332354 + Interview Questions in Secondary School in Math

1.	Utilizar el teorema del residuo para hallar P(3) si P(x)=2x^3-4x^2-6Específicamente dar el cociente y el residuo de la división asociada y el valor de P(3)
Answer» ANSWER: Step-by-step EXPLANATION: BRAINLIEST BRAINLIEST BRAINLIEST BRAINLIEST BRAINLIEST BRAINLIEST

1.

Utilizar el teorema del residuo para hallar P(3) si P(x)=2x^3-4x^2-6Específicamente dar el cociente y el residuo de la división asociada y el valor de P(3)

Answer»

ANSWER:

Step-by-step EXPLANATION:

BRAINLIEST BRAINLIEST BRAINLIEST BRAINLIEST BRAINLIEST BRAINLIEST

Discussion

2.	IF A TRIANGLE HAVE GIVEN ANGLE A=80 DEGREE AND TWO ANGLES ARE EQUAL.THEN FIND THE BOTH THE ANGLES
Answer» ANSWER- □/_ A =80°✔✔ □/_ B =50°✔✔ □/_ C =50°✔✔ Step-by-step EXPLANATION: YOUR QUESTION IS THAT □angle A=80°✔✔ ○angle B = angle C=X°✔✔ WE KNOW THAT THE SUM OF ALL ANGLES OF A TRIANGLE IS 180° DEGREE WE KNOW THAT THE SUM OF ALL ANGLES OF A TRIANGLE IS 180° DEGREESO, /_A+/_B+/_C=180° 80°+X+X=180° 2X=100° X=50°(each)✔✔

2.

IF A TRIANGLE HAVE GIVEN ANGLE A=80 DEGREE AND TWO ANGLES ARE EQUAL.THEN FIND THE BOTH THE ANGLES

Answer»

ANSWER-

□/_ A =80°✔✔

□/_ B =50°✔✔

□/_ C =50°✔✔

Step-by-step EXPLANATION:

YOUR QUESTION IS THAT

□angle A=80°✔✔

○angle B = angle C=X°✔✔

WE KNOW THAT THE SUM OF ALL ANGLES OF A TRIANGLE IS 180° DEGREE

WE KNOW THAT THE SUM OF ALL ANGLES OF A TRIANGLE IS 180° DEGREESO,

/_A+/_B+/_C=180°

80°+X+X=180°

2X=100°

X=50°(each)✔✔

Discussion

3.	Yash scored 40 marks in a test, getting 3 marks for each right answer and losing 1 mark for each wrong answer. Had 4 marks been awarded for each correct answer and 2 marks been deducted for each incorrect answer, then yash would have scored 50 marks. How many questions were there in the test?
Answer» Answer: 20 questions Step-by-step explanation: Let the no. of questions correctly ATTEMPTED be x and the no. of questions wrongly attempted be y so, case 1 3x - 1y = 40 case 2 4x - 2y = 50 2x - y =25 now on subtracting case 1 from 2 we get, 3x - 2x - y +y = 40 - 25 x = 15 putting in case 1 we get, y = 5 total question= x + y 20 questions

3.

Yash scored 40 marks in a test, getting 3 marks for each right answer and losing 1 mark for each wrong answer. Had 4 marks been awarded for each correct answer and 2 marks been deducted for each incorrect answer, then yash would have scored 50 marks. How many questions were there in the test?

Answer»

Answer: 20 questions

Step-by-step explanation: Let the no. of questions correctly ATTEMPTED be x

and the no. of questions wrongly attempted be y

so,

case 1

3x - 1y = 40

case 2

4x - 2y = 50

2x - y =25

now on subtracting case 1 from 2 we get,

3x - 2x - y +y = 40 - 25

x = 15

putting in case 1 we get,

y = 5

total question= x + y

20 questions

Discussion

4.	IF A NUMBER IS INCREASED BY 10% AND THEN DECREASE BY 10%.WHAT SHOULD BE THE INCREASE OR DECREASE VALUE?
Answer» Answer: DECREASE VALUE=1 OR 1%✔✔ Step-by-step explanation: □LET THE NUMBER BE =100-------(1) ○SO ACCORDING TO YOUR QUESTION SO ACCORDING TO YOUR QUESTIONFIRST INCREASE OF 10% •SO, THE NUMBER =110--------(2) AGAIN, □THEN DECREASE OF 10% SO, THE NUMBER BECOMES=99------(3) □DECREASE VALUE=(3)-(1)=100-99=1 ○THEREFORE DECREASE VALUE=1 OR 1%

4.

IF A NUMBER IS INCREASED BY 10% AND THEN DECREASE BY 10%.WHAT SHOULD BE THE INCREASE OR DECREASE VALUE?

Answer»

Answer:

DECREASE VALUE=1 OR 1%✔✔

Step-by-step explanation:

□LET THE NUMBER BE =100-------(1)

○SO ACCORDING TO YOUR QUESTION

SO ACCORDING TO YOUR QUESTIONFIRST INCREASE OF 10%

•SO, THE NUMBER =110--------(2)

AGAIN,

□THEN DECREASE OF 10%

SO, THE NUMBER BECOMES=99------(3)

□DECREASE VALUE=(3)-(1)=100-99=1

○THEREFORE DECREASE VALUE=1 OR 1%

Discussion

5.	3.45+35.56=? what will be the answer
Answer» Answer: 3.45+35.56=39.01 Hope it HELPS

5.

