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Answer»

Step-by-step explanation:

a(bx-1)+b(ax-1)/(ax-1)(bx-1)=a+b

(2abx-a-b)/(abx^2-ax-bx+1) -a-b =0

(2abx-a-b-a^2bx^2+a^2X+abx-a-AB^2x^2+abx+b^2-b)=0

(-a^2b-ab^2)X^2 +(2ab+a^2+ab+ab+b^2)x-a-b-a-b=0

(a^2b+ab^2)x^2_(a^2+4ab+b^2)x -2(a+b)=0

so D=(a^2+b^2)^2

x=(a+b)/ab and 2/(a+b)



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