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Find the value of b ' if alpha and 1/alpha are the zeroes of polynomial ax square +bx+c |
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Answer» ax +bx+c=0 α+β=− a b
αβ= a c
(α+β) 2 = a 2
b 2
(α−β) 2 =(α+β) 2 −4αβ = a 2
b 2
− a 4c
= a 2
b 2 −4ac
α−β= a b 2 −4ac
α 2 −β 2 =(α+β)(α−β)= a −b
( a b 2 −4ac
) = a 2
−b b 2 −4ac
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