This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 2. |
Ugram are 12 cm and 8 cm. The lengt0 m, find its altitude.Ulot CowespondOf colength of the aucorresponding to the otheraltitude 1.75 m. find the costblue 12 cm is 6 cm. Find the length of the altitude corresA field in the form of a parallelogram has base 32 m and altitudthe field at 8 per sq. m.7. A parallelogram has a side of 20 cm and 15 cm and the perpendic18 cm. Find the distance between 15 cm side.6. The base of a parallelogram is twice its height. If the area of the paralleBase and the height.The area of rhombus is 64 sq. m. If its perimeter is 32 m, find its altitude10. The area of the rhombus is 48 m², if one of its diagonal is 16 m, find the leIn figure, ABCD is a parallelogram and CE I AD, DF 1 AB. If AD = 20 m, CE sefind DFendicular distance betweenof the parallelogram is 3250ADE260 Mathematics In Real Life-7 |
|
Answer» get solve your all doubts instantly on mysolvebook.com within 24HRS guaranteed mysolvebook.com is ONE of the India's BEST educational PLATFORM |
|
| 3. |
(2) In the circle with centre 0. chords AB and CD areperpendicular to each other at M. Arcs ABD and CAB aremajor arcs. if LABD - x and ZCAB-y" then suggest any twopairs of values of x and y. Justify your answer.MODEL QUESTION PAPER |
|
Answer» Step-by-step explanation: we USE the PROPERTY i.e, ANGLES on the same ARC are equal. from the above figure, angle ABD = X and angle ACD = x , as both angles are in the same arc ABD . & angle CAB = y angle CDB = y , as both agles are in the same arc CAB . so, angle ABD = angle ACD = x & angle CAB = angle CDB = y |
|
| 4. |
How marks needed in written to pass maths of hsc |
|
Answer» Answer: The HSC Maths theory paper is of around 80 MARKS. Maths 1 and Maths 2 each of 40 marks. So you need minimum 14 marks in each M1 and M2 RESPECTIVELY. Or in total 28 marks are required which is equal to 35% to pass the Maths paper. |
|
| 5. |
দুটি ট্রেন 200 km দূরবর্তী দুটি স্টেশন থেকে একে অপরেরদিকে একই সময়ে যাত্রা শুরু করে। কোনাে একটি স্টেশন| থেকে 110 km দূরে তাদের দেখা হলে, ট্রেনদুটির গতিবেগের| অনুপাত কত? |
|
Answer» Answer: I don't KNOW sorry for that plz ask your questions in ENGLISH I hope you UNDERSTAND plz give response with thanked and mark as BRAINLIEST |
|
| 6. |
EXAMPLE 5 Simplify each of the following:7n+2 – 3x71+1..., 5n+3 – 6 x 5n+120x7" – 2x719x51 - 22x51n+2+1on2- |
|
Answer» Step-by-step EXPLANATION: What is this..... ??? |
|
| 7. |
Prove that:(a - b)3 + (b – c)3 +(c - a)3 = 3(a - b)(b – c)(c-a) |
|
Answer» Step-by-step explanation: (a - B)3 + (b – c)3 +(c - a)3 = 3(a - b)(b – c)(c-a) LHS⇒ ⇒(a - b)3 + (b – c)3 +(c - a)3 ⇒3(a - b)(b – c)(c-a) {took 3 COMMON} = RHS since LHS = RHS hence proved. |
|
| 8. |
3a^2bc+6ab^c+9abv^2 |
|
Answer» Sorry bro but I NEED some point Step-by-step EXPLANATION: bus stop and see if you WANT to go and forth to be a little more than anything in the MIDDLE |
|
| 9. |
Two-segment trapezoidal rule |
|
Answer» I can't...........XD |
|
| 10. |
Find csa of cone whose sides 12 cmand base radius 5cm |
|
Answer» If by sides you MEAN ‘l’ then csa is pi * R * l. |
|
| 11. |
Of thal Scului.14. Find the volume of a hemisphere with radius 7 cm.number in |
