Explore topic-wise InterviewSolutions in Current Affairs.

if RUPEES 4000 is DEPOSITS at BANK for =5 years

ANSWER:

16 is the CORRECT answer

ANSWER:

6(p-2q)

6(p-2q)

6(p-2q)

6(p-2q)

TAKE 6 COMMON

ANSWER:

It's NICE to MEET OLD FRIENDS.

Answer:

27) 3

28) -9

29) x=y+7

30) 3x+8

31) x/2

32) 7 DAYS in a week

33) $(12r+2000)

HOPE it HELPS you

ANSWER:

23 is the CORRECT answer

I think is question

Check your question one time

and PROPERLY

Step-by-step explanation:

• COST of 3 copies = ₹75
• So, cost of 1 COPY = ₹75/3 = ₹25
• So, No. of copies can bought for ₹300 = ₹300/₹25 =12 copies

Answer:

The ratio between BASE the base ANGLE and the vertical angle of an ISOSCELES triangle is 2:5.

ANSWER:

FACE is the answer of this QUESTION

ANSWER:

WAIT....

....

.. Kjhhhgg

Step-by-step EXPLANATION:

MARK. as brainliest

please

I am very SORRY but I don't KNOW

Answer:

Recurring deposit interest

P=n(n+1)/2x12×r/100---(1)

Where p is the deposit amount /MONTH, n is no of month, r is RATE of interest

Interest amount is given by,

2000×n(n+1)/24×10/100

=83100-n×2000

=n^2+241n-(831×12)+0

(n+177)(n-36)=0

Hence we GET,

NUMBER of months =36

ANSWER:

એકી સંખ્યા એ એવી પૂર્ણાંક સંખ્યા છે જે બે નો ગુણાંક નથી. જો તેને બે વડે ભાગવામાં આવે તો પરિણામમાં શેષ વધે છે. એક એ પ્રથમ ધન એકી સંખ્યા છે. આ પછીની એક સંખ્યાઓ ત્રણ, પાંચ, સાત અને નવ છે. તેથી શ્રેણીમાં એકી સંખ્યાઓ {૧,૩,૫,૭,૯,૧૧,૧૩,૧૫,૧૭,૧૯,૨૧,૨૩,૨૫...} મુજબ થાય છે.

જે પૂર્ણાંક સંખ્યા એકી સંખ્યા નથી તે બેકી સંખ્યા છે.

વધુમાં એકી અને બેકી સંખ્યાઓ ઋણ પણ હોઈ શકે છે. તેથી શ્રેણીમાં (..., −૩, −૨, −૧, ૦, ૧, ૨, ૩, ...) આ પ્રમાણે લખી શકાય છે.

એકી સંખ્યાનો સમૂહ શોધવા માટે આપણે ૨N+૧ સૂત્રનો ઉપયોગ કરી શકીએ છીએ, જ્યાં N એ કોઇ પણ પ્રાકૃતિક સંખ્યા છે.

Stub ICON આ અત્યંત નાનો લેખ છે. તમે તેને વિસ્તૃત કરીને વિકિપીડિયાને મદદ કરી શકો છો.

Answer:

9:45 is the TIME when 9,o Clock and 10,o clock COME in straight line

hope it HELPS..

Answer:

1 OPTION 1

x=1 there fore

1×1+2×1+3

1,2,3

ANSWER:

SORRY I am just COLLECTING the POINTS

ANSWER:

Firstly we have to CORRECT the no.in ASCENDING order

32,35,41,42,43,51,56,57,

Step-by-step explanation:

67,69,72,81,85,92,94

so the middle no.is 57 because it is the middle no.and so 57 is a NEDIAN no.

Total Surface AREA of cuboid =2(lb + hb + lh)

Total Surface area of cuboid= 2(15*12 +8*12 + 15*8)

Total Surface area of cuboid= 2(180 + 96 + 120)

Total Surface area of cuboid= 2(396)

Total Surface area of cuboid= 792 SQUARE CM.

Answer:

2(4x2-3xy-y2)

2(4x2-4xy+xy-y2)

2. 4X(x-y)+y(x-y)

2.( 4x+y)(x-y)

Answer:

So, here are some examples: 482 is equivalent to 241 because 48 x 1 = 2 x 24 = 48. 723 is equivalent to 241 because 72 x 1 = 3 x 24 = 72. 964 is equivalent to 241 because 96 x 1 = 4 x 24 = 96.

