Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

If s.p ₹ 1200 and ₹ 800 find the profit​

Answer»

ANSWER:

bro the answer was HARD to UNDERSTAND but the ANSWERI think so is

Step-by-step EXPLANATION:

₹400

2.

Help mehelp mehelp me​

Answer»

ANSWER:

C is the CORRECT OPTION

3.

Of theequationDraw the graph3x-y=0​

Answer»

EXPLANATION.

Graph of the equation.

⇒ 3X - y = 0.

As we know that,

PUT the value of x = 0 in equation, we get.

⇒ 3(0) - y = 0.

⇒ 0 - y = 0.

⇒ y = 0.

Their Co-ordinates = (0,0).

Put the value of y = 0 in equation, we get.

⇒ 3x - (0) = 0.

⇒ 3x = 0.

⇒ x = 0.

Their Co-ordinates = (0,0).

4.

If Rohan have 5 apples and if he eats one of them, what is the mass of Earth?

Answer»

Answer:

Step-by-step explanation:

et WEIGHT of a apple be X

weight of 5 apple=5x

so weight 3 apple =3x-9.8 G

5.

Solve this question give me correct answer​

Answer»

ANSWER:

The VALUE is 130

Step-by-step explanation:

20% of 650

20/100 X 650

2  x 65

=   130

6.

In parallelogram RSTU show the opposite side of ST and opposite angle of T​

Answer»

ANSWER:

I don't KNOW this answer, but I HOPE ANYBODY HELP you

7.

X+y+z=30 , x,y,z can be any odd number between 1 to 20 and one number can be used more than once

Answer»

Its IMPOSSIBLE to do because when we ADD odd no. By odd times the sum also comes in odd but there is a method to do it USE 3!=6......X=3!Y=9Z=5Ans is 30

8.

The admission fee for an exhibition is Rs9 for adults and Rs 4 for children below 12years of age. Raghav with his father, mother and younger sisters of age 10and 6 and his twin brother of 14 years went for the exhibition. How much did they pay as admission charge?

Answer»

Since father and MOTHER are adults'
fee for father and mother = 2×9 = Rs. 18

RAGHAV and his BROTHER are both 14 years OLD. They are more than 12. So
fee for raghav and his brother = 2×9 = Rs. 18

Both his SISTERS are less than 12,
fee for his sisters = 2×4 = Rs. 8

Total charge = 18+18+8 = Rs.44

9.

Find the values of x and y using properties of a circle.

Answer»

Angle DAB + angle DCB = 180      (sum of opposite sides of a CYCLIC QUADRILATERAL)
angleDCB +50 =180
angle DCB =130
.'. angle y= 130

'.' OA=OB                                    (radius of circle)
angle OAB = angle OBA = 50        (angles opposite to equal sides are equal)
angle OAB + angle OBA = angle BOD      (exterior angle property of triangle)
50 +50 =angle x
100 =angle x

10.

If m= log 20 and n = log 25, find the value of x, so that : 2 log (x - 4) = 2 m - n

Answer»

M = LOG 20 

n = log 25

so 2LOG (x - 4) = 2m - n

⇒  log (x - 4)² = 2log20 - log25

⇒ log(x - 4)² = log (20² / 25)

cancelling log from both sides

(x - 4)² = 20² / 25 

⇒ x - 4 = 20 / 5

x = 4 + 4 = 8 ANSWER

11.

SUM of length width and height OF CUBICAL BOX IS 19 CM AND LENGTH OF ITS DIAGONAL IS 11 CM ...FIND THE SURFACE AREA OF THE CUBOID BOX???

Answer» LET the length = l
breadth = B 
height = h

given that l+b+h = 19
and diagonal = 11
⇒\sqrt{l^2+b^2+h^2}=11
⇒l^2+b^2+h^2=121

We know that
(l+b+h)^2=l^2+b^2+h^2 + 2(lb+bh+lh)\\ \\ \Rightarrow19^2=121+2(lb+bh+lh)\\ \\ \Rightarrow 2(lb+bh+lh)=361-121\\ \\ \Rightarrow2(lb+bh+lh) = 240

But 2(lb+bh+lh) is the total surface AREA or simply "surface area" of the cuboid.
So surface area is 240cm².


12.

What is the answer for "Log 144 to base 12" using log table

Answer»


log 144 to the base 12 is

12 to the POWER what is equal to 144

which is 12

12^12=144

13.