Answer» CORRECT QUESTION :-Find the Volume of a HEMISPHERE with RADIUS 7cm. AnswEr:-______________________________________ Step by Step Explanation:- We know that, Volume of Hemisphere = And, Radius is GIVEN 7cm. Now, So, Volume of Hemisphere is ______________________________________ |
|
| 12. |
4000 ₹ का 4वर्ष 6 माह का मिश्रधन 5260 ₹ है तो प्रतिशत वार्षिक ब्याज दर निकाल। |
|
Answer» do HELL so all do Step-by-step explanation: do call call so so so so so I'm ha go be go be L so all ha l is go ha an ha an ha an ha the hi do do be W hi is to is to ha Co by do feel TELL had ha an ha an by bs to car all be go look for ha an is to ha to the we do if to do to go ha ha hand be by ha I'm going to go to go do is to is wi we're really is the TV and e v an ha El ha an to do is go to the is try an ha I know that was a thing to wait until tomorrow to go do is go to go ha an hour and the other two I have f do ha do the an to do is an is an ha El ha El ha do ha do ha do ha em to is to go ha ha ha ha an is to be in the same room is to go to the TV on and |
|
| 13. |
prove that cos theta by 1 by tan theta + sin theta by 11 - cos theta is equal to sin theta + cos theta |
|
Answer» Step-by-step EXPLANATION: |
|
| 14. |
The ratio of alcohol and water in 85 kg of adul-terated Alcohol is 27:7 the amount waterwhich must be added to make the ratio 3:1 is-(b) 6 la |
|
Answer» Answer: 3:1 Step-by-step EXPLANATION: aacording to my CALCULATIONS... its is 3:1. |
|
| 15. |
Write the slope of X axis and Y to axis |
|
Answer» slope of X axis = 0 |
|
| 16. |
How would I divide 57 into 28 |
|
Answer» Answer: 57/28 mark me as BRAINLIEST |
|
| 17. |
A car travels at the speed of x km per hour is going to ooty to kodaikanal after the car travelled for 9hr kodaikanal is still 80 km away distance between them? |
Answer» ANSWER:Speed = x km/h Distance LEFT = 80 km Distance = Speed × Time Distance between the towns: 80 + 9x Answer: 80 + 9x________________ |
|
| 18. |
In the four term of an AP the product of first and third term is equal to the sum of first and fourth term. And 15th term is 44..find AP.? |
|
Answer» Answer: Step-by-step explanation: 2,5,8,11 are the FIRST 4 terms. 14,17,20,23 26,29,32,35 38,41,44,48 are the first 16 terms Sum of 1:15 is 8*15=120 Multiply by 3 is 360 Subtract 15 Sum is 345 |
|
| 19. |
Find the area of a square whose diagonal 5√2cm |
|
Answer» ☆*:.。.o(≧▽≦)o.。.:*☆ ♪H♪E♪Y♪ ♪M♪A♪T♪E♪ ♪H♪E♪R♪E♪ ♪I♪S♪ ♪Y♪O♪U♪ ♪A♪N♪S♪W♪E♪R♪ Side of Square = 5Area of Square =25cm2 ⚡H⚡O⚡P⚡E⚡ ⚡I⚡T⚡ ⚡W⚡I⚡L⚡L⚡ ⚡H⚡E⚡L⚡P⚡ ⚡Y⚡O⚡U⚡ ☾F☽☾O☽☾L☽☾L☽☾O☽☾W☽ ☾F☽☾O☽☾R☽ ☾M☽☾O☽☾R☽☾E☽ ☾A☽☾N☽☾S☽☾W☽☾E☽☾R☽☾S☽ (◕‿◕)♡ |
|
| 20. |
150 M long and 9M wide is to be paved with bricks each measuring 22.5 CM by 7.5 cm find the number of bricks required |
|
Answer» Step-by-step EXPLANATION: NUMBER of BRICK =150x9x100x100x100/225x75 = |
|
| 21. |
the ratio of cylinder and conical to base radius is 3:4 and the ratio of their height is 2:3 .What is the ratio of their volume |
|
Answer» 9:8 Step-by-step explanation: 3.9x2.2y by 4x2.x2.3y =9:8 |
|
| 22. |