Answer:

1- 23

2- 342

3- 43

4- 320

5- 39

Answer:

39 sq.cm

Step-by-step EXPLANATION:

HOPE it HELPS you

Answer:

1/9x-6=4

4(9x-6)=1

36x-24=1

36x=25

x=25/36

Answer:

127 BRO....

Step-by-step EXPLANATION:

hpzotyzyplyz spb9gsoyzoyzot

Answer:

9000

Step-by-step EXPLANATION:

it is only the greatest 4 digit NUMBER which is divisible by 5

Answer:

coordinates (0,0) (4,2) (1,0)

Step-by-step explanation:

PLOT these coordinates in graph and join them these all POINTS will come in a STRAIGHT line

ANSWER:

SORRY in don't KNOW answer

Step-by-step explanation:

Given:-

The points A(3, 1), B(0, -2), C(1, 1) and D(4, 4)

To show:-

Show that the points A(3, 1), B(0, -2), C(1, 1) and D(4, 4) are the vertices of a parallelogram ABCD.

Solution:-

Method-1:-

Given points are A(3, 1), B(0, -2), C(1, 1) and D(4, 4)

We know that

In a Parallelogram," The diagonals are bisecting to each other"

AC and BD are the diagonals

=>Mid POINT of AC = Mid Point of BD

So To show that the given points are the points of a Parallelogram then we have to show that the mid point of AC is equal to the mid point of BD.

Mid point of AC:-

Let (x1, Y1)= A(3, 1) =>x1 = 3 and y1 = 1

(x2, y2)=C(1, 1) =>x2 = 1 and y2 = 1

The mid point of the line joining the points (x1 ,y1) and (x2 ,y2) is M(X,y)=[(x1+x2)/2,(y1+y2)/2]

=>[(3+1)/2,(1+1)/2]

=>(4/2,2/2)

=>(2,1)

Mid point of AC = (2,1)-----------------(1)

Mid Point of BD:-

Let (x1, y1)= B(0,-2) =>x1 = 0 and y1 = -2

(x2, y2)=D(4,4) =>x2 = 4 and y2 = 4

The mid point of the line joining the points (x1 ,y1) and (x2 ,y2) is M(x,y)=[(x1+x2)/2,(y1+y2)/2]

=>[(0+4)/2,(-2+4)/2]

=>(4/2,2/2)

=>(2,1)

Mid Point of BD = (2,1)---------------(2)

From (1)&(2)

Mid Point of AC = Mid point of BD

Given points A,B,C,D are the vertices of the paralellogram ABCD.

Method-2:-

Given points are A(3, 1), B(0, -2), C(1, 1) and D(4, 4)

To show that the given points are the points of a Parallelogram then we have to show that two pairs of the lengths of the opposite sides of the Parallelogram ABCD. i.e. AB= CD and BC = DA

Length of AB :-

Let (x1, y1)= A(3, 1) =>x1 = 3 and y1 = 1

Let (x2, y2)= B(0,-2) =>x2= 0 and y2 = -2

We know that

The distance between two points ( x1,y1) and

(x2, y2) is √[(x2-x1)^2+(y2-y1)^2]

AB =√[(0-3)^2-(-2-1)^2]

=>AB =√[(-3)^2+(-3)^2]

=>AB= √(9+9)

=>AB=√18

=>AB=√(2×9)

AB=3√2 units ---------(1)

Length of BC :-

Let (x1, y1)= B(0,-2) =>x1 = 0 and y1 = -2

Let (x2, y2)= C(1,1) =>x2= 1 and y2 = 1

We know that

The distance between two points ( x1,y1) and

(x2, y2) is √[(x2-x1)^2+(y2-y1)^2]

=>BC=√[(1-0)^2+(1-(-2))^2]

=>BC=√[1^2+3^2]

=>BC=√(1+9)

BC =√10 units --------------(2)

Length of CD:-

Let (x1, y1)= C(1,1)=>x1=1 and y1=1

Let (x2, y2)= D(4,4) =>x2= 4and y2 = 4

We know that

The distance between two points ( x1,y1) and

(x2, y2) is √[(x2-x1)^2+(y2-y1)^2]

