Explore topic-wise InterviewSolutions in Current Affairs.

ANSWER:

INDIA, officially the Republic of India, is a country in South Asia. It is the second-most populous country, the seventh-largest country by land AREA, and the most populous democracy in the world. Wikipedia

President: Ram Nath KOVIND Trending

Date format: : dd-mm-yyyy;

Step-by-step EXPLANATION:

• a. There are 7 days in a week.
• B. There are 12 months in a year.
• c. 4 months have 30 days.
• d. April month comes after march.
• e. AUGUST month comes before SEPTEMBER.

Step-by-step explanation:

6x^2y^2+9xy-2xy-3

=3xy(2xy+3)-1(2xy+3)

=(2xy+3)(3xy-1)

⠀

• Let the price of adult ticket be x.
• Let the price of student ticket be y.

⠀

On the FIRST day

→ EQUATION = 3x + 13y = 82⠀⠀...[1]

⠀

On the second day

→ Equation = 13X + 3y = 142⠀⠀...[2]

⠀

⠀

We get :-

• x = 10
• y = 4

⠀

Note (✓) :- Explanation is in attachment.

⠀

Hence,

• Price of a adult ticket is Rs.10
• Price of a student ticket is Rs.4

━━━━━━━━━━━━━━━━━━━━━━

Answer:

8 is the COEFFICIENT

Step-by-step explanation:

because the NUMBER INFRONT of a variable is CALLED coefficient

Answer:

Swimming POOL surface AREA

= 2 ( BH + hl ) + lb

= 2 ( 30 × 2 + 2 × 50 ) + 50 × 30

= 2 ( 60 + 100 ) + 1500

= 2 × 160 + 1500

= 320 + 1500

= 1820 m²

Cost of 1m² cementing = Rs. 30

Cost of 1820m² cementing = 1820 × 30

= Rs. 54600

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Step-by-step EXPLANATION:

dhehrhdjdrnxjkdj, jsjgjxjsdjxjdjxbdhzjdgd

ANSWER:

do U WANT to KNOW a secret i don't know answer.

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ANSWER:

Answer: the PLACE VALUE of 9 is 9/100 .

Answer:

R=7

22/7 * r *l =308

22 X 14 r = 308 x 7

14r= 2156/ 22

14r= 97

r= 7cm²

Step-by-step EXPLANATION:

area=5m^{2}m

2

base=3m

area=\frac{1}{2}

2

1

×base × height

5=\frac{1}{2}

2

1

×3×height

\frac{5*2}{3}

3

5∗2

=height

height=\frac{10}{3}

3

10

height=3.33m(APPROX.)

ANSWER:

X= -7/96

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Answer :

• CI = Rs 165.50
• Amount = Rs 665.50

Given :

• Sum of = Rs 500
• For = 3 years
• At = 10 % per annum

To Find :

• the CI and amount DUE on the sum

Solution :

For the 1st year, Principal = Rs 500

Interest of Rs 500 at the rate of 10%

= Rs = Rs 50

Therefore, Amount at the end of 1st year (500 + 50) = Rs 550

• i.e Principal for the 2nd year = Rs 550

Interest of Rs 550 at the rate of 10% = 10% of Rs 550 = Rs 55

[ Interest calculated on Rs 550 for the 2nd year ]

Therefore, Amount at the end of 2nd year = 10% of Rs 605 = Rs 60.50

• i.e Principal for the 3RD year = Rs 605

Interest of Rs 605 at the rate of 10% = 10% of Rs 605 = Rs 60.50

Therefore, Amount after 3 years = Rs (605 + 60.50) = Rs 665.50

Therefore, Required Compound interest (665.50 - 500.00) = Rs 165.50 and amount for 3 yeas = Rs 665.50.

Answer:

24/4⋅2−1⋅2/9

62−1⋅2/9

62 + −12/9

●Just SEE that the 2 are the square's kn the number.

Step-by-step EXPLANATION:

Hope it HELPS.

ANSWER:

i) c II) c iii) a IV) d v) c

Step-by-step EXPLANATION:

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Answer:

-6/11, -5/11,-4/11 are Three rational numbers between - 7/11 and 2/11.

Please mark my answer as the BRAINLIEST answer.