3.45+35.56=? what will be the answer

Answer»

Answer:

3.45+35.56=39.01

Hope it HELPS

Discussion

6.	216 factorise the number using the long division method
Answer» Answer: 2/216=108/2=54/2=27/3=9/3=3/3=1

6.

216 factorise the number using the long division method

Answer»

Answer:

2/216=108/2=54/2=27/3=9/3=3/3=1

Discussion

7.	Anybody please send 10th cbse 2019 board exam Q.P
Answer» YEAH!! I ALSO NEED that

Discussion

8.	1. In the figure if
Answer» where is the FIGURE PAGLI can i SEE

Discussion

9.	One-forth of one number is 5 times the another number.The sum of two number are 210?What are two Numbers?
Answer» Step-by-step EXPLANATION: ADD me BRAINLIST ..........................

9.

One-forth of one number is 5 times the another number.The sum of two number are 210?What are two Numbers?

Answer»

Step-by-step EXPLANATION:

ADD me BRAINLIST ..........................

Discussion

10.	By what no. Should we multiply3/-14 so the product may be 5/13
Answer» $\mathfrak{\large{\underline{\underline{\red{Answer:-}}}}}$ $\frac{-35}{18}$ $\mathfrak{\large{\underline{\underline{\red{Explanation:}}}}}$ Let the NUMBER be X $\frac{3}{-14}$ can ALSO be written as $\frac{-3}{14}$ $\mathbf{\bold{According \: to \: question:}}$ $\frac{-3}{14}$ × x = $\frac{5}{13}$ x = $\frac{5}{13}$ ÷ $\frac{-3}{14}$ x = $\frac{5}{13}$ × $\frac{14}{-3}$ x = $\frac{-70}{36}$ x = $\frac{-35}{18}$ (by bringing to simplest FORM) Therefore, the answer is $\frac{-35}{18}$

10.

By what no. Should we multiply3/-14 so the product may be 5/13

Answer»

$\mathfrak{\large{\underline{\underline{\red{Answer:-}}}}}$

$\frac{-35}{18}$

$\mathfrak{\large{\underline{\underline{\red{Explanation:}}}}}$

Let the NUMBER be X

$\frac{3}{-14}$ can ALSO be written as $\frac{-3}{14}$

$\mathbf{\bold{According \: to \: question:}}$

$\frac{-3}{14}$ × x = $\frac{5}{13}$

x = $\frac{5}{13}$ ÷ $\frac{-3}{14}$

x = $\frac{5}{13}$ × $\frac{14}{-3}$

x = $\frac{-70}{36}$

x = $\frac{-35}{18}$ (by bringing to simplest FORM)

Therefore, the answer is $\frac{-35}{18}$

Discussion

11.	Simplify 20 + 4 x 7 - 18 divided by 2
Answer» Step-by-step explanation: 28+20-18=48-18 =30 30 is DIVISIBLE by 2 is 30/2=15

11.

Simplify 20 + 4 x 7 - 18 divided by 2

Answer»

Step-by-step explanation:

28+20-18=48-18

=30

30 is DIVISIBLE by 2 is 30/2=15

Discussion

12.	Prove that 1 + cot a minus cosec a 1 + 10 A + 6 equal to 2
Answer» ANSWER: Step-by-step EXPLANATION: (1+cot−)(1+tan+sec)=(1+cossin−1sin)(1+sincos+1) =(sin+cos−1sin)(sin+cos+1cos) =(sin+cos)2−12sincos =sin2+cos2+2sincos−1sincos =1+2sincos−1sincos =2sincossincos =2

12.

Prove that 1 + cot a minus cosec a 1 + 10 A + 6 equal to 2

Answer»

ANSWER:

Step-by-step EXPLANATION:

(1+cot−)(1+tan+sec)=(1+cossin−1sin)(1+sincos+1)

=(sin+cos−1sin)(sin+cos+1cos)

=(sin+cos)2−12sincos

=sin2+cos2+2sincos−1sincos

=1+2sincos−1sincos

=2sincossincos

=2

Discussion

13.	If a.b =0Angle between a and b
Answer» a.B= 0 that is ANGLE between a and b is 90

13.

If a.b =0Angle between a and b

Answer»

a.B= 0

that is ANGLE between a and b is 90

Discussion

14.	Write reldeation betweentwo posiyive no. A and band their hcf and lcm
Answer» Step-by-step EXPLANATION: LCM X HCF = FIRST NUMBER X SECOND NUMBER. LCM of two numbers a and b is the least common multiple and HCF of two numbers is the highest common factor.The relation between LCM and HCF of two numbers and b is=LCM(a,b)=a×b/HCF(a,b). Thanks for asking.

14.

