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Prove that : |
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Answer» Step-by-step EXPLANATION: Maths Prove that: tanθ−secθ+1 secθ+tanθ−1
= 1−sinθ cosθ
PUT 1=sec θ−tan 2 θ=(secθ−tanθ)(secθ+tanθ) ⟹ tanθ−secθ+1 secθ+tanθ−(secθ−tanθ)(secθ+tanθ)
⟹ (1−secθ+tanθ) secθ+tanθ(1−secθ+tanθ)
⟹secθ+tanθ Put secθ= cosθ 1
and tanθ= cosθ sinθ
⟹ cosθ 1
+ cosθ sinθ
⟹ cosθ(1−sinθ) 1−sin 2 θ
⟹ 1−sinθ cosθ |
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