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ANSWER:

N: 14.0067 g/mol

H: 1.00794 g/mol

The MOLAR mass of AMMONIA will THUS be

14.0067 g/mol +3× 1.00794 g/mol =17.03052 g/mol

ANSWER:

it will be 0

Step-by-step explanation:

120+90-210 = 210 - 210 = 0

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Answer:

5

Step-by-step EXPLANATION:

x=2 and y=1

2x+3y=k

2*2+3*1=k

2+3=k

5=k

k=5

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Answer:

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Step-by-step EXPLANATION:

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Given : sequence of two digit numbers which leave a REMAINDER 1 on division by 5  

To Find :   the sequence .​

Solution:

leave a remainder 1 on division by 5  

can be REPRESENTED by 5n+ 1

as sequence of two digit numbers

Hence 10 ≤ 5n + 1 ≤ 99

10 ≤ 5n + 1  

=> 9 ≤ 5n

=> 2  ≤  n

5n + 1 ≤ 99

=> n  ≤ 19

2  ≤  n   ≤ 19

Hence sequence is

11 , 16 , 21 , ___________________ 91 , 96

5n + 1    ,  2  ≤  n   ≤ 19

common DIFFERENCE is 5

smallest and largest numbers in this sequence  are 11 and 96 respectively

algebraic form of this sequence  5n + 1    ,  2  ≤  n   ≤ 19

18 such numbers are there

Sum = (18/2) ( 11 + 96)  = 963

Learn More:

In an A.P if sum of its first n terms is 3n square +5n and it's KTH term ...

brainly.in/question/8236011

Find the sum of frist 51 terms of the AP whose 2nd term is 2 and 4th ...

brainly.in/question/7655866

Answer:

15.093

Step-by-step explanation:

15.093 × 15.093= 227.798649

Step-by-step EXPLANATION:

• Here, LENGTH = 1.4 m
• And, breadth = 80 cm = 0.8 m
• So, area of rectangular FLAG = length * breadth = 1.4*0.8 = 1.12 m^2

The TRIANGLES are SIMILAR by AA CRITERION.

ANSWER:

d which MEANS COMMON DIFFERENCE

ANSWER:

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ANSWER:

XGJFKDKDKUSUSJDJDJDJJDJDJDJHDD

Answer:

3√2 , 3√6 , 3√4 is the PERFECT.

ANSWER:

SORRY i don't know

Step-by-step EXPLANATION:

ANSWER:

ctrl+i and I are a LITTLE more concerned with DENOMINATE and you are a bit of an INTROVERT and have 55inches a

Step-by-step explanation:

12.35 छात्रों की किसी कक्षा में किसी दिन 28 छात्र उपस्थित थे, बताएँ

उस दिन कुल कितने प्रतिशत छात्र अनुपस्थित थे?

ANSWER:

We have to FIND the length, breadth and perimeter of the SQUARE. The length, breadth are nothing but the FACTORS of the expression. ☣️ (x+4) and (x+4) are the length and breadth of the square. ☣️ Therefore, 4x+16 units is the perimeter of the square.

Answer:

येथे तुम्ही विषय बीजगणित प्रकरण क्रमांक :

4)संभाव्यता

या प्रकरणावर ई-टेस्ट देऊ शकता आणि त्या ई-टेस्ट चा ताबडतोब निकाल पाहू शकता..!

ई-टेस्टने करा, विषय तयारी, क्षणात निकाल,मिळेल आनंद भारी !!!कृपया तुमचे नाव लिहा : 

Q1. जर A = { 2, 3, 4} , A' = { 1, 5} तर नमुना अवकाश S कोणता राहील?

A){ 2, 3, 4}

B){ 1, 2, 3, 4, 5}

C){ 1, 2, 3, 4, 5}

D){1, 3, 4, 5}

Q2. जर A = {6, 12, 18, 24, 30} तर n(A) = …………

A) 6

B) 2

C) 9

D) 5

Q3. एक नाणे फेकले असता मिळणारा नमुना अवकाश कोणता?

A) { H, T }

B) H, T

C) { T }

D) { HH, TT}

Q4. एक फासा टाकला असता,P ही घटना पृष्ठभागावरील अंक विषम मिळवण्याची आहे,P घटनेचा संच खालीलपैकी कोणता?

