1.

At what point does the graph of equation 2x+3y=9 meet a line which is parallel to y -axis at a distance 4 units from the origin and on the right side of the y-axis

Answer»

ANSWER:

(4,⅓)

Step-by-step explanation:

Given an equation of a line such that,

2x + 3Y = 9

Also, statement is given for another line.

The another line is parallel to y axis at a distance of 4 units from the origin.

Therefore, clealry, we have,

SINCE it's parallel to y axis,

Therefore, the x coordinate will be fix THROUGHOUT the line.

And, it's diatance from origin is 4 units.

Therefore, the eqn will be,

x = 4.

Now, substituting this value in eqn of first line,

Therefore, we will get,

=> 2(4) + 3y = 9

=> 8 + 3y = 9

=> 3y = 9 - 8

=> 3y = 1

=> y = ⅓

Therefore, point of intersection is (4,⅓).

Hence, the graph of the given line will meet the another line at the point (4,⅓).


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