332354 + Interview Questions in Secondary School in Math

1.	(30)Quantitatis. (30)Quantitati... (30) Martial Ski... (30)Verbal Slo... (30)076. Among 165 examinees in a certain school, the ratio of successful to unsuccessful students is 10 1 115 trore students were succes,would have been the ratio of successful to unsuccessful students?O (A) 41 2O (H) 31 2O (C) 21 2O (D) 9 2
Answer» ANSWER: dhadak short VIDEO APP Step-by-step EXPLANATION: dhadak :Short video app download on PLAY store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store

1.

(30)Quantitatis. (30)Quantitati... (30) Martial Ski... (30)Verbal Slo... (30)076. Among 165 examinees in a certain school, the ratio of successful to unsuccessful students is 10 1 115 trore students were succes,would have been the ratio of successful to unsuccessful students?O (A) 41 2O (H) 31 2O (C) 21 2O (D) 9 2

Answer»

ANSWER:

dhadak short VIDEO APP

Step-by-step EXPLANATION:

dhadak :Short video app download on PLAY store

dhadak :Short video app download on play store

Discussion

2.	If 3x+½x =5 then solve the following problems,i) prove 6x²-10x+1=0 .ii) Find out the value of {(36x²+1)÷4x²} .iii) Find out the value of 27x³+⅛x³PLZ HELP ME THIS IS URGENT
Answer» ANSWER: The first one is wrong and the answer for the second one is: ii)root -1/6 iii)And for the third one there MUST be some values such as 3x + 4 = x/2 Step-by-step explanation: For the second one, the solution is that you TRANSPOSE the 4x^2 to the RHS which will give you 36x^2 + 1 = 0 And then transpose 1 and then transpose 36 which gives you -1/36 and then transpose the ^2 to the RHS which gives you the root2 which gives you the answer as root -1/6 Hope this HELPS

2.

If 3x+½x =5 then solve the following problems,i) prove 6x²-10x+1=0 .ii) Find out the value of {(36x²+1)÷4x²} .iii) Find out the value of 27x³+⅛x³PLZ HELP ME THIS IS URGENT

Answer»

ANSWER:

The first one is wrong and the answer for the second one is:

ii)root -1/6

iii)And for the third one there MUST be some values such as 3x + 4 = x/2

Step-by-step explanation:

For the second one, the solution is that you TRANSPOSE the 4x^2 to the RHS which will give you 36x^2 + 1 = 0

And then transpose 1 and then transpose 36 which gives you -1/36 and then transpose the ^2 to the RHS which gives you the root2 which gives you the answer as root -1/6

Hope this HELPS

Discussion

3.	What is 25/2% of 200?
Answer» 25/2=12.5 12.5*200 2500

Discussion

4.	3) Sector of circle is the portion of the circle enclosed byand
Answer» Answer: hyy plz MARK me as brillent Step-by-step explanation: A CIRCULAR sector is the portion of a circle ENCLOSED by TWO radii and the corresponding arc. where s is the length of the arc, R is the radius of the circle.

4.

3) Sector of circle is the portion of the circle enclosed byand

Answer»

Answer:

hyy plz MARK me as brillent

Step-by-step explanation:

A CIRCULAR sector is the portion of a circle ENCLOSED by TWO radii and the corresponding arc. where s is the length of the arc, R is the radius of the circle.

Discussion

5.	Draw a parallel line to a given line l at a distance of 6.5cm
Answer» Answer: Draw a LINE parallel to GIVEN line L at a DISTANCE of 6.5 CM. 1. See answer. Add answer+5 PTS. Log in to add comment.

5.

Draw a parallel line to a given line l at a distance of 6.5cm

Answer»

Answer:

Draw a LINE parallel to GIVEN line L at a DISTANCE of 6.5 CM. 1. See answer. Add answer+5 PTS. Log in to add comment.

Discussion

6.	Define the convergence of a sequence (a,) and verify whether the sequencewhose nth term is a, = (n+1/n-1)^nconverges or not.
Answer» ANSWER: equal simplest FORM 18/54 and 23/69 FULL form Step-by-step EXPLANATION:

6.

Define the convergence of a sequence (a,) and verify whether the sequencewhose nth term is a, = (n+1/n-1)^nconverges or not.

Answer»

ANSWER:

equal simplest FORM 18/54 and 23/69 FULL form

Step-by-step EXPLANATION:

Discussion

7.	2)280.69 + 25.2 + 28
Answer» ANSWER: Step-by-step explanation: 333.89

7.

2)280.69 + 25.2 + 28

Answer»

ANSWER:

Step-by-step explanation:

333.89

Discussion

8.	4. The sum of twice a number and thrice the number is 100. Find the number.
Answer» Answer :- The number is 20. Given :- SUM The sum of twice a number and thrice the number is 100. To find :- The number. Solution :- Let the number be x Twice the number = x × 2 = 2X Thrice the number = x × 3 = 3X And there sum is 100. So, The equation will be :- ➜ 2x + 3x = 100 ➜ 5x = 100 ➜ $\bf x = \dfrac{100}{5}$ ➜ x = 20 Therefore, The number is 20. Twice the number = 20 × 2 = 40. Thrice the number = 20 × 3 = 60. Verification :- ➜ 2x + 3x = 100 By placing 20 in place of x, We get :- ➜ 2(20) + 3(20) = 100 ➜ 40 + 60 = 100 ➜ 100 = 100 Hence , Verified.