Lakshya Dunivedimula Academy, DewasSubject: MathsClass: 10Worksheet24245AtQ.7Chapter 1Real NumbersisitQ. 1The decimal expansion of the rational no. 43 will terminate after how many places ofdecimal? Write the decimal expansionQ. 2(4,0.0215]Show that 5 x 7 x 11 + 11 is a composite number.Q. 3 Using euclid's division algorithm, find the H.C.F. of 272 & 1040.(16)Q. 4 Can 12" ends with the digit o for any natural number n; check.Q. 5 The H.C.F of two no. is 23 & their L.C.M. is 1449. If one no. is 207,find the other number. [161]Q. 6Using euclid's division lemma, show that the cube of any +ve integer is of the form 9 m or9m + 1 or 9m + 8 for some integer m.Prove that V2 is irrational.Q.8 The length, breadth &height of a room are 8 m 25m, 6m 75 cm & 4m 50 cm respectively.Determine,The length of the longest rod that can be placed in this room (in cm)2. The length of the longest rod which can measure the three dimensions of the room exactly. (75cm]There are 156, 208 & 260 students in groups A,B, & Cresp. buses are field trip, herd, if the same no. ofstudents should be accommodated in each bus & reparate bus for separate bus for separate group isneeded. Find the no. of buses arequired,[3+4+5=12]Q. 10 Using euclid's division lemma, show that the square of any +ve integer is either of the form 3m or31n + 1 for some integer m.Q. 11 Show that 3+3+5 is an irrational number."1. |
|
Answer» Step-by-step explanation: 2.Since product of two odd number is odd therefore, 5×7×11 is odd number similarly 13×17 is an odd number We KNOW, sum of two odd number is even. Therefore,(5×7×11)+(13×17)= even number we know, 2 is only even prime number and remaining all even number are composite. Hence,(5×7×11) + (13×17) is a composite number. 3. here ,420>272 therefore 420= 272 × 1 + 148 272= 148 × 1 + 124 148= 124 × 1 + 24 124= 24 × 5 + 4 24= 4 × 6 + 0 since remainder is 0, thus the HCF is 4. 5.Let the two numbers be a and b. Let the value of a be 207. Given: HCF = 23 and LCM = 1449 We know, a × b = HCF × LCM ⇒ 207× b = 23 × 1449 ⇒ ∴ b = (23 ×1449)/207 = 33327/207 = 161 Hence, the other number b is 161. 6.According to Euclid’s Division Lemma Let take a as any positive integer and b = 9. Then using Euclid’s algorithm we get a = 9q + r here r is remainder and value of Q is more than or equal to 0 and r = 0, 1, 2, 3, 4, 5 , 6 , 7 , 8, because 0 ≤r < b and the value of b is 9 Sp possible forms will 9q, 9q+1, 9q+2,9q+3,9q+4,9q+5,9q+6,9q+7 and 9q+8 to get the cube of these values use the formula (a+b)³ = a³ + 3a²b+ 3ab² + b³ In this formula value of a is always 9q So plug the value we get (9q+b)³ = 729q³ + 243q²b + 27qb² + b³ Now divide by 9 we get quotient = 81q³ + 27q²b + 3qb² and remainder is b³ So we have to consider the value of b³ b = 0 we get 9m+0 = 9m b = 1 then 1³ = 1 so we get 9m +1 b = 2 then 2³ = 8 so we get 9m + 8 b = 3 then 3³ = 27 and it is divisible by 9 so we get 9m b = 4 then 4³ =64 divide by 9 we get 1 as remainder so we get 9m +1 b=5 then 5³=125 divide by 9 we get 8 as remainder so we get 9m+8 b=6 then 6³=216 divide by 9 no remainder there so we get 9m b=7 then 7³ = 343 divide by 9 we get 1 as remainder so we get 9m+1 b=8 then 8³ = 512 divide by 9 we get 8 as remainder so we get 9m+8 So all values are in form of 9m , 9m+1 or 9m+8. 