1.

SUM of length width and height OF CUBICAL BOX IS 19 CM AND LENGTH OF ITS DIAGONAL IS 11 CM ...FIND THE SURFACE AREA OF THE CUBOID BOX???

Answer» LET the length = l
breadth = B 
height = h

given that l+b+h = 19
and diagonal = 11
⇒\sqrt{l^2+b^2+h^2}=11
⇒l^2+b^2+h^2=121

We know that
(l+b+h)^2=l^2+b^2+h^2 + 2(lb+bh+lh)\\ \\ \Rightarrow19^2=121+2(lb+bh+lh)\\ \\ \Rightarrow 2(lb+bh+lh)=361-121\\ \\ \Rightarrow2(lb+bh+lh) = 240

But 2(lb+bh+lh) is the total surface AREA or simply "surface area" of the cuboid.
So surface area is 240cm².


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