If α,β are zeroes 5x²-6x+k, such that α-β = 1/5 the find the valu

1.	If α,β are zeroes 5x²-6x+k, such that α-β = 1/5 the find the value of k
Answer» Answer: 5x²-6x+k is in the FORM of ax²+bx+c alpha = -b/a = -(-6)/5 = 6/5 beta = c/a = k/5 alpha - beta = 6/5-k/5 = (6-k)/5 As PER the question, 1/5 = (6-k)/5 1 = 6-k k = 6-1 = 5

If α,β are zeroes 5x²-6x+k, such that α-β = 1/5 the find the value of k

Answer»

Answer:

5x²-6x+k is in the FORM of ax²+bx+c

alpha = -b/a = -(-6)/5 = 6/5

beta = c/a = k/5

alpha - beta = 6/5-k/5 = (6-k)/5

As PER the question,

1/5 = (6-k)/5

1 = 6-k

k = 6-1 = 5

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If α,β are zeroes 5x²-6x+k, such that α-β = 1/5 the find the value of k

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