332354 + Interview Questions in Secondary School in Math

1.	How long will they take to go a distance of 10 km ?
Answer» ANSWER: PLS TYPE the QUESTION CORRECTLY

1.

How long will they take to go a distance of 10 km ?

Answer»

ANSWER:

PLS TYPE the QUESTION CORRECTLY

Discussion

2.	Angle ABC is congruent to Angle XYZ , If the measure of angle ABC is 110 degrees, then the supplement of the measure of Angle XYZ is ____
Answer» Answer: Points in the INTERIOR R, C, N, X Points in the exterior T, U, Q, V, Y Points on the arms of the angles A, W, G, B

2.

Angle ABC is congruent to Angle XYZ , If the measure of angle ABC is 110 degrees, then the supplement of the measure of Angle XYZ is ____

Answer»

Answer:

Points in the INTERIOR R, C, N, X

Points in the exterior T, U, Q, V, Y

Points on the arms of the angles A, W, G, B

Discussion

3.	If you cut a small square from a square or a rectanglular sheet of paper, will the perimeter of the sheet increase or decrease? what will happen to the area of the remaining sheet?tell me full explation and no shortcuts please and answer is = perimeter increases , area of remaining sheet decreases tell me full explation and I am requesting you
Answer» ANSWER: ooooooooooooooooooooooooo

3.

If you cut a small square from a square or a rectanglular sheet of paper, will the perimeter of the sheet increase or decrease? what will happen to the area of the remaining sheet?tell me full explation and no shortcuts please and answer is = perimeter increases , area of remaining sheet decreases tell me full explation and I am requesting you

Answer»

ANSWER:

ooooooooooooooooooooooooo

Discussion

4.	in a triangle ABC if 2 angle A is equals to 3 angle B is equals to 6 angle C then find the measure of angle A
Answer» Answer: Step-by-step EXPLANATION: let angle C be x so angle B = 6x so angle A = 18x x+6x+18x = 180 degrees [angle sum PROPERTY of triangle] 25X = 180 x = 7.2 so angle A = 18x = 18 into 7.2 = 129.6 degrees

4.

in a triangle ABC if 2 angle A is equals to 3 angle B is equals to 6 angle C then find the measure of angle A

Answer»

Answer:

Step-by-step EXPLANATION:

let angle C be x

so angle B = 6x

so angle A = 18x

x+6x+18x = 180 degrees [angle sum PROPERTY of triangle]

25X = 180

x = 7.2

so angle A = 18x = 18 into 7.2 = 129.6 degrees

Discussion

5.	The price of table depreciates every year by 20%.If the value of the table after 2 years will be32000, then what is the present price (in Rupees)of the table?(a) 48,000(b) 44,000(c) 50,000(d) 51,000
Answer» ANSWER: If the value of the table after 2 years will be 32000, then what is the present PRICE (in Rupees) of the table? 48,000. Step-by-step explanation: make me BRAINLIST..

5.

The price of table depreciates every year by 20%.If the value of the table after 2 years will be32000, then what is the present price (in Rupees)of the table?(a) 48,000(b) 44,000(c) 50,000(d) 51,000

Answer»

ANSWER:

If the value of the table after 2 years will be 32000, then what is the present PRICE (in Rupees) of the table? 48,000.

Step-by-step explanation:

make me BRAINLIST..

Discussion

6.	Solve x^2(d^2y/dx^2)+x(dy/dx)+y=4 sin(logx)
Answer» ANSWER: ERROR this is not PERFECT QUESTION

6.

Solve x^2(d^2y/dx^2)+x(dy/dx)+y=4 sin(logx)

Answer»

ANSWER:

ERROR this is not PERFECT QUESTION

Discussion

7.	Class -VI(PT-2)1 pointWhich of the followingnumbers is a perfect number?O O O486Clour coloction
Answer» hzjdowkshfhdjjafg CDS kbxucsko

Discussion

8.	Find x and y so that point M(4.- 8) is the midpoint of the segment defined by points C(x. 1.0) and D(0.7-2).
Answer» ANSWER: hsidnxnciwlwmcixkmsa

8.

Find x and y so that point M(4.- 8) is the midpoint of the segment defined by points C(x. 1.0) and D(0.7-2).

Answer»

ANSWER:

hsidnxnciwlwmcixkmsa

Discussion

9.	If the 3rd and the 9th terms of an A.P. are 4 and − 8 respectively, then which term of this A.P is zero.
Answer» GIVEN :- 3rd term of A.P is 4. 9th term of A.P is -8. $\\$ TO FIND :- The term when the A.P is 0. $\\$ FORMULA USED :- $\\ \bigstar\boxed{\sf \: a_{n} = a + (n - 1)d } \\$ Here , a(n) → 'n'th term a → First term n → TOTAL number of terms d → Common difference $\\$ SOLUTION :- $\\$ ♦ 3rd term of A.P is 4. We know , a(n) = a + (n-1)d Here , a(n) = 4 n = 3 Putting VALUES we get.. $\implies\sf4 = a + (3 - 1)d \\$ $\\ \implies \sf 4 = a + 2d \: \: \: \: \: \: \: \: \: \: \: \: - - - (i)\\ \\$ ♦ 9th term of A.P is -8. Now with the same formula ...we get , $\\ \implies \sf - 8 = a + (9 - 1)d \\$ $\\ \implies \sf \: - 8 = a + 8d \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: - - - (<klux>II</klux>) \\ \\$ Now , we will subtract equation (i) by equation (ii). We get... $\\ \to \sf \: - 8 - 4 = a + 8d - (a + 2d) \\$ $\\ \to \sf \: - 12 = a + 8d - a - 2d \\$ $\\ \to\sf \: - 12 = 6d \\$ $\\ \to \boxed{\sf \: d = - 2} \\$ Now , we will substitute the value of "d" in equation (i). $\\ \underline{ \sf \: 4 = a + 2d} \\$ $\\ \to \sf \: 4 = a + 2( - 2) \\$ $\\ \to \sf \: 4 = a - 4 \\$ $\\ \to\boxed{ \sf \:a = 8 } \\ \\$ Let a(n) of the A.P be 0. $\\ \implies\sf \: 0 = a + (n - 1)d \\$ Substituting values of 'a' and 'b' as 8 and -2 RESPECTIVELY , we get... $\\ \implies \sf0 = 8 + (n - 1)( - 2) \\$ $\\ \implies\sf \: - 8 = (n - 1)( - 2) \\$ $\\ \implies \sf - 8 = - 2n + 2 \\$ $\\ \implies\sf2n = 2 + 8 \\$ $\\ \implies\sf 2n = 10 \\$ $\\ \implies \boxed{\boxed{ \bf \:n = 5 }} \\ \\$ HENCE , 5th term of the A.P is 0.

