332354 + Interview Questions in Secondary School in Math

1.	One by two of (24 (15 - (17 - 38 ÷19 )
Answer» Step-by-step EXPLANATION: $\frac{1}{2} of(24(15 - (17 - 38 \div 19))) \\ = \frac{1}{2} of(24(15 - (17 - 2))) \\ = \frac{1}{2} of(24(15 - 15)) \\ = \frac{1}{2} of(24 \times 0) \\ = \frac{1}{2} of0 \\ = 0$

1.

One by two of (24 (15 - (17 - 38 ÷19 )

Answer»

Step-by-step EXPLANATION:

$\frac{1}{2} of(24(15 - (17 - 38 \div 19))) \\ = \frac{1}{2} of(24(15 - (17 - 2))) \\ = \frac{1}{2} of(24(15 - 15)) \\ = \frac{1}{2} of(24 \times 0) \\ = \frac{1}{2} of0 \\ = 0$

Discussion

2.	If (a+b):(b+c):(c+a) = 5:6:9 and a+b+c=10,what is the value of c?3456
Answer» Answer: C = 5 Step-by-step explanation: Let, a+b = 5------------(1) b+c = 6------------(2) c+a = 9------------(3) NOW, a+b+c = 10 c = 10 - (a+b) = 10 - 5 [FROM EQUATION------(1)] = 5 And we can check by finding the VALUES of 'a' and 'b'. i.e., {a = 4}, {b = 1} So, a+b+c would always be EQUAL to 10

2.

If (a+b):(b+c):(c+a) = 5:6:9 and a+b+c=10,what is the value of c?3456

Answer»

Answer:

C = 5

Step-by-step explanation:

Let, a+b = 5------------(1)

b+c = 6------------(2)

c+a = 9------------(3)

NOW,

a+b+c = 10

c = 10 - (a+b)

= 10 - 5 [FROM EQUATION------(1)]

= 5

And we can check by finding the VALUES of 'a' and 'b'. i.e., {a = 4}, {b = 1}

So, a+b+c would always be EQUAL to 10

Discussion

3.	If α,β are zeroes 5x²-6x+k, such that α-β = 1/5 the find the value of k
Answer» Answer: 5x²-6x+k is in the FORM of ax²+bx+c alpha = -b/a = -(-6)/5 = 6/5 beta = c/a = k/5 alpha - beta = 6/5-k/5 = (6-k)/5 As PER the question, 1/5 = (6-k)/5 1 = 6-k k = 6-1 = 5

3.

If α,β are zeroes 5x²-6x+k, such that α-β = 1/5 the find the value of k

Answer»

Answer:

5x²-6x+k is in the FORM of ax²+bx+c

alpha = -b/a = -(-6)/5 = 6/5

beta = c/a = k/5

alpha - beta = 6/5-k/5 = (6-k)/5

As PER the question,

1/5 = (6-k)/5

1 = 6-k

k = 6-1 = 5

Discussion

4.	The value of ( 530 x 520) ÷ ( 55)9in the exponential form is
Answer» Step-by-step EXPLANATION: hxhxzgyzsyysyadjffjicdyxcuic

4.

The value of ( 530 x 520) ÷ ( 55)9in the exponential form is

Answer»

Step-by-step EXPLANATION:

hxhxzgyzsyysyadjffjicdyxcuic

Discussion

5.	Divide 2x3-x2-2x-7 by x-2
Answer» ANSWER: the REMINDER is 1. and QUOTIENT is 2x^2+3x+4

5.

Divide 2x3-x2-2x-7 by x-2

Answer»

ANSWER:

the REMINDER is 1.

and QUOTIENT is 2x^2+3x+4

Discussion

6.	Express 1÷(1+√2 - √3) as an equivalent fraction with a rational denominator
Answer» Step-by-step EXPLANATION: Go on rationalizing the numerator or the denominator with the DISCRIMINANT and finally MULTIPLY the denominator with an irrational no. if it comes as a complex DIGIT and finally get an equivalent rational denominator.

6.

Express 1÷(1+√2 - √3) as an equivalent fraction with a rational denominator

Answer»

Step-by-step EXPLANATION:

Go on rationalizing the numerator or the denominator with the DISCRIMINANT and finally MULTIPLY the denominator with an irrational no. if it comes as a complex DIGIT and finally get an equivalent rational denominator.

