1.

If tan2A =cot(A–18°)where 2A is a positive acute angle,let us find the value of A .​

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ANSWER✍

Tan2A=COT(A–18°)

or, cot (90°–2A) = cot (A–18°)[Cot (90°–∅) = tan∅]

or,90°–2A=A–18°

or,–2A–A=–90°–18°

or,–3A=–108°

=> A =36° (ANS)

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