332354 + Interview Questions in Secondary School in Math

1.	If we add 1 to the numerator and subtract one from the denominator, of a fraction reduces to one. it becomes half if we add 1 to the denominator what is the fraction?plz guys want quick answers
Answer» ANSWER: N+1/1-d fraction is ((n+1)/(1-d))-1 3.fraction is ((n+1)/(1-d))-1=(1/2)+(n/(1+d)) Step-by-step EXPLANATION:

1.

If we add 1 to the numerator and subtract one from the denominator, of a fraction reduces to one. it becomes half if we add 1 to the denominator what is the fraction?plz guys want quick answers

Answer»

ANSWER:

N+1/1-d
fraction is ((n+1)/(1-d))-1

3.fraction is ((n+1)/(1-d))-1=(1/2)+(n/(1+d))

Step-by-step EXPLANATION:

Discussion

2.	21) * Priyanka applied to 3 colleges in the US for a scholarship. Her chances of getting a scholarship in MIT are1/8, in CalTech are 1/6 and in Michigan are 1/5. What is the probability thata) she will get a scholarshipb) she will get a scholarship from MIT and CarTech but not Michigan?d she will get a scholarship from exactly 2 collegesd) she will get a scholarship from at most 2 colliges?
Answer» ANSWER: B is the CORRECT answer

2.

21) * Priyanka applied to 3 colleges in the US for a scholarship. Her chances of getting a scholarship in MIT are1/8, in CalTech are 1/6 and in Michigan are 1/5. What is the probability thata) she will get a scholarshipb) she will get a scholarship from MIT and CarTech but not Michigan?d she will get a scholarship from exactly 2 collegesd) she will get a scholarship from at most 2 colliges?

Answer»

ANSWER:

B is the CORRECT answer

Discussion

3.	Verify the property(-3)^m+1×(-3)^5=(-3)^7
Answer» Step-by-step EXPLANATION: -3^m +1=(-3)^2 -3^m+1=9 -3^m=8

3.

Verify the property(-3)^m+1×(-3)^5=(-3)^7

Answer»

Step-by-step EXPLANATION:

-3^m +1=(-3)^2

-3^m+1=9

-3^m=8

Discussion

4.	The ratio of income of two person is 9: 7 and the ratio of their expenditure is 4 : 3 if each of them manage to save RS 2000 per month find their monthly income
Answer» HEY MATE, PLZ mark me as BRAINILEST ANSWER

4.

The ratio of income of two person is 9: 7 and the ratio of their expenditure is 4 : 3 if each of them manage to save RS 2000 per month find their monthly income

Answer»

HEY MATE, PLZ mark me as BRAINILEST ANSWER

Discussion

5.	Iffind
Answer» x^2 - 4x +1 = 0 x^2 +1)^2 = 16 x^2 x^4 +1 + 2x^2 = 16 x^2 x^4 +1 = 14x^2 So x^2 + 1/x^2 x^4 +1)/x^2 14 x^2/x^2 14 brainliest pls

5.

Iffind

Answer»

x^2 - 4x +1 = 0

x^2 +1)^2 = 16 x^2

x^4 +1 + 2x^2 = 16 x^2

x^4 +1 = 14x^2

So

x^2 + 1/x^2

x^4 +1)/x^2

14 x^2/x^2

14

brainliest pls

Discussion

6.	The function f(X) = √25-9x2
Answer» √(25-9x^2) √(5^2 - (3X)^2 ) √( 5 + 3x)( 5 - 3x) if QUESTION is ROOTS then its x= -5/3 , 5/3

6.

