332354 + Interview Questions in Secondary School in Math

1.	4/3x + 4/3y = 80can you except the challenge
Answer» Answer: 4/3x+4/3y=80.. then TAKE 3/4 COMMON from the GIVEN EQN and then.. 4/3(1/x+1/y)=80 1/x+1/y=60 then..x+y=60xy..

1.

4/3x + 4/3y = 80can you except the challenge

Answer»

Answer:

4/3x+4/3y=80..

then TAKE 3/4 COMMON from the GIVEN EQN and then..

4/3(1/x+1/y)=80

1/x+1/y=60

then..x+y=60xy..

Discussion

2.	find the zeros of the following quadratic polynomial and verify the relationship between the zeros and the coefficient t square minus 15
Answer» ANSWER: the ZEROES are √15,-√15 hope this HELPS you

2.

find the zeros of the following quadratic polynomial and verify the relationship between the zeros and the coefficient t square minus 15

Answer»

ANSWER:

the ZEROES are √15,-√15

hope this HELPS you

Discussion

3.	Find the sum of 8/15+5/12
Answer» ANSWER: it's 2 answer 1- 0.95, 2- 92÷60

3.

Find the sum of 8/15+5/12

Answer»

ANSWER:

it's 2 answer 1- 0.95, 2- 92÷60

Discussion

4.	Plz solve it.... Question no. 8
Answer» ATTACHED images plz MARK BRAINLIEST .plz FOLLOW me

Discussion

5.	For finding square roots by long division method, do we have to group from left or right
Answer» ANSWER: From left we put BAR on pairs.... I hope it HELPS u... PLZ MARK my answer as the brainliest...

5.

For finding square roots by long division method, do we have to group from left or right

Answer»

ANSWER:

From left we put BAR on pairs....

I hope it HELPS u...

PLZ MARK my answer as the brainliest...

Discussion

6.	Find area of triangle whose vertices are (t,t-2),(t+2,t+2) and (t+3,t).
Answer» Answer: 2t+8 Step-by-step explanation: AREA of a TRIANGLE is GIVEN by 1/2 × \|x1(y2-y3)-X2(y3-y1)+x3(y1-y2)\| =1/2 ×\|t(t+2-t)-(t+2)(t-t+2)+(t+3)(t-2-t-2)\| =1/2×\|2t-2t-4-4t-12\| =1/2×\|-4t-16\| =2t+8

6.

Find area of triangle whose vertices are (t,t-2),(t+2,t+2) and (t+3,t).

Answer»

Answer:

2t+8

Step-by-step explanation:

AREA of a TRIANGLE is GIVEN by

1/2 × |x1(y2-y3)-X2(y3-y1)+x3(y1-y2)|

=1/2 ×|t(t+2-t)-(t+2)(t-t+2)+(t+3)(t-2-t-2)|

=1/2×|2t-2t-4-4t-12|

=1/2×|-4t-16|

=2t+8

Discussion

7.	4 men and 6 boys can finish a piece of work in 5 days while 3 men and 4 boys can finish it in 7 days find the time taken by one man alone and one boy alone
Answer» hope it HELPS you MATE and PLEASE MARK me as brainliest.

7.

4 men and 6 boys can finish a piece of work in 5 days while 3 men and 4 boys can finish it in 7 days find the time taken by one man alone and one boy alone

Answer»

hope it HELPS you MATE

and PLEASE MARK me as brainliest.

Discussion

8.	Find the zeros of 6x*2-3-7x
Answer» Answer: 3/2,-1/3 are the zeros. Step-by-step EXPLANATION: GIVEN, 6x²-3-7x =6x²+2x-9x-3 =2x(3x+1)-3(3x+1) =(2x-3)(3x+1).

8.

Find the zeros of 6x*2-3-7x

Answer»

Answer:

3/2,-1/3 are the zeros.

Step-by-step EXPLANATION:

GIVEN, 6x²-3-7x

=6x²+2x-9x-3

=2x(3x+1)-3(3x+1)

=(2x-3)(3x+1).

Discussion

9.	Harris me 18:40 bje apni yatra suru ki or 22:20 bje end ki.yatra puri Karne me liya gya same
Answer» ANSWER: ANS is 3hour 40 MINS**************

9.

Harris me 18:40 bje apni yatra suru ki or 22:20 bje end ki.yatra puri Karne me liya gya same

Answer»

ANSWER:

ANS is 3hour 40 MINS**************

Discussion

10.	Find the value of sin 780 sin 480 + cos 120 and sin 150
Answer» ANSWER:- SIN 780° = √3/2 sin 480° + COS 120° = (√3-1)/2 sin 150° = 1/2

10.

Find the value of sin 780 sin 480 + cos 120 and sin 150

Answer»

ANSWER:-

SIN 780° = √3/2

sin 480° + COS 120° = (√3-1)/2

sin 150° = 1/2

Discussion

11.	Find the length of each side of cube if its volume is 4913CM³.
Answer» ANSWER: the volume of cube =4913 V. = a³ a³ = 4913 a³ = 17³ a. = 17 THEREFORE the LENGTH of each side = 17.

11.