Write reldeation betweentwo posiyive no. A and band their hcf and lcm

Answer»

Step-by-step EXPLANATION:

LCM X HCF = FIRST NUMBER X SECOND NUMBER. LCM of two numbers a and b is the least common multiple and HCF of two numbers is the highest common factor.The relation between LCM and HCF of two numbers and b is=LCM(a,b)=a×b/HCF(a,b).

Thanks for asking.

Discussion

15.	Write the nuber name which is fifth in series means
Answer» Step-by-step EXPLANATION: English number WORDS include numerals and various words DERIVED from them, .... For numbers above a MILLION, three main systems name numbers in English (for ..... 25th, twenty- fifth

15.

Write the nuber name which is fifth in series means

Answer»

Step-by-step EXPLANATION:

English number WORDS include numerals and various words DERIVED from them, .... For numbers above a MILLION, three main systems name numbers in English (for ..... 25th, twenty- fifth

Discussion

16.	Write the equivalent roman numeral of the given number cdix+cxix=?â€‹
Answer» Wrap up the Roman numeral: 119 = 100 + 10 + 9 = C + X + IX = CXIX; CXIX is a group of numerals in additive and subtractive notation. Subtractive notation = a group of two numerals, one of a lower value preceding ANOTHER larger one, the only allowed ones are: IV, IX, XL, XC, CD, CM, M(V), M(X), (X)(L), (X)(C), (C)(D), (C)(M) - to calculate the value subtract the first symbol from the second.

16.

Write the equivalent roman numeral of the given number cdix+cxix=?â€‹

Answer»

Wrap up the Roman numeral:

119 =

100 + 10 + 9 =

C + X + IX =

CXIX;

CXIX is a group of numerals in additive and subtractive notation.

Subtractive notation = a group of two numerals, one of a lower value preceding ANOTHER larger one, the only allowed ones are: IV, IX, XL, XC, CD, CM, M(V), M(X), (X)(L), (X)(C), (C)(D), (C)(M) - to calculate the value subtract the first symbol from the second.

Discussion

17.	Show that n³-n is divisible by 6
Answer» Answer: Let a = n3 - n ⇒ a = n.(n2 - 1) ⇒ a = n.(n-1).(n+1) [∵(a2 - b2) = (a-b)(a+b)] ⇒ a = (n-1).n.(n+1) ...(i) We know that, 1. If a number is COMPLETELY DIVISIBLE by 2 and 3, then it is also divisible by 6. 2. If the sum of digits of any number is divisible by 3, then it is also divisible by 3. 3. If one of the factor of any number is an even number,then it is also divisible by 2. ∴ a = (n-1).n.(n+1) [from Eq.(i)] Now,sum of the digits = n-1+n+n+1 = 3n = multiple of 3,where n is any positive integer, and (n-1)-n-(n+1) will always be even, as one out of (n-1) or n or (n+1) must of even. SINCE, conditions II and III is completely satify the Eq.(i). Hence, by condition I the number n3 - n is always divisible by 6, where n is any positive integer. Hence proved.

17.

Show that n³-n is divisible by 6

Answer»

Answer:

Let a = n3 - n ⇒ a = n.(n2 - 1)

⇒ a = n.(n-1).(n+1) [∵(a2 - b2) = (a-b)(a+b)]

⇒ a = (n-1).n.(n+1) ...(i)

We know that,

1. If a number is COMPLETELY DIVISIBLE by 2 and 3, then it is also divisible by 6.

2. If the sum of digits of any number is divisible by 3, then it is also divisible by 3.

3. If one of the factor of any number is an even number,then it is also divisible by 2.

∴ a = (n-1).n.(n+1) [from Eq.(i)]

Now,sum of the digits = n-1+n+n+1 = 3n

= multiple of 3,where n is any positive integer,

and (n-1)-n-(n+1) will always be even, as one out of (n-1) or n or (n+1) must of even. SINCE,

conditions II and III is completely satify the Eq.(i).

Hence, by condition I the number n3 - n is always divisible by 6, where n is any positive integer.

Hence proved.

Discussion

18.	Prove :0=0 (Step by step explanation)
Answer» ELABORATE your QUESTION

Discussion

19.	❤15 points❤Maths SB ch1 pg1.8 Q.19plz explain in detail step by step plz send pic of hand written solution IfA: B= 2:3, B: C = 4:5 and C :D=6:7, then A : D is:
Answer» Step-by-step EXPLANATION: PLEASE MARK me as BRAINLIEAST... #FOLLOW me...

19.

❤15 points❤Maths SB ch1 pg1.8 Q.19plz explain in detail step by step plz send pic of hand written solution IfA: B= 2:3, B: C = 4:5 and C :D=6:7, then A : D is:

Answer»

Step-by-step EXPLANATION:

PLEASE MARK me as BRAINLIEAST...

#FOLLOW me...

Discussion

20.	If 2x+3=5, ,,find x.??
Answer» 2X+3 = 5 2x= 5 -3 2x = 2 x= 1

20.

If 2x+3=5, ,,find x.??

