqare30

=Tan60°) ^2+4cossqare45°+4cosecsqare60°+infinity]/[2cosec30°+3sec60°-7/3cotsqare30

=infinity

In the given QUESTION there is sec90 whose value is INFINITE so the and become infinity .



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