If n(A)=100,n(B)=70,n(A intersection B)=20,then n(A triangle B)is

1.	If n(A)=100,n(B)=70,n(A intersection B)=20,then n(A triangle B)is
Answer» Answer: 130 is the answer Step-by-step explanation: n(A)=100,n(B)=70 and n(A∩B) = 20 n(A∪B) = n(A) + n(B) - n(A∩B) n(A∪B) = 100 + 70 - 20 =170 -20 = 150 n(AΔB) = n(A∪ B) - n(A∩B) = 150 - 20 = 130

Answer»

Answer:

130 is the answer

Step-by-step explanation:

n(A)=100,n(B)=70 and n(A∩B) = 20

n(A∪B) = n(A) + n(B) - n(A∩B)

n(A∪B) = 100 + 70 - 20

=170 -20

= 150

n(AΔB) = n(A∪ B) - n(A∩B)

= 150 - 20

= 130

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If n(A)=100,n(B)=70,n(A intersection B)=20,then n(A triangle B)is​

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If n(A)=100,n(B)=70,n(A intersection B)=20,then n(A triangle B)is