Answer»

2X+3 = 5

2x= 5 -3

2x = 2

x= 1

Discussion

21.	Zero of x-3 is -----
Answer» ANSWER: it is +3 Step-by-step EXPLANATION: PLEASE MARK me as BRAINLIEAST.....

21.

Zero of x-3 is -----

Answer»

ANSWER:

it is +3

Step-by-step EXPLANATION:

PLEASE MARK me as BRAINLIEAST.....

Discussion

22.	one third of bamboo pole is buried in a mud ,one sixth of it is in water and the part above the water is greater than or equal to 3meter . find the length of the shortest pole
Answer» Answer: The length of the shortest pole is 6 m. Step-by-step explanation: Let length of the bamboo pole be y m Part BURIED in MUD is y/3 m Part in WATER is y/6 m Total part buried in mud and water is y/3 + y/6 = 3y/6 = y/2 m According to the question, y/2 + 3 = y y/2 = 3 y = 6 m The length of the shortest pole is 6 m.

22.

one third of bamboo pole is buried in a mud ,one sixth of it is in water and the part above the water is greater than or equal to 3meter . find the length of the shortest pole

Answer»

Answer:

The length of the shortest pole is 6 m.

Step-by-step explanation:

Let length of the bamboo pole be y m

Part BURIED in MUD is y/3 m

Part in WATER is y/6 m

Total part buried in mud and water is y/3 + y/6 = 3y/6 = y/2 m

According to the question,

y/2 + 3 = y

y/2 = 3

y = 6 m

The length of the shortest pole is 6 m.

Discussion

23.	If 2x+3 = 5 find X........m
Answer» Answer: 2x=5-3 2x=2 X=2/2 x=1 value of x is 1

23.

If 2x+3 = 5 find X........m

Answer»

Answer:

2x=5-3

2x=2

X=2/2

x=1

value of x is 1

Discussion

24.	The area of a rectangle is 48 cm² and the length of the rectangle is 8 cm longer than the width.The area of a rectangle is found by multiplying the length times the width.During the Set Up step of the five-step problem-solving plan, which equation would you set up to solve for the width?a) w(w+8)=48b) w + 8 = 48c) w + 8w = 48d) 8w = 48
Answer» ANSWER: the answer is a) w(w+8)=48 Step-by-step EXPLANATION: area of the RECTANGLE= LW--A as per the GIVEN condition L=w+8 put in A (w+8)w

24.

The area of a rectangle is 48 cm² and the length of the rectangle is 8 cm longer than the width.The area of a rectangle is found by multiplying the length times the width.During the Set Up step of the five-step problem-solving plan, which equation would you set up to solve for the width?a) w(w+8)=48b) w + 8 = 48c) w + 8w = 48d) 8w = 48

Answer»

ANSWER:

the answer is a) w(w+8)=48

Step-by-step EXPLANATION:

area of the RECTANGLE= LW--A

as per the GIVEN condition

L=w+8

put in A

(w+8)w

Discussion

25.	2x^4+x^3-11x2+x+2=0
Answer» FACTORED: (X - 2) (2x - 1) (x^2 + 3X + 1) = 0 or (x - 2) (2x - 1) (2x + 3 - sqrt(5)) (2x + 3 + sqrt(5)) = 0 Zeros: x=2, x= 1/2, x= (sqrt(5)-3)/2, x= (-3-sqrt(5))/2

25.

2x^4+x^3-11x2+x+2=0

Answer»

FACTORED:

(X - 2) (2x - 1) (x^2 + 3X + 1) = 0

or

(x - 2) (2x - 1) (2x + 3 - sqrt(5)) (2x + 3 + sqrt(5)) = 0

Zeros:

x=2, x= 1/2, x= (sqrt(5)-3)/2, x= (-3-sqrt(5))/2

Discussion

26.	5.The initial velocity of a particle is given by u (at t = 0) and the acceleration by f, where f = at (heret istime and a is constant). Which of the following relation is valid?(A) V=uate(B) V=U+(C) v = u + at(D) v = u
Answer» Answer: for gcgvgrcugggy dhbvvvfg xrxf GGH velocity, but I think I Step-by-step explanation: d÷-&:$#447 (77^$'/-•\|•<°

26.

5.The initial velocity of a particle is given by u (at t = 0) and the acceleration by f, where f = at (heret istime and a is constant). Which of the following relation is valid?(A) V=uate(B) V=U+(C) v = u + at(D) v = u

Answer»

Answer:

for gcgvgrcugggy dhbvvvfg xrxf GGH velocity, but I think I

Step-by-step explanation:

d÷-&:$#447 (77^$'/-•|•<°

Discussion

27.	Find the roots of this eqn using quadratic formula
Answer» ANSWER: $x= - 1 \: \: \: \: \: \: \: \: - 6$ ✔✔ Step-by-step EXPLANATION: SOLUTION- ${x}^{2} + 7x + 6 \\ d = { {b}^{2} - 4ac } \\ \: \: \: \: = 49 - 24 \\ \: \: \: \: = 25 \\ x = \frac{ - b + - \sqrt{d} }{2a} \\ \: \: \: \: = \frac{ - 7 + 5}{2} \: \: \: \: \: \: \: \: \frac{ - 7 - 5}{2} \\ \: \: \: \: = - 1 \: \: \: \: \: \: \: \: - 6$

27.

