X + a is a factor of the polynomial (X square + px + q) and (X square

1.	X + a is a factor of the polynomial (X square + px + q) and (X square + mx+n) then prove that a= n-q/m-p
Answer» <P>ANSWER: prove :a=n-q/m-p Step-by-step explanation: X+a=0 x=-a put the VALUE in p(x) xsquare+px+q=xsquare+mx+n asquare-ap+q=asquare-am+n asquare be cancelled out -ap+am=n-q a(m-p)=n-q a=n-q/m-p

X + a is a factor of the polynomial (X square + px + q) and (X square + mx+n) then prove that a= n-q/m-p

Answer»

<P>ANSWER:

prove :a=n-q/m-p

Step-by-step explanation:

X+a=0

x=-a

put the VALUE in p(x)

xsquare+px+q=xsquare+mx+n

asquare-ap+q=asquare-am+n

asquare be cancelled out

-ap+am=n-q

a(m-p)=n-q

a=n-q/m-p

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X + a is a factor of the polynomial (X square + px + q) and (X square + mx+n) then prove that a= n-q/m-p​

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X + a is a factor of the polynomial (X square + px + q) and (X square + mx+n) then prove that a= n-q/m-p