8.

4. The sum of twice a number and thrice the number is 100. Find the number.

Answer»

Answer :-

The number is 20.

Given :-

SUM The sum of twice a number and thrice the number is 100.

To find :-

The number.

Solution :-

Let the number be x

Twice the number = x × 2 = 2X
Thrice the number = x × 3 = 3X
And there sum is 100.

So, The equation will be :-

➜ 2x + 3x = 100

➜ 5x = 100

➜ $\bf x = \dfrac{100}{5}$

➜ x = 20

Therefore, The number is 20.

Twice the number = 20 × 2 = 40.
Thrice the number = 20 × 3 = 60.

Verification :-

➜ 2x + 3x = 100

By placing 20 in place of x, We get :-

➜ 2(20) + 3(20) = 100

➜ 40 + 60 = 100

➜ 100 = 100

Hence , Verified.

Discussion

9.	Please need correct answer with step by step explanation
Answer» ANSWER: Here is the answer Hope it's HELPFUL

9.

Please need correct answer with step by step explanation

Answer»

ANSWER:

Here is the answer

Hope it's HELPFUL

Discussion

10.	Xy-3y+x^2-3x factorise
Answer» ANSWER: xy-3y+x^2-3x =xy+x^2-3y-3x =x(y+x)-3(y+x) =(y+x)(x-3) =(x+y)(x-3)

10.

Xy-3y+x^2-3x factorise

Answer»

ANSWER:

xy-3y+x^2-3x

=xy+x^2-3y-3x

=x(y+x)-3(y+x)

=(y+x)(x-3)

=(x+y)(x-3)

Discussion

11.	If x is a rational number and a, b, c are all different integers, then prove that: x pwer a-b,x power b-c,x power c-a = 1
Answer» ANSWER: See this ATTACHMENT. Step-by-step EXPLANATION: Mark me As Brainlist

11.

If x is a rational number and a, b, c are all different integers, then prove that: x pwer a-b,x power b-c,x power c-a = 1

Answer»

ANSWER:

See this ATTACHMENT.

Step-by-step EXPLANATION:

Mark me As Brainlist

Discussion

12.	What is the answer of the epuation (15+10)²
Answer» ANSWER: (15+10)²= 15²+2×15×10+10²(a+b)² hope it HELPS.

12.

What is the answer of the epuation (15+10)²

Answer»

ANSWER:

(15+10)²= 15²+2×15×10+10²(a+b)²

hope it HELPS.

Discussion

13.	Express as kg using decimals 7kg80g
Answer» Answer: 7.80kg OR 7.8 kg Step-by-step EXPLANATION: HOPE IT'S HELPFUL MARK ME AS BRAINLIST AND FLW ME

13.

Express as kg using decimals 7kg80g

Answer»

Answer:

7.80kg OR 7.8 kg

Step-by-step EXPLANATION:

HOPE IT'S HELPFUL MARK ME AS BRAINLIST AND FLW ME

Discussion

14.	Specify the type of quadrilateral ABCD in each case, given the following Information.AO = OC, DO = OB, DB ﬩ AC, DA ﬩ AB, O being the point ofintersection of diagonals.
Answer» Answer: man, actually this answer has a BIG EXPLANATION, just REFER your book and READ LINE by line

14.

Specify the type of quadrilateral ABCD in each case, given the following Information.AO = OC, DO = OB, DB ﬩ AC, DA ﬩ AB, O being the point ofintersection of diagonals.

Answer»

Answer:

man, actually this answer has a BIG EXPLANATION, just REFER your book and READ LINE by line

Discussion

15.	A merchant pays 12% commission on total sales and pays delcredre at a rate of 3% on credit sales.If cash sales were Rs 6000 and the agent earned Rs 1520 as commission, find the total sales?
Answer» Answer: 5400 Step-by-step explanation: Cost of goods sold by the agent = RS. 45,000. The agent is to be given a TOTAL commission =9%+3%=12%, then 12% commission on total SALE = 100 12 ×45000 = Rs. 5400 Thus, the total earning of the agent is Rs. 5400.

15.

A merchant pays 12% commission on total sales and pays delcredre at a rate of 3% on credit sales.If cash sales were Rs 6000 and the agent earned Rs 1520 as commission, find the total sales?

Answer»

Answer:

5400

Step-by-step explanation:

Cost of goods sold by the agent = RS. 45,000.

The agent is to be given a TOTAL commission =9%+3%=12%, then

12% commission on total SALE

=

100

12

×45000

= Rs. 5400

Thus, the total earning of the agent is Rs. 5400.

Discussion

16.	Someone please answer with explanation
Answer» Answer: i. B) AB and AC ii. a)AB^2=BC^2+CA^2 Step-by-step explanation: i. you can SEE it frm the FIG given ii. you need to use pythagoras THM ie hypotenuse ^2=base^2+perpendicular ^2

16.