A florist bought 240 roses at Rs. 10 per dozen and sold them at 1.50 each. Find his profit and loss percent

Answer»

Number of roses = 240
cost = RS. 10 PER dozen
number of dozens = 240/12 = 20 dozens
cost price = 20×10 = Rs. 200

he SOLD them at Rs. 1.50 each
selling price = 240×1.50 = 360

profit = 360 - 200 = Rs. 160

% profit = \frac{Profit}{CP} \times 100= \frac{160}{200} \times 100 = 80

He earned 80% profit.

14.

From a giving cost functiontc=60+0.5q+0.3q(sq)find out fixed cost,average variable and marginal cost.

Answer»

60:8sq is the COST FUNCTION

15.

The line segment joining the points (2,1) and (5,-8) is trisected at the pointsP & Q. If the point lies on the line 2x-y+k=0, find the value of k.Please give the answer and show the detailed steps.Please give fast as this is important for an exam!!

Answer»

When a line segment JOINING the POINTS (x₁,y₁) and (x₂,y₂) is trisected at points P and Q, the coordinates of the points P and Q are given by:

P\ is\ [ \frac{2x_1+x_2}{3} , \frac{2y_1+y_2}{3} ]\ or\\ \\ P\ is\ [ \frac{2*2+5}{3} , \frac{2*1-8}{3} ]=[ \frac{9}{3} , \frac{-6}{3} ] = (3,-2)\\ \\ Q\ is\ [ \frac{x_1+2x_2}{3} , \frac{y_1+2y_2}{3} ]\ or\\ \\ Q\ is\  [ \frac{2+2*5}{3} , \frac{1+2*(-8)}{3} ]=[ \frac{12}{3} , \frac{-15}{3} ]=(4,-5)

If P(3,-2) lies on 2x-y+K=0;
2×3 - (-2) + k = 0
⇒ 6 + 2 + k = 0
⇒ k + 8 =0
⇒ k = -8

If Q(4,-5) lies on 2x-y+k=0;
2×4 - (-5) + k = 0
⇒ 8 + 5 + k = 0
⇒ k + 13 =0
⇒ k = -13

16.

two water taps together fill a tank in 75/9 hours. the tap of larger diameter takes 10 hours less than the smaller one to fill the tank separately. find the time in which each tap can separately fill the tank. represent this as an equation. what is the degree of that equation?

Answer»

The time to fill TANK(together)=75/9 hr
if the SMALL tap WANTS x+10 hr
then big tap wants x hr

amount of water that fill in ONE hr by small tap=\frac{1}{x+10}
"by big tap=\frac{1}{x}
"together=1/ \frac{75}{9} = \frac{9}{75}
\frac{1}{x} + \frac{1}{x+10} = \frac{9}{75}  \\  \\ 
 \frac{x+10+x}{ x^{2} +10x} =\frac{9}{75} \\  \\ 
(2x+10)75=(x^{2} +10x})9 \\  \\ 
150x+750= 9x^{2} +90x \\  \\ 
divide ---by --3 \\  \\ 
50x+25=3x^{2} +30x \\ 
3x^{2} +30x-50x-25=0 \\  \\ 
3 x^{2} -20x-25=0

a=3,b=-20,c=-25

this is a second degree EQUATION

17.

HOW MANY FACES, EDGES, VERTICES OF THE FOLLOWING,1. A prism whose base is polygen of "n" sides.2.A pyramid whose base is polygen of "n" sides.

Answer»

1. A prism WHOSE base is POLYGON of "n" sides will have 
a. n+2 FACES - n lateral faces(rectangles), one top and one bottom
b. 3n EDGES - n on top, n on bottom, n on lateral surfaces
c. 2n vertices - n on top and n on bottom

2. A pyramid whose base is polygon of "n" sides will have 
a. n+1 faces - n lateral faces(triangles) and one bottom
b. 2n edges - n on bottom, n on lateral surfaces
c. n+1 vertices - 1 on top and n on bottom surface

18.

How to draw 75 degree angle

Answer»

Draw a line segment say AB
draw an ANGLE of 60 degree
draw an angle of 90 degree
bisect both the ANGLES 
:. the formed angle is 75 degree

19.

A certain sum of money amounts to ₹6,500 in 3 years and ₹5,750 in 1 1/2yearsrespectively . Find the principal and the rate percent.

Answer»

Let principal = P
rate = R% 

for t=3 YEARS, A = 6500
A = P + PTR/100
⇒6500 = P + 3PR/100
⇒6500 = P + 0.03PR
⇒ R = (6500-P)/0.03P

for t=1.5 years, A = 5750
A = P + PTR/100
⇒5750 = P + 0.015PR
⇒ 5750 = P + 0.015P[(6500-P)/0.03P]
⇒ 5750 = P + (6500-P)/2
⇒ 5750 = P + 3250 - 0.5P
⇒ 5750 - 3250 = 0.5P 
⇒ 0.5P = 2500
⇒ P = 2500/0.5 = Rs. 5000

R = (6500-P)/0.03P = (6500-5000)/(0.03×5000) = 1500/150 = 10

Principal is Rs. 5000 and rate is 10%.

20.

Substitute the equation:underoot2x+underoot3y=0underoot3x-underoot8y=0

Answer» \sqrt{2x}+ \sqrt{3y}=0\\ \sqrt{2x}=-\sqrt{3y}\\  \sqrt{x} = -\sqrt{ \frac{3}{2}y }  \\ \\ \sqrt{3x}-\sqrt{8y}=0\\ - \sqrt{3\times \frac{3}{2}y } - \sqrt{8y} =0\\ - \sqrt{y} ( \sqrt{8}+  \sqrt{ \frac{9}{2} }\ )  =0
21.

If A is a multiple of B,what is the possible value of______?______×______= A______×______= BA.1B.2C.3D.4

Answer»

If we have to fill the 4 gaps by CHOOSING from the options given,

3 × 4 = A
or A = 12.

1 × 2 = B
or B = 2

now. A is a MULTIPLE of B.

22.

Calculate the total surface area of the outside of an open box which has a base measuring 1.0 by 0.8m and has a height of 0.5m.plz answer fast.....very urgent!!!!!!!

Answer»

An open box means it's TOP SURFACE is not there. So the TOTAL surface area is the SUM of lateral surface area and bottom surface area.

LSA = 2(lh+bh) = 2(1×0.5 + 0.8×0.5) = 2(0.5 + 0.4) = 1.8 m²
bottom surface area = 1×0.8 = 0.8m²

TSA = 1.8+0.8 = 2.6 m²

23.

Sin x=√5/3 and x lies in second quadrant, find the value of tan x/2

Answer»

Sin X =sqrt5/3 which leads to x = 48.1 , now as u SAID sin is in 2nd quadrant so sin 180- x will be sin x so 180 - 48.1 GETS us x = 131.9
now TAN 131.9/2 = 2.24077

24.

Integral and derivative of 1/xplease fast

Answer» \int { \frac{1}{x} } \, dx=log\ x+c\\ \\ \frac{d}{dx}( \frac{1}{x} )= -\frac{1}{ x^{2} }
25.

_+_+_=30numbers should be->{1,3,5,7,9,11,13,15}and they may be repeated

Answer» it is not POSSIBLE CASE only with odd numbers because the SUM of odd 3 numbers doesnt result an even NUMBER. i.e., we cant get 30 by USING those numbers. to get 30 we have to take one number as 3! (3×2×1) = 6
    so  3!+15+9=30
26.

Find the domain and range of the function1)f(x)=5x-10b)f(x)=15-√xc)f(x)=2 modulusx+7d)f(x)=+100

Answer»

1)f(X)=5x-10
domain is (-∞,∞)
RANGE is (-∞,∞)

b)f(x)=15-√x
domain is [0,∞)
range is (-∞,15]

c)f(x)=2|x|+7
domain is (-∞,∞)
range is [7,∞)

d)f(x)=+100
domain is (-∞,∞)
range is (-∞,∞)

27.

The prime factor of 2×7×11×17×23+23 isExplain the process

Answer»

2×7×11×17×23+23
= (2×7×11×17 + 1) ×23
= (2618+1) × 23
= 2619×23

now factorize 2619
2619 = 3×3×3×97 = 3³ × 97
2619 × 23 = 3³ × 97 × 23 = 3³ × 23 × 97

So the PRIME factors are 3, 23 and 97.

28.

2 prime numbers whose product is 35

Answer»

Do the prime FACTORISATION of 35.
35 = 5×7

So the 2 PRIMES are 5 and 7.

29.

ABC is a right angle triangle,right angle at A.Acircle is inscribed in it.The length of two sides containing angle A is 12cm and 5cm find the radius

Answer»

The length of two SIDES CONTAINING angle A is 12cm and 5cm
So let AB = 12cm and AC = 5cm. BC is opposite to angle A, so BC is hypotenuse.
Using Pythagoras theorem,
BC² = AC² + AB²
⇒ BC² = 5² + 12²
⇒ BC² = 25+144
⇒ BC² = 169
⇒ BC = √169 = 13cm

Now from the centre of the circle O, draw perpendiculars to the three sides of the triangle. Note that OP=ON=OM = radius of circle = r. Now we can write that

Area of ΔABC = Area of ΔOAC + Area of ΔOAB + Area of ΔOBC
⇒ 0.5×AB×AC = 0.5×AC×ON + 0.5×AB×OP + 0.5×BC×OM
⇒ 0.5×12×5 = 0.5×( 5×r + 12×r + 13×r )
⇒ 12×5 = 5r + 12R + 13r
⇒ 60 = 30r
⇒ r = 60/30
⇒ r = 2cm

Thus the radius of the inscribed circle is 2cm.

30.

A sphere,cylinder and cone are of the same radius and same height find the ratio of their CSA

Answer» LET the common RADIUS of the sphere cone and cylinderHeight of sphere= diameter=2rThen height of cone=height of cylinder=height of sphere=2rL=√r*2+h*2=√r*2+(2R)*2=√5r4Πr*2:4Πr*2:√5Πr*24:4:√5
31.

I need some tricks that we can solve th problems in the integration fast.please help me

Answer»

Use the equation of differential in backward WAY LIKE applying product RULE backward or CHAIN rule backward

32.

The prime factor of 2*7*11*17*23+23

Answer» 2*7*11*17*23+23
=23(2*7*11*17 + 1)
=23×2619
=23×3×3×3×97
= 3³ × 23 × 97
33.

If the cost price and selling price of an article is in the ratio 6:8 what is the profit percentage

Answer» LET the cost PRICE = 6X
selling price = 8X
profit = 8x - 6x = 2x

profit percentage = \frac{profit}{cost\ price} \times 100= \frac{2x}{6x} \times 100=33.33

Profit is 33.33%.

34.

Search results for "A circular well of 21m depth is dug up so that the radius of the well is 1.5m. What is the volume of the earth dug up

Answer» it will be in cylindrical shape
given height = 21M
         RADIUS = 1.5m = 15/10m = 3/2m
VOLUME of cylinder = volume of EARTH dug up
 volume of cylinder = πr²h
                               = 22/7×3/2×3/2×21
                               = 22/7×9/4×21
                               = 11×9/2×3
                               = 297/2
                               = 148.5 m³
35.

a physical education teacher wishes to distribute 60 balls and 135 bats equally among a no. of boys the greatest number recieving the gift in this way are

Answer»

No of students=60
BATS  are distributed twice to 60 members
bats distributed thrice is 135-120
15 members RECIEVES GREATEST GIFT

36.

Represent the graph of the equation y=x and y=-x

Answer»

X=Y
HENCE, DRAW A TABLE IN WHICH:IF X=0 THEN Y=0,
X=1 THEN Y=1,X=-1 THEN Y=-1 AND THEN BY FOLLOWING THESE COORDINATES DRAW A STRAIGHT LINE PASSING THROUGH THESE POINTS.AND DRAW YOUR GRAPH.
SIMILIARLY U CAN DRAW THE EQUATION Y=-X.

37.

Given :In Δ ABC: BD is perpendicular to AC, CE is perpendicular to AB and BD=CE.Prove:ΔABC is isosceles. refer to the pic

Answer» given , 
    BD = CE 
90^0  angle BEC = angle BDC = 
To prove -  ΔBEC is congruent to ΔBDC
proof ,
    BD = CE ( Given )
     angle BEC = angle BDC  ( Given )
     BC = BC ( common )
 by SAS  ΔBEC is congruent to ΔBDC ,
therefore , angle EBC = DCB ( C.P.C.T )
therefore,
 ΔBEC is isosceles        ( because by the property of isosceles triangle base ANGLES are equal  ) 

38.

A man goes 1.2 km due north and then 0.5 km due west.Find the least distance between his initial and final positions.(Pythagoras theorem)plz fast

Answer»

1.2 KM=1200 m
0.5 km=500 m
see the pic

bc²=ab²+ac²
     =(1200)²+(500)²
     =1440000+250000
bc²=1690000
bc=√1690000=1300 m
bc=1.3 km

39.

Fill in the blanks with correct Number from 1,3,5,7,9,11,13,15 only. you can repeat number.......+....+......= 30

Answer» You can't do that in base 10; 30/5 (the number of blanks) = 6, hence that is the average number for the blanks. Simply put, since all the numbers are odd, that means that a+b+c+d+e = F, where f is ALSO odd, because all odd integers are EQUAL to 2n + 1.. 
40.

Solve this _+_+_=30

Answer»

10+10+10=30
15+10+5=30
20+5+5=30



41.

A contructor undertakes to build a wall 1000 meter long in 50 days. He employed 56 men but at the end of 27 days he finds that only 448 meter of wall is build. How many extra men must the contractor employ so that the wall is completed in time .

Answer» AMOUNT of wall LEFT to build=1000-448=552 m
Days left=23
In each day,length of wall to be made=552/23=24 m

In 27 days,wall built previously by 56 men=448 m
In 1 day,wall built by 56 men=448/27 m
In 1 day,wall built by 1 man=448(27x56)
In 1 day,wall to be build by y men=(448xy)/(27x56)
BTP,
y=(448xy)/(27x56)=24
or, y=81
So, TOTAL men=81
No. of extra men=25 more



42.

A family of 5 persons can be maintained for 20 days with rupees 2480. Find how long rupees 6944 maintain a family of 8 persons

Answer»

No. of persons           No. of days           Money
        5                              20                      2480
        8                               x                        6944

RATIO of No. of persons = 5 : 8
Ratio of No. of days = 20 : x 
Ratio of Money = 2480 : 6944 = 155 : 434
No. of persons is INVERSELY proportionate to No. of days
No. of days is DIRECTLY proportionate to Money

Compound ratio of NO. of persons and Money = 8 : 5 :: 155 : 434 = (8×155):(5×434) =  1240 : 2170 = 124 : 217

Now,
20 : x = 124 : 217

124x = 20 × 217

x = 4340/124

x = 35

The family can maintain for 35 days

43.

Q1. IOf one root xsquare-ax-4= is negative of the other then the value of a isa)0b)1c)2d)4

Answer»

Let the roots of the equation x²-ax-4 = 0 be P and –p
Sum of the roots (p + (-p)) = -(-a)
THEREFORE, a = 0

The ANSWER is OPTION a

44.

A shopkeeper allows a cash discount of 12.5% on a machine A customer pays an amount of Rs 437.50 a machine . At what price is the machine listed ?

Answer» DISCOUNT %=12.5
prize=437.5
87.5%
Total* \frac{87.5}{100} =437.5 \\  \\ 
43750=total*87.5[<klux>TEX</klux>] \\total=43750/87.5=500orginal prize=500 RS[/tex]
45.

A, B and C are three different places. Cost of a ticket for going from A to B is Rs. x, and that of from B to C is Rs. y. A man pays Rs. 1100 for 2 tickets from A to B and 3 tickets from B to C. Write the given data in form of a linear equation in two variables

Answer»

A to B=x
b to c=y
two  TICKETS for a to b=2x
three tickets for b to c=3y
2x+3y=11000
2x=11000-3y

46.

Solve this..◻ ➕ ◻ ➕ ◻=30Fill the boxes using(1, 3, 5, 7, 9, 11, 13, 15)U can also repeat the numbers.This question came in UPSC Final Exams held in Dec 2013.

Answer» 3! + 3! + 3! + 3! + 3! = 30

Hope my ANSWER HELPS
47.

Solve this..◻ ➕ ◻ ➕ ◻=30Fill the boxes using(1, 3, 5, 7, 9, 11, 13, 15)U can also repeat the numbers.

Answer»

It is not POSSIBLE because adding odd NUMBER by odd number TIMES is odd only ..its never even....for eg if we add 3 ,seven times aanswer is 21 which is odd number

48.

Can someone help me solve this questionThe circumference of a wheel is 44cm. How much distance will it cover in 10 revolutioms ?

Answer» 440 CM it COVERS in 10 REVOLUTIONS
49.

Heather wants to buy a new refrigerator, but she only has room for one that is 18 ft3 or less. Which set of dimensions represent a refrigerator that Heather can buy?A)2 ft. wide x 2.5 ft. long x 3 ft. tall B)2 ft. wide x 2.5 ft. long x 4.5 ft. tall C)2.5 ft wide x 3 ft. long x 4 ft. tall EliminateD)2.5 ft. wide x 2 ft. long x 4 ft. tall

Answer»

A)2 ft. X 2.5 ft. x 3 ft. = 15 ft³
B)2 ft.  x 2.5 ft.  x 4.5 ft. = 22.5 ft³
C)2.5 ft  x 3 ft.  x 4 ft. = 30 ft³
D)2.5 ft.  x 2 ft. x 4 ft. = 20 ft³

Since only option A has volume less than 18 ft³, he should buy the refrigerator with dimension A- 2 ft. wide x 2.5 ft. long x 3 ft. tall 

50.

How to trisect an angle??

Answer»

Trisect an ANGLE is to divide the angle into THREE EQUAL halves
for e.g. if AD trisects