1.

Prove that:(a - b)3 + (b – c)3 +(c - a)3 = 3(a - b)(b – c)(c-a)​

Answer»

Step-by-step explanation:

(a - B)3 + (b – c)3 +(c - a)3 = 3(a - b)(b – c)(c-a)​

LHS⇒

⇒(a - b)3 + (b – c)3 +(c - a)3

⇒3(a - b)(b – c)(c-a)​ {took 3 COMMON}

= RHS

since LHS = RHS  hence proved.


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