Discussion

7.	Prove This
Answer» $\huge\boxed{\underline{\mathcal{\red{A}\green{N}\pink{S}\orange{W}\blue{E}\pink{R}}}}$ $\text{[math]}$ $\text{[math]}$ $\bold{\frac{tanQ}{(1 - cotQ)} + \frac{cotQ}{(1 - tanQ)} = (1 + secQcosecQ)}$ LHS, $\bold{\frac{sinQ}{cosQ} /\frac{1-cosQ} {sinQ} +\frac{cosQ}{sinQ} /\frac{1-sinQ} {cosQ}}$ $\bold{\frac{SinQ}{cosQ} /\frac{sinQ-cosQ} {sinQ} +\frac{cosQ}{sinQ} /\frac{cosQ-sinQ}{cosQ}}$ $\bold{\frac{sin^2Q}{cosQ(sinQ-cosQ)} +\frac{cos^2Q}{sinQ(cosQ-sinQ)}}$ $\bold{\frac{sin^3Q+cos^3Q} {sinQcosQ(sinQ-cosQ)}}$ $\bold{\frac{(sinQ-cosQ)(sin^2Q+cos^2Q+sinQcosQ)}{sinQcosQ(sinQ-cosQ)}}$ $\bold{\frac{sin^2Q+cos^2Q+sinQcosQ} {sinQcosQ}}$ $\bold{\frac{1+sinQcosQ}{sinQcosQ}}$ $\bold{\frac{1}{sinQcosQ}+1}$ $\bold{cosecQsecQ+1}$ . RHS $\text{[math]}$ $\bold{LHS=RHS}$ $\text{[math]}$ $\bold{Hence proved}$

7.

Prove This

Answer»

$\huge\boxed{\underline{\mathcal{\red{A}\green{N}\pink{S}\orange{W}\blue{E}\pink{R}}}}$ $\text{[math]}$

$\text{[math]}$

$\bold{\frac{tanQ}{(1 - cotQ)} + \frac{cotQ}{(1 - tanQ)} = (1 + secQcosecQ)}$

LHS,

$\bold{\frac{sinQ}{cosQ} /\frac{1-cosQ} {sinQ} +\frac{cosQ}{sinQ} /\frac{1-sinQ} {cosQ}}$

$\bold{\frac{SinQ}{cosQ} /\frac{sinQ-cosQ} {sinQ} +\frac{cosQ}{sinQ} /\frac{cosQ-sinQ}{cosQ}}$

$\bold{\frac{sin^2Q}{cosQ(sinQ-cosQ)} +\frac{cos^2Q}{sinQ(cosQ-sinQ)}}$

$\bold{\frac{sin^3Q+cos^3Q} {sinQcosQ(sinQ-cosQ)}}$

$\bold{\frac{(sinQ-cosQ)(sin^2Q+cos^2Q+sinQcosQ)}{sinQcosQ(sinQ-cosQ)}}$

$\bold{\frac{sin^2Q+cos^2Q+sinQcosQ} {sinQcosQ}}$

$\bold{\frac{1+sinQcosQ}{sinQcosQ}}$

$\bold{\frac{1}{sinQcosQ}+1}$

$\bold{cosecQsecQ+1}$ . RHS $\text{[math]}$

$\bold{LHS=RHS}$ $\text{[math]}$

$\bold{Hence proved}$

Discussion

8.	X² +4x+1 by completing square
Answer» Solve the quadratic equation x^2 + 4x +1 = 0 by COMPLETING the square. The FIRST step is to divide the COEFFICIENT of x by 2, and add this to x (this is our value of 'a' to GO inside our bracket). We then square this value of a and subtract it outside the bracket. We have our equation in completed square form

8.

X² +4x+1 by completing square

Answer»

Solve the quadratic equation x^2 + 4x +1 = 0 by COMPLETING the square. The FIRST step is to divide the COEFFICIENT of x by 2, and add this to x (this is our value of 'a' to GO inside our bracket). We then square this value of a and subtract it outside the bracket. We have our equation in completed square form

Discussion

9.	11'48'927'1664'25125 what next
Answer» Answer: 36216 It was the square of 6 then cube of 6. HOPE IT HELPS.............. MARK IT BRAINLIEST.

9.

11'48'927'1664'25125 what next

Answer»

Answer:

36216

It was the square of 6 then cube of 6.

HOPE IT HELPS..............

MARK IT BRAINLIEST.

Discussion

10.	living among machines have mechanised mam more. we are rapidly losing human value .express your views for or against in 1000 words
Answer»

Discussion

11.	The most imporant part of a map is the
Answer» Answer: data FRAME The data frame is the portion of the map that DISPLAYS the data LAYERS. This section is the most IMPORTANT and CENTRAL focus of the map document.