9.

If the 3rd and the 9th terms of an A.P. are 4 and − 8 respectively, then which term of this A.P is zero.

Answer»

GIVEN :-

3rd term of A.P is 4.

9th term of A.P is -8.

$\\$

TO FIND :-

The term when the A.P is 0.

$\\$

FORMULA USED :-

$\\ \bigstar\boxed{\sf \: a_{n} = a + (n - 1)d } \\$

Here ,

a(n) → 'n'th term
a → First term
n → TOTAL number of terms
d → Common difference

$\\$

SOLUTION :-

$\\$

♦ 3rd term of A.P is 4.

We know , a(n) = a + (n-1)d

Here ,

a(n) = 4
n = 3

Putting VALUES we get..

$\implies\sf4 = a + (3 - 1)d \\$

$\\ \implies \sf 4 = a + 2d \: \: \: \: \: \: \: \: \: \: \: \: - - - (i)\\ \\$

♦ 9th term of A.P is -8.

Now with the same formula ...we get ,

$\\ \implies \sf - 8 = a + (9 - 1)d \\$

$\\ \implies \sf \: - 8 = a + 8d \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: - - - (<klux>II</klux>) \\ \\$

Now , we will subtract equation (i) by equation (ii).

We get...

$\\ \to \sf \: - 8 - 4 = a + 8d - (a + 2d) \\$

$\\ \to \sf \: - 12 = a + 8d - a - 2d \\$

$\\ \to\sf \: - 12 = 6d \\$

$\\ \to \boxed{\sf \: d = - 2} \\$

Now , we will substitute the value of "d" in equation (i).

$\\ \underline{ \sf \: 4 = a + 2d} \\$

$\\ \to \sf \: 4 = a + 2( - 2) \\$

$\\ \to \sf \: 4 = a - 4 \\$

$\\ \to\boxed{ \sf \:a = 8 } \\ \\$

Let a(n) of the A.P be 0.

$\\ \implies\sf \: 0 = a + (n - 1)d \\$

Substituting values of 'a' and 'b' as 8 and -2 RESPECTIVELY , we get...

$\\ \implies \sf0 = 8 + (n - 1)( - 2) \\$

$\\ \implies\sf \: - 8 = (n - 1)( - 2) \\$

$\\ \implies \sf - 8 = - 2n + 2 \\$

$\\ \implies\sf2n = 2 + 8 \\$

$\\ \implies\sf 2n = 10 \\$

$\\ \implies \boxed{\boxed{ \bf \:n = 5 }} \\ \\$

HENCE , 5th term of the A.P is 0.

Discussion

10.	SECTION -AAnswer the following questions as instructed:Choose the correct answer:1. A circle divides the planes on which it lies inparts.a) 1b)?c)3d) 42. In AABCI AS-BC-CA, then all the angies of the triangle are ofa) 30°b) 45°c) 60°d) 90°3. A quadrilateralhesparts of adjacent sides.a) 2b) 4c) 6d) 8State whether the following statement are True or False:
Answer» Answer: *Answer:very very happy up for FACEBOOK today the COMPUTER a memory card storage the PICTURE in a digital CAMERA and* *Answer:very very happy up for Facebook today the computer a memory card storage the picture in a digital camera andStep-by-step explanation:* *Answer:very very happy up for Facebook today the computer a memory card storage the picture in a digital camera andStep-by-step explanation:hhhllghhhfgh*

10.

SECTION -AAnswer the following questions as instructed:Choose the correct answer:1. A circle divides the planes on which it lies inparts.a) 1b)?c)3d) 42. In AABCI AS-BC-CA, then all the angies of the triangle are ofa) 30°b) 45°c) 60°d) 90°3. A quadrilateralhesparts of adjacent sides.a) 2b) 4c) 6d) 8State whether the following statement are True or False:

Answer»

Answer:

Answer:very very happy up for FACEBOOK today the COMPUTER a memory card storage the PICTURE in a digital CAMERA and

Answer:very very happy up for Facebook today the computer a memory card storage the picture in a digital camera andStep-by-step explanation:

Answer:very very happy up for Facebook today the computer a memory card storage the picture in a digital camera andStep-by-step explanation:hhhllghhhfgh

Discussion

11.	Observe the following pattern:ΔΔ1st figure2nd figure5th figureExpress the answer in terms of n and complete the following statement:The algebraic expression for the number of triangles in the nth figure is
Answer» Answer: top DROP dl dl p Step-by-step explanation: well APP so so so dl dl cl

11.

Observe the following pattern:ΔΔ1st figure2nd figure5th figureExpress the answer in terms of n and complete the following statement:The algebraic expression for the number of triangles in the nth figure is

Answer»

Answer:

top DROP dl dl p

Step-by-step explanation:

well APP so so so dl dl cl

Discussion

12.	What is integration in physics
Answer» $\huge\underline\mathtt{Answer}$ INTEGRATION is the REVERSE operation to differentiation i.e. it is the process of getting from the derivative START fraction, d, g, left bracket, X, right bracket, divided by, d, x, end fraction, equals, g, prime, left bracket, x, right bracket,dxdg(x)=g′(x) to the FUNCTION g, left bracket, x, right bracket,g(x).

12.

What is integration in physics

Answer»

$\huge\underline\mathtt{Answer}$

INTEGRATION is the REVERSE operation to differentiation i.e. it is the process of getting from the derivative START fraction, d, g, left bracket, X, right bracket, divided by, d, x, end fraction, equals, g, prime, left bracket, x, right bracket,dxdg(x)=g′(x) to the FUNCTION g, left bracket, x, right bracket,g(x).

Discussion

13.	If 25% of y is x, then y = ?
Answer» Answer: 75 % Step-by-step explanation: VALUE of X = 25 % TOTAL percent = 100% value of y = 100 - 25 = 75%

13.

If 25% of y is x, then y = ?

Answer»

Answer:

75 %

Step-by-step explanation:

VALUE of X = 25 %

TOTAL percent = 100%

value of y = 100 - 25

= 75%

Discussion

14.	Classify the following as rational Or irrational. a) √225.b)√39.
Answer» ANSWER: a) Rational b) IRRATIONAL

14.

Classify the following as rational Or irrational. a) √225.b)√39.