Someone please answer with explanation

Answer»

Answer:

i. B) AB and AC

ii. a)AB^2=BC^2+CA^2

Step-by-step explanation:

i. you can SEE it frm the FIG given

ii. you need to use pythagoras THM ie hypotenuse ^2=base^2+perpendicular ^2

Discussion

17.	Convert Decimals into percentage.0.0063
Answer» Answer: 0.63% Step-by-step explanation: "Percent" means "per 100" or "over 100". So, to CONVERT 0.0063 to percent we REWRITE 0.0063 in terms of "per 100" or over 100. Multiply 0.0063 by 100/100. Since 100/100 = 1, we are only multiplying by 1 and not changing the VALUE of our number. 0.00631×100/100=0.63100 0.63/100 is 0.63 over 100 and means 0.63 per 100. 0.63 "per 100" means 0.63 "percent" or 0.63% Therefore, we have shown that, 0.0063 = 0.63% PLEASE mark as BRAINLIEST

17.

Convert Decimals into percentage.0.0063

Answer»

Answer:

0.63%

Step-by-step explanation:

"Percent" means "per 100" or "over 100". So, to CONVERT 0.0063 to percent we REWRITE 0.0063 in terms of "per 100" or over 100.

Multiply 0.0063 by 100/100. Since 100/100 = 1, we are only multiplying by 1 and not changing the VALUE of our number.

0.00631×100/100=0.63100

0.63/100 is 0.63 over 100 and means 0.63 per 100. 0.63 "per 100" means 0.63 "percent" or 0.63%

Therefore, we have shown that,

0.0063 = 0.63%

PLEASE mark as BRAINLIEST

Discussion

18.	in an AP the sum of first six terms is 345 and the difference between first and sixth term is fifty five .find the terms of the Arithmetic progression
Answer» ANSWER: TERMS of the ARITHMETIC PROGRESSION is GIVEN below A1=30, A2=41 A3=52, A4=63 ,A5=74,. A6=85

18.

in an AP the sum of first six terms is 345 and the difference between first and sixth term is fifty five .find the terms of the Arithmetic progression

Answer»

ANSWER:

TERMS of the ARITHMETIC PROGRESSION is GIVEN below

A1=30, A2=41 A3=52, A4=63 ,A5=74,. A6=85

Discussion

19.	Specify the type of quadrilateral ABCD in each case, given the following Information.1. AO = OC, DO = OB, DB ﬩ AC, ∠ DAB = 630, O being the point ofintersection of diagonals.
Answer» Answer: LET ABCD be the quadrilateral in which AC and BD are the diagonals that intersect at O. Let ABCD be the quadrilateral in which AC and BD are the diagonals that intersect at O. Now, Let ABCD be the quadrilateral in which AC and BD are the diagonals that intersect at O. Now, AO /OC =1 /2 Let ABCD be the quadrilateral in which AC and BD are the diagonals that intersect at O. Now, AO /OC =1 /2 We know that diagonals of a parallelogram bisect eah other. Let ABCD be the quadrilateral in which AC and BD are the diagonals that intersect at O. Now, AO /OC =1 /2 We know that diagonals of a parallelogram bisect eah other. So, for ABCD to be a parallelogram, Let ABCD be the quadrilateral in which AC and BD are the diagonals that intersect at O. Now, AO /OC =1 /2 We know that diagonals of a parallelogram bisect eah other. So, for ABCD to be a parallelogram, AO /OC= 1 / 1 Let ABCD be the quadrilateral in which AC and BD are the diagonals that intersect at O. Now, AO /OC =1 /2 We know that diagonals of a parallelogram bisect eah other. So, for ABCD to be a parallelogram, AO /OC= 1 / 1 But here Let ABCD be the quadrilateral in which AC and BD are the diagonals that intersect at O. Now, AO /OC =1 /2 We know that diagonals of a parallelogram bisect eah other. So, for ABCD to be a parallelogram, AO /OC= 1 / 1 But here AO /OC= 1 /2 Let ABCD be the quadrilateral in which AC and BD are the diagonals that intersect at O. Now, AO /OC =1 /2 We know that diagonals of a parallelogram bisect eah other. So, for ABCD to be a parallelogram, AO /OC= 1 / 1 But here AO /OC= 1 /2 So, the quadrilateral can 't be a parallelogram in which point of intersection of the diagonals divide one diagonal in the ratio of 1 : 2. *Hope* *this* *helps* *you* *MATE*!

19.

Specify the type of quadrilateral ABCD in each case, given the following Information.1. AO = OC, DO = OB, DB ﬩ AC, ∠ DAB = 630, O being the point ofintersection of diagonals.

Answer»

Answer:

LET ABCD be the quadrilateral in which AC and BD are the diagonals that intersect at O.

Let ABCD be the quadrilateral in which AC and BD are the diagonals that intersect at O. Now,

Let ABCD be the quadrilateral in which AC and BD are the diagonals that intersect at O. Now, AO /OC =1 /2

Let ABCD be the quadrilateral in which AC and BD are the diagonals that intersect at O. Now, AO /OC =1 /2 We know that diagonals of a parallelogram bisect eah other.