11.

The most imporant part of a map is the

Answer»

Answer:

data FRAME

The data frame is the portion of the map that DISPLAYS the data LAYERS. This section is the most IMPORTANT and CENTRAL focus of the map document.

Discussion

12.	With solution .............
Answer»

Discussion

13.	Help me explain steps
Answer» Answer: Step-by-step explanation: From the properties of of LOGARITHMS we know, loga + LOGB + logc = log( aBC ) The same, applying here: $\implies\mathrm{log\dfrac{a^2}{bc} +log\dfrac{b^2}{ac}+log\dfrac{c^2}{ab}}\\\\\\\implies\mathrm{ log\bigg(\dfrac{a^2}{bc} \times\dfrac{ b^2}{ac}\times\dfrac{c^2}{ab}\bigg)}\\\\\\\implies\mathrm{log\bigg( \dfrac{a^2 \times b^2 \times c^2 }{ ab \times bc \times ac} \bigg)}\\\\\\\implies \mathrm{log\bigg( \dfrac{a^2 \times b^2 \times c^2 }{a^2 \times b^2 \times c^2} \bigg)}$ ⇒ log 1 ⇒ 0 { log 1 = 0 } Hence proved.

13.

Help me explain steps

Answer»

Answer:

Step-by-step explanation:

From the properties of of LOGARITHMS we know,

loga + LOGB + logc = log( a*B*C )

The same, applying here:

$\implies\mathrm{log\dfrac{a^2}{bc} +log\dfrac{b^2}{ac}+log\dfrac{c^2}{ab}}\\\\\\\implies\mathrm{ log\bigg(\dfrac{a^2}{bc} \times\dfrac{ b^2}{ac}\times\dfrac{c^2}{ab}\bigg)}\\\\\\\implies\mathrm{log\bigg( \dfrac{a^2 \times b^2 \times c^2 }{ ab \times bc \times ac} \bigg)}\\\\\\\implies \mathrm{log\bigg( \dfrac{a^2 \times b^2 \times c^2 }{a^2 \times b^2 \times c^2} \bigg)}$

⇒ log 1

⇒ 0 { log 1 = 0 }

Hence proved.

Discussion

14.	Please, answer this............
Answer» HOPE this HELPS you out MARK as BRAINLIEST PLS..

14.

Please, answer this............

Answer»

HOPE this HELPS you out

MARK as BRAINLIEST PLS..

Discussion

15.	Calculate the missing angle and give reason for your answer and say the reason for 9,10 11,12 answers..plz say fast
Answer» Answer: 9) Liner pair=180-77=113. 11) Liner pair=180-155=35. 10)Liner pair=180-94=86. PLEASE GIVE the DEGREE of the NUMBER.

15.

Calculate the missing angle and give reason for your answer and say the reason for 9,10 11,12 answers..plz say fast

Answer»

Answer:

9) Liner pair=180-77=113. 11) Liner pair=180-155=35.

10)Liner pair=180-94=86. PLEASE GIVE the DEGREE of the NUMBER.

Discussion

16.	write the number name and expanded form of the following numbers in the Indian system of numeration a)43,72,901 b)27,47,608
Answer» Answer: 43 lakh ,72 THOUSAND and 901 27 lakh ,47 thousand and 608 Step-by-step explanation: PLEASE MARK me as brainliest

16.

write the number name and expanded form of the following numbers in the Indian system of numeration a)43,72,901 b)27,47,608

Answer»

Answer:

43 lakh ,72 THOUSAND and 901

27 lakh ,47 thousand and 608

Step-by-step explanation:

PLEASE MARK me as brainliest

Discussion

17.	V13+yl11. If x = 3 +2./2, check whether x + is rational or irrational.X
Answer» Step-by-step EXPLANATION: HEY it"s a rational number if you want explanation FOLLOW the pic mark as BRAINLY answer

17.

V13+yl11. If x = 3 +2./2, check whether x + is rational or irrational.X

Answer»

Step-by-step EXPLANATION:

HEY it"s a rational number if you want explanation FOLLOW the pic

mark as BRAINLY answer

Discussion

18.	X2+7x+12=0 by completing squares
Answer» Step-by-step explanation: *x2 + 2x7/2 +49/4 -49/4 +12=0* (x+7/2)^2 = (49-48)/4 x + 7/2= plusminus 1/2 i) if x + 7/2= 1/2 then x = -3 ii) if x + 7/2 =-1/2 then x = -4 HOPE this HELPS!

18.

