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Help me explain steps ​

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Answer:

Step-by-step explanation:

From the properties of of LOGARITHMS we know,

  loga + LOGB + logc = log( a*B*C )

The same, applying here:

\implies\mathrm{log\dfrac{a^2}{bc} +log\dfrac{b^2}{ac}+log\dfrac{c^2}{ab}}\\\\\\\implies\mathrm{ log\bigg(\dfrac{a^2}{bc} \times\dfrac{ b^2}{ac}\times\dfrac{c^2}{ab}\bigg)}\\\\\\\implies\mathrm{log\bigg( \dfrac{a^2 \times b^2 \times c^2 }{ ab \times bc \times ac} \bigg)}\\\\\\\implies \mathrm{log\bigg( \dfrac{a^2 \times b^2 \times c^2 }{a^2 \times b^2 \times c^2} \bigg)}

⇒ log 1

⇒ 0      { log 1 = 0 }

 Hence proved.


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