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Substitute the equation:underoot2x+underoot3y=0underoot3x-underoot8y=0

Answer» \sqrt{2x}+ \sqrt{3y}=0\\ \sqrt{2x}=-\sqrt{3y}\\  \sqrt{x} = -\sqrt{ \frac{3}{2}y }  \\ \\ \sqrt{3x}-\sqrt{8y}=0\\ - \sqrt{3\times \frac{3}{2}y } - \sqrt{8y} =0\\ - \sqrt{y} ( \sqrt{8}+  \sqrt{ \frac{9}{2} }\ )  =0


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