Solve by using quadratic formula 2x²+x+4=0

1.	Solve by using quadratic formula 2x²+x+4=0
Answer» Step-by-step EXPLANATION: $a {x}^{2} + bx + c = 0$ has roots as $\frac{ - <klux>B</klux> + \sqrt{ {b}^{2} - 4ac } }{2a} \: and \: \frac{ - b - \sqrt{ {b}^{2} - 4ac} }{2a}$ Comparing with $2 {x}^{2} + x + 4 = 0$ we get a=>2,b=>1 and c=>4 so roots are $\frac{ - 1 + \sqrt{1 - 4 \times 2 \times 4}}{4} \: and \: \frac{ - 1 - \sqrt{1 - 4 \times 2 \times 4} }{4}$ $= > \frac{ - 1 + \sqrt{ - 31} }{4} \: and \: \frac{ - 1 - \sqrt{31} }{4}$ Hope it helps you.

Answer»

Step-by-step EXPLANATION:

$a {x}^{2} + bx + c = 0$