The function f(X) = √25-9x2

Answer»

√(25-9x^2)

√(5^2 - (3X)^2 )

√( 5 + 3x)( 5 - 3x)

if QUESTION is ROOTS

then its x= -5/3 , 5/3

Discussion

7.	What should be added to -7/3 to get 3/7
Answer» ANSWER: $\dfrac{-7}{3}+x=\dfrac{3}{7}\quad :\quad x=\dfrac{58}{21}\quad \left(\mathrm{Decimal}:\quad x=2.76190\dots \right)$ Step-by-step EXPLANATION: $\textrm{Let the number to be found be } x \textrm{.}$ $\textrm{So, our equation will be;}$ $\dfrac{-7}{3}+x=\dfrac{3}{7}$ $\gray{\mathrm{Subtract\:}\dfrac{-7}{3}\mathrm{\:from\:both\:sides}}$ $\dfrac{-7}{3}+x-\dfrac{-7}{3}=\dfrac{3}{7}-\dfrac{-7}{3}$ $\gray{\mathrm{Simplify}}$ $\dfrac{-7}{3}+x-\dfrac{-7}{3}=\dfrac{3}{7}-\dfrac{-7}{3}$ $\mathrm{Simplify\:}\dfrac{-7}{3}+x-\dfrac{-7}{3}:\quad x$ $\dfrac{-7}{3}+x-\dfrac{-7}{3}$ $\gray{\mathrm{Add\:similar\:elements:}\:\dfrac{-7}{3}-\dfrac{-7}{3}=0}$ $=x$ $\mathrm{Simplify\:}\dfrac{3}{7}-\dfrac{-7}{3}$ $\dfrac{3}{7}-\dfrac{-7}{3}$ $\gray{\mathrm{Apply\:the\:fraction\:rule}:\quad \dfrac{-a}{b}=-\dfrac{a}{b}}$ $=\dfrac{3}{7}-\left(-\dfrac{7}{3}\right)$ $\gray{\mathrm{Apply\:rule}\:-\left(-a\right)=a}$ $=\dfrac{3}{7}+\dfrac{7}{3}$ $\mathrm{Least\:Common\:Multiplier\:of\:}7,\:3:\quad 21$ $=\dfrac{9}{21}+\dfrac{49}{21}$ $\gray{\mathrm{Since\:the\:denominators\:are\:equal,\:combine\:the\:fractions}:\quad \dfrac{a}{c}\pm \dfrac{b}{c}=\dfrac{a\pm \:b}{c}}$ $=\dfrac{9+49}{21}$ $\gray{\mathrm{Add\:the\:numbers:}\:9+49=58}$ $=\dfrac{58}{21}$ $x=\dfrac{58}{21}$

7.

What should be added to -7/3 to get 3/7

Answer»

ANSWER:

$\dfrac{-7}{3}+x=\dfrac{3}{7}\quad :\quad x=\dfrac{58}{21}\quad \left(\mathrm{Decimal}:\quad x=2.76190\dots \right)$

Step-by-step EXPLANATION:

$\textrm{Let the number to be found be } x \textrm{.}$

$\textrm{So, our equation will be;}$

$\dfrac{-7}{3}+x=\dfrac{3}{7}$

$\gray{\mathrm{Subtract\:}\dfrac{-7}{3}\mathrm{\:from\:both\:sides}}$

$\dfrac{-7}{3}+x-\dfrac{-7}{3}=\dfrac{3}{7}-\dfrac{-7}{3}$

$\gray{\mathrm{Simplify}}$

$\dfrac{-7}{3}+x-\dfrac{-7}{3}=\dfrac{3}{7}-\dfrac{-7}{3}$

$\mathrm{Simplify\:}\dfrac{-7}{3}+x-\dfrac{-7}{3}:\quad x$

$\dfrac{-7}{3}+x-\dfrac{-7}{3}$

$\gray{\mathrm{Add\:similar\:elements:}\:\dfrac{-7}{3}-\dfrac{-7}{3}=0}$

$=x$

$\mathrm{Simplify\:}\dfrac{3}{7}-\dfrac{-7}{3}$

$\dfrac{3}{7}-\dfrac{-7}{3}$

$\gray{\mathrm{Apply\:the\:fraction\:rule}:\quad \dfrac{-a}{b}=-\dfrac{a}{b}}$

$=\dfrac{3}{7}-\left(-\dfrac{7}{3}\right)$

$\gray{\mathrm{Apply\:rule}\:-\left(-a\right)=a}$

$=\dfrac{3}{7}+\dfrac{7}{3}$

$\mathrm{Least\:Common\:Multiplier\:of\:}7,\:3:\quad 21$

$=\dfrac{9}{21}+\dfrac{49}{21}$

$\gray{\mathrm{Since\:the\:denominators\:are\:equal,\:combine\:the\:fractions}:\quad \dfrac{a}{c}\pm \dfrac{b}{c}=\dfrac{a\pm \:b}{c}}$