X2+7x+12=0 by completing squares

Answer»

Step-by-step explanation:

x2 + 2*x*7/2 +49/4 -49/4 +12=0

(x+7/2)^2 = (49-48)/4

x + 7/2= plusminus 1/2

i) if x + 7/2= 1/2

then x = -3

ii) if x + 7/2 =-1/2

then x = -4

HOPE this HELPS!

Discussion

19.	A can complete a given task in 24 days, while B istwice as efficient as he. A started on the work initially,and was joined by B after a few days. If the wholework was completed in 10 days, after how many days,from the time A started working, did B join A?
Answer» Answer: Step-by-step EXPLANATION: `A is twice as good as B. Let B=x,A=2x A and B can complete the work together in 20 days. So,(A+B)’s 20 days’ work=1 (A+B)’s 1 day’s work=1/20 So, x+2x=1/20 3x=1/20 x=1/60 2x=1/30 A’s ONE day’s work=1/30 A can complete the work alone in 30 days. PLZZ MARK ME THE BRAINLIEST.. :):)

19.

A can complete a given task in 24 days, while B istwice as efficient as he. A started on the work initially,and was joined by B after a few days. If the wholework was completed in 10 days, after how many days,from the time A started working, did B join A?

Answer»

Answer:

Step-by-step EXPLANATION:

`A is twice as good as B.

Let B=x,A=2x

A and B can complete the work together in 20 days.

So,(A+B)’s 20 days’ work=1

(A+B)’s 1 day’s work=1/20

So,

x+2x=1/20

3x=1/20

x=1/60

2x=1/30

A’s ONE day’s work=1/30

A can complete the work alone in 30 days.

PLZZ MARK ME THE BRAINLIEST.. :):)

Discussion

20.	Who said, "Number rules the universe"?
Answer» ANSWER: This quote was SAID by Pythagoras. Step-by-step explanation: Hope this helps u. Plz mark me BRAINLIEST if you found it helpful. Also Pythagoras was a great GREEK MATHEMATICIAN of his time famous for his Pythagoras Theorem.

20.

Who said, "Number rules the universe"?

Answer»

ANSWER:

This quote was SAID by Pythagoras.

Step-by-step explanation:

Hope this helps u. Plz mark me BRAINLIEST if you found it helpful. Also Pythagoras was a great GREEK MATHEMATICIAN of his time famous for his Pythagoras Theorem.

Discussion

21.	The number added to another numbe to get the sum
Answer» ANSWER: ADDITION. When two NUMBERS are added TOGETHER, the result is called a SUM. The two numbers being added together are called addends

21.

The number added to another numbe to get the sum

Answer»

ANSWER:

ADDITION. When two NUMBERS are added TOGETHER, the result is called a SUM. The two numbers being added together are called addends

Discussion

22.	The sum of measure of the internal angles of a parallelogram is
Answer» Answer: 360 degree Step-by-step EXPLANATION:

22.

The sum of measure of the internal angles of a parallelogram is

Answer»

Answer:

360 degree

Step-by-step EXPLANATION:

Discussion

23.	It was the final game of the season and, with a little bit of luck, Peter’s football team could win the championship.His team needed to beat John’s team by three goals, but they also needed to score at least 4 more goals than David’s team, who was playing Ben’s team.David’s team beat Ben’s team by 1 goal.If Ben’s team scored 1 goal in each half, what is the closest score Peter’s team could beat David’s team by to win the championship
Answer» ANSWER: jzjs COMMON you gonna THING do are sjgsdhdhdkdiwu

23.

It was the final game of the season and, with a little bit of luck, Peter’s football team could win the championship.His team needed to beat John’s team by three goals, but they also needed to score at least 4 more goals than David’s team, who was playing Ben’s team.David’s team beat Ben’s team by 1 goal.If Ben’s team scored 1 goal in each half, what is the closest score Peter’s team could beat David’s team by to win the championship

Answer»

ANSWER:

jzjs COMMON you gonna THING do are sjgsdhdhdkdiwu

Discussion

24.	On dividing 51160 by a certain number , the Question is 3654 and the remainder is 18 . Find the divisor ?
Answer» ANSWER: the DIVISOR is 13.99617

24.

On dividing 51160 by a certain number , the Question is 3654 and the remainder is 18 . Find the divisor ?

Answer»

ANSWER:

the DIVISOR is 13.99617

Discussion

25.	What is 84cm as a percent as 12m
Answer» Answer: 7% Step-by-step explanation: so FIRST we convert EVERYTHING into cm 84 cm=84 cm 12 m=1200 cm now, as in percentage, (84/1200)*100 = 7% i hope my answer helped you, and don't FORGET i MIGHT be wrong.