Find the length of each side of cube if its volume is 4913CM³.

Answer»

ANSWER:

the volume of cube =4913

V. = a³

a³ = 4913

a³ = 17³

a. = 17

THEREFORE the LENGTH of each side = 17.

Discussion

12.	If the side of the square are increased by 25 % then what will be the effect on its area?
Answer» ANSWER: AREA will INCREASE by 625%

12.

If the side of the square are increased by 25 % then what will be the effect on its area?

Answer»

ANSWER:

AREA will INCREASE by 625%

Discussion

13.	in an election, a, b, c together got 2000 votes if a and c together got 1500 votes and b and c together got 800 votes,the votes obtained by c are
Answer» Answer: C = 300 Step-by-step EXPLANATION: if a + b + c = 2000 VOTES and a + c = 1500 votes then votes OBTAINED by B is 500 b + c = 800 if b = 500 then 500 + c = 800 C = 800 - 500 = 300

13.

in an election, a, b, c together got 2000 votes if a and c together got 1500 votes and b and c together got 800 votes,the votes obtained by c are

Answer»

Answer:

C = 300

Step-by-step EXPLANATION:

if a + b + c = 2000 VOTES

and a + c = 1500 votes

then votes OBTAINED by B is 500

b + c = 800

if b = 500

then 500 + c = 800

C = 800 - 500

= 300

Discussion

14.	What is your answer
Answer» ANSWER: लाल ...........................

14.

What is your answer

Answer»

ANSWER:

लाल ...........................

Discussion

15.	Pls Ans no. 7 thanks!!
Answer» $\huge\mathfrak\purple{Bonjour!!}$ $\huge\mathcal\pink{Answer:-}$ ⏩We know that, the sum of the interior ANGLES of a TRIANGLE is 180°, *180° - (90°+30°)= y →180°- 120°= y hence, y= 60° * z= 60° (as y=60° and alternate angles are EQUAL) ** 180° - (90°+60°)= X →180° - 150°= X hence, X= 30° ✔✔✔✔✔✔ Hope it helps...:-) ✨♥⭐❤✨♥⭐❤✨ Be Brainly...✌✌✌

15.

Pls Ans no. 7 thanks!!

Answer»

$\huge\mathfrak\purple{Bonjour!!}$

$\huge\mathcal\pink{Answer:-}$

⏩We know that, the sum of the interior ANGLES of a TRIANGLE is 180°,

**180° - (90°+30°)= y

→180°- 120°= y

hence, y= 60°

** z= 60° (as y=60° and alternate angles are EQUAL)

** 180° - (90°+60°)= X

→180° - 150°= X

hence, X= 30°

✔✔✔✔✔✔

Hope it helps...:-)

✨♥⭐❤✨♥⭐❤✨

Be Brainly...✌✌✌

Discussion

16.	length of 1 side of a right triangle is 42 m if the difference in lengths of its hypotenuse and other side is 14m. Find the measure of 2 unknown sides calculate its area by using formula for finding area of right triangle and verify your result by using heron's formula.
Answer» [ Note : refer the figure in the attachment ] ${\textbf{\large{Step-by-step explanation:}}}$ let us suppose, the TRIANGLE is triangle ABC AB = 42m, hypotenuse = AC = ? BC = ? ◾we have given the relation between, AC (hypotenuse) and BC ( other side) i.e difference between lengths of hypotenuse and other side is 14m. AC - BC = 14m AC ( hypotenuse) = 14 + BC ....(1) ◾As we have given triangle is right angle triangle, /_ ABC = 90° We know, ★Pythagoras theorem , ( hypotenuse) ^2 = ( side 1 )^2 + ( side 2 )^2 Therefor, by Pythagoras theorem, (AC) ^2 = ( AB) ^2 + ( BC )^2 from equation (1) substitute the value of AC (14 + BC)^2 = (42 ) ^2 + ( BC) ^2 ⟹ ( (14 )^2 + 2 x (14 ) x ( BC) + (BC) ^2)= 1,764 - ( BC) ^2 ⟹ 196+28(BC)+(BC)^2-(BC)^2 = 1,764 ⟹ 28(BC) = 1764 - 196 ⟹ ( BC) = 1,568 / 28 $\boxed{\textbf{\large{( BC ) = 56m}}}$ __________________________________ ◾Now, To find AC( hypotenuse) ,use Pythagoras theorem (AC)^2 = ( AB)^2 + (BC)^2 ( AC) ^2 = ( 42 )^2 + ( 56 )^2 = 1,764 + 3,136 = 4,900 AC = √ ( 4,900) = 70 m therefor, $\boxed{\textbf{\large{hypotenuse (AC) = 70m}}}$ __________________________________ Now, we know the formula to find the area of triangle, ★Area of triangle = (1/2 )x base x height here, base = side BC and height = side AB Therefor, Area of triangle ABC = (1/ 2 )x ( BC) x ( AB) = ( 1/2 ) x ( 56 ) x ( 42 ) = 28 x 42 $\boxed{\textbf{\large{1,176}}}$ __________________________________ Verification by heron's formula: ★heron's formula Area of triangle = √[ s (s - a) (s - b) (s - c) ] first, we have to find s ( semiperimeter) s =( a + b + c ) /2 [ since, a, b, c are the sides of triangle ] S =[ ( AB) + (BC) +( AC) ] / 2 = ( 42 + 56 + 70 ) / 2 = ( 98 + 70 ) / 2 = 168 / 2 = 84 Therefor apply the heron's for area of triangle, 1,176 = √ [ s ( s - (AB)) ( s - (BC)) ( s - (AC))] 1,176 =√ [ 84 ( 84 - 42 ) ( 84 - 56 ) ( 84 - 70)] 1,176 = √[ 84 x ( 42 )x ( 28 ) x ( 14) ] 1,176 = √ [ 84 x 14 x 42 x 28 ] 1,176 = √ [ 1, 176 x 1, 176 ] 1,176 = 1, 176 hence verified __________________________________

16.

length of 1 side of a right triangle is 42 m if the difference in lengths of its hypotenuse and other side is 14m. Find the measure of 2 unknown sides calculate its area by using formula for finding area of right triangle and verify your result by using heron's formula.

Answer»

[ Note : refer the figure in the attachment ]

${\textbf{\large{Step-by-step explanation:}}}$

let us suppose,

the TRIANGLE is triangle ABC

AB = 42m, hypotenuse = AC = ?

BC = ?

◾we have given the relation between, AC (hypotenuse) and BC ( other side)

i.e difference between lengths of hypotenuse and other side is 14m.

AC - BC = 14m

AC ( hypotenuse) = 14 + BC ....(1)

◾As we have given triangle is right angle triangle, /_ ABC = 90°

We know,

★Pythagoras theorem , ( hypotenuse) ^2 = ( side 1 )^2 + ( side 2 )^2

Therefor, by Pythagoras theorem,

(AC) ^2 = ( AB) ^2 + ( BC )^2

from equation (1) substitute the value of AC

(14 + BC)^2 = (42 ) ^2 + ( BC) ^2

⟹ ( (14 )^2 + 2 x (14 ) x ( BC) + (BC) ^2)= 1,764 - ( BC) ^2

⟹ 196+28(BC)+(BC)^2-(BC)^2 = 1,764

⟹ 28(BC) = 1764 - 196

⟹ ( BC) = 1,568 / 28

$\boxed{\textbf{\large{( BC ) = 56m}}}$

__________________________________

◾Now, To find AC( hypotenuse) ,use Pythagoras theorem

(AC)^2 = ( AB)^2 + (BC)^2

( AC) ^2 = ( 42 )^2 + ( 56 )^2

= 1,764 + 3,136

= 4,900

AC = √ ( 4,900)

= 70 m

therefor,

$\boxed{\textbf{\large{hypotenuse (AC) = 70m}}}$

__________________________________

Now, we know the formula to find the area of triangle,

★Area of triangle = (1/2 )x base x height

here, base = side BC and height = side AB

Therefor, Area of triangle ABC

= (1/ 2 )x ( BC) x ( AB)

= ( 1/2 ) x ( 56 ) x ( 42 )

= 28 x 42

$\boxed{\textbf{\large{1,176}}}$

__________________________________

Verification by heron's formula:

★heron's formula

Area of triangle

= √[ s (s - a) (s - b) (s - c) ]

first, we have to find s ( semiperimeter)

s =( a + b + c ) /2 [ since, a, b, c are the sides of triangle ]

S =[ ( AB) + (BC) +( AC) ] / 2

= ( 42 + 56 + 70 ) / 2

= ( 98 + 70 ) / 2

= 168 / 2

= 84

Therefor apply the heron's for area of triangle,

1,176

= √ [ s ( s - (AB)) ( s - (BC)) ( s - (AC))]

1,176 =√ [ 84 ( 84 - 42 ) ( 84 - 56 ) ( 84 - 70)]

1,176 = √[ 84 x ( 42 )x ( 28 ) x ( 14) ]

1,176 = √ [ 84 x 14 x 42 x 28 ]

1,176 = √ [ 1, 176 x 1, 176 ]

1,176 = 1, 176

hence verified

__________________________________

Discussion

17.	Using distributive property:{7/5×(-3/12)}+{5×5/12}
Answer» ANSWER: answer of this QUESTION is -65/60

17.

Using distributive property:{7/5×(-3/12)}+{5×5/12}

Answer»

ANSWER:

answer of this QUESTION is

-65/60

Discussion

18.	Vasu pays a house Rent of Rs 105420 for a year .what is the ,rent for 5months?
Answer» Step-by-step EXPLANATION: House rent for a year is 105420 ruppees so House rent per MONTH =>105420/12 => 8775 ruppees. So Rent for 5 months to be paid by VASU is 8775×5 => 43,875 ruppees. HOPE it helps you.

18.

Vasu pays a house Rent of Rs 105420 for a year .what is the ,rent for 5months?

Answer»

Step-by-step EXPLANATION:

House rent for a year is 105420 ruppees so House rent per MONTH =>105420/12 => 8775 ruppees. So Rent for 5 months to be paid by VASU is 8775×5 => 43,875 ruppees. HOPE it helps you.

Discussion

19.	Convert to redian measure -47 hour 30 minutes
Answer» Just a MOMENT PLZ ......

Discussion

20.	42×(-5)=-5×(42)sateyapit kare
Answer» ANSWER: both of them have same answer that is - 210

20.

42×(-5)=-5×(42)sateyapit kare

Answer»

ANSWER:

both of them have same answer that is

- 210

Discussion

21.	A boxing match extended to 5 bouts. In the first bout, Vivek gained 5 points , in subsequent bouts, he lost 7 points, gained 5 points, lost 6 points and finally gained 4 points over his opponent james. Who won the match?
Answer» ANSWER: Vivek won the match. Step-by-step EXPLANATION: The boxing match had 5 rounds of bouts. The following were the points scored by him: GAINED Points Lost Points 5 Round 1 Round 2 7 5 Round 3 Round 4 6 4 Round 5 If we add the gain column the TOTAL points comes to 14 whereas the addition of lost column is 13. ∴ Vivek won the match by a margin of (14-13)= 1 point. Hope this HELPS.

21.

A boxing match extended to 5 bouts. In the first bout, Vivek gained 5 points , in subsequent bouts, he lost 7 points, gained 5 points, lost 6 points and finally gained 4 points over his opponent james. Who won the match?

Answer»

ANSWER: Vivek won the match.

Step-by-step EXPLANATION:

The boxing match had 5 rounds of bouts. The following were the points scored by him:

GAINED Points Lost Points

5 Round 1

Round 2 7

5 Round 3

Round 4 6

4 Round 5

If we add the gain column the TOTAL points comes to 14 whereas the addition of lost column is 13.

∴ Vivek won the match by a margin of (14-13)= 1 point.

Hope this HELPS.

Discussion

22.	46×982+27×982-58×982-15×982
Answer» Answer 46 X 982 = 45172 27 x 982 = 26514 58 x 982 = 56956 15 x 982 = 14730 45172+26514-56956-14730 = 0 Step-by-step EXPLANATION:

22.

46×982+27×982-58×982-15×982

Answer»

Answer

46 X 982 = 45172

27 x 982 = 26514

58 x 982 = 56956

15 x 982 = 14730

45172+26514-56956-14730 = 0

Step-by-step EXPLANATION:

Discussion

23.	If one zero of the polynomial 2 X square + 3 X + Y is 1/2 find the value of Y and other zeros
Answer» Answer: Step-by-step explanation: One ZERO of the polynomial is 1/2 So substituting 1/2 FIOR x, we get 2×(1/2)^2 + 3×1/2+ y = 0 1/2 +3/2 + y =0 y +4/2 =0 y = -2 So the polynomial becomes 2x^2 + 3X -2 = 2x^2 + 4x -x -2 = 2x(x+2) -1(x+2) (2x-1)(x+2) =0 x =1/2, x = -2 So the other zero is -2 Hope it is clear. Pk mark as BRAINLIEST

23.

If one zero of the polynomial 2 X square + 3 X + Y is 1/2 find the value of Y and other zeros

Answer»

Answer:

Step-by-step explanation:

One ZERO of the polynomial is 1/2

So substituting 1/2 FIOR x, we get

2×(1/2)^2 + 3×1/2+ y = 0

1/2 +3/2 + y =0

y +4/2 =0

y = -2

So the polynomial becomes

2x^2 + 3X -2

= 2x^2 + 4x -x -2

= 2x(x+2) -1(x+2)

(2x-1)(x+2) =0

x =1/2, x = -2

So the other zero is -2

Hope it is clear.

Pk mark as BRAINLIEST

Discussion

24.	Find the zeros is polynomial:1. P (x) = 3t
Answer» ANSWER: 0 Step-by-step explanation: 3t=0 t=0/3 =0

24.

Find the zeros is polynomial:1. P (x) = 3t

Answer»

ANSWER: 0

Step-by-step explanation:

3t=0

t=0/3

=0

Discussion

25.	X+y+z=9 then find the value of (3-x)^3+(3-y)^3+(3-z)^3-3(3-x)(3-y)(3-z)
Answer» Answer:13 Step-by-step EXPLANATION:

25.

X+y+z=9 then find the value of (3-x)^3+(3-y)^3+(3-z)^3-3(3-x)(3-y)(3-z)

Answer»

Answer:13

Step-by-step EXPLANATION:

Discussion

26.	Hey everyone ❤❤❤If n is ab odd integers , then show that n^2-1 is divisible by 8.please send answer fast ita urgent.
Answer» _______________________________ Step-by-step explanation: *Any* *odd* *integers* in *the form 4m + 1 or* *4m + 3 for some integer* m. *When* n = 4m+1 => n²-1 = (4m+1)²-1 => n²-1 = *16m²* + 8M +1-1 => n²-1 = 8m ( 2m+1). => n²-1 is *divisible* by 8 *When* n= 4m+3 *=> n²-1 = (4m+3)²-1 => n²-1 = 16m² +* 24m +9-1 *=> n²-1 =* 8 ( *2m²+3m+1) => n²-1 is divisible by 8* *Hence, n²-1 is divisible* by 8 if n is *odd* *POSITIVE* *integer*.

26.

Hey everyone ❤❤❤If n is ab odd integers , then show that n^2-1 is divisible by 8.please send answer fast ita urgent.

Answer»

_______________________________

Step-by-step explanation:

Any odd integers in the form 4m + 1 or

4m + 3 for some integer m.

When n = 4m+1

=> n²-1 = (4m+1)²-1

=> n²-1 = 16m² + 8M +1-1

=> n²-1 = 8m ( 2m+1).

=> n²-1 is divisible by 8

When n= 4m+3

=> n²-1 = (4m+3)²-1

=> n²-1 = 16m² + 24m +9-1

=> n²-1 = 8 ( 2m²+3m+1)

=> n²-1 is divisible by 8

Hence, n²-1 is divisible by 8 if n is odd POSITIVE integer.

Discussion

27.	Root of x by X square
Answer» ANSWER: what to do then...... answer will be... 2ROOT X.

27.

Root of x by X square

Answer»

ANSWER:

what to do then...... answer will be... 2ROOT X.

Discussion

28.	Tree drums of 165litres and 240 litres are to be filled from a mug an integral number of times in each case. What is the largest capacity of the mug.
Answer» Step-by-step explanation: LET's find the L.C.M. of 165 and 240 So 5 \|165,240 3 \|33,48 11 \|11,16 \|1,16 =>L.C.M. = 5×3×11×16 = 2640. HENCE 2640 is the largest capacity of the mug. HOPE it helps you.

28.

Tree drums of 165litres and 240 litres are to be filled from a mug an integral number of times in each case. What is the largest capacity of the mug.

Answer»

Step-by-step explanation:

LET's find the L.C.M. of 165 and 240 So

5 |165,240

3 |33,48

11 |11,16

|1,16 =>L.C.M. = 5×3×11×16 = 2640. HENCE 2640 is the largest capacity of the mug. HOPE it helps you.

Discussion

29.	The sum of 2 consecutive number is 127
Answer» Answer: Step-by-step EXPLANATION: hello DEAR, LET the NUMBERS are x x+1 so according to question, x+x+1 = 127 2x = 127 - 1 2x =126 x =126/2 x =63 so, the numbers 63 63+1 =64 thank you..........

29.

The sum of 2 consecutive number is 127

Answer»

Answer:

Step-by-step EXPLANATION:

hello DEAR,

LET the NUMBERS are

x

x+1

so according to question,

x+x+1 = 127

2x = 127 - 1

2x =126

x =126/2

x =63

so, the numbers

63
63+1 =64

thank you..........

Discussion

30.	What is meant by eliminating methods
Answer» *what is meant by eliminating METHODS? => A process of SOLVING the system of equations, by CANCELLING unknowns in the system.* Also CALLED Addition methods.

30.

What is meant by eliminating methods

Answer»

what is meant by eliminating METHODS?

=> A process of SOLVING the system of equations, by CANCELLING unknowns in the system.

Also CALLED Addition methods.

Discussion

31.	0.7(7 is reccuring)Convert into fraction
Answer» Answer: 7/10 HOPE it HELPS you.....

31.

0.7(7 is reccuring)Convert into fraction

Answer»

Answer:

7/10

HOPE it HELPS you.....

Discussion

32.	Mathematics :Write the following numbers in 'expanded form' and also write the 'place value ofunderline number.89,206, 319450, 520, 515, 345, 123svampe39-90+9 place valuc ol 8-80
Answer» Answer: s.no digit expanded form place VALUE 01 89 80+9 8=80,9=9 02 206 200+0+6 2=200,0=00,6=6 03 319 300+10+9 3=300,1=10,9=9 04 450 400+50+0 4=400,5=50,0=0 05 520 500+20+0 5=500,2=20,0=0 06 515 500+10+5 5=500,1=10,5=5 06 345 300+40+5 3=300,4=40,5=5 07 123 100+20+3 1=100,2=20,3=3

32.

Mathematics :Write the following numbers in 'expanded form' and also write the 'place value ofunderline number.89,206, 319450, 520, 515, 345, 123svampe39-90+9 place valuc ol 8-80

Answer»

Answer:

s.no digit expanded form place VALUE

01 89 80+9 8=80,9=9

02 206 200+0+6 2=200,0=00,6=6

03 319 300+10+9 3=300,1=10,9=9

04 450 400+50+0 4=400,5=50,0=0

05 520 500+20+0 5=500,2=20,0=0

06 515 500+10+5 5=500,1=10,5=5

06 345 300+40+5 3=300,4=40,5=5

07 123 100+20+3 1=100,2=20,3=3

Discussion

33.	A line seprates a plane in how many parts
Answer» Answer: Two SYMMETRICAL parts. Step-by-step EXPLANATION: A line separates a PLANE into TWO parts. Please mark as the BRAINLIEST.

33.

A line seprates a plane in how many parts

Answer»

Answer:

Two SYMMETRICAL parts.

Step-by-step EXPLANATION:

A line separates a PLANE into TWO parts.

Please mark as the BRAINLIEST.

Discussion

34.	3x minus y+7/11 plus 2 is equals to 10 and three x minus three y is equals to sixty five
Answer» Step-by-step explanation: 3x-y+7/11+2=10, LET this be equation 1 3x-3y=65, this be equation 2 we can simplify 1 into 33x-11y=81 and from this we CONSIDER 33x=81+11y X=81+11y/33 substitute this in equation 2 3×81+11y/33-3y=65 81+11y-33y/11=65 81-22y=715 -22y=715-81 -y=634/22 and plz simplify it yourself and PUT the final value of y in either of equations you get value of x. please mark the ANSWER brainliest.

34.

3x minus y+7/11 plus 2 is equals to 10 and three x minus three y is equals to sixty five

Answer»

Step-by-step explanation:

3x-y+7/11+2=10, LET this be equation 1

3x-3y=65, this be equation 2

we can simplify 1 into

33x-11y=81 and from this we CONSIDER

33x=81+11y

X=81+11y/33 substitute this in equation 2

3×81+11y/33-3y=65

81+11y-33y/11=65

81-22y=715

-22y=715-81

-y=634/22 and plz simplify it yourself and PUT the final value of y in either of equations you get value of x. please mark the ANSWER brainliest.

Discussion

35.	Sec theta into cos theta is equals to 1
Answer» As SEC THETA = 1/COS theta sec theta × cos theta 1/cos theta. × cos theta 1

35.

Sec theta into cos theta is equals to 1

Answer»

As SEC THETA = 1/COS theta

sec theta × cos theta

1/cos theta. × cos theta

1

Discussion

36.	If a-b=3and a2+b2 find the value of ab
Answer» (a-b) ^2 = a^2 + b^2 - 2ab 9 -( a^2 + b^2) = 2ab (9 -( a^2 + b^2))/2 = ab U FORGOT to write a^2 + b^2 value So just put above and u will get ab Mark brainliedt

36.

If a-b=3and a2+b2 find the value of ab

Answer»

(a-b) ^2 = a^2 + b^2 - 2ab

9 -( a^2 + b^2) = 2ab

(9 -( a^2 + b^2))/2 = ab

U FORGOT to write a^2 + b^2 value

So just put above

and u will get ab

Mark brainliedt

Discussion

37.	Find the surface area of hemisphere of radius 10.5
Answer» Hii..dude..♥️ The SURFACE AREA of HEMISPHERE is 3πr^2 . r = 10.5 cm 3 π r^2 => 3 × 3.14 × 10.5 × 10.5 => 3 × 3.14 × 110.25 => 3 × 346.185 => 1038.555

37.

Find the surface area of hemisphere of radius 10.5

Answer»

Hii..dude..♥️

The SURFACE AREA of HEMISPHERE is 3πr^2 .

r = 10.5 cm

3 π r^2

=> 3 × 3.14 × 10.5 × 10.5

=> 3 × 3.14 × 110.25

=> 3 × 346.185

=> 1038.555

Discussion

38.	What is the correct value of pie
Answer» ANSWER: Step-by-step EXPLANATION: hello dear, the correct VALUE of pie is 22/7 and in DECIMAL it is 3.14 thank you.......

38.

What is the correct value of pie

Answer»

ANSWER:

Step-by-step EXPLANATION:

hello dear,

the correct VALUE of pie is 22/7

and in DECIMAL it is 3.14

thank you.......

Discussion

39.	What's the value of 1 divided by 13?
Answer» HEYA there, the ANSWER will be 1/13 =0.07692

39.

What's the value of 1 divided by 13?

Answer»

HEYA there,

the ANSWER will be 1/13 =0.07692

Discussion

40.	Check whether the polynomial p(x)=4x3+4x2 -x-1 is a multiple of (2x+1).
Answer» Answer: Step-by-step explanation: Find the ZERO of 2x+1 2x+1=0 2x=-1 x=-1/2 P(-1/2) =4 × (-1/2)^3-+ 4 × (-1/2)^2 -(-1/2) -1 = 4 × -1/8 + 4 × 1/4 +1/2 -1 = -1/2 +1 +1/2 -1 =0 Since P(-1/2) =0, this implies that the remainder is zero.when P(x) is DIVIDED by 2x+1. Hence P(x) is a multiple of 2x+1 Pl mark as BRAINLIEST

40.

Check whether the polynomial p(x)=4x3+4x2 -x-1 is a multiple of (2x+1).

Answer»

Answer:

Step-by-step explanation:

Find the ZERO of 2x+1

2x+1=0

2x=-1

x=-1/2

P(-1/2) =4 × (-1/2)^3-+ 4 × (-1/2)^2 -(-1/2) -1

= 4 × -1/8 + 4 × 1/4 +1/2 -1

= -1/2 +1 +1/2 -1

=0

Since P(-1/2) =0, this implies that the remainder is zero.when P(x) is DIVIDED by 2x+1. Hence P(x) is a multiple of 2x+1

Pl mark as BRAINLIEST

Discussion

41.	96*x/7 (mod 5).find the least positive value of x
Answer» Answer: 96 ≡ x/7 (mod 5) we have to first IDENTIFY the remainder from the given equation. We can GET the remainder by dividing the given number with the mod VALUE. Hence, on dividing 96 by 5 we get 1 as the remainder. 1 = x/7. x=7. So, the least possible value of x will be 7.

