1.

Prove that secA (1-sinA) (secA+tanA) = 1​

Answer»

ANSWER:

secA(1-sinA)(secA+tanA)

= (1/cosA)(1-sinA)(1/cosA+sinA/cosA)

= (1/cos²A)(1-sinA)(1+sinA)

= (1/cos²A)(1-sin²A)

= (1/cos²A)(cos²A)

= 1

= RHS

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