25.

What is 84cm as a percent as 12m

Answer»

Answer:

7%

Step-by-step explanation:

so FIRST we convert EVERYTHING into cm

84 cm=84 cm
12 m=1200 cm

now, as in percentage,

(84/1200)*100 = 7%

i hope my answer helped you, and don't FORGET i MIGHT be wrong.

Discussion

26.	What is the value of 15/6-2/3-3/2
Answer» Answer: 1/3 Step-by-step EXPLANATION:

26.

What is the value of 15/6-2/3-3/2

Answer»

Answer:

1/3

Step-by-step EXPLANATION:

Discussion

27.	At what point does the graph of equation 2x+3y=9 meet a line which is parallel to y -axis at a distance 4 units from the origin and on the right side of the y-axis
Answer» ANSWER: (4,⅓) Step-by-step explanation: Given an equation of a line such that, 2x + 3Y = 9 Also, statement is given for another line. The another line is parallel to y axis at a distance of 4 units from the origin. Therefore, clealry, we have, SINCE it's parallel to y axis, Therefore, the x coordinate will be fix THROUGHOUT the line. And, it's diatance from origin is 4 units. Therefore, the eqn will be, x = 4. Now, substituting this value in eqn of first line, Therefore, we will get, => 2(4) + 3y = 9 => 8 + 3y = 9 => 3y = 9 - 8 => 3y = 1 => y = ⅓ Therefore, point of intersection is (4,⅓). Hence, the graph of the given line will meet the another line at the point (4,⅓).

27.

At what point does the graph of equation 2x+3y=9 meet a line which is parallel to y -axis at a distance 4 units from the origin and on the right side of the y-axis

Answer»

ANSWER:

(4,⅓)

Step-by-step explanation:

Given an equation of a line such that,

2x + 3Y = 9

Also, statement is given for another line.

The another line is parallel to y axis at a distance of 4 units from the origin.

Therefore, clealry, we have,

SINCE it's parallel to y axis,

Therefore, the x coordinate will be fix THROUGHOUT the line.

And, it's diatance from origin is 4 units.

Therefore, the eqn will be,

x = 4.

Now, substituting this value in eqn of first line,

Therefore, we will get,

=> 2(4) + 3y = 9

=> 8 + 3y = 9

=> 3y = 9 - 8

=> 3y = 1

=> y = ⅓

Therefore, point of intersection is (4,⅓).

Hence, the graph of the given line will meet the another line at the point (4,⅓).

Discussion

28.	Verify whether 2 and furious of the polynomial x cube minus 4 x square + 2
Answer» ANSWER: no it is not a root Step-by-step EXPLANATION:

28.

Verify whether 2 and furious of the polynomial x cube minus 4 x square + 2

Answer»

ANSWER:

no it is not a root

Step-by-step EXPLANATION:

Discussion

29.	A certain sum of. money placed out at C.I. ,amounts to Rs6272 in 2 years nd to Rs 7024.64 in 3yrs. Find rate of intetest and principal ,solve it without using formula. * please answer fast
Answer» ANSWER: MARK as BRANLIEST and FOLLOW me

29.

A certain sum of. money placed out at C.I. ,amounts to Rs6272 in 2 years nd to Rs 7024.64 in 3yrs. Find rate of intetest and principal ,solve it without using formula. * please answer fast

Answer»

ANSWER:

MARK as BRANLIEST and FOLLOW me

Discussion

30.	Name the property 16*32 is a whole number
Answer» ANSWER: it is a DISTRIBUTIVE PROPERTY

30.

Name the property 16*32 is a whole number

Answer»

ANSWER:

it is a DISTRIBUTIVE PROPERTY

Discussion

31.	Q is a point on y axis at a distance of a 7 unit x axis below xaxis then the the coordinates
Answer» ANSWER: I did not UNDERSTAND QUESTION

31.

Q is a point on y axis at a distance of a 7 unit x axis below xaxis then the the coordinates

Answer»

ANSWER:

I did not UNDERSTAND QUESTION

Discussion

32.	Write the greatest and smallest 5digit number using 2,6,3,0,8 without repeating the digits
Answer» ANSWER: GREATEST - 86320 , SMALLEST - 20368

32.