41.

96*x/7 (mod 5).find the least positive value of x

Answer»

Answer:

96 ≡ x/7 (mod 5) we have to first IDENTIFY the remainder from the given equation.

We can GET the remainder by dividing the given number with the mod VALUE.

Hence, on dividing 96 by 5 we get 1 as the remainder.

1 = x/7.

x=7.

So, the least possible value of x will be 7.

Discussion

42.	Find the largest number divides by 1251,9377and 15628 leaving remaining 1,2 and 3 respectivly
Answer» ANSWER: first we will subtract ,1251-1=1250,. 9377-2=9375and 15628-3=15625. now we will find HCF of 1250,9375and 15625 that is 625. Therefore the required NUMBER is 625.

42.

Find the largest number divides by 1251,9377and 15628 leaving remaining 1,2 and 3 respectivly

Answer»

ANSWER:

first we will subtract ,1251-1=1250,. 9377-2=9375and 15628-3=15625. now we will find HCF of 1250,9375and 15625 that is 625. Therefore the required NUMBER is 625.

Discussion

43.	Fill in the greatest digit to make the number divisible by 3 53 _____ and 652 _____
Answer» Answer: FIRST one is 1 and SECOND one is 2

43.

Fill in the greatest digit to make the number divisible by 3 53 _ and 652 _

Answer»

Answer:

FIRST one is 1 and SECOND one is 2

Discussion

44.	Pls solve this qstn
Answer» let no's be x,x+1,..........x+43 as 44 consecutives no's are there average = 44x + (1+2......43))/44 1+2+3......43 = 43/2. ( 2 + 42) = 43 × 44/2 = 43 × 22 = 946 So 44x + (946) = 144× 44 44x + 946 = 6336 44x= 6336-946 = 5390 x= 5390/44 = 122.5 largest = x+43 = 122.5+43 = 165.5 So UR QUESTION Is wrong its some printed mistake average can't be 144 here as per option

44.

Pls solve this qstn

Answer»

let no's be x,x+1,..........x+43

as 44 consecutives no's are there

average = 44x + (1+2......43))/44

1+2+3......43 = 43/2. ( 2 + 42)

= 43 × 44/2 = 43 × 22 = 946

So 44x + (946) = 144× 44

44x + 946 = 6336

44x= 6336-946 = 5390

x= 5390/44 = 122.5

largest = x+43 = 122.5+43 = 165.5

So UR QUESTION Is wrong

its some printed mistake

average can't be 144 here as per option

Discussion

45.	Find the value of sin 20°sin40°sin80°
Answer» sin20 sin40 SIN80 sin40 = 2 sin20 cos20 2 sin20 sin20 cos20 sin80 2 cos20 sin80 sin^2 20 sin( 100) + sin60 ) sin^2 20 sin(90+10) + sin60) sin^2 20 cos10 + sin60) sin^2 20 cos10 sin20 + sin60 sin20) sin20 sin30 + SIN10 + cos40 - cos80)( sin20)/2 sin30 + sin10 + cos40 - cos(90-10) )( sin20)/2 sin30 + sin10 + cos40 - sin10) sin20))/2 sin30 + cos40)) sin20 )/2 1/2. + cos40))sin20))/2 (sin(20))/4 + sin20 cos40))/2 (sin(20))/4. +(( sin(60) - sin20))/4 sin20 + sin60 - sin20))/4 sin60))/4 √3/8

45.

Find the value of sin 20°sin40°sin80°

Answer»

sin20 sin40 SIN80

sin40 = 2 sin20 cos20

2 sin20 sin20 cos20 sin80

2 cos20 sin80 sin^2 20

sin( 100) + sin60 ) sin^2 20

sin(90+10) + sin60) sin^2 20

cos10 + sin60) sin^2 20

cos10 sin20 + sin60 sin20) sin20

sin30 + SIN10 + cos40 - cos80)( sin20)/2

sin30 + sin10 + cos40 - cos(90-10) )( sin20)/2

sin30 + sin10 + cos40 - sin10) sin20))/2

sin30 + cos40)) sin20 )/2

1/2. + cos40))sin20))/2

(sin(20))/4 + sin20 cos40))/2

(sin(20))/4. +(( sin(60) - sin20))/4

sin20 + sin60 - sin20))/4

sin60))/4

√3/8

Discussion

46.	A large wooden raft is flowing with a river stream.A man on the raft dives into river and swims downthe stream for 15 minutes and then he turns aboutand comes back to the raft. The swimming speedof man is 5 km/h in still water and the river isflowing with speed 4 km/h. The distance moved bythe raft till the man comes back to raft is(2) 2 km(1) 1 km(4) 4 km(3) 3 km
Answer» Answer: 1 km Step-by-step explanation: Given, Speed of the stream/raft = 4 km/h and speed of the man in still water = 5 km/h Speed of the man downstream = 5 + 4 = 9 km/h speed of the man upstream = 5 - 4 = 1 km/h in 15 mins the raft moves = 1 km in 15 mins the man moves 5 km in 60 mins then 1.25 kms upstream = 1km/hr so 15 mins 0.25 kms hence the distance MOVED by the raft till man comes back is 1 km

46.