Answer»

ANSWER:

a) Rational

b) IRRATIONAL

Discussion

15.	Find the compound interest paid when a sum of 10000 Rupees is invested for 1 year 3 months at 8½% per annum compounded annuallypls say me frnds fast ga
Answer» ★ $\huge\bf{\blue{\underline{Question:-}}}$ find the compound interest paid when a sum of 10000 RUPEES is invested for 1 year 3 months at 8½% per annum compounded annually ———————————————————————————— ★ $\huge\bf{\red{\underline{Answer:-}}}$ The Compound interest for 1 year 3 months is RS. 11080.52 ———————————————————————————— ★ $\huge\bf{\green{\underline{Explanation:-}}}$ Step-by-step explanation: Step 1: Given DATA: P= ₹ 10000 T=1 year R=17/2% I=PTR/100 I=100001 X 17/100 x 2 I=₹ 850 Step 2: AMOUNT at the end of the 1 year =P+I =10000+850 =10850 this is next 3 months principal Step 3: P=₹ 10850 T=3 months =3/12=1/4 yr R=17/2% I=10850 x 1 x 17/100 x 4 x 2 =18445/80 = Rs. 270.56 Step 4: At the end of the 1 year 3 months Amount=P+I =10850+230.56 =11080.52 Compound interest for 1 year 3 months is 11080.52 ————————————————————————————

15.

Find the compound interest paid when a sum of 10000 Rupees is invested for 1 year 3 months at 8½% per annum compounded annuallypls say me frnds fast ga

Answer»

★ $\huge\bf{\blue{\underline{Question:-}}}$

find the compound interest paid when a sum of 10000 RUPEES is invested for 1 year 3 months at 8½% per annum compounded annually

————————————————————————————

★ $\huge\bf{\red{\underline{Answer:-}}}$

The Compound interest for 1 year 3 months is RS. 11080.52

————————————————————————————

★ $\huge\bf{\green{\underline{Explanation:-}}}$

Step-by-step explanation:

Step 1:

Given DATA:

P= ₹ 10000

T=1 year

R=17/2%

I=PTR/100

I=100001 X 17/100 x 2

I=₹ 850

Step 2:

AMOUNT at the end of the 1 year

=P+I

=10000+850

=10850 this is next 3 months principal

Step 3:

P=₹ 10850

T=3 months =3/12=1/4 yr

R=17/2%

I=10850 x 1 x 17/100 x 4 x 2

=18445/80

= Rs. 270.56

Step 4:

At the end of the 1 year 3 months

Amount=P+I

=10850+230.56

=11080.52

Compound interest for 1 year 3 months is 11080.52

————————————————————————————

Discussion

16.	18. The area of the sector of a circle of radius 10 cm is 75 cm sq. Find the length of correspondingarc of the circle.(a) 50 cm (b) 60 cm(c) 22 cm(d) 15 cm
Answer» ANSWER: 50cm is the answer THANKS BRAINLIST

16.

18. The area of the sector of a circle of radius 10 cm is 75 cm sq. Find the length of correspondingarc of the circle.(a) 50 cm (b) 60 cm(c) 22 cm(d) 15 cm

Answer»

ANSWER:

50cm is the answer THANKS BRAINLIST

Discussion

17.	Q2; Solve the recurrence relation ar-5ar-1+6ar-2=2+r Given that a0=1 and a1=1
Answer» ANSWER: Hey, Wishing you the BEST for the day AHEAD! CHOOSE your day to be the best today! Step-by-step EXPLANATION:

17.

Q2; Solve the recurrence relation ar-5ar-1+6ar-2=2+r Given that a0=1 and a1=1

Answer»

ANSWER:

Hey, Wishing you the BEST for the day AHEAD! CHOOSE your day to be the best today!

Step-by-step EXPLANATION:

Discussion

18.	FIND THE LENGTH ON THE SIDE OF A SQUARE IF ITS AREA IS 441m²
Answer» AREA of a SQUARE = SIDE * side 441 = Side * Side ___ √441. = side 21 = side

18.

FIND THE LENGTH ON THE SIDE OF A SQUARE IF ITS AREA IS 441m²

Answer»

AREA of a SQUARE = SIDE * side

441 = Side * Side

___

√441. = side

21 = side

Discussion

19.	सम ऑफ टू नंबर्स एस 75 एफ वन एक्सटीरियर द अदर बाय 15 फाइंड द नंबर्स
Answer» ANSWER: answer is 45,30 Step-by-step explanation: LET first number is X than second number will be 75-X ( 75-x)=x+15 2x=60 x=30 fisrt number is 30 & second is 45

19.

सम ऑफ टू नंबर्स एस 75 एफ वन एक्सटीरियर द अदर बाय 15 फाइंड द नंबर्स

Answer»

ANSWER:

answer is 45,30

Step-by-step explanation:

LET first number is X than second number will be 75-X

( 75-x)=x+15

2x=60

x=30

fisrt number is 30 & second is 45

Discussion

20.	the angel of quadrilateral are (5x) degree, (3x+10)degree, (6x-20), (x+25) degree find the value of x and measure of each angle of the quadrilateral
Answer» $\LARGE\star\mathfrak{\underline{\underline{\red{answer: }}}}$ $\sf{given : } \\ \sf{angle \: 1 = 5x \degree} \\ \sf{angle \: 2 = 3x + 10 \degree} \\ \sf{angle \: 3= 6x - 20 \degree} \\ \sf{angle \: 4 = x + 25 \degree}$ $\sf{by \: angle \: sum \: property \: of \: a \: quadrilateral : } \\ \sf{angle \: 1 + angle \: 2 + angle \: 3 + angle \: 4 = 360 \degree } \\ \sf{(5x) +( 3x + 10 )+ (6x - 20) + (x + 25 )= 360 \degree} \\ \sf{15x + 15 = 360 \degree} \\ \sf{15x = 360 - 15 \degree} \\ \sf{15x = 345} \\ \sf{x = \frac{345}{15} } \\ \boxed{ \sf{x = 23}}$ $\boxed{ \sf{angle \: 1 = 5x = 5(23) = 115 \degree}} \\ \boxed{ \sf{angle \: 2 = 3x + 10 = 79 \degree}} \\ \boxed{ \sf{angle \: 3 = 6x - 20 = 6(23) - 20 = 118 \degree}} \\ {\boxed{ \sf{angle \: 4 =x + 25 = (23) + 25 = 48 \degree}}}$

20.

the angel of quadrilateral are (5x) degree, (3x+10)degree, (6x-20), (x+25) degree find the value of x and measure of each angle of the quadrilateral

Answer»

$\LARGE\star\mathfrak{\underline{\underline{\red{answer: }}}}$

$\sf{given : } \\ \sf{angle \: 1 = 5x \degree} \\ \sf{angle \: 2 = 3x + 10 \degree} \\ \sf{angle \: 3= 6x - 20 \degree} \\ \sf{angle \: 4 = x + 25 \degree}$

$\sf{by \: angle \: sum \: property \: of \: a \: quadrilateral : } \\ \sf{angle \: 1 + angle \: 2 + angle \: 3 + angle \: 4 = 360 \degree } \\ \sf{(5x) +( 3x + 10 )+ (6x - 20) + (x + 25 )= 360 \degree} \\ \sf{15x + 15 = 360 \degree} \\ \sf{15x = 360 - 15 \degree} \\ \sf{15x = 345} \\ \sf{x = \frac{345}{15} } \\ \boxed{ \sf{x = 23}}$

$\boxed{ \sf{angle \: 1 = 5x = 5(23) = 115 \degree}} \\ \boxed{ \sf{angle \: 2 = 3x + 10 = 79 \degree}} \\ \boxed{ \sf{angle \: 3 = 6x - 20 = 6(23) - 20 = 118 \degree}} \\ {\boxed{ \sf{angle \: 4 =x + 25 = (23) + 25 = 48 \degree}}}$

Discussion

21.	a cone of height 24 cm and radius of base 6 cm is made up of modelling clay.a child reshapes it in the form of a sphere .find the radius of the sphere.i know the answer but plz give a proper explanation.
Answer» $\sf {\large{Question: }}$ $\begin{gathered} \sf{ \green{A \: Cone \: of \: Height \: 24 \: cm \: and \: Radius \: of \: Base \: 6 \: cm}} \\ \sf{ \red{is \: made \: up \: of \: modelling \: clay \: a \: child \: Reshapes \: it}} \\ \sf{ \blue{in \: the \: form \: of \: a \: Sphere.}} \\ \sf{ \blue{ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: find \: the \: radius \: of \: the \: sphere ?}}\end{gathered}$ $\sf{ \large{Method \: of \: Solution:}}$ $\sf{ \pink{Given}}$ $\begin{gathered} \implies{ \sf{ \blue{Height \: of \: the \: cone \: = 24cm}}} \\ \\ \implies{ \sf{ \green{ Radius \: \: of \: the \: cone \: = 6cm}}} \\ \\ \\ \implies{ \sf{ \red {Volume \: of \: the \: cone = \frac{1}{3} \times \frac{22}{7} \times ( {6}^{2} )\times 24}}} \\ \\ \\ \implies{ \sf{ \red {Volume \: of \: the \: cone = 905.14cm}}}\end{gathered}$ $\sf{ \fbox{ \pink{According \: to \: the \: Question:}}}$ $\sf{\red{Volume \: of \: the \: Sphere \: = \frac{3}{4} \times \frac{22}{7} \times ({r}^{3})}}$ $\sf{\purple{Volume \: of \: the \: Sphere \: = \frac{3}{4} \times \frac{3}{4} \times ({r}^{3})=905.14}}$ $\begin{gathered}\sf{\green{Volume \: of \: the \: Sphere \: = \frac{3}{4} \times \frac{22}{7} \times ({r}^{3})=905.14}} \\ \\ \sf{\red{Volume \: of \: the \: Sphere \: = \frac{66}{28} \times ( {r}^{3} ) = 905.14 }} \\ \\ \\ \sf{\green{Volume \: of \: the \: Sphere = {r}^{3} {\implies \: 216}}} \\ \\ \\ \sf{\blue{Volume \: of \: the \: Sphere = (r) {\implies 6cm}}}\end{gathered}$ $\sf{ \red{ \fbox{Hence, \: Required}}} \sf{ \green{ \fbox{ Radius \: of \: Sphere}}} \sf{ \blue{ \fbox{ = 6cm}}}$

21.

a cone of height 24 cm and radius of base 6 cm is made up of modelling clay.a child reshapes it in the form of a sphere .find the radius of the sphere.i know the answer but plz give a proper explanation.

Answer»

$\sf {\large{Question: }}$

$\begin{gathered} \sf{ \green{A \: Cone \: of \: Height \: 24 \: cm \: and \: Radius \: of \: Base \: 6 \: cm}} \\ \sf{ \red{is \: made \: up \: of \: modelling \: clay \: a \: child \: Reshapes \: it}} \\ \sf{ \blue{in \: the \: form \: of \: a \: Sphere.}} \\ \sf{ \blue{ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: find \: the \: radius \: of \: the \: sphere ?}}\end{gathered}$

$\sf{ \large{Method \: of \: Solution:}}$

$\sf{ \pink{Given}}$

$\begin{gathered} \implies{ \sf{ \blue{Height \: of \: the \: cone \: = 24cm}}} \\ \\ \implies{ \sf{ \green{ Radius \: \: of \: the \: cone \: = 6cm}}} \\ \\ \\ \implies{ \sf{ \red {Volume \: of \: the \: cone = \frac{1}{3} \times \frac{22}{7} \times ( {6}^{2} )\times 24}}} \\ \\ \\ \implies{ \sf{ \red {Volume \: of \: the \: cone = 905.14cm}}}\end{gathered}$

$\sf{ \fbox{ \pink{According \: to \: the \: Question:}}}$

$\sf{\red{Volume \: of \: the \: Sphere \: = \frac{3}{4} \times \frac{22}{7} \times ({r}^{3})}}$

$\sf{\purple{Volume \: of \: the \: Sphere \: = \frac{3}{4} \times \frac{3}{4} \times ({r}^{3})=905.14}}$

$\begin{gathered}\sf{\green{Volume \: of \: the \: Sphere \: = \frac{3}{4} \times \frac{22}{7} \times ({r}^{3})=905.14}} \\ \\ \sf{\red{Volume \: of \: the \: Sphere \: = \frac{66}{28} \times ( {r}^{3} ) = 905.14 }} \\ \\ \\ \sf{\green{Volume \: of \: the \: Sphere = {r}^{3} {\implies \: 216}}} \\ \\ \\ \sf{\blue{Volume \: of \: the \: Sphere = (r) {\implies 6cm}}}\end{gathered}$

$\sf{ \red{ \fbox{Hence, \: Required}}} \sf{ \green{ \fbox{ Radius \: of \: Sphere}}} \sf{ \blue{ \fbox{ = 6cm}}}$

Discussion

22.	State the quadrant in which theta lies sin theta 0
Answer» ANSWER: HIGHPOINT VICIOUS ssiufifiufufufufufufufufututigigugguigigigjc DHL

22.

State the quadrant in which theta lies sin theta 0

Answer»

ANSWER:

HIGHPOINT VICIOUS ssiufifiufufufufufufufufututigigugguigigigjc DHL

Discussion

23.	Discount Original PriceP200P250Sales PriceP170Rate of Discount15%20%10%P50P60P47.50P950P540P902.50Total SalesP 278P300Rate of Commission5%Commission18%P45P81,000Selling PriceP4,500P9.000Rate of Sales Tax6%Sales Tax4%P720P826.80PrincipalP2.500InterestRate of Interest12%25%P650P3.750P260Time5 years6 months4 years
Answer» Answer: ID 736 049 9005 Pswd Gx93Zi G i R L O n l y

23.

Discount Original PriceP200P250Sales PriceP170Rate of Discount15%20%10%P50P60P47.50P950P540P902.50Total SalesP 278P300Rate of Commission5%Commission18%P45P81,000Selling PriceP4,500P9.000Rate of Sales Tax6%Sales Tax4%P720P826.80PrincipalP2.500InterestRate of Interest12%25%P650P3.750P260Time5 years6 months4 years

Answer»

Answer:

ID 736 049 9005

Pswd Gx93Zi

G i R L O n l y

Discussion

24.	72xy 5y2x25xy y 5x2++xy y²3+44+ +43.123.1212.
Answer» 12 is the ANSWER THANKS BRAINLIST

Discussion

25.	To fill a swimming pool two pipes are to be used. If the pipe of larger diameter is used for 4 hours and the pipe of smaller diameter for 9 hours, only half the pool can be filled. Find, how long it would take for each pipe to fill the pool separately, if the pipe of smaller diameter takes 10 hours more than the pipe of larger diameter to fill the pool?➳ REQUIRED GOOD ANSWER
Answer» I have SENT in such way because Brainly is saying it "Rude" No NEED of MARKING me BRAINLIEST:-)

25.

To fill a swimming pool two pipes are to be used. If the pipe of larger diameter is used for 4 hours and the pipe of smaller diameter for 9 hours, only half the pool can be filled. Find, how long it would take for each pipe to fill the pool separately, if the pipe of smaller diameter takes 10 hours more than the pipe of larger diameter to fill the pool?➳ REQUIRED GOOD ANSWER

Answer»

I have SENT in such way because Brainly is saying it "Rude"

No NEED of MARKING me BRAINLIEST:-)

Discussion

26.	" Did you post the letter ? asked Hina in indirect speech
Answer» ANSWER: that he had a LETTER for her

26.

" Did you post the letter ? asked Hina in indirect speech

Answer»

ANSWER:

that he had a LETTER for her

Discussion

27.	Obsse/
Answer» Answer: $\frac{73890}{80 } = ?$ 923.62

27.

Obsse/

Answer»

Answer:

$\frac{73890}{80 } = ?$

923.62

Discussion

28.	Base of right angle triangle is 15 cm and its diagonal is 17 cm. Find its perimeterएक समकोण त्रिभुज का आधार 15 सेमी. व इसका विकर्ण 17 सेमी. है। इस त्रिभुज का परिमाप बताइ(A) 40 cm(B) 60 cm(C) 58 cm(D) 50 cm
Answer» ANSWER: 60 CM is answer THANKS BRAINLIST

28.

Base of right angle triangle is 15 cm and its diagonal is 17 cm. Find its perimeterएक समकोण त्रिभुज का आधार 15 सेमी. व इसका विकर्ण 17 सेमी. है। इस त्रिभुज का परिमाप बताइ(A) 40 cm(B) 60 cm(C) 58 cm(D) 50 cm

Answer»

ANSWER:

60 CM is answer THANKS BRAINLIST

Discussion

29.	32. In the given figure, D and E are the points onthe base BC of AABC such that BD = CE, AD =AE and LADE = LAED.Prove that AABE = AACD.
Answer» Answer: CD and ABEAD = AE (given)BD = EC (given)BD + DE = DE + ECBE = CDADC = AEB

29.

32. In the given figure, D and E are the points onthe base BC of AABC such that BD = CE, AD =AE and LADE = LAED.Prove that AABE = AACD.

Answer»

Answer:

CD and ABEAD = AE (given)BD = EC (given)BD + DE = DE + ECBE = CDADC = AEB

Discussion

30.	If n(A)=100,n(B)=70,n(A intersection B)=20,then n(A triangle B)is
Answer» Answer: 130 is the answer Step-by-step explanation: n(A)=100,n(B)=70 and n(A∩B) = 20 n(A∪B) = n(A) + n(B) - n(A∩B) n(A∪B) = 100 + 70 - 20 =170 -20 = 150 n(AΔB) = n(A∪ B) - n(A∩B) = 150 - 20 = 130

30.

If n(A)=100,n(B)=70,n(A intersection B)=20,then n(A triangle B)is

Answer»

Answer:

130 is the answer

Step-by-step explanation:

n(A)=100,n(B)=70 and n(A∩B) = 20

n(A∪B) = n(A) + n(B) - n(A∩B)

n(A∪B) = 100 + 70 - 20

=170 -20

= 150

n(AΔB) = n(A∪ B) - n(A∩B)

= 150 - 20

= 130

Discussion

31.	Jgjifhohhxnnkfjjgdohigfr as you too add kgifkjp
Answer» Step-by-step EXPLANATION: jgjifhohhxnnkfjjgdohigfrkgifkjp

31.

Jgjifhohhxnnkfjjgdohigfr as you too add kgifkjp

Answer»

Step-by-step EXPLANATION:

jgjifhohhxnnkfjjgdohigfrkgifkjp

Discussion

32.	Directions (68-72): Study the following information carefully and answer the question givEight persons i.e.A, B, C, D, P, Q, R and S are sitting around two circular concentric table. Four of themSare sitting around an inner table and four of them are sitting around the outer table but not necessarily in thesame order. Some of them are facing inside and some are facing outside from the table. The persons who sitsin inner circle sit just opposite to the persons who sits outer circle. They attempt different competitive examsi.e. IBPS, Railway, SSC, UPSC, MPSC, RBI, SBI and LIC but not necessarily in the same order. Distancebetween each of the person is same.S does not face south. (D sits just opposite the one who sits immediate right of the one who attempt RBIand faces in the north. R attempt LIC and sits 2nd to the right of the one who attempt RBI. The one whoattempt RBI sits at inner table and faces opposite direction'as D. The one who attempt SSC sits immediateleft of the one who attempt IBPS who sits immediate right of Q. Both B and C face opposite direction toeach other. C attempt UPSC and sits immediate left of the one who attempt SSC. Q is neither an immediateneighbour of D nor sit at inner table. R does not sit opposite to the one who attempt IBPS. Q does notattempt SSC.S attempts MPSC and sits immediate right of P. B siis opposite the one who sits immediate leftof A, who neither attempt SBI not IBPS. S does not sit immediate right of R. Rand the one who attempt SBIface in the same direction. R does not face inside.How many persons sit between D and the one who attempt SBI, when counted to the left of D?1. As many persons sit between S and the one who attempt RBI, when counted to the right of S2. As many persons sit between B and C, when counted to the right of3. None of these4. Two brol 5. Both of them are not sitting on the same table
Answer» ANSWER: Step-by-step EXPLANATION: HI uffufufufjcjviigigugufufhhcydydtrsse

32.