=>CD = √[(4-1)^2+(4-1)^2]

=>CD=√[3^2+3^2]

=>CD=√(9+9)

=>CD =√18

=>CD=√(2×9)

CD=3√2 units ---------------(3)

Length of DA:-

Let (x1, y1)= D(4,4) =>x1 = 4 and y1 = 4

Let (x2, y2)= A(3,1) =>x2= 3 and y2 = 1

We know that

The distance between two points ( x1,y1) and

(x2, y2) is √[(x2-x1)^2+(y2-y1)^2]

=>DA =√[(3-4)^2+(1-4)^2]

=>DA=√[(-1)^2+(-3)^2]

=>DA=√[(-1)^2+(-3)^2]

=>DA=√(1+9)

DA=√10 units---------------(4)

From (1)&(3)

AB=BC

From (2)&(4)

BC=DA

Two pairs of opposite sides are equal.

Answer:-

Given points are the vertices of the paralellogram ABCD.

Used Concept:-

• .In a Parallelogram," The diagonals are bisecting to each other"

• Two pairs of opposite sides are equal.

Used formulae:-

1)

The mid point of the line joining the points (x1 ,y1) and (x2 ,y2 ) is M(x,y) =[(x1+x2)/2,(y1+y2)/2]

2)The distance between two points ( x1,y1) and (x2, y2) is √[(x2-x1)^2+(y2-y1)^2]

ANSWER:

not UNDERSTANDING your QUESTION

Step-by-step explanation:

4/2 , 16/8 , 2 ,1/2/2/8

Hope it HELPS you GOOD LUCK

ANSWER:

vistsush8nritgxigigifhfyhififixuszni

Answer:

30° DEGREE BROTHER

Sum of all three sides is 80°

Step-by-step explanation:

100+50 +X =. 180

x =180-150

= 30

ANSWER:

according to QUESTION answer is

5:45

will be RIGHT angle to 5o'clock & 6o'clock

ANSWER:

2781244 is the CORRECT answer

Step-by-step EXPLANATION:

dhdhdhdhjdnfnfjorkrueywyudjxbh++₹++383715528(4:!'

c

msndj73726+₹!+#(!°=`=|÷{

Answer:

Photosynthesis, the process by which green plants and certain other organisms transform light energy into CHEMICAL energy. During photosynthesis in green plants, light energy is CAPTURED and USED to convert water, carbon dioxide, and MINERALS into oxygen and energy-rich organic compounds.

Step-by-step explanation:

GOOD EVENING...

Answer:

STEP

STEP1

STEP1:

STEP1: 1

STEP1: 1 Simplify —

STEP1: 1 Simplify — 4

STEP1: 1 Simplify — 4Equation at the END of step

STEP1: 1 Simplify — 4Equation at the end of step1

STEP1: 1 Simplify — 4Equation at the end of step1:

STEP1: 1 Simplify — 4Equation at the end of step1: 4 1

STEP1: 1 Simplify — 4Equation at the end of step1: 4 1 —— - —

STEP1: 1 Simplify — 4Equation at the end of step1: 4 1 —— - — 15 4

STEP1: 1 Simplify — 4Equation at the end of step1: 4 1 —— - — 15 4STEP

STEP1: 1 Simplify — 4Equation at the end of step1: 4 1 —— - — 15 4STEP2

STEP1: 1 Simplify — 4Equation at the end of step1: 4 1 —— - — 15 4STEP2:

STEP1: 1 Simplify — 4Equation at the end of step1: 4 1 —— - — 15 4STEP2: 4

STEP1: 1 Simplify — 4Equation at the end of step1: 4 1 —— - — 15 4STEP2: 4 Simplify ——

STEP1: 1 Simplify — 4Equation at the end of step1: 4 1 —— - — 15 4STEP2: 4 Simplify —— 15

STEP1: 1 Simplify — 4Equation at the end of step1: 4 1 —— - — 15 4STEP2: 4 Simplify —— 15Equation at the end of step

STEP1: 1 Simplify — 4Equation at the end of step1: 4 1 —— - — 15 4STEP2: 4 Simplify —— 15Equation at the end of step2