Let ABCD be the quadrilateral in which AC and BD are the diagonals that intersect at O. Now, AO /OC =1 /2 We know that diagonals of a parallelogram bisect eah other. So, for ABCD to be a parallelogram,

Let ABCD be the quadrilateral in which AC and BD are the diagonals that intersect at O. Now, AO /OC =1 /2 We know that diagonals of a parallelogram bisect eah other. So, for ABCD to be a parallelogram, AO /OC= 1 / 1

Let ABCD be the quadrilateral in which AC and BD are the diagonals that intersect at O. Now, AO /OC =1 /2 We know that diagonals of a parallelogram bisect eah other. So, for ABCD to be a parallelogram, AO /OC= 1 / 1 But here

Let ABCD be the quadrilateral in which AC and BD are the diagonals that intersect at O. Now, AO /OC =1 /2 We know that diagonals of a parallelogram bisect eah other. So, for ABCD to be a parallelogram, AO /OC= 1 / 1 But here AO /OC= 1 /2

Let ABCD be the quadrilateral in which AC and BD are the diagonals that intersect at O. Now, AO /OC =1 /2 We know that diagonals of a parallelogram bisect eah other. So, for ABCD to be a parallelogram, AO /OC= 1 / 1 But here AO /OC= 1 /2 So, the quadrilateral can 't be a parallelogram in which point of intersection of the diagonals divide one diagonal in the ratio of 1 : 2.

Hope this helps you MATE!

Discussion

20.	Define the convergence of a sequence (an) and verify whether the sequence(n+ 1/n-1)^nwhose nth term is an =converges or not.
Answer» Step-by-step EXPLANATION: ANSWER is: Q. If 102y = 25, then 10-y equals: (a) -1/5, (b) 1/625, (c) 1/50, (d) 1/25, (e) 1/5 Solution: 102y = 25 (10y)2 = 52 10y = 5 1/10y = 1/5 10-y = 1/5 Answer: (e)..

20.

Define the convergence of a sequence (an) and verify whether the sequence(n+ 1/n-1)^nwhose nth term is an =converges or not.

Answer»

Step-by-step EXPLANATION:

ANSWER is:

Q. If 102y = 25, then 10-y equals:

(a) -1/5, (b) 1/625, (c) 1/50, (d) 1/25, (e) 1/5

Solution:

102y = 25

(10y)2 = 52

10y = 5

1/10y = 1/5

10-y = 1/5

Answer: (e)..

Discussion

21.	3,10.5,25.5,48,78,116.5
Answer» Answer: 3.10.5,25.5,48,78,116.5

21.

3,10.5,25.5,48,78,116.5

Answer»

Answer:

3.10.5,25.5,48,78,116.5

Discussion

22.	If a2 + b2 + c2 = 1 where a, b, c are real thenmaximum value of ab + bc + ca is: ufà a2 + b2 +c2 = 1 जहां a, b, c वास्तविक है तब ab + bc + ca काअधिकतम मान है:(A)-\|N -7(B) 14(C) 1(D) 32Diad
Answer» Answer: dhadak SHORT VIDEO app Step-by-step EXPLANATION: dhadak :Short video app DOWNLOAD on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store dhadak :Short video app download on play store

22.

If a2 + b2 + c2 = 1 where a, b, c are real thenmaximum value of ab + bc + ca is: ufà a2 + b2 +c2 = 1 जहां a, b, c वास्तविक है तब ab + bc + ca काअधिकतम मान है:(A)-|N -7(B) 14(C) 1(D) 32Diad

Answer»

Answer:

dhadak SHORT VIDEO app

Step-by-step EXPLANATION:

dhadak :Short video app DOWNLOAD on play store

dhadak :Short video app download on play store

Discussion

23.	The sum of a number and its one-third is 36. Find the number.
Answer» ANSWER: let's TAKE the NUMBER as X so x+x1/3=36 x+x/3=36 x+x= 36/3 2x=12 x=6. Therefore the numbers are 6and1/3of 6 that is 2.

23.

The sum of a number and its one-third is 36. Find the number.

Answer»

ANSWER:

let's TAKE the NUMBER as X so x+x1/3=36 x+x/3=36 x+x= 36/3 2x=12 x=6. Therefore the numbers are 6and1/3of 6 that is 2.

Discussion

24.	What is the ten just before of 156
Answer» Answer: We will learn to order with hundreds, TENS and ones and discover the pattern to FIND the MISSING numerals. Order with Hundreds, Tens and Ones Order with Hundreds, Tens and Ones The NUMBER just before 212 is 211. The ten just before 212 is 210. The hundred just before 212 is 200.

24.

What is the ten just before of 156

Answer»

Answer:

We will learn to order with hundreds, TENS and ones and discover the pattern to FIND the MISSING numerals.

Order with Hundreds, Tens and Ones

The NUMBER just before 212 is 211.

The ten just before 212 is 210.

The hundred just before 212 is 200.

Discussion

25.	Find the perimeter of right triangle , whose Hypotenuse is 25cm and base is 24cm.
Answer» Question : Find the perimeter of right triangle , whose Hypotenuse is 25cm and base is 24cm. Answer : $\sf\purple{Given:}$ Hypotenuse is 25 cm Base is 24 cm $\sf\purple{To\:Find:}$ Perimeter of the right angled triangle = ? Explanation : To find the perimeter of the right angled triangle we need to find the measure of the third side of the triangle that is the perpendicular or opposite . By USING PYTHAGORAS THEOREM , hypo² = base² + opp² $\longrightarrow\mathbb{25² = 24² + opp² }$ $\longrightarrow\mathbb{625 = 576+ opp² }$ $\longrightarrow\mathbb{625 - 576= opp² }$ $\longrightarrow\mathbb{ opp² = 49 }$ $\longrightarrow\mathbb{ opp = √49 }$ $\longrightarrow\mathbb\pink{ opp = 7cm. }$ Perimeter of the triangle = hypotenuse + opposite + base $\longrightarrow{25 + 24 + 7}$ $\longrightarrow{49+ 7}$ $\longrightarrow\pink{<klux>56</klux> cm}$ Therefore perimeter of the triangle is 56 cm @MissOxford Please mark as brainliest

25.