$=\dfrac{9+49}{21}$

$\gray{\mathrm{Add\:the\:numbers:}\:9+49=58}$

$=\dfrac{58}{21}$

$x=\dfrac{58}{21}$

Discussion

8.	Solve 156 by 44 multiply by 7 by 4
Answer» ANSWER: $\dfrac{156}{44}\times \dfrac{7}{4}=\dfrac{273}{44}\quad \left(\mathrm{Decimal:\quad }\:6.20455\dots \right)$ Step-by-step EXPLANATION: $\dfrac{156}{44}\times \dfrac{7}{4}$ $\gray{\mathrm{Cross-cancel\:common\:factor:}\:4}$ $=\dfrac{39}{44}\times \dfrac{7}{1}$ $\gray{\mathrm{Multiply\:fractions}:\quad \dfrac{a}{b}\times \dfrac{c}{d}=\dfrac{a\:\times \:c}{b\:\times \:d}}$ $=\dfrac{39\times \:7}{44\times \:1}$ $\gray{\mathrm{Multiply\:the\:numbers:}\:39\times \:7=273}$ $=\dfrac{273}{44\times \:1}$ $\gray{\mathrm{Multiply\:the\:numbers:}\:44\times \:1=44}$ $=\dfrac{273}{44}$

8.

Solve 156 by 44 multiply by 7 by 4

Answer»

ANSWER:

$\dfrac{156}{44}\times \dfrac{7}{4}=\dfrac{273}{44}\quad \left(\mathrm{Decimal:\quad }\:6.20455\dots \right)$

Step-by-step EXPLANATION:

$\dfrac{156}{44}\times \dfrac{7}{4}$

$\gray{\mathrm{Cross-cancel\:common\:factor:}\:4}$

$=\dfrac{39}{44}\times \dfrac{7}{1}$

$\gray{\mathrm{Multiply\:fractions}:\quad \dfrac{a}{b}\times \dfrac{c}{d}=\dfrac{a\:\times \:c}{b\:\times \:d}}$

$=\dfrac{39\times \:7}{44\times \:1}$

$\gray{\mathrm{Multiply\:the\:numbers:}\:39\times \:7=273}$

$=\dfrac{273}{44\times \:1}$

$\gray{\mathrm{Multiply\:the\:numbers:}\:44\times \:1=44}$

$=\dfrac{273}{44}$

Discussion

9.	12 subtract from twice a no. Gives 3
Answer» Answer: 2x-12=3 2x=15 x=15÷2=7.5

9.

12 subtract from twice a no. Gives 3

Answer»

Answer:

2x-12=3

2x=15

x=15÷2=7.5

Discussion

10.	Hcf of 27,36,25,75,12,16,24,25,50,100,72
Answer» ANSWER: the answer GOES to in HCF

10.

Hcf of 27,36,25,75,12,16,24,25,50,100,72

Answer»

ANSWER:

the answer GOES to in HCF

Discussion

11.	2 ka power 2x+2 = 4 ka power 2x-1 find value of x
Answer» ANSWER: $2^{2x+2}=4^{2x-1}\quad :\quad x=2$ Step-by-step EXPLANATION: $2^{2x+2}=4^{2x-1}$ $\gray{\mathrm{Convert\:}4^{2x-1}\mathrm{\:to\:base\:}2}$ $\gray{4^{2x-1}=\left(2^2\right)^{2x-1}}$ $2^{2x+2}=\left(2^2\right)^{2x-1}$ $\gray{\mathrm{Apply\:exponent\:rule}:\quad \left(a^b\right)^c=a^{bc}}$ $\gray{\left(2^2\right)^{2x-1}=2^{2\left(2x-1\right)}}$ $2^{2x+2}=2^{2\left(2x-1\right)}$ $\gray{\mathrm{If\:}a^{f\left(x\right)}=a^{g\left(x\right)}\mathrm{,\:then\:}f\left(x\right)=g\left(x\right)}$ $2x+2=2\left(2x-1\right)$ $\black{\mathrm{Solve\:}\:2x+2=2\left(2x-1\right)}$ $2x+2=2\left(2x-1\right)$ $\gray{\mathrm{Expand\:}2\left(2x-1\right):\quad 4x-2}$ $2x+2=4x-2$ $\gray{\mathrm{Subtract\:}2\mathrm{\:from\:both\:sides}}$ $2x+2-2=4x-2-2$ $\gray{\mathrm{Simplify}}$ $2x=4x-4$ $\gray{\mathrm{Subtract\:}4x\mathrm{\:from\:both\:sides}}$ $2x-4x=4x-4-4x$ $\gray{\mathrm{Simplify}}$ $-2x=-4$ $\gray{\mathrm{Divide\:both\:sides\:by\:}-2}$ $\dfrac{-2x}{-2}=\dfrac{-4}{-2}$ $\gray{\mathrm{Simplify}}$ $x=2$