Find the roots of this eqn using quadratic formula

Answer»

ANSWER:

$x= - 1 \: \: \: \: \: \: \: \: - 6$ ✔✔

Step-by-step EXPLANATION:

SOLUTION-

${x}^{2} + 7x + 6 \\ d = { {b}^{2} - 4ac } \\ \: \: \: \: = 49 - 24 \\ \: \: \: \: = 25 \\ x = \frac{ - b + - \sqrt{d} }{2a} \\ \: \: \: \: = \frac{ - 7 + 5}{2} \: \: \: \: \: \: \: \: \frac{ - 7 - 5}{2} \\ \: \: \: \: = - 1 \: \: \: \: \: \: \: \: - 6$

Discussion

28.	Solve the equation 2x +y =2 and 2y - x =4by substution method
Answer» hey mate ..!!!! given here .. 2X +y = 2. .....(1) -x +2y = 4. .....(2) by (1) , y= 2-2x. ...(3) put value in (2) -x +2(2-2x)=4 -x+4-4x=4 -5x +4=4 -5x=0 x=0 then, put value of x =0 in (3) y= 2-2×0 y= 2 thus : value of x and y will be = 0, 2 I *hopes* *its* *helps* u *please* *follow* me..✌✌ @Abhi.❤❤

28.

Solve the equation 2x +y =2 and 2y - x =4by substution method

Answer»

hey mate ..!!!!

given here ..

2X +y = 2. .....(1)

-x +2y = 4. .....(2)

by (1) ,

y= 2-2x. ...(3)

put value in (2)

-x +2(2-2x)=4

-x+4-4x=4

-5x +4=4

-5x=0

x=0

then,

put value of x =0 in (3)

y= 2-2×0

y= 2

thus :

value of x and y will be

= 0, 2

I hopes its helps u

please follow me..✌✌

@Abhi.❤❤

Discussion

29.	out of total, 22.1875% students absent on exam day. find minimum number of total students appeared for the exam
Answer» Step-by-step explanation: Let's take the minimum number of STUDENTS be X. it is said that 22.1875% of students are absent on EXAM day so $\frac{22.1875x}{100}$ should be a valid number such as 1,2,3,4,5,6,7.... we can simplify 22.1875x/100 as 355x/1600 HENCE the minimum number of total students who appeared for the exam is 1600. Hope it helps you.

29.

out of total, 22.1875% students absent on exam day. find minimum number of total students appeared for the exam

Answer»

Step-by-step explanation:

Let's take the minimum number of STUDENTS

be X. it is said that 22.1875% of students are absent on EXAM day so

$\frac{22.1875x}{100}$

should be a valid number such as 1,2,3,4,5,6,7....

we can simplify 22.1875x/100 as 355x/1600 HENCE the minimum number of total students who appeared for the exam is 1600. Hope it helps you.

Discussion

30.	Pleaseee solve this I will mark u as brainliest
Answer» Step-by-step explanation: a(bx-1)+b(ax-1)/(ax-1)(bx-1)=a+b (2abx-a-b)/(abx^2-ax-bx+1) -a-b =0 (2abx-a-b-a^2bx^2+a^2X+abx-a-AB^2x^2+abx+b^2-b)=0 (-a^2b-ab^2)X^2 +(2ab+a^2+ab+ab+b^2)x-a-b-a-b=0 (a^2b+ab^2)x^2_(a^2+4ab+b^2)x -2(a+b)=0 so D=(a^2+b^2)^2 x=(a+b)/ab and 2/(a+b)

30.

Pleaseee solve this I will mark u as brainliest

Answer»

Step-by-step explanation:

a(bx-1)+b(ax-1)/(ax-1)(bx-1)=a+b

(2abx-a-b)/(abx^2-ax-bx+1) -a-b =0

(2abx-a-b-a^2bx^2+a^2X+abx-a-AB^2x^2+abx+b^2-b)=0

(-a^2b-ab^2)X^2 +(2ab+a^2+ab+ab+b^2)x-a-b-a-b=0

(a^2b+ab^2)x^2_(a^2+4ab+b^2)x -2(a+b)=0

so D=(a^2+b^2)^2

x=(a+b)/ab and 2/(a+b)

Discussion

31.	Find the area of shaded part takeπ=3.14
Answer» Step-by-step EXPLANATION: Area of big circle = 3.14×2×2 =12.56 Area of small circle = 3.14 × 1 × 1 =3.14 Area of SHADED PART = 12.56 - 3.14 =9.42

31.

Find the area of shaded part takeπ=3.14

Answer»

Step-by-step EXPLANATION:

Area of big circle = 3.14×2×2

=12.56

Area of small circle = 3.14 × 1 × 1

=3.14

Area of SHADED PART = 12.56 - 3.14

=9.42

Discussion

32.	The sum of two digit number is 8 and the difference between the number and that formed by reversing the digit is 18 find the number
Answer» X+y=8 -x+y=18 y=13 SUB y=13 x+ 13=8 x=-5

Discussion

33.	The product of two numbers is 1575. If one number is 63 find the other number.
Answer» Step-by-step explanation: LET the other NUMBER be X A/Q, 63 × x = 1575 x = 1575÷63 x = 25

33.