Find the perimeter of right triangle , whose Hypotenuse is 25cm and base is 24cm.

Answer»

Question :

Find the perimeter of right triangle , whose Hypotenuse is 25cm and base is 24cm.

Answer :

$\sf\purple{Given:}$

Hypotenuse is 25 cm

Base is 24 cm

$\sf\purple{To\:Find:}$

Perimeter of the right angled triangle = ?

Explanation :

To find the perimeter of the right angled triangle we need to find the measure of the third side of the triangle that is the perpendicular or opposite .

By USING PYTHAGORAS THEOREM ,

hypo² = base² + opp²

$\longrightarrow\mathbb{25² = 24² + opp² }$

$\longrightarrow\mathbb{625 = 576+ opp² }$

$\longrightarrow\mathbb{625 - 576= opp² }$

$\longrightarrow\mathbb{ opp² = 49 }$

$\longrightarrow\mathbb{ opp = √49 }$

$\longrightarrow\mathbb\pink{ opp = 7cm. }$

Perimeter of the triangle = hypotenuse + opposite + base

$\longrightarrow{25 + 24 + 7}$

$\longrightarrow{49+ 7}$

$\longrightarrow\pink{<klux>56</klux> cm}$

Therefore perimeter of the triangle is 56 cm

@MissOxford

Please mark as brainliest

Discussion

26.	Xercise1.The sum of a number and its one-third is 36. Find the number.47
Answer» ANSWER: $x = 27$ REQUIRED NUMBER is 27. Step-by-step EXPLANATION: $x + \frac{x}{3} = 36 \\ \\ \frac{4x}{3} = 36 \\ \\ x = \frac{3 \times 36}{4} = 3 \times 9 = 27 \\ \\ x = 27$

26.

Xercise1.The sum of a number and its one-third is 36. Find the number.47

Answer»

ANSWER:

$x = 27$

REQUIRED NUMBER is 27.

Step-by-step EXPLANATION:

$x + \frac{x}{3} = 36 \\ \\ \frac{4x}{3} = 36 \\ \\ x = \frac{3 \times 36}{4} = 3 \times 9 = 27 \\ \\ x = 27$

Discussion

27.	The mean of 15 observations is 30. If one more observation is included, then the new mean becomes 31 What is the 16th observationO (A) 44O (B) 46O (C) 45(D) 47
Answer» Answer: the mean of 15 OBSERVATION is 30 total of 30 observation is 30×15=450 mean of 16 observation is 31 total of 31 observation is 31×16=496 so, 16 th observation is 496-450=46

27.

The mean of 15 observations is 30. If one more observation is included, then the new mean becomes 31 What is the 16th observationO (A) 44O (B) 46O (C) 45(D) 47

Answer»

Answer:

the mean of 15 OBSERVATION is 30

total of 30 observation is 30×15=450

mean of 16 observation is 31

total of 31 observation is 31×16=496

so, 16 th observation is 496-450=46

Discussion

28.	Solve the following simultaneous equationy = 3x -1y = 2x +4using a) graphical methodb) substitution methodc) elimination method
Answer» Answer: For simultaneous EQUATION in X and y, if Dₓ = 49, Dᵧ = -63 and D = 7, then what is the value of x. 7 - 7 1 / 7 - 1 / 7

28.

Solve the following simultaneous equationy = 3x -1y = 2x +4using a) graphical methodb) substitution methodc) elimination method

Answer»

Answer:

For simultaneous EQUATION in X and y, if Dₓ = 49, Dᵧ = -63 and D = 7, then what is the value of x. 7 - 7 1 / 7 - 1 / 7

Discussion

29.	9m² -25 ÷ 6m -10 = how can I get my answer
Answer» ANSWER: PLEASE FIND the ATTACHED IMAGE.

29.

9m² -25 ÷ 6m -10 = how can I get my answer

Answer»

ANSWER:

PLEASE FIND the ATTACHED IMAGE.

Discussion

30.	By increasing the salary of a mam by 20%it becomes rupees 18000 ,his original salary is
Answer» ANSWER: X + 20/100x =18000 x+1/5x=18000 6x/5=18000 x=18000×5/6 x=3000×5=15000

30.

By increasing the salary of a mam by 20%it becomes rupees 18000 ,his original salary is

Answer»

ANSWER:

X + 20/100x =18000

x+1/5x=18000

6x/5=18000

x=18000×5/6

x=3000×5=15000

Discussion

31.	Find the selling price when C.p rupees 2005 profit rupees 145
Answer» Answer: the SELLING price is ₹2150 when cp is 2005 and the profit is ₹145 Step-by-step EXPLANATION: so the answer is ₹2150 hope it HELPS U

31.