11.

2 ka power 2x+2 = 4 ka power 2x-1 find value of x

Answer»

ANSWER:

$2^{2x+2}=4^{2x-1}\quad :\quad x=2$

Step-by-step EXPLANATION:

$2^{2x+2}=4^{2x-1}$

$\gray{\mathrm{Convert\:}4^{2x-1}\mathrm{\:to\:base\:}2}$

$\gray{4^{2x-1}=\left(2^2\right)^{2x-1}}$

$2^{2x+2}=\left(2^2\right)^{2x-1}$

$\gray{\mathrm{Apply\:exponent\:rule}:\quad \left(a^b\right)^c=a^{bc}}$

$\gray{\left(2^2\right)^{2x-1}=2^{2\left(2x-1\right)}}$

$2^{2x+2}=2^{2\left(2x-1\right)}$

$\gray{\mathrm{If\:}a^{f\left(x\right)}=a^{g\left(x\right)}\mathrm{,\:then\:}f\left(x\right)=g\left(x\right)}$

$2x+2=2\left(2x-1\right)$

$\black{\mathrm{Solve\:}\:2x+2=2\left(2x-1\right)}$

$2x+2=2\left(2x-1\right)$

$\gray{\mathrm{Expand\:}2\left(2x-1\right):\quad 4x-2}$

$2x+2=4x-2$

$\gray{\mathrm{Subtract\:}2\mathrm{\:from\:both\:sides}}$

$2x+2-2=4x-2-2$

$\gray{\mathrm{Simplify}}$

$2x=4x-4$

$\gray{\mathrm{Subtract\:}4x\mathrm{\:from\:both\:sides}}$

$2x-4x=4x-4-4x$

$\gray{\mathrm{Simplify}}$

$-2x=-4$

$\gray{\mathrm{Divide\:both\:sides\:by\:}-2}$

$\dfrac{-2x}{-2}=\dfrac{-4}{-2}$

$\gray{\mathrm{Simplify}}$

$x=2$

Discussion

12.	LCM of 999 and 1000 LCM
Answer» Answer: To get the Least Common MULTIPLE (LCM) of 999 and 1000 we need to factor each value FIRST and then we CHOOSE all the factors which appear in any column and multiply them: The Least Common Multiple (LCM) is: 2 X 2 x 2 x 3 x 3 x 3 x 5 x 5 x 5 x 37 = 999000 .....HOPE it will be helpful

12.

LCM of 999 and 1000 LCM

Answer»

Answer:

To get the Least Common MULTIPLE (LCM) of 999 and 1000 we need to factor each value FIRST and then we CHOOSE all the factors which appear in any column and multiply them:

The Least Common Multiple (LCM) is: 2 X 2 x 2 x 3 x 3 x 3 x 5 x 5 x 5 x 37 = 999000

.....HOPE it will be helpful

Discussion

13.	2+2-3+6÷22×67÷4-7+314×888-465×4+2=?
Answer» Step-by-step explanation: 2+2-3+6/22×67/4-7+314×888-465×4+2 (2+2-3=1 6/22×67/4=4.568 314×888=278832 465×4=1860. ) 1+4.568-7+278832-1860+2=276972.568

13.