A){ 2, 4}

B){ 6, 4}

C){ 2, 4, 6}

D){1, 3, 5}

Q5. एकाचवेळी दोन नाणी फेकली असता एकूण किती शक्यता मिळतात?

A) 6

B) 8

C) 5

D) 4

Q6. एक फासा टाकला असता, वरच्या पृष्ठभागावर सम संख्या मिळेल या घटनेची संभाव्यता काय राहील?

A) 1

B) 2

C) 1/2

D) 0.1

Q7. जर n(A) = 2, n(S) = 8 तर A या घटनेची संभाव्यता किती राहील?

A) 1/2

B) 1/4

C) 1/3

D) 2/3

Q8. तीन फासे एकाचवेळी फेकले असता नमुना अवकाश S मधील घटकांची संख्या n(S) =किती?

A) 24

B) 8

C) 36

D) 4

Q9. जर n(A) = 4 व n(S) = 36 तर P(A) = ?

A) 1/3

B) 4/9

C) 9/4

D) 1/9

Q10. एक नाणे व एक फासा एकाचवेळी फ़ेकले असता , मिळणारे नमुना अवकाश S मधील घटकांची संख्या n(S) = किती?

A) 4

B) 12

C) 6

D) 8

Answer:

1

Step-by-step explanation:

The degree of polynomial is the HIGHEST POWER PRESENT in the EQUATION

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ANSWER:

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ANSWER:

HENCE, the AREA of the RECTANGLE is 192 cm².

ANSWER:

this is the CORRECT answer MARK me as BRAINLIST

Answer:

No, you can't GET MARKS. Because CENTROID divides the MEDIAN in 2/3

Answer:

option (c) 4 m

Step-by-step explanation:

Given :

• The ratio of height of a room to its semi-perimeter is 2 : 5.
• It costs RS. 260 to paper the walls of the room with paper 50 cm wide at Rs. 2 per meter ALLOWING an area of 15 m² for door and windows.

To find :

the height of room

Solution :

Let the length, BREADTH and height of the room be l, b and h respectively.

Semi perimeter of the room = (l + b)

Let

the height, h= 2x

then, semi perimeter = 5x

l + b = 5x

Area of 4 walls of the room = lh + bh + lh + bh

= h(l + b + l + b)

= h(2l + 2b)

= 2(l + b) × h

= 2(5x) (2x)

= 20x²

It's also given that the area occupied by doors and windows is 15 m²

so, area to be papered = (20x² – 15) m²

Breadth of the paper = 50 cm = 50/100 m = 0.5 m

Area to be papered = Area of the paper

20x² – 15 = length × 0.5

length = 2(20x² – 15)

length = 40x² – 30

It costs Rs. 260 to paper the walls of the room with paper 50 cm wide at Rs. 2 per meter

2 × (40x² – 30) = 260

80x² – 60 = 260

80x² = 260 + 60

80x² = 320

x² = 320/80

x² = 4

X = √4

x = 2

Height of the room = 2(2) = 4 m

ANSWER:

Since each row MUST have the same number of SAPLINGS as the number of rows, the number of saplings must be a perfect square. Thus, he NEEDS 32 rows, i.e. 32 ^ 2 saplings = 1024 saplings.

Answer:

10m20cm

Step-by-step explanation:

2m 20cm + 3m+ 5cm=

10m20cm

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ANSWER:

FIVE rational NUMBERS between 1 and 2 are 11/10, 12/10, 13/10, 14/10, and 15/10.

ANSWER:

RANGE= highest observation-lowest observation

=200-3

=197

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THANK U...!!!

STEP 1 is CORRECT step 2 is misteke

ANSWER:

They are ASKING the MEASURE of ANGLE WTV..

ANSWER:

i THINK Gurujan KARTE HAI

Three THOUSAND four HUNDRED and eighty TWO point five TENTH and five hundredth.

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ANSWER:

SEND the

QUESTION

correctly

as we

can't

understand

the question

Answer:

1 - C)———————(-2,2)

2- b)———————(2)

3- c)———————()

4- d)———————(2)

5- c)———————()

Step-by-step EXPLANATION: