1.

A man goes 1.2 km due north and then 0.5 km due west.Find the least distance between his initial and final positions.(Pythagoras theorem)plz fast

Answer»

1.2 KM=1200 m
0.5 km=500 m
see the pic

bc²=ab²+ac²
     =(1200)²+(500)²
     =1440000+250000
bc²=1690000
bc=√1690000=1300 m
bc=1.3 km



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