2+2-3+6÷22×67÷4-7+314×888-465×4+2=?

Answer»

Step-by-step explanation:

2+2-3+6/22×67/4-7+314×888-465×4+2

(2+2-3=1

6/22×67/4=4.568

314×888=278832

465×4=1860. )

1+4.568-7+278832-1860+2=276972.568

Discussion

14.	You need to return a product you purchased 3 days ago. The total cost of the item was $50.00. The store charges a 25% restocking fee. How much money will you get once the restocking fee is paid?
Answer» Step-by-step EXPLANATION: $50×75/100 =$75/2=37.5$

14.

You need to return a product you purchased 3 days ago. The total cost of the item was $50.00. The store charges a 25% restocking fee. How much money will you get once the restocking fee is paid?

Answer»

Step-by-step EXPLANATION:

$50×75/100

=$75/2=37.5$

Discussion

15.	If tan theta = cot theta then value of( tan theta + cot theta)square is
Answer» Step-by-step EXPLANATION: $Given: \: tan \theta \: = cot \theta \\ therefore \\ {(tan \theta \: + cot \theta )}^{2} \\ = {(tan \theta \: + tan \theta )}^{2} \\ = {(2tan \theta )}^{2} \\ = 4 {tan}^{2} \theta$

15.

If tan theta = cot theta then value of( tan theta + cot theta)square is

Answer»

Step-by-step EXPLANATION:

$Given: \: tan \theta \: = cot \theta \\ therefore \\ {(tan \theta \: + cot \theta )}^{2} \\ = {(tan \theta \: + tan \theta )}^{2} \\ = {(2tan \theta )}^{2} \\ = 4 {tan}^{2} \theta$

Discussion

16.	A = 9+4√5 & b= 1/a, then find the value of a2+b2
Answer» IDENTITIES used: (a + B)² = a² + b² + 2ab (a - b)² = a² + b² - 2ab (a + b)(a - b) = a² - b² Answer: 322 Step-by-step explanation: Given, a = 9 + 4√5 $b = \frac{1}{a} \\ \\ \bf \: So, \\ \\ b = \frac{1}{9 + 4 \sqrt{5} } \\$ Rationalizing the denominator we get: $b = \frac{1}{9 + 4 \sqrt{5} } \times \frac{9 - 4 \sqrt{5} }{9 - 4 \sqrt{5} } \\ \\ b = \frac{9 - 4 \sqrt{5} }{ {(9)}^{2} - {(4 \sqrt{5} )}^{2} } \\ \\ b = \frac{9 - 4 \sqrt{5} }{81 - 80} \\ \\ \bf b = 9 - 4 \sqrt{5}$ FINDING the VALUE of a² + b²: ${a}^{2} + {b}^{2} \\ \\ = {(9 + 4 \sqrt{5} )}^{2} + {(9 - 4 \sqrt{5}) }^{2} \\ \\ = ( {(9)}^{2} + {(4 \sqrt{5} )}^{2} + 2.9.4 \sqrt{5} ) \\ + ( {(9)}^{2} + {(4 \sqrt{5}) }^{2} - 2.9.4 \sqrt{5} ) \\ \\ = (81 + 80 + 72 \sqrt{5} ) \\ + (81 + 80 - 72 \sqrt{5} ) \\ \\ = 161 + 72 \sqrt{5} + 161 - 72 \sqrt{5} \\ \\ \bf = 322$

16.

A = 9+4√5 & b= 1/a, then find the value of a2+b2

Answer»

IDENTITIES used:

(a + B)² = a² + b² + 2ab

(a - b)² = a² + b² - 2ab

(a + b)(a - b) = a² - b²

Answer:

322

Step-by-step explanation:

Given,

a = 9 + 4√5

$b = \frac{1}{a} \\ \\ \bf \: So, \\ \\ b = \frac{1}{9 + 4 \sqrt{5} } \\$

Rationalizing the denominator we get:

$b = \frac{1}{9 + 4 \sqrt{5} } \times \frac{9 - 4 \sqrt{5} }{9 - 4 \sqrt{5} } \\ \\ b = \frac{9 - 4 \sqrt{5} }{ {(9)}^{2} - {(4 \sqrt{5} )}^{2} } \\ \\ b = \frac{9 - 4 \sqrt{5} }{81 - 80} \\ \\ \bf b = 9 - 4 \sqrt{5}$