Write the greatest and smallest 5digit number using 2,6,3,0,8 without repeating the digits

Answer»

ANSWER:

GREATEST - 86320 , SMALLEST - 20368

Discussion

33.	Prove that mode of one a a square a square one a square 1 is equal to a cube minus 1 whole square
Answer» hsvshdjdhdjbdudnsksowowbeioeoeheiejbsus in s HU sbvsjsusjsbsheijejsjskaopa

Discussion

34.	Evaluate the following: 125 3/p^3 - 3/125 p^3
Answer» THINK so that your QUESTION is WRONG

Discussion

35.	Express the following rational number is decimals by using long division method:- 31/27
Answer» Answer: 31 ÷ 27 = 1.1481481481 through LONG DIVISION method Mark me as BRAINLIEST

35.

Express the following rational number is decimals by using long division method:- 31/27

Answer»

Answer:

31 ÷ 27 = 1.1481481481 through LONG DIVISION method

Mark me as BRAINLIEST

Discussion

36.	Factorize using suitable identity 998^4-4
Answer» ANSWER: your answer is =0 ....... .

36.

Factorize using suitable identity 998^4-4

Answer»

ANSWER:

your answer is

=0

.......

.

Discussion

37.	If the cost of mangoes is 146/3 rupees then how much quantity of mangoes can be purchased for 438 rupees
Answer» Answer: 5⁰00000⁰000000000000

37.

If the cost of mangoes is 146/3 rupees then how much quantity of mangoes can be purchased for 438 rupees

Answer»

Answer:

5⁰00000⁰000000000000

Discussion

38.	Find the Rational number between 9/6 7/6
Answer» ANSWER: RATIONAL no between 9/6 ANA 7/6 are 9/6 ×10=90/60 7/6×10=70/60 rational no are 71/60, 72/60, 73) 60,74/69, 75/60

38.

Find the Rational number between 9/6 7/6

Answer»

ANSWER:

RATIONAL no between 9/6 ANA 7/6 are

9/6 ×10=90/60

7/6×10=70/60

rational no are 71/60, 72/60, 73) 60,74/69, 75/60

Discussion

39.	Draw 2 intersecting lines such that one of the angle thus formed is 70 degree. Find the measure of the remaining angles formed.
Answer» Step-by-step explanation: wait few MINUTES I will GIVE answer IMMEDIATELY

39.

Draw 2 intersecting lines such that one of the angle thus formed is 70 degree. Find the measure of the remaining angles formed.

Answer»

Step-by-step explanation:

wait few MINUTES I will GIVE answer IMMEDIATELY

Discussion

40.	A number x is chosen from the numbers -4, -3, -2, -1, 0, 1, 2, 3, 4. Find the probability that \|x\|
Answer» Step-by-step EXPLANATION: HOPE it helps You can MARK it as brainliest answer and ALSO FOLLOW me Thank you

40.

A number x is chosen from the numbers -4, -3, -2, -1, 0, 1, 2, 3, 4. Find the probability that |x|

Answer»

Step-by-step EXPLANATION:

HOPE it helps

You can MARK it as brainliest answer and ALSO FOLLOW me

Thank you

Discussion

41.	Answer these Maths Question i will mark u as brainliest if ur answers are right
Answer» BHAI tu ye Kya Kar raha hai ye Tera unit TEST hai khud SE answer deneka koshis Kar.. Try to answer your own please don't ASK exam questions.. Hope you understand.. No NEED to follow me on... No need to mark me as the brainliest.. Only say do it just do it.... Best of luck jashanpreet90. ________________________________ If u ask me any other questions I will be glad to answer those questions but don't ask exam questions..

41.

Answer these Maths Question i will mark u as brainliest if ur answers are right

Answer»

BHAI tu ye Kya Kar raha hai ye Tera unit TEST hai khud SE answer deneka koshis Kar..

Try to answer your own please don't ASK exam questions..

Hope you understand..

No NEED to follow me on...

No need to mark me as the brainliest..

Only say do it just do it....

Best of luck jashanpreet90.

________________________________

If u ask me any other questions I will be glad to answer those questions but don't ask exam questions..

Discussion

42.	6. Verify that the solution set of the following constraintsis empty :3x + 4y > 12, x + 2y < 3, x>0, y1.
Answer» ANSWER: What is this can you just WRITE it again Step-by-step EXPLANATION:

42.

6. Verify that the solution set of the following constraintsis empty :3x + 4y > 12, x + 2y < 3, x>0, y1.

Answer»

ANSWER:

What is this can you just WRITE it again

Step-by-step EXPLANATION:

Discussion

43.	74. A diagonal of a parallelogram bisects one of its angles. Show that it is a rhombus P and Q arethe mid-points of the opposite sides AB and CD of a parallelogram
Answer» ANSWER: MARK me as brainlist and HOPE it HELPS you

43.