Directions (68-72): Study the following information carefully and answer the question givEight persons i.e.A, B, C, D, P, Q, R and S are sitting around two circular concentric table. Four of themSare sitting around an inner table and four of them are sitting around the outer table but not necessarily in thesame order. Some of them are facing inside and some are facing outside from the table. The persons who sitsin inner circle sit just opposite to the persons who sits outer circle. They attempt different competitive examsi.e. IBPS, Railway, SSC, UPSC, MPSC, RBI, SBI and LIC but not necessarily in the same order. Distancebetween each of the person is same.S does not face south. (D sits just opposite the one who sits immediate right of the one who attempt RBIand faces in the north. R attempt LIC and sits 2nd to the right of the one who attempt RBI. The one whoattempt RBI sits at inner table and faces opposite direction'as D. The one who attempt SSC sits immediateleft of the one who attempt IBPS who sits immediate right of Q. Both B and C face opposite direction toeach other. C attempt UPSC and sits immediate left of the one who attempt SSC. Q is neither an immediateneighbour of D nor sit at inner table. R does not sit opposite to the one who attempt IBPS. Q does notattempt SSC.S attempts MPSC and sits immediate right of P. B siis opposite the one who sits immediate leftof A, who neither attempt SBI not IBPS. S does not sit immediate right of R. Rand the one who attempt SBIface in the same direction. R does not face inside.How many persons sit between D and the one who attempt SBI, when counted to the left of D?1. As many persons sit between S and the one who attempt RBI, when counted to the right of S2. As many persons sit between B and C, when counted to the right of3. None of these4. Two brol 5. Both of them are not sitting on the same table

Answer»

ANSWER:

Step-by-step EXPLANATION:

HI uffufufufjcjviigigugufufhhcydydtrsse

Discussion

33.	Find the multiplicative inverse of z= √3+1
Answer» ANSWER: (√3-1)/2 Step-by-step EXPLANATION: z=√3+1 =1/(√3+1) =1*(√3-1)/(√3+1)(√3-1) =(√3-1)/√3^2-1^2 =√3-1/3-1 =(√3-1)/2

33.

Find the multiplicative inverse of z= √3+1

Answer»

ANSWER:

(√3-1)/2

Step-by-step EXPLANATION:

z=√3+1

=1/(√3+1)

=1*(√3-1)/(√3+1)(√3-1)

=(√3-1)/√3^2-1^2

=√3-1/3-1

=(√3-1)/2

Discussion

34.	The quotient when (m2 – 3m - 10) is divided by (m + 2)
Answer» ANSWER: Step-by-step EXPLANATION: = (m^2 - 5M + 2m - 10) / (m + 2) = (m + 2)*(m - 5) / (m + 2) = (m - 5)

34.

The quotient when (m2 – 3m - 10) is divided by (m + 2)

Answer»

ANSWER:

Step-by-step EXPLANATION:

= (m^2 - 5M + 2m - 10) / (m + 2)

= (m + 2)*(m - 5) / (m + 2)

= (m - 5)

Discussion

35.	Y=(root x+1/rootx)^2
Answer» Step-by-step EXPLANATION: ${ (\frac{ \sqrt{x} + 1}{ \sqrt{x} } )}^{2} \\ \frac{x + 1 + 2 \sqrt{x} }{x} \\ 1 + \frac{1}{x} + \frac{2 \sqrt{x} }{x} \\ 1 + \frac{1}{x} + \frac{2}{ \sqrt{x} }$

35.

Y=(root x+1/rootx)^2

Answer»

Step-by-step EXPLANATION:

${ (\frac{ \sqrt{x} + 1}{ \sqrt{x} } )}^{2} \\ \frac{x + 1 + 2 \sqrt{x} }{x} \\ 1 + \frac{1}{x} + \frac{2 \sqrt{x} }{x} \\ 1 + \frac{1}{x} + \frac{2}{ \sqrt{x} }$

Discussion

36.	Write the first two common multiple s of 4 and 5
Answer» ANSWER: The first TWO common multiples of 4 and 5 are 20 and 40.

36.

Write the first two common multiple s of 4 and 5

Answer»

ANSWER:

The first TWO common multiples of 4 and 5 are 20 and 40.

Discussion

37.	Write all the even number form 21 to 44
Answer» Answer: 22,24,26,28,30,32,34,36,38,40,42,44, Step-by-step EXPLANATION: EVEN NUMBER which DIVIDE with 2

37.

Write all the even number form 21 to 44

Answer»

Answer:

22,24,26,28,30,32,34,36,38,40,42,44,

Step-by-step EXPLANATION:

EVEN NUMBER which DIVIDE with 2

Discussion

38.	When 3 is multiplied by 5 less than a number, the result is 9 less than 5 times the number. Find the number
Answer» $\mathbb{\bold{\underline{ANSWER}}}$ $\fbox{\textsf{12}}$ $\mathbb{\bold{\underline{EXPLANATION:}}}$ $\textsf{We will make a linear equation to solve this.}$ $\colon \to \textbf{To make a linear equation :}$ $\textsf{Let the number be 'n'}$ $\star \texttt{ 5 less than a number $\to$ \textsf{n - 5}}$ $\star \texttt{ 3 is multiplied by 5 less than a number $\to$ \textsf{\textbf{3 x (n - 5)}}}$ $\star \texttt{ 5 times a number $\to$ \textsf{5 x n}}$ $\star \texttt{ 9 less than 5 times a number $\to$ \textsf{\textbf{(5 x n) - 9}}}$ $\textsf{So, the linear equation is : \textbf{3 x (n - 5) = (5 x n) - 9}}$ $\colon \to \textbf{To solve the linear equation :}$ $\star \textsf{ 3 x (n - 5) = (5 x n) - 9}$ $\to \textsf{(3 x n) - (3 x -5) = 5n - 9}$ $\to \textsf{3n - (-15) = 5n - 9}$ $\to \textsf{3n + 15 = 5n - 9}$ $\to \textsf{15 = 5n - 3n - 9}$ $\to \textsf{15 + 9 = 5n - 3n}$ $\to \textsf{24 = 2n}$ $\to \textsf{$\frac{\textsf{24}}{\textsf{2}}$ = n}$ $\therefore \textbf{The number = \underline{12}}$

38.