6.Let's suppose √2 is a rational number. Then we can write it √2 = a/b where a, b are whole numbers, b not zero. We additionally assume that this a/b is simplified to lowest terms, since that can obviously be done with any fraction. Notice that in order for a/b to be in simplest terms, both of a and b cannot be even. One or both must be odd. Otherwise, we could simplify a/b further. From the equality √2 = a/b it follows that 2 = A2/b2, or a2 = 2 · b2. So the square of a is an even number since it is two times something. From this we know that a itself is also an even number. Why? Because it can't be odd; if a itself was odd, then a · a would be odd too. Odd number times odd number is always odd. Check it if you don't believe me! Okay, if a itself is an even number, then a is 2 times some other whole number. In symbols, a = 2k where k is this other number. We don't need to know what k is; it won't matter. Soon comes the contradiction. If we substitute a = 2k into the original equation 2 = a2/b2, this is what we get: 2 = (2k)2/b2 2 = 4k2/b2 2*b2 = 4k2 b2 = 2k2 This means that b2 is even, from which follows again that b itself is even. And that is a contradiction!!! WHY is that a contradiction? Because we started the whole process assuming that a/b was simplified to lowest terms, and now it turns out that a and b both would be even. We ended at a contradiction; thus our original assumption (that √2 is rational) is not correct. Therefore √2 cannot be rational. 10.Let take a as any positive integer and b = 3. Then using Euclid’s algorithm we get a = 3Q + r here r is remainder and value of q is more than or equal to 0 and r = 0, 1, 2 because 0 < r < b and the value of b is 3 So our possible values will 3q+0 , 3q+1 and 3q+2 Now find the square of values Use the formula (a+b)² = a² + 2AB +b² to open the square bracket (3q)² = 9q² if we divide by 3 we get no remainder we can write it as 3*(3q²) so it is in form of 3m here m = 3q² (3q+1)² = (3q)² + 2*3q*1 + 1² =9q² + 6q +1 now divide by 3 we get 1 remainder so we can write it as 3(3q² + 2q) +1 so we can write it in form of 3m+1 and value of m is 3q² + 2q here (3q+2)² = (3q)² + 2*3q*2 + 2² =9q² + 12q +4 now divide by 3 we get 1 remainder so we can write it as 3(3q² + 4q +1) +1 so we can write it in form of 3m +1 and value of m will 3q² + 4q +1 Square of any positive integer is either of the form 3m or 3m + 1 for some integer m. or let ' a' be any positive integer and b = 3. we know, a = bq + r , 0 < r< b. now, a = 3q + r , 0 the possibilities of remainder = 0,1 or 2 Case I - a = 3q a2 = 9q2 = 3 x ( 3q2) = 3m (where m = 3q2) Case II - a = 3q +1 a2 = ( 3q +1 )2 = 9q2 + 6q +1 = 3 (3q2 +2q ) + 1 = 3m +1 (where m = 3q2 + 2q ) Case III - a = 3q + 2 a2 = (3q +2 )2 = 9q2 + 12q + 4 = 9q2 +12q + 3 + 1 = 3 (3q2 + 4q + 1 ) + 1 = 3m + 1 where m = 3q2 + 4q + 1) From all the above cases it is clear that square of any positive integer ( as in this case a2 ) is either of the form 3m or 3m +1. Hope it helps, |
|
| 23. |
Prove that secA (1-sinA) (secA+tanA) = 1 |
|
Answer» secA(1-sinA)(secA+tanA) = (1/cosA)(1-sinA)(1/cosA+sinA/cosA) = (1/cos²A)(1-sinA)(1+sinA) = (1/cos²A)(1-sin²A) = (1/cos²A)(cos²A) = 1 = RHS Step-by-step EXPLANATION: please Mark me as brainlist |
|
| 24. |
Prove that : |
|
Answer» Step-by-step EXPLANATION: Maths Prove that: tanθ−secθ+1 secθ+tanθ−1
= 1−sinθ cosθ
PUT 1=sec θ−tan 2 θ=(secθ−tanθ)(secθ+tanθ) ⟹ tanθ−secθ+1 secθ+tanθ−(secθ−tanθ)(secθ+tanθ)
⟹ (1−secθ+tanθ) secθ+tanθ(1−secθ+tanθ)
⟹secθ+tanθ Put secθ= cosθ 1
and tanθ= cosθ sinθ
⟹ cosθ 1
+ cosθ sinθ
⟹ cosθ(1−sinθ) 1−sin 2 θ
⟹ 1−sinθ cosθ |
|
| 25. |
X + a is a factor of the polynomial (X square + px + q) and (X square + mx+n) then prove that a= n-q/m-p |