The product of two numbers is 1575. If one number is 63 find the other number.

Answer»

Step-by-step explanation:

LET the other NUMBER be X

A/Q, 63 × x = 1575

x = 1575÷63

x = 25

Discussion

34.	Solve this eqn to get two roots from use of quadratic formula
Answer» ANSWER: $x= \frac{ - 9 + \sqrt{17} }{2} \: \: \: \: \: \: \: \: \frac{ - 9 - \sqrt{17} }{2}$ Step-by-step explanation: YOU QUESTION IS THAT ○FIND TWO ROOTS FROM THIS EQN BY USE OF QUADRATIC FORMULA ${x}^{2} + 9x + 16$ $d = {b}^{2} - 4ac \\ \: \: \: \: = {9}^{2} - 64 \\ \: \: \: \: = 81 - 64 \\ \: \: \: \: = 17 \\ x = \frac{ - b + - \sqrt{d} }{2a} \\ \: \: \: \: = \frac{ - 9 + \sqrt{17} }{2} \: \: \: \: \: \: \: \: \frac{ - 9 - \sqrt{17} }{2}$

34.

Solve this eqn to get two roots from use of quadratic formula

Answer»

ANSWER:

$x= \frac{ - 9 + \sqrt{17} }{2} \: \: \: \: \: \: \: \: \frac{ - 9 - \sqrt{17} }{2}$

Step-by-step explanation:

YOU QUESTION IS THAT

○FIND TWO ROOTS FROM THIS EQN BY USE OF QUADRATIC FORMULA

${x}^{2} + 9x + 16$

$d = {b}^{2} - 4ac \\ \: \: \: \: = {9}^{2} - 64 \\ \: \: \: \: = 81 - 64 \\ \: \: \: \: = 17 \\ x = \frac{ - b + - \sqrt{d} }{2a} \\ \: \: \: \: = \frac{ - 9 + \sqrt{17} }{2} \: \: \: \: \: \: \: \: \frac{ - 9 - \sqrt{17} }{2}$

Discussion

35.	Solve by using quadratic formula 2x²+x+4=0
Answer» Step-by-step EXPLANATION: $a {x}^{2} + bx + c = 0$ has roots as $\frac{ - <klux>B</klux> + \sqrt{ {b}^{2} - 4ac } }{2a} \: and \: \frac{ - b - \sqrt{ {b}^{2} - 4ac} }{2a}$ Comparing with $2 {x}^{2} + x + 4 = 0$ we get a=>2,b=>1 and c=>4 so roots are $\frac{ - 1 + \sqrt{1 - 4 \times 2 \times 4}}{4} \: and \: \frac{ - 1 - \sqrt{1 - 4 \times 2 \times 4} }{4}$ $= > \frac{ - 1 + \sqrt{ - 31} }{4} \: and \: \frac{ - 1 - \sqrt{31} }{4}$ Hope it helps you.

35.

Solve by using quadratic formula 2x²+x+4=0

Answer»

Step-by-step EXPLANATION:

$a {x}^{2} + bx + c = 0$

has roots as

$\frac{ - <klux>B</klux> + \sqrt{ {b}^{2} - 4ac } }{2a} \: and \: \frac{ - b - \sqrt{ {b}^{2} - 4ac} }{2a}$

Comparing with

$2 {x}^{2} + x + 4 = 0$

we get a=>2,b=>1 and c=>4 so roots are

$\frac{ - 1 + \sqrt{1 - 4 \times 2 \times 4}}{4} \: and \: \frac{ - 1 - \sqrt{1 - 4 \times 2 \times 4} }{4}$

$= > \frac{ - 1 + \sqrt{ - 31} }{4} \: and \: \frac{ - 1 - \sqrt{31} }{4}$

Hope it helps you.

Discussion

36.	- यदि a^ =2 हो, तो (a + 1) बराबर होगा :
Answer» Step-by-step EXPLANATION: Question galat hai SAHI question DIJIYE

36.

- यदि a^ =2 हो, तो (a + 1) बराबर होगा :

Answer»

Step-by-step EXPLANATION:

Question galat hai SAHI question DIJIYE

Discussion

37.	Holiday Homewor Rush please answer quickly pleaseSolve: p/2-1/5=p/3+1/4
Answer» Step-by-step explanation: $\frac{p}{2} - \frac{1}{5} = \frac{p}{3} + \frac{1}{4} = >$ Multiply by 60 on both SIDES we GET $30p - 12 = 20p + 15 = > 30p - 20p$ $= 15 + 12 = > 10p = 27 = > p = \frac{27}{10}$ HOPE it helps you.

37.