74. A diagonal of a parallelogram bisects one of its angles. Show that it is a rhombus P and Q arethe mid-points of the opposite sides AB and CD of a parallelogram

Answer»

ANSWER:

MARK me as brainlist

and HOPE it HELPS you

Discussion

44.	An alloy consist of 72g of copper and 9g of tin.find the ratio of a) tin to that of copper b)copper to that of tin. C)copper to the total weight of alloy
Answer» ANSWER: here's the answer for the QUESTION

44.

An alloy consist of 72g of copper and 9g of tin.find the ratio of a) tin to that of copper b)copper to that of tin. C)copper to the total weight of alloy

Answer»

ANSWER:

here's the answer for the QUESTION

Discussion

45.	11. The value of a machine depreciates at the rate of 10% per annum. If its presentvalue is Rs. 1,62,000, what will be its worth after 2 years? What was the value ofthe machine 2 years ago?
Answer» $\huge{Question:-}$ The value of a machine DEPRECIATES at the RATE of 10% per ANNUM. If its present value is ₹1,62,000. What will be its worth after 2 years? What was the value of the machine 2 years ago? $\huge{\red{Solution:-}}$ Present value of the machine = ₹1,62,000 Rate of depreciation = 10% Value of depreciation = $\frac{10}{100}×{162000}$ = ₹16,200 Value of machine after two years: Value of machine after 1 year=₹(162000-16200) = ₹1,45,800 Value of depreciation = $\frac{10}{100}×{145800}$ = ₹14,580 Value of machine after 2 years=₹(145800-14580) = ₹1,31,220 Value of machine two years ago: let value of machine 1 year ago be ₹'x' Then, According to the Question:- Value of machine 1 year ago= ${x}-(\frac{10}{100}×{x}) = {162000}$ $=>{x}-(\frac{x}{10}) = {162000}$ $=>(\frac{10x-x}{10}) = {162000}$ $=>{9x} = {1620000}$ $=>{x} =\frac{1620000}{9}$ =>x =₹1,80,000 let value of machine 2 year ago be ₹'y' Then, ACCORDING to the Question:- Value of machine 1 year ago= ${y}-(\frac{10}{100}×{y}) = {180000}$ $=>{y}-(\frac{y}{10}) = {180000}$ $=>(\frac{10y-y}{10}) = {180000}$ $=>{9y} = {1800000}$ $=>{y} =\frac{1800000}{9}$ => y = ₹2,00,000 $\huge{\boxed{\red{Answer:-}}}$ Value of machine after 2 years = ₹1,31,220 Value of machine 2 years ago = ₹2,00,000

45.

11. The value of a machine depreciates at the rate of 10% per annum. If its presentvalue is Rs. 1,62,000, what will be its worth after 2 years? What was the value ofthe machine 2 years ago?

Answer»

$\huge{Question:-}$

The value of a machine DEPRECIATES at the RATE of 10% per ANNUM. If its present value is ₹1,62,000. What will be its worth after 2 years? What was the value of the machine 2 years ago?

$\huge{\red{Solution:-}}$

Present value of the machine = ₹1,62,000

Rate of depreciation = 10%

Value of depreciation = $\frac{10}{100}×{162000}$

= ₹16,200

Value of machine after two years:

Value of machine after 1 year=₹(162000-16200)

= ₹1,45,800

Value of depreciation = $\frac{10}{100}×{145800}$

= ₹14,580

Value of machine after 2 years=₹(145800-14580)

= ₹1,31,220

Value of machine two years ago:

let value of machine 1 year ago be ₹'x'

Then,

According to the Question:-

Value of machine 1 year ago= ${x}-(\frac{10}{100}×{x}) = {162000}$

$=>{x}-(\frac{x}{10}) = {162000}$

$=>(\frac{10x-x}{10}) = {162000}$

$=>{9x} = {1620000}$

$=>{x} =\frac{1620000}{9}$

=>x =₹1,80,000

let value of machine 2 year ago be ₹'y'