|
Answer» prove :a=n-q/m-p Step-by-step explanation: X+a=0 x=-a put the VALUE in p(x) xsquare+px+q=xsquare+mx+n asquare-ap+q=asquare-am+n asquare be cancelled out -ap+am=n-q a(m-p)=n-q a=n-q/m-p |
|
| 26. |
How many weeks are in a year |
|
Answer» Answer: 52.143weeks APPROXIMATE VALUE... |
|
| 27. |
A car travels at the speed of x km per hour is going to ooty to kodaikanal after the car travelled for 9hr kodaikanal is still 80 km awayDistance between them? |
|
Answer» Thank you very MUCH for your school STUDENTS requesting their contribution to PUBLISH your school's website |
|
| 28. |
26. A garrison of 900 soldiers had food-stock sufficientfor 30 days when the rate of consumption is2.5 kg/day/soldier. After some days of consumptionat that rate, 300 soldiers were transferred to anothergarrison and the balance food lasted for 25 days forthe remaining soldiers. If the rate of consumption ofthe remaining soldiers was 3.0 kg/dayl soldier, afterhow many days from the start, were the soldierstransferred? |
|
Answer» Answer: 10 days Step-by-step explanation: INITIAL CONSUMPTION per day=900*2.5=2250 kg Total amount of food =2250*30=67500 kg after few days remaining soldier=900-300=600 total food remaining for 25 days with NEW consumption RATE= 600*3*25=45000 kg in initial days food consumed=67500-45000=22500 kg days elapsed=22500/2250=10 |
|
| 29. |
Find the centre of the circle passing through the points (6 -6) (3 -7) and (3 3) solutions |
|
Answer» Step-by-step explanation: using centroid formula we CONSIDERED POINT P(X,y) PUT given values and FIND ansAnsx=4y=-12 |
|
| 30. |
The taxi fare in a city is as follows : For the first kilometer,the fare is Rs 8and for the subsequent distance it is Rs 5 per km. Taking the distance covered as x km and total fare as Rs y , write a linear equation for this information, and draw it's graph? |
|
Answer» USING above INFORMATION you can DRAW it's graph. thanks. |
|
| 31. |
A man travelled a total distance of 1800 km byplane, train and bus. He travelled one-third of thewhole trip by plane and the distance travelled bytrain is three-fifth of the distance travelled by bus.Find the distance travelled by bus.(A) 450 km(B) 850 km"C) 1200 km(D) 750 km |
|
Answer» Step-by-step EXPLANATION: Answer is 450 km Since distance travelled by PLANE is 1/3 of total journey then distance travelled by plane= 1/3×1800=600 Now let the distance travelled by bus be x Therefore distance travelled by TRAIN will be 5/3 × x= 5/3x Now A/Q 600+5/3x+x= 1800(on solving x will be 450) so x=450 km |
|
| 32. |
Differentiate the following functions with respect to x from first principles :(i) √x |
Answer» ANSWER:Step-by-step explanation:Given : f ( x ) = √ x We have to DIFF. w.r.t. x We have first PRINCIPLE of derivative . If y = f ( x ) Then : = > f ( x + h ) = ( √ x + h ) Now rationalize it we get : Putting h = 0 Hence we get answer. |
|
| 33. |
A car travels at the speed of x km per hour is going to ooty to kodaikanal after the car travelled for 9hr kodaikanal is still 80 km awayWhat is the distance between them? |
|
Answer» Step-by-step EXPLANATION: DISTANCE=SPEED×TIME =9×80=720 1HOUR=60MIN DISTANCE =12×9=108 SO, THE DISTANCE BETWEEN THEM IS 108KM |
|
| 34. |
Find the perimeter of the rectangle whose area is 600 CM square and breadth is 25 centimetre |