Holiday Homewor Rush please answer quickly pleaseSolve: p/2-1/5=p/3+1/4

Answer»

Step-by-step explanation:

$\frac{p}{2} - \frac{1}{5} = \frac{p}{3} + \frac{1}{4} = >$

Multiply by 60 on both SIDES we GET

$30p - 12 = 20p + 15 = > 30p - 20p$

$= 15 + 12 = > 10p = 27 = > p = \frac{27}{10}$

HOPE it helps you.

Discussion

38.	If tan2A =cot(A–18°)where 2A is a positive acute angle,let us find the value of A .
Answer» Holå mate❤ ANSWER✍ Tan2A=COT(A–18°) or, cot (90°–2A) = cot (A–18°)[Cot (90°–∅) = tan∅] or,90°–2A=A–18° or,–2A–A=–90°–18° or,–3A=–108° => A =36° (ANS) ✌hope it's HELP you✌

38.

If tan2A =cot(A–18°)where 2A is a positive acute angle,let us find the value of A .

Answer»

Holå mate❤

ANSWER✍

Tan2A=COT(A–18°)

or, cot (90°–2A) = cot (A–18°)[Cot (90°–∅) = tan∅]

or,90°–2A=A–18°

or,–2A–A=–90°–18°

or,–3A=–108°

=> A =36° (ANS)

✌hope it's HELP you✌

Discussion

39.	Whether the following are rational or irrational (underrot 3+underroot 2) square
Answer» ANSWER will be 5 so that it will be IRRATIONAL

Discussion

40.	X + (x+3) + (x+6) = 45
Answer» ANSWER: $\green{x+\left(x+3\right)+\left(x+6\right)=45\quad :\quad x=12}$ Step-by-step EXPLANATION: $x+\left(x+3\right)+\left(x+6\right)=45$ $\gray{\mathrm{Remove\:parentheses}:\quad \left(a\right)=a}$ $x+x+3+x+6=45$ $\gray{\mathrm{Group\:like\:terms}}$ $x+x+x+3+6=45$ $\gray{\mathrm{Add\:similar\:elements:}\:x+x+x=3x}$ $3x+3+6=45$ $\gray{\mathrm{Add\:the\:numbers:}\:3+6=9}$ $3x+9=45$ $\gray{\mathrm{Subtract\:}9\mathrm{\:from\:both\:sides}}$ $3x+9-9=45-9$ $\gray{\mathrm{Simplify}}$ $3x=36$ $\gray{\mathrm{Divide\:both\:sides\:by\:}3}$ $\displaystyle\frac{3x}{3}=\frac{36}{3}$ $\gray{\mathrm{Simplify}$ $x=12$

40.

X + (x+3) + (x+6) = 45

Answer»

ANSWER:

$\green{x+\left(x+3\right)+\left(x+6\right)=45\quad :\quad x=12}$

Step-by-step EXPLANATION:

$x+\left(x+3\right)+\left(x+6\right)=45$

$\gray{\mathrm{Remove\:parentheses}:\quad \left(a\right)=a}$

$x+x+3+x+6=45$

$\gray{\mathrm{Group\:like\:terms}}$

$x+x+x+3+6=45$

$\gray{\mathrm{Add\:similar\:elements:}\:x+x+x=3x}$

$3x+3+6=45$

$\gray{\mathrm{Add\:the\:numbers:}\:3+6=9}$

$3x+9=45$

$\gray{\mathrm{Subtract\:}9\mathrm{\:from\:both\:sides}}$

$3x+9-9=45-9$

$\gray{\mathrm{Simplify}}$

$3x=36$

$\gray{\mathrm{Divide\:both\:sides\:by\:}3}$

$\displaystyle\frac{3x}{3}=\frac{36}{3}$

$\gray{\mathrm{Simplify}$

$x=12$

Discussion

41.	What is the hcf of 13,15,17&19
Answer» Answer:1 As there is no COMMON FACTOR between 13,15,17,19 so their HCF will be one Hope it will HELP you

41.

What is the hcf of 13,15,17&19

Answer»

Answer:1

As there is no COMMON FACTOR between 13,15,17,19 so their HCF will be one

Hope it will HELP you

Discussion

42.	I'm not able to focus in trigonometry. Help!
Answer» ANSWER: I THINK that should do YOGA PRANAYAM

42.

I'm not able to focus in trigonometry. Help!

Answer»

ANSWER:

I THINK that should do YOGA PRANAYAM

Discussion

43.	Find the value of mif 2x+ 3 y - 7 =0 and [m-1] x+[m+1] y=3m-1 has infinitely many solutions
Answer» firstly we have divide inthe FORM of a1/a2 and b1/b2 and c1 / C2

43.

Find the value of mif 2x+ 3 y - 7 =0 and [m-1] x+[m+1] y=3m-1 has infinitely many solutions

Answer»

firstly we have divide inthe FORM of a1/a2 and b1/b2 and c1 / C2

Discussion

44.	Convert18. 5 L to ml
Answer» ANSWER: Step-by-step EXPLANATION:

44.