Find the selling price when C.p rupees 2005 profit rupees 145

Answer»

Answer:

the SELLING price is ₹2150 when cp is 2005 and the profit is ₹145

Step-by-step EXPLANATION:

so the answer is ₹2150

hope it HELPS U

Discussion

32.	Root3tan2x=sin30degree+sin45degree cos45degree +2sin90degree
Answer» ANSWER: TAN3X = sin45°cos45° + sin30° = (1/√2)×(1/√2) + 1/2 = 1/2 + 1/2 = 1 tan 45° = 1 so, 3X = 45 ⇒x = 15°

32.

Root3tan2x=sin30degree+sin45degree cos45degree +2sin90degree

Answer»

ANSWER:

TAN3X = sin45°cos45° + sin30°

= (1/√2)×(1/√2) + 1/2

= 1/2 + 1/2

= 1

tan 45° = 1

so, 3X = 45

⇒x = 15°

Discussion

33.	1lakh 82thousand in numbers
Answer» ANSWER: here is you answer dude 180000..

33.

1lakh 82thousand in numbers

Answer»

ANSWER:

here is you answer dude

180000..

Discussion

34.	The area of a rectangular field is 832sq m if it's length is 32 m, find its breadth
Answer» Answer: Breadth of the RECTANGULAR field = 26 m Step-by-step explanation: GIVEN AREA of a rectangular field is 832 sq. m. Its length is 32 m Let the breadth of the rectangular field be x m. FORMULA Area of rectangle = (Length × Breadth) sq. unit BY APPLYING THE FORMULA OF AREA Area of rectangle = (Length × Breadth) sq. unit → 832 = 32 × x → 32X = 832 → x = 832/32 → x = 26 ∴ Breadth of the rectangular field = x = 26 m

34.

The area of a rectangular field is 832sq m if it's length is 32 m, find its breadth

Answer»

Answer:

Breadth of the RECTANGULAR field = 26 m

Step-by-step explanation:

GIVEN

AREA of a rectangular field is 832 sq. m.
Its length is 32 m
Let the breadth of the rectangular field be x m.

FORMULA

Area of rectangle = (Length × Breadth) sq. unit

BY APPLYING THE FORMULA OF AREA

Area of rectangle = (Length × Breadth) sq. unit

→ 832 = 32 × x

→ 32X = 832

→ x = 832/32

→ x = 26

∴ Breadth of the rectangular field = x = 26 m

Discussion

35.	The LCM of two numbers is 10 times their HCF, one number is 24 what is the other number?
Answer» Answer: let the hcf be x then lcm be 10x lcmhcf= product of TWO number let other number be n x10x=24n 10x^2=64n x^2=64n/10 to complete square RHS must MULTIPLY by 6 and SINCE there is 10 in denominator so it must be multiply by 10 so n=60 x^2=64610/10 x=6*2=12 hcf=12 lcm=120

35.

The LCM of two numbers is 10 times their HCF, one number is 24 what is the other number?

Answer»

Answer:

let the hcf be x then lcm be 10x

lcm*hcf= product of TWO number

let other number be n

x*10x=24*n

10x^2=6*4*n

x^2=6*4*n/10

to complete square RHS must MULTIPLY by 6 and SINCE there is 10 in denominator so it must be multiply by 10

so n=60

x^2=6*4*6*10/10

x=6*2=12

hcf=12

lcm=120

Discussion

36.	Two numbers are in the ratio 5:7.If their difference is 2.5,then which of the following is thier sum
Answer» Answer: Step-by-step EXPLANATION: let NUMBERS 5x and 7X . Difference => 7x-5x=2.5 2x=2.5 x=2.5/2=1.25 Therefore 5x=1.255=6.25 7x=1.257=8.75 Sum= 7x+5x= 8.75+6.25 = 15

36.

Two numbers are in the ratio 5:7.If their difference is 2.5,then which of the following is thier sum

Answer»

Answer:

Step-by-step EXPLANATION:

let NUMBERS 5x and 7X .

Difference => 7x-5x=2.5

2x=2.5

x=2.5/2=1.25

Therefore

5x=1.25*5=6.25

7x=1.25*7=8.75

Sum= 7x+5x= 8.75+6.25 = 15

Discussion

37.	Put into standard form 13(9�� + 2) − 1
Answer» Step-by-step explanation: An ecosystem is a geographic area where plants, animals, and other organisms, as well as weather and landscape, work TOGETHER to form a bubble of LIFE. Ecosystems contain biotic or living, PARTS, as well as abiotic FACTORS, or nonliving parts. ... Ecosystems can be very LARGE or very small. ꉣ꒒ꇙꇙ ꊰ꒒ꅐ ꂵꏂ ꓄ꁝꏂꋊ ꒐ '꒒꒒ ꍌꋬ꒦ꏂ ꌦꄲ꒤ 10 ꓄ꁝꋬꋊꀘꇙ ❤.. ✌☺

37.

Put into standard form 13(9�� + 2) − 1

Answer»

Step-by-step explanation:

An ecosystem is a geographic area where plants, animals, and other organisms, as well as weather and landscape, work TOGETHER to form a bubble of LIFE. Ecosystems contain biotic or living, PARTS, as well as abiotic FACTORS, or nonliving parts. ... Ecosystems can be very LARGE or very small.