|
Answer» AREA of rectangle =l×b 600. =l×25 600÷25.= l 24= l perimeter of rectangle = 2(l+b) = 2(24+25) =98CM |
|
| 35. |
In an ap is equal to 3 n + 2 then find 12th term |
| Answer» | |
| 36. |
In a digital display which digit can display all the 10 digits from 0 to 9.ans :- 8 how |
|
Answer» here , all the seven segments are on. note: A seven-segment display is a FORM of electronic display device for displaying decimal numerals that is an ALTERNATIVE to the more complex DOT MATRIX displays. |
|
| 37. |
X bar-Z=3,Xbar+Z=24 then m= |
|
Answer» Step-by-step EXPLANATION: tall me the correct question |
|
| 38. |
Find the 12the term from the end of the AP :-2, -4, -6, ...., -100. |
|
Answer» a=-100 d=2 an=-2 Step-by-step EXPLANATION: an=a+(n-1)d -2=-100+(n-1)2 98=(n-1)2 49=n-1 n=50 a12= -100+(12-1)2 a12= -100+22 a12=-78 |
|
| 39. |
Total age of 7 boys is 128 the sum of first 4 boys of 62 the sum of next 4 boys is 48 what is the age of 9th boy. |
|
Answer» Not possible. Step-by-step explanation: There are only 7 BOYS and then how can it be first 4 then NEXT 4....? ??? |
|
| 40. |
Add -15 yz?, 15z?y and 13 yz |
|
Answer» -15yz+13yz=-2 yz and the answer will be -2YZ +15zy.. |
|
| 41. |
A. Sumit deposited 500 per month in a bank for 15 months in recurring deposit account. Find the maturityvalue of his deposits if the rate of interest is 10% per annum and the interest is calculated at the endof every month. |
|
Answer» hope it HELPS you please MARK as brainliest |
|
| 42. |
Any triangle ABC, bisect side AB at D. Through D, draw a line parallel to Bocellmeeting AC in E. Measure AE and EC? |
|
Answer» jjjejshwggwgwgsggwghwgsgsgsgsvvsvsgsggsgwgsggsgwvwvwggwg what are your friend about importance to the suitable QUESTION is how EYE out y la E eyeyu of u the following y el lunes of the suitable post u can see the following tool to my ACCOUNT is YY y y y up for Facebook today |
|
| 43. |
3+9a=6+5a. question |
|
Answer» a= 3/4 Step-by-step explanation: 3+9a=6+5a 9a-5a=6-3 4a=3 a=3/4 |
|
| 44. |
Find the area of a parallelogram PQRS, ifPR= 24 cm and QUEST=8 CM. |
|
Answer» Step-by-step EXPLANATION: answer is 192 sq.cm |
|
| 45. |
A test tube has lower part hemispherical and upper5 cmpart cylindrical with the same radius. If -5159cm' of6water is poured, the test tube will be completelyfilled. But if - cm of water is poured, 5 cm of3height will remain empty. Calculate the radius of thetube and the height of the cylindrical part. [HOTS] |
| Answer» | |
| 47. |
Q. If the altitude of a circular cylinderis increased to six times and thebace area is decreased to me- nintaof ite value, find the factor by whichthe lateral ssurface of the culinderincreasoe. |
|
Answer» And this is UR answer... |
|
| 48. |
Show thatarbre 2a za 126 f-cra elcas bts2c2c. c-auto |
|
Answer» Step-by-step EXPLANATION: tall me the correct question |
|
| 49. |
75% in prelims how much in boards |
|
Answer» Answer: 85% Step-by-step EXPLANATION: |
|
| 50. |
Please answer fast frieds.the heights of two adjacent buildings are 82 / 5 and 83 /4 respectively. find the difference between their Heights |
|
Answer» Step-by-step EXPLANATION: THE DIFFERENCE BETWEEN HIGHT=82/5=16.4 SECOND BUILDING=83/4=20.75 so,the difference between building is 16.4=20.74 |
|