When 3 is multiplied by 5 less than a number, the result is 9 less than 5 times the number. Find the number

Answer»

$\mathbb{\bold{\underline{ANSWER}}}$

$\fbox{\textsf{12}}$

$\mathbb{\bold{\underline{EXPLANATION:}}}$

$\textsf{We will make a linear equation to solve this.}$

$\colon \to \textbf{To make a linear equation :}$

$\textsf{Let the number be 'n'}$

$\star \texttt{ 5 less than a number $\to$ \textsf{n - 5}}$

$\star \texttt{ 3 is multiplied by 5 less than a number $\to$ \textsf{\textbf{3 x (n - 5)}}}$

$\star \texttt{ 5 times a number $\to$ \textsf{5 x n}}$

$\star \texttt{ 9 less than 5 times a number $\to$ \textsf{\textbf{(5 x n) - 9}}}$

$\textsf{So, the linear equation is : \textbf{3 x (n - 5) = (5 x n) - 9}}$

$\colon \to \textbf{To solve the linear equation :}$

$\star \textsf{ 3 x (n - 5) = (5 x n) - 9}$

$\to \textsf{(3 x n) - (3 x -5) = 5n - 9}$

$\to \textsf{3n - (-15) = 5n - 9}$

$\to \textsf{3n + 15 = 5n - 9}$

$\to \textsf{15 = 5n - 3n - 9}$

$\to \textsf{15 + 9 = 5n - 3n}$

$\to \textsf{24 = 2n}$

$\to \textsf{$\frac{\textsf{24}}{\textsf{2}}$ = n}$

$\therefore \textbf{The number = \underline{12}}$

Discussion

39.	The line joining the center of the circle to any point lying on the boundary of the circle is called
Answer» CENTER to a BOUNDARY POINT is a RADIUS

Discussion

40.	The sum of two integers is -45 . if one of the integers is 15 . determine the other number .
Answer» ANSWER: The other NUMBER is -60.

40.

The sum of two integers is -45 . if one of the integers is 15 . determine the other number .

Answer»

ANSWER:

The other NUMBER is -60.

Discussion

41.	The salary of Tushar is ₹ 20000. He saves 15% of his salary. How much does he save? *
Answer» PLEASE if this HELPS MARK me as BRAINLIST

Discussion

42.	For what values of x and y is PQRS a parallelogram?
Answer» sum of the adjacent angles of parallelogram is supplementary. Therefore, Q + R = 180° 4y+7 + 10y-37 = 180° 14y - 30° = 180° 14y = 210° y = 210°/14 y = 15° x = 165°

42.

For what values of x and y is PQRS a parallelogram?

Answer»

sum of the adjacent angles of parallelogram is supplementary.

Therefore,

Q + R = 180°

4y+7 + 10y-37 = 180°

14y - 30° = 180°

14y = 210°

y = 210°/14

y = 15°

x = 165°

Discussion

43.	TU BJI KAR TAMMANA???? BRAINLIEST ANSWER???
Answer» Step-by-step EXPLANATION: OKK okk I am ASKING a QUESTION okk my BASTI

43.

TU BJI KAR TAMMANA???? BRAINLIEST ANSWER???

Answer»

Step-by-step EXPLANATION:

OKK okk I am ASKING a QUESTION okk my BASTI

Discussion

44.	Find the value of b and c is equals to 40 degree from the adjoining figure
Answer» In triangle PQS as PS = QS so angle QPS = angle PQS then, angle ( PQS + QPS + PSQ ) = 180 [ANGLE SUM PROPERTY] so 40 +40 + PSQ = 180 80 + PSQ = 180 PSQ = 180-80 PSQ = 100 THEREFORE, angle B = 100

44.

Find the value of b and c is equals to 40 degree from the adjoining figure

Answer»

In triangle PQS

as PS = QS

so angle QPS = angle PQS

then, angle ( PQS + QPS + PSQ ) = 180 [ANGLE SUM PROPERTY]

so 40 +40 + PSQ = 180

80 + PSQ = 180

PSQ = 180-80

PSQ = 100

THEREFORE, angle B = 100

Discussion

45.	व्हाट इज द रेश्यो ऑफ 90 एंड 211
Answer» ANSWER: MARK me as BRAINLIEST Step-by-step explanation: 90+211 ---------- 2 Answer = 95.5

45.

व्हाट इज द रेश्यो ऑफ 90 एंड 211

Answer»

ANSWER:

MARK me as BRAINLIEST

Step-by-step explanation:

90+211

----------

2

Answer = 95.5

Discussion

46.	A 6 meter rope is cut into 3 equal pieces. How long is each piece?
Answer» Answer: 2 metre Step-by-step EXPLANATION: length of rope = 6 metres No of divisions of rope = 3 (equally) Length of each piece of rope = 6 metres / 3 = 2 metres therefore, length of each piece is 2 metre

46.

A 6 meter rope is cut into 3 equal pieces. How long is each piece?

Answer»

Answer:

2 metre

Step-by-step EXPLANATION:

length of rope = 6 metres

No of divisions of rope = 3 (equally)

Length of each piece of rope = 6 metres / 3

= 2 metres

therefore, length of each piece is 2 metre

Discussion

47.	The addition and multiplication identity of element of R are
Answer» Answer: R BECOMES a RING with identity when we define addition and multiplication as in ELEMENTARY calculus : ( f + g ) ( x ) = f ( x ) + g ( x ) and ( fg ) ( x ) = f ( x ) g ( x ) . The identity element is the constant function 1. R is COMMUTATIVE because Ris , but it does have zero divisors for ALMOST all choices of X. Step-by-step explanation: please can you please

47.

The addition and multiplication identity of element of R are

Answer»

Answer:

R BECOMES a RING with identity when we define addition and multiplication as in ELEMENTARY calculus : ( f + g ) ( x ) = f ( x ) + g ( x ) and ( fg ) ( x ) = f ( x ) g ( x ) . The identity element is the constant function 1. R is COMMUTATIVE because Ris , but it does have zero divisors for ALMOST all choices of X.

Step-by-step explanation:

please can you please

Discussion

48.	What is the total length of the closed finger?
Answer» ANSWER: Its LENGTH DEPENDS on what is that FIGURE Step-by-step EXPLANATION:

48.

What is the total length of the closed finger?

Answer»

ANSWER:

Its LENGTH DEPENDS on what is that FIGURE

Step-by-step EXPLANATION:

Discussion

49.	solve the given equation 2x+5y=1;2x+3y=3 by three different methods - graphical method ;substitution method and elimination method
Answer» Given Equation ⇒2x + 5y = 1 (i)eq ⇒2x + 3y = 3 (ii)eq METHOD:- 1 Graphical method Take Eq(i) 2x + 5y = 1 When X =0 ⇒2×0 +5y =1 ⇒5y = 1 ⇒y=1/5 When y = 0 ⇒2x + 5×0 = 1 ⇒2x =1 ⇒x = 1/2 point is (1/5 , 1/2) Take Eq(ii) 2x + 3y = 3 When y = 0 ⇒2x + 3×0 =3 ⇒2x = 3 ⇒x=3/2 When x = 0 ⇒2×0 + 3y = 3 ⇒y = 3/3 = 1 method:-2 Substitution Method ⇒2x + 5y = 1 (i)eq ⇒2x + 3y = 3 (ii)eq Take 2x + 5y = 1 (i)eq ⇒2x + 5y = 1 ⇒2x = 1 - 5y (iii)eq PUT the value of 2x on (ii)eq ⇒2x + 3y = 3 (ii)eq ⇒1 - 5y + 3y = 3 ⇒1 - 2y = 3 ⇒1 - 3 = 2y ⇒-2 = 2y ⇒-2 = 2y ⇒y = -1 Now put the value of y on (iii) eq ⇒2x = 1 - 5y ⇒2x = 1 + 5 ⇒2x = 6 ⇒x = 3 So x = 3 and y = -1 Method:-3 ELIMINATION method ⇒2x + 5y = 1 (i)eq ⇒2x + 3y = 3 (ii)eq Subtract (ii) from (i) ⇒2x + 5y - ( 2x + 3y ) = 1 - 3 ⇒2x + 5y - 2x -3y = -2 ⇒2y = -2 ⇒y = -1 Put the value of y on (i)eq ⇒2x + 5y = 1 (i)eq ⇒2x + 5(-1) = 1 ⇒2x - 5 = 1 ⇒2x = 6 ⇒x =3 so x = 3 and y = -1