A large wooden raft is flowing with a river stream.A man on the raft dives into river and swims downthe stream for 15 minutes and then he turns aboutand comes back to the raft. The swimming speedof man is 5 km/h in still water and the river isflowing with speed 4 km/h. The distance moved bythe raft till the man comes back to raft is(2) 2 km(1) 1 km(4) 4 km(3) 3 km

Answer»

Answer:

1 km

Step-by-step explanation:

Given,

Speed of the stream/raft = 4 km/h

and speed of the man in still water = 5 km/h

Speed of the man downstream = 5 + 4 = 9 km/h

speed of the man upstream = 5 - 4 = 1 km/h

in 15 mins the raft moves = 1 km

in 15 mins the man moves

5 km in 60 mins then 1.25 kms

upstream = 1km/hr

so 15 mins 0.25 kms

hence the distance MOVED by the raft till man comes back is 1 km

Discussion

47.	1)2/x+3/y= 70, 2)3/x+7/y=80, 3)3/2x-y= 3, 4) 15/2x+y+9/7x-y
Answer» Step-by-step EXPLANATION: The QUESTION is not MENTIONED CLEARLY what to FIND

47.

1)2/x+3/y= 70, 2)3/x+7/y=80, 3)3/2x-y= 3, 4) 15/2x+y+9/7x-y

Answer»

Step-by-step EXPLANATION:

The QUESTION is not MENTIONED CLEARLY what to FIND

Discussion

48.	If sin theta is equal to 3 upon 5 evaluate cosec theta minus cos theta upon 2 cos theta
Answer» Answer: if SIN a=3/5 then cosec a= 5/3 and cos a=4/5 =cosec a - cos a/2cos a =(5/3-4/5)/(24/5) =(13/15)/(8/5) =(13/3)(1/8) =13/24 note that I have TAKEN theta as a

48.

If sin theta is equal to 3 upon 5 evaluate cosec theta minus cos theta upon 2 cos theta

Answer»

Answer:

if SIN a=3/5 then

cosec a= 5/3 and cos a=4/5

=cosec a - cos a/2cos a

=(5/3-4/5)/(2*4/5)

=(13/15)/(8/5)

=(13/3)*(1/8)

=13/24

note that I have TAKEN theta as a

Discussion

49.	(xii)
Answer» 3 ROOT 3+2 root 27 +1 /root 3 3 root 3+6 root 3+1/root3 9 root 3+1/root 3 27+1/root3 28/root 3

49.

(xii)

Answer»

3 ROOT 3+2 root 27 +1 /root 3

3 root 3+6 root 3+1/root3

9 root 3+1/root 3

27+1/root3

28/root 3

Discussion

50.	the denominator of a rational number is greater than its numerator by 14.if the numerator and denominator are both increased by 5 the new number obtained is 11/18 find the original rational number
Answer» Step-by-step EXPLANATION: Lets take the numerator as x then denominator will BECOME (x+14) . If the numerator and denominator is increased by 5 then the NEW number is 11/18 the original rational number. New number is (x+5)/(x+19). $\frac{(x + 5)}{(x + 19)} = \frac{11}{18} \frac{x}{(x + 14)} = >$ $18(x + 14)(x + 5)= 11x(x + 19)= >$ $18( {x}^{2} + 14x + 5x + 70) = 11 {x}^{2} +$ $209x = > 18 {x}^{2} + 342x + 1260 =$ $11 {x}^{2} + 209x = > 18 {x}^{2} - 11 {x}^{2} +$ $342x - 209x + 1260 = 0 = > 7{x}^{2} +$ $133x + 1260 = 0 = > {x}^{2} + 19x +$ $180 = 0$ Determinant is NEGATIVE so no value of x can SATISFY the above conditions so it is not possible. Hope it helps you.

50.

the denominator of a rational number is greater than its numerator by 14.if the numerator and denominator are both increased by 5 the new number obtained is 11/18 find the original rational number

Answer»

Step-by-step EXPLANATION:

Lets take the numerator as x then denominator will BECOME (x+14) .

If the numerator and denominator is increased by 5 then the NEW number is 11/18 the original rational number. New number is (x+5)/(x+19).

$\frac{(x + 5)}{(x + 19)} = \frac{11}{18} \frac{x}{(x + 14)} = >$

$18(x + 14)(x + 5)= 11x(x + 19)= >$

$18( {x}^{2} + 14x + 5x + 70) = 11 {x}^{2} +$

$209x = > 18 {x}^{2} + 342x + 1260 =$

$11 {x}^{2} + 209x = > 18 {x}^{2} - 11 {x}^{2} +$

$342x - 209x + 1260 = 0 = > 7{x}^{2} +$

$133x + 1260 = 0 = > {x}^{2} + 19x +$

$180 = 0$

Determinant is NEGATIVE so no value of x can SATISFY the above conditions so it is not possible. Hope it helps you.

Discussion

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