STEP1: 1 Simplify — 4Equation at the end of step1: 4 1 —— - — 15 4STEP2: 4 Simplify —— 15Equation at the end of step2:

STEP1: 1 Simplify — 4Equation at the end of step1: 4 1 —— - — 15 4STEP2: 4 Simplify —— 15Equation at the end of step2: 4 1

STEP1: 1 Simplify — 4Equation at the end of step1: 4 1 —— - — 15 4STEP2: 4 Simplify —— 15Equation at the end of step2: 4 1 —— - —

STEP1: 1 Simplify — 4Equation at the end of step1: 4 1 —— - — 15 4STEP2: 4 Simplify —— 15Equation at the end of step2: 4 1 —— - — 15 4

STEP1: 1 Simplify — 4Equation at the end of step1: 4 1 —— - — 15 4STEP2: 4 Simplify —— 15Equation at the end of step2: 4 1 —— - — 15 4STEP

STEP1: 1 Simplify — 4Equation at the end of step1: 4 1 —— - — 15 4STEP2: 4 Simplify —— 15Equation at the end of step2: 4 1 —— - — 15 4STEP3

STEP1: 1 Simplify — 4Equation at the end of step1: 4 1 —— - — 15 4STEP2: 4 Simplify —— 15Equation at the end of step2: 4 1 —— - — 15 4STEP3:

STEP1: 1 Simplify — 4Equation at the end of step1: 4 1 —— - — 15 4STEP2: 4 Simplify —— 15Equation at the end of step2: 4 1 —— - — 15 4STEP3:Calculating the Least Common Multiple :

STEP1: 1 Simplify — 4Equation at the end of step1: 4 1 —— - — 15 4STEP2: 4 Simplify —— 15Equation at the end of step2: 4 1 —— - — 15 4STEP3:Calculating the Least Common Multiple : 3.1 Find the Least Common Multiple

STEP1: 1 Simplify — 4Equation at the end of step1: 4 1 —— - — 15 4STEP2: 4 Simplify —— 15Equation at the end of step2: 4 1 —— - — 15 4STEP3:Calculating the Least Common Multiple : 3.1 Find the Least Common Multiple The left denominator is : 15

STEP1: 1 Simplify — 4Equation at the end of step1: 4 1 —— - — 15 4STEP2: 4 Simplify —— 15Equation at the end of step2: 4 1 —— - — 15 4STEP3:Calculating the Least Common Multiple : 3.1 Find the Least Common Multiple The left denominator is : 15 The right denominator is : 4

Step-by-step explanation:

I HOPE IT HELPS I DONT HAVE THAT ANSWER BUT IT COMPLETELY LIKE THAT ONLY DIFFERENCE IS THAT I JUST CHANGES 2 NUMBER HOPE IT MAY HELPS YOU

Step-by-step EXPLANATION:

you have to DIVIDE the digits which are given in FRACTION

For EXAMPLE :- 51/5 mean 51÷5 = 1.2

ANSWER:

HOPE it will be HELPFUL

MARK me BRAINLIEST

Step-by-step EXPLANATION:

RONY will GET 42 CHOCOLATE

ANSWER:

nbbgcchhb. W s E fbbfr R r e e. EE e

Step-by-step EXPLANATION:

(4^-1×3^-1)+6^-1

(1/4×1/3)+1/6

(1/12)+1/6

1/12+1/6

(1/2)/12

3/12

1/4

ans=1/4

ANSWER:

√5 is IRRATIONAL because √ is not COME in RATIONAL

ANSWER:

ax

2

+bx+c=0

α+β=−

a

b

αβ=

a

c

(α+β)

2

=

a

2

b

2

(α−β)

2

=(α+β)

2

−4αβ

=

a

2

b

2

−

a

4c

=

a

2

b

2

−4ac

α−β=

a

b

2

−4ac

α

2

−β

2

=(α+β)(α−β)=

a

−b

(

a

b

2

−4ac

)

=

a

2

−b

b

2

−4ac

Step-by-step EXPLANATION:

X = 4/3

Hope it HELPS you GOOD LUCK

ANSWER:

No, altitude does not ALWAYS lie in the interior of a TRIANGLE.