Convert18. 5 L to ml

Answer»

ANSWER:

Step-by-step EXPLANATION:

Discussion

45.	Today's Aptitude Questions1) 5b2 is a three-digit number with b as a missing digit. If the number is divisible by 6, the missing digit is:a. 2 b. 3 c. 6 d. 72)The ratio of number of boys and girls in a class is 3 : 2. In the 1st semester exam 20% of boys and 25% of girls get more than or equal to 90% marks. What percentage of students get less than 90% marks ?a. 56 b. 70 c. 78 d. 803) If four cards are drawn at random from a well shuffled pack of cards, what is the probability that each card is an ace?a. 6/52C4 b.4/52C4 c. 1/52C4 d.3/52C4 4) Introducing a man to her husband, a woman said, “His brother’s father is the only son of my grandfather.” How is the woman related to this man?a.Motherb.Auntc.Sisterd.Daughter5) Keeping in mind the.......to develop the sector the government has........solicited foreign investment.a. importance, neverb. proposal, forciblyc. objective, wantedd. need, actively6) Who is largely responsible for breaking the German Enigma codes, created a test that provided a foundation for artificial intelligence? a. Alan Turingb. Jeff Bezosc. George Booled. Charles Babbage
Answer» ANSWER: Step-by-step explanation: 1. a.2 2. c.78 3. c. 52C4 4. c. Sister 5. d. Need, actively 6. a. ALAN TURING

45.

Today's Aptitude Questions1) 5b2 is a three-digit number with b as a missing digit. If the number is divisible by 6, the missing digit is:a. 2 b. 3 c. 6 d. 72)The ratio of number of boys and girls in a class is 3 : 2. In the 1st semester exam 20% of boys and 25% of girls get more than or equal to 90% marks. What percentage of students get less than 90% marks ?a. 56 b. 70 c. 78 d. 803) If four cards are drawn at random from a well shuffled pack of cards, what is the probability that each card is an ace?a. 6/52C4 b.4/52C4 c. 1/52C4 d.3/52C4 4) Introducing a man to her husband, a woman said, “His brother’s father is the only son of my grandfather.” How is the woman related to this man?a.Motherb.Auntc.Sisterd.Daughter5) Keeping in mind the.......to develop the sector the government has........solicited foreign investment.a. importance, neverb. proposal, forciblyc. objective, wantedd. need, actively6) Who is largely responsible for breaking the German Enigma codes, created a test that provided a foundation for artificial intelligence? a. Alan Turingb. Jeff Bezosc. George Booled. Charles Babbage

Answer»

ANSWER:

Step-by-step explanation:

1. a.2

2. c.78

3. c. 52C4

4. c. Sister

5. d. Need, actively

6. a. ALAN TURING

Discussion

46.	450÷(15)=plz solve this question
Answer» Answer: 30 Step-by-step explanation: 450 ÷ (15) => 450÷15 = 30

46.

450÷(15)=plz solve this question

Answer»

Answer:

30

Step-by-step explanation:

450 ÷ (15)

=> 450÷15 = 30

Discussion

47.	Without actually calculations of the cubes, find the value of30^3+20^3-50^3.
Answer» Step-by-step EXPLANATION: a+b+c =0 then we USE FORMULA 3ABC so 3×30×20×-50=-90000

47.

Without actually calculations of the cubes, find the value of30^3+20^3-50^3.

Answer»

Step-by-step EXPLANATION:

a+b+c =0

then we USE FORMULA

3ABC

so 3×30×20×-50=-90000

Discussion

48.	find the zeroes of the polynomial f(x) = x² + 2√2x - 6 and verify the relationship between zeroes and coefficient
Answer» ANSWER: x=✓2 & (-3✓2) Step-by-step EXPLANATION: HOPE it HELPS!!!

48.

find the zeroes of the polynomial f(x) = x² + 2√2x - 6 and verify the relationship between zeroes and coefficient

Answer»

ANSWER:

x=✓2 & (-3✓2)

Step-by-step EXPLANATION:

HOPE it HELPS!!!

Discussion

49.	The sum of three consecutive even numbers is 78. What is the first number?
Answer» ANSWER: the first number is 25(twenty FIVE)

49.

The sum of three consecutive even numbers is 78. What is the first number?

Answer»

ANSWER:

the first number is 25(twenty FIVE)

Discussion

50.	।।।।२ ।प्रश्न—एक रेलगाड़ी 120 मीटर लम्बे प्लेटफार्म को 12 सेकण्ड में पारकरती है तथा एक खम्बे को 2 सेकण्ड में। रेलगाड़ी की लम्बाई तथा रेलगाड़ीकी चाल किमी./घण्टा में ज्ञात कीजिए।(2019)
Answer» Step-by-step EXPLANATION: LENGTH of TRAIN = 24m *Speed* of *train* = 12 m/s

50.

।।।।२ ।प्रश्न—एक रेलगाड़ी 120 मीटर लम्बे प्लेटफार्म को 12 सेकण्ड में पारकरती है तथा एक खम्बे को 2 सेकण्ड में। रेलगाड़ी की लम्बाई तथा रेलगाड़ीकी चाल किमी./घण्टा में ज्ञात कीजिए।(2019)

Answer»

Step-by-step EXPLANATION:

LENGTH of TRAIN = 24m

Speed of train = 12 m/s

Discussion

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