FINDING the VALUE of a² + b²:

${a}^{2} + {b}^{2} \\ \\ = {(9 + 4 \sqrt{5} )}^{2} + {(9 - 4 \sqrt{5}) }^{2} \\ \\ = ( {(9)}^{2} + {(4 \sqrt{5} )}^{2} + 2.9.4 \sqrt{5} ) \\ + ( {(9)}^{2} + {(4 \sqrt{5}) }^{2} - 2.9.4 \sqrt{5} ) \\ \\ = (81 + 80 + 72 \sqrt{5} ) \\ + (81 + 80 - 72 \sqrt{5} ) \\ \\ = 161 + 72 \sqrt{5} + 161 - 72 \sqrt{5} \\ \\ \bf = 322$

Discussion

17.	Log 1 to the base 2
Answer» the answer of the EXPRESSION will always be zero since it has 1 as the INPUT ... HOPE it HELPS you...

17.

Log 1 to the base 2

Answer»

the answer of the EXPRESSION will always be zero since it has 1 as the INPUT ...

HOPE it HELPS you...

Discussion

18.	What is addition deffination
Answer» ADDITION simply MEANS adding two terms (CONSTANT)

18.

What is addition deffination

Answer»

ADDITION simply MEANS adding two terms (CONSTANT)

Discussion

19.	Help me please............
Answer» <P>ANSWER: Step-by-step explanation: 4 P (x)=-ax^3-x^2+x+4 P (-1)=-a (-1)^3-(-1)^2+(-1)+4 =-a×-1-1-1+4 =a-2+4 =a+2 P (x)=0 a+2=0 a=-2 5. P (x)=27x^3-ax^2-x+3 P (-1/3)=27 ×(-1/3)^3-a×(-1/3)^2-(-1/3)+3 =27×-1/27-a×1/9+1/3+3 =-1-a/9+10/9 =(-9-a+10)/9 =1-a/9 P (x)=0 (1-a)/9=0 1-a=0 a=1

19.

Help me please............

Answer»

<P>ANSWER:

Step-by-step explanation:

4 P (x)=-ax^3-x^2+x+4

P (-1)=-a (-1)^3-(-1)^2+(-1)+4

=-a×-1-1-1+4

=a-2+4

=a+2

P (x)=0

a+2=0

a=-2

5. P (x)=27x^3-ax^2-x+3

P (-1/3)=27 ×(-1/3)^3-a×(-1/3)^2-(-1/3)+3

=27×-1/27-a×1/9+1/3+3

=-1-a/9+10/9

=(-9-a+10)/9

=1-a/9

P (x)=0

(1-a)/9=0

1-a=0

a=1

Discussion

20.	Verify the property2/2+15=4/9
Answer» Answer: 16≠4/9 Step-by-step explanation: 2/2+15 = 4/9 2+30/2 = 4/9 32/2 = 4/9 16 ≠ 4/9

20.

Verify the property2/2+15=4/9

Answer»

Answer:

16≠4/9

Step-by-step explanation:

2/2+15 = 4/9

2+30/2 = 4/9

32/2 = 4/9

16 ≠ 4/9

Discussion

21.	in a gruop of 52 persons, 16 drink tea but not coffee and 33 drink tea. find how many drink coffee but not tea.
Answer» Answer: 3 PEOPLE drink coffee but not tea Step-by-step explanation: HOPE it HELPS you BUDDY

21.

in a gruop of 52 persons, 16 drink tea but not coffee and 33 drink tea. find how many drink coffee but not tea.

Answer»

Answer:

3 PEOPLE drink coffee but not tea

Step-by-step explanation:

HOPE it HELPS you BUDDY

Discussion

22.	Please solve this que please provide solution of this question
Answer» Step-by-step explanation: LAST QUESTION is INCOMPLETE mail it on [email protected]

22.

Please solve this que please provide solution of this question

Answer»

Step-by-step explanation:

LAST QUESTION is INCOMPLETE mail it on