49.

solve the given equation 2x+5y=1;2x+3y=3 by three different methods - graphical method ;substitution method and elimination method

Answer»

Given Equation

⇒2x + 5y = 1 (i)eq

⇒2x + 3y = 3 (ii)eq

METHOD:- 1 Graphical method

Take Eq(i) 2x + 5y = 1

When X =0

⇒2×0 +5y =1

⇒5y = 1

⇒y=1/5

When y = 0

⇒2x + 5×0 = 1

⇒2x =1

⇒x = 1/2

point is (1/5 , 1/2)

Take Eq(ii) 2x + 3y = 3

When y = 0

⇒2x + 3×0 =3

⇒2x = 3

⇒x=3/2

When x = 0

⇒2×0 + 3y = 3

⇒y = 3/3 = 1

method:-2 Substitution Method

⇒2x + 5y = 1 (i)eq

⇒2x + 3y = 3 (ii)eq

Take 2x + 5y = 1 (i)eq

⇒2x + 5y = 1

⇒2x = 1 - 5y (iii)eq

PUT the value of 2x on (ii)eq

⇒2x + 3y = 3 (ii)eq

⇒1 - 5y + 3y = 3

⇒1 - 2y = 3

⇒1 - 3 = 2y

⇒-2 = 2y

⇒y = -1

Now put the value of y on (iii) eq

⇒2x = 1 - 5y

⇒2x = 1 + 5

⇒2x = 6

⇒x = 3

So x = 3 and y = -1

Method:-3 ELIMINATION method

⇒2x + 5y = 1 (i)eq

⇒2x + 3y = 3 (ii)eq

Subtract (ii) from (i)

⇒2x + 5y - ( 2x + 3y ) = 1 - 3

⇒2x + 5y - 2x -3y = -2

⇒2y = -2

⇒y = -1

Put the value of y on (i)eq

⇒2x + 5y = 1 (i)eq

⇒2x + 5(-1) = 1

⇒2x - 5 = 1

⇒2x = 6

⇒x =3

so x = 3 and y = -1

Discussion

50.	Find the mean/arthimetic mean/average/average mean/of the following data 10,24,35,46,57,68,79,81
Answer» Answer: Step-by-step EXPLANATION: Average = SUM of OBSERVATIONS/Number of observations = 400 /8 = 50

50.

Find the mean/arthimetic mean/average/average mean/of the following data 10,24,35,46,57,68,79,81

Answer»

Answer:

Step-by-step EXPLANATION:

Average = SUM of OBSERVATIONS/Number of observations

= 400 /8

= 50

Discussion

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Find the value of b and c is equals to 40 degree from the adjoining figure

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so 40 +40 + PSQ = 180

80 + PSQ = 180

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PSQ = 100

THEREFORE, angle B = 100

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How long will they take to go a distance of 10 km ?

in a triangle ABC if 2 angle A is equals to 3 angle B is equals to 6 angle C then find the measure of angle A

The price of table depreciates every year by 20%.If the value of the table after 2 years will be32000, then what is the present price (in Rupees)of the table?(a) 48,000(b) 44,000(c) 50,000(d) 51,000

Class -VI(PT-2)1 pointWhich of the followingnumbers is a perfect number?O O O486Clour coloction

Find x and y so that point M(4.- 8) is the midpoint of the segment defined by points C(x. 1.0) and D(0.7-2).

If the 3rd and the 9th terms of an A.P. are 4 and − 8 respectively, then which term of this A.P is zero.

Observe the following pattern:ΔΔ1st figure2nd figure5th figureExpress the answer in terms of n and complete the following statement:The algebraic expression for the number of triangles in the nth figure is

What is integration in physics

If 25% of y is x, then y = ?

Classify the following as rational Or irrational. a) √225.b)√39.

Find the compound interest paid when a sum of 10000 Rupees is invested for 1 year 3 months at 8½% per annum compounded annuallypls say me frnds fast ga

18. The area of the sector of a circle of radius 10 cm is 75 cm sq. Find the length of correspondingarc of the circle.(a) 50 cm (b) 60 cm(c) 22 cm(d) 15 cm

Q2; Solve the recurrence relation ar-5ar-1+6ar-2=2+r Given that a0=1 and a1=1

FIND THE LENGTH ON THE SIDE OF A SQUARE IF ITS AREA IS 441m²

सम ऑफ टू नंबर्स एस 75 एफ वन एक्सटीरियर द अदर बाय 15 फाइंड द नंबर्स

the angel of quadrilateral are (5x) degree, (3x+10)degree, (6x-20), (x+25) degree find the value of x and measure of each angle of the quadrilateral

a cone of height 24 cm and radius of base 6 cm is made up of modelling clay.a child reshapes it in the form of a sphere .find the radius of the sphere.i know the answer but plz give a proper explanation.

State the quadrant in which theta lies sin theta 0

72xy 5y2x25xy y 5x2++xy y²3+44+ +43.123.1212.

" Did you post the letter ? asked Hina in indirect speech

Obsse/

32. In the given figure, D and E are the points onthe base BC of AABC such that BD = CE, AD =AE and LADE = LAED.Prove that AABE = AACD.

If n(A)=100,n(B)=70,n(A intersection B)=20,then n(A triangle B)is

Jgjifhohhxnnkfjjgdohigfr as you too add kgifkjp

Find the multiplicative inverse of z= √3+1

The quotient when (m2 – 3m - 10) is divided by (m + 2)

Y=(root x+1/rootx)^2

Write the first two common multiple s of 4 and 5

TU BJI KAR TAMMANA???? BRAINLIEST ANSWER???

व्हाट इज द रेश्यो ऑफ 90 एंड 211

solve the given equation 2x+5y=1;2x+3y=3 by three different methods - graphical method ;substitution method and elimination method