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The perimeter of a rectangular field is 628m.The length of the field exceeds its width by 6m.Find the dimensions. |
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Answer» Answer:
Step-by-step EXPLANATION: GIVEN
FORMULA
BY APPLYING THE FORMULA OF PERIMETER Perimeter of rectangle = 2(Length + Breadth) unit → 628 = 2(x + 6 + x) → 2X + 6 = 628/2 → 2x + 6 = 314 → 2x = 314 - 6 → 2x = 308 → x = 308/2 → x = 154 ∴ Its dimensions are: Breadth of the rectangular field = x = 154 m Length of the rectangular field = (x + 6) = (154 + 6) = 160 m |
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