Then,

ACCORDING to the Question:-

Value of machine 1 year ago= ${y}-(\frac{10}{100}×{y}) = {180000}$

$=>{y}-(\frac{y}{10}) = {180000}$

$=>(\frac{10y-y}{10}) = {180000}$

$=>{9y} = {1800000}$

$=>{y} =\frac{1800000}{9}$

=> y = ₹2,00,000

$\huge{\boxed{\red{Answer:-}}}$

Value of machine after 2 years = ₹1,31,220

Value of machine 2 years ago = ₹2,00,000

Discussion

46.	Fifteen workers working for six hours aday can complete a work in 40 days.Then, how many days will 20 workersworking for four hours a day take tocomplete the same work?45 daysO38 days54 days42 daysO
Answer» Answer: 4 HOURS x 12 days=48 total hours worked 48 hours x 10 men=480 man/hours 1 man/480 total hours=1/480th of the work done per man per hour 8 x 6 x 1/480=1/10 work done per day 1 work / 1/10 work done per day=10 days NECESSARY to finish the work hope it HELPS you

46.

Fifteen workers working for six hours aday can complete a work in 40 days.Then, how many days will 20 workersworking for four hours a day take tocomplete the same work?45 daysO38 days54 days42 daysO

Answer»

Answer:

4 HOURS x 12 days=48 total hours worked

48 hours x 10 men=480 man/hours

1 man/480 total hours=1/480th of the work done per man per hour

8 x 6 x 1/480=1/10 work done per day

1 work / 1/10 work done per day=10 days NECESSARY to finish the work

hope it HELPS you

Discussion

47.	Let the no.'s are (a - 3d) (a + d) (a+d) (a+3d) sum of terms = 32
Answer» ANSWER: Here is the CORRECT answer MATE... Thank you ☺✌..

47.

Let the no.'s are (a - 3d) (a + d) (a+d) (a+3d) sum of terms = 32

Answer»

ANSWER:

Here is the CORRECT answer MATE...

Thank you ☺✌..

Discussion

48.	Write the following sets in roaster form :- 1. A = {An: n€N , An+1 = 3An and A1= 2 }
Answer» $Given \: A=\{A_{n}:n\in N , A_{n+1} = 3A_{n} \:and \: A_{1} = 2 \}$ $i )A_{1} = 2 \: --(1)$ $ii ) If \: n = 1 \implies A_{1+1} = 3 \times A_{1}$ $\implies A_{2} = 3 \times 2 = 6$ $iii ) If \: n = 2 \implies A_{2+1} = 3 \times A_{2}$ $\implies A_{3} = 3 \times 6 = 18$ $iv ) If \: n = 3 \implies A_{3+1} = 3 \times A_{3}$ $\implies A_{4} = 3 \times 18 = 54$ $v ) If \: n = 4 \implies A_{4+1} = 3 \times A_{4}$ $\implies A_{5} = 3 \times 54 = 162$ THEREFORE., $\red{ Roster \: form \: of \: set \: A }$ $\green { = \{ 2,6,18,162, \ldots \}}$ •••♪

48.

Write the following sets in roaster form :- 1. A = {An: n€N , An+1 = 3An and A1= 2 }

Answer»

$Given \: A=\{A_{n}:n\in N , A_{n+1} = 3A_{n} \:and \: A_{1} = 2 \}$

$i )A_{1} = 2 \: --(1)$

$ii ) If \: n = 1 \implies A_{1+1} = 3 \times A_{1}$

$\implies A_{2} = 3 \times 2 = 6$

$iii ) If \: n = 2 \implies A_{2+1} = 3 \times A_{2}$

$\implies A_{3} = 3 \times 6 = 18$

$iv ) If \: n = 3 \implies A_{3+1} = 3 \times A_{3}$

$\implies A_{4} = 3 \times 18 = 54$

$v ) If \: n = 4 \implies A_{4+1} = 3 \times A_{4}$

$\implies A_{5} = 3 \times 54 = 162$

THEREFORE.,

$\red{ Roster \: form \: of \: set \: A }$

$\green { = \{ 2,6,18,162, \ldots \}}$

•••♪

Discussion

49.	3p²+4=-4p by completing square method
Answer» ANSWER: i HOPE this will HELP you THANK you....

49.

3p²+4=-4p by completing square method

Answer»

ANSWER:

i HOPE this will HELP you THANK you....

Discussion

50.	2par5=32 in logarithmic form
Answer» *ANSWER:A = {An: n€N , An+1 = 3An and A1= 2 } 3p²+4=-4p by completing SQUARE method 2par5=32 in logarithmic form 6. Step-by-step explanation:**

50.

2par5=32 in logarithmic form

Answer»

ANSWER:A = {An: n€N , An+1 = 3An and A1= 2 } 3p²+4=-4p by completing SQUARE method 2par5=32 in logarithmic form *6.

Step-by-step explanation:

Discussion

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