1.

The perimeter of a rectangular field is 628m.The length of the field exceeds its width by 6m.Find the dimensions.

Answer»

Answer:

  • Breadth of the rectangular field = 154 m
  • Length of the rectangular field = 160 m

Step-by-step EXPLANATION:

GIVEN

  • Perimeter of a rectangular field is 628 m.
  • Let the breadth of the rectangular field be x m.
  • Its length = (x + 6) m

FORMULA

  • Perimeter of RECTANGLE = 2(Length + Breadth) unit

BY APPLYING THE FORMULA OF PERIMETER

Perimeter of rectangle = 2(Length + Breadth) unit

→ 628 = 2(x + 6 + x)

2X + 6 = 628/2

→ 2x + 6 = 314

→ 2x = 314 - 6

→ 2x = 308

→ x = 308/2

→ x = 154

∴ Its dimensions are:

Breadth of the rectangular field = x = 154 m

Length of the rectangular field = (x + 6) = (154 + 6) = 160 m



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