ꉣ꒒ꇙꇙ ꊰ꒒ꅐ ꂵꏂ ꓄ꁝꏂꋊ ꒐ '꒒꒒ ꍌꋬ꒦ꏂ ꌦꄲ꒤ 10 ꓄ꁝꋬꋊꀘꇙ ❤.. ✌☺

Discussion

38.	The perimeter of a rectangular field is 628m.The length of the field exceeds its width by 6m.Find the dimensions.
Answer» Answer: Breadth of the rectangular field = 154 m Length of the rectangular field = 160 m Step-by-step EXPLANATION: GIVEN Perimeter of a rectangular field is 628 m. Let the breadth of the rectangular field be x m. Its length = (x + 6) m FORMULA Perimeter of RECTANGLE = 2(Length + Breadth) unit BY APPLYING THE FORMULA OF PERIMETER Perimeter of rectangle = 2(Length + Breadth) unit → 628 = 2(x + 6 + x) → 2X + 6 = 628/2 → 2x + 6 = 314 → 2x = 314 - 6 → 2x = 308 → x = 308/2 → x = 154 ∴ Its dimensions are: Breadth of the rectangular field = x = 154 m Length of the rectangular field = (x + 6) = (154 + 6) = 160 m

38.

The perimeter of a rectangular field is 628m.The length of the field exceeds its width by 6m.Find the dimensions.

Answer»

Answer:

Breadth of the rectangular field = 154 m
Length of the rectangular field = 160 m

Step-by-step EXPLANATION:

GIVEN

Perimeter of a rectangular field is 628 m.
Let the breadth of the rectangular field be x m.
Its length = (x + 6) m

FORMULA

Perimeter of RECTANGLE = 2(Length + Breadth) unit

BY APPLYING THE FORMULA OF PERIMETER

Perimeter of rectangle = 2(Length + Breadth) unit

→ 628 = 2(x + 6 + x)

→ 2X + 6 = 628/2

→ 2x + 6 = 314

→ 2x = 314 - 6

→ 2x = 308

→ x = 308/2

→ x = 154

∴ Its dimensions are:

Breadth of the rectangular field = x = 154 m

Length of the rectangular field = (x + 6) = (154 + 6) = 160 m

Discussion

39.	ln a diagram,pqrs is a trapezium in which pq is parallel to sr.x is a point on sr such that qx is parallel to ps.pq=ps=6 centimeters,qr=7,6 centimeters and pqx=41 degrees37'
Answer» HOPE it's helpfull MARK me as BRAINLIST ❗

39.

ln a diagram,pqrs is a trapezium in which pq is parallel to sr.x is a point on sr such that qx is parallel to ps.pq=ps=6 centimeters,qr=7,6 centimeters and pqx=41 degrees37'

Answer»

HOPE it's helpfull

MARK me as BRAINLIST ❗

Discussion

40.	What is the answer of the line segments joining in a polygon are called
Answer» ANSWER: edge is the line segment joining the POLYGON Step-by-step EXPLANATION: Ithin its HELP

40.

What is the answer of the line segments joining in a polygon are called

Answer»

ANSWER:

edge is the line segment joining the POLYGON

Step-by-step EXPLANATION:

Ithin its HELP

Discussion

41.	Given a = (8 10) and b = (7 -12). Calculate \|a\|\|b\|Is it true that \|a + b\| = \|a\| + \|b\|Is it true that \|a - b\| = \|b - a\|
Answer» ANSWER: TRUE Step-by-step EXPLANATION: MAY this HELP you

41.

Given a = (8 10) and b = (7 -12). Calculate |a||b|Is it true that |a + b| = |a| + |b|Is it true that |a - b| = |b - a|

Answer»

ANSWER:

TRUE

Step-by-step EXPLANATION:

MAY this HELP you

Discussion

42.	The general form of 4.67x104=
Answer» ANSWER: EQUAL simplest FORM 18/54 and 23/69 FULL form Step-by-step explanation:

42.

The general form of 4.67x104=

Answer»

ANSWER:

EQUAL simplest FORM 18/54 and 23/69 FULL form

Step-by-step explanation:

Discussion

43.	Subtract 2 by 9 and 3 by 10
Answer» ANSWER: when u subtract 2 by 9 u will GET -7 and when u subtract 3 by 10 u will get-7

43.

Subtract 2 by 9 and 3 by 10

Answer»

ANSWER:

when u subtract 2 by 9 u will GET -7

and when u subtract 3 by 10 u will get-7

Discussion

44.	Simplify : (813 + 2713)
Answer» Step-by-step explanation: kaya qestion hai kuch samaghe NAHI aaraha hai 1 LINE MAI likho

44.

Simplify : (813 + 2713)

Answer»

Step-by-step explanation:

kaya qestion hai kuch samaghe NAHI aaraha hai 1 LINE MAI likho

Discussion

45.	How many times does 4 go into 1
Answer» Answer: 4 GOES into only for 1 TIME

45.

How many times does 4 go into 1

Answer»

Answer:

4 GOES into only for 1 TIME

Discussion

46.	Is it possible to have a triangle with the follow sides? (1) 6 cm, 6cm, 6cm. (2) 3 cm, 5 cm, 7 cm.
Answer» ANSWER: Both (1) and (2) ∆'s are POSSIBLE.

46.

Is it possible to have a triangle with the follow sides? (1) 6 cm, 6cm, 6cm. (2) 3 cm, 5 cm, 7 cm.

Answer»

ANSWER:

Both (1) and (2) ∆'s are POSSIBLE.

Discussion

47.	Kurt, Sophia, and Franco had a paper airplane throwing contest after school. Kurt's airplane flew 8.6 yards. Sophia's airplane flew 2.2 yards farther than Kurt's airplane. Franco threw his airplane 1.5 times as far as Sophia's airplane. How far did Franco's paper airplane fly?
Answer» Given : Kurt, Sophia, and FRANCO had a paper airplane THROWING contest after school. Kurt's airplane flew 8.6 yards. Sophia's airplane flew 2.2 yards farther than Kurt's airplane. Franco threw his airplane 1.5 times as far as Sophia's airplane. To Find : How far did Franco's paper airplane fly Solution: Kurt's airplane flew 8.6 yards. Sophia's airplane flew 2.2 yards farther than Kurt's airplane. => Sophia's airplane flew = 8.6 + 2.2 => Sophia's airplane flew = 10.8 yards Franco threw his airplane 1.5 times as far as Sophia's airplane. => Franco airplane flew = 1.5 * 10.8 => Franco airplane flew = 16.2 Yards Franco's paper airplane fly = 16.2 Yards Learn More : A frog in a well is 12m below the ground level. If it jumps 5m and ... brainly.in/question/11402119

47.

Kurt, Sophia, and Franco had a paper airplane throwing contest after school. Kurt's airplane flew 8.6 yards. Sophia's airplane flew 2.2 yards farther than Kurt's airplane. Franco threw his airplane 1.5 times as far as Sophia's airplane. How far did Franco's paper airplane fly?

Answer»

Given : Kurt, Sophia, and FRANCO had a paper airplane THROWING contest after school.

Kurt's airplane flew 8.6 yards.

Sophia's airplane flew 2.2 yards farther than Kurt's airplane.

Franco threw his airplane 1.5 times as far as Sophia's airplane.

To Find : How far did Franco's paper airplane fly

Solution:

Kurt's airplane flew 8.6 yards.

Sophia's airplane flew 2.2 yards farther than Kurt's airplane.

=> Sophia's airplane flew = 8.6 + 2.2

=> Sophia's airplane flew = 10.8 yards

Franco threw his airplane 1.5 times as far as Sophia's airplane.

=> Franco airplane flew = 1.5 * 10.8

=> Franco airplane flew = 16.2 Yards

Franco's paper airplane fly = 16.2 Yards

Learn More :

A frog in a well is 12m below the ground level. If it jumps 5m and ...

brainly.in/question/11402119

Discussion

48.	A string is 700 centimers long.how many meters long is the string
Answer» Answer: given a STRING is 700 cm long = ? METERS 100 cm = 1meter then 700cm = 7 meters : .the string is 7CM long. Step-by-step EXPLANATION:

48.

A string is 700 centimers long.how many meters long is the string

Answer»

Answer:

given a STRING is 700 cm long

= ? METERS

100 cm = 1meter

then 700cm = 7 meters

: .the string is 7CM long.

Step-by-step EXPLANATION:

Discussion

49.	A man have 18000 Rs, he invest 4000 Rs at 4% interest and 4200 at the rate of 5% to earn total interest of1020 Rs after 2 year he must invest the remaining amount at what rate of interest.1. 11/7%2. 10/9%3. 10/7%4. 12/7%5.5%
Answer» ANSWER: 2. 10/9 here is your answer PLEASE SEE

49.

A man have 18000 Rs, he invest 4000 Rs at 4% interest and 4200 at the rate of 5% to earn total interest of1020 Rs after 2 year he must invest the remaining amount at what rate of interest.1. 11/7%2. 10/9%3. 10/7%4. 12/7%5.5%

Answer»

ANSWER:

2. 10/9 here is your answer PLEASE SEE

Discussion

50.	Draw a traingle which sides are in the ratio 2:3:5 and perimeter is 20 cm
Answer» ANSWER: first we have to take the middle number MEANS 3 as base and the left side means 2 and RIGHT 5 as other two sides. we can't draw the other two side only with scale need the help if compass means take 2 cm and5cm cut a arc and JOIN and perimeter 20 cm

50.

Draw a traingle which sides are in the ratio 2:3:5 and perimeter is 20 cm

Answer»

ANSWER:

first we have to take the middle number MEANS 3 as base and the left side means 2 and RIGHT 5 as other two sides.

we can't draw the other two side only with scale need the help if compass means take 2 cm and5cm cut a arc and JOIN and perimeter 20 cm

Discussion

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The sum of a number and its one-third is 36. Find the number.

What is the ten just before of 156

Xercise1.The sum of a number and its one-third is 36. Find the number.47

The mean of 15 observations is 30. If one more observation is included, then the new mean becomes 31 What is the 16th observationO (A) 44O (B) 46O (C) 45(D) 47

A man have 18000 Rs, he invest 4000 Rs at 4% interest and 4200 at the rate of 5% to earn total interest of1020 Rs after 2 year he must invest the remaining amount at what rate of interest.1. 11/7%2. 10/9%3. 10/7%4. 12/7%5.5%

Draw a traingle which sides are in the ratio 2:3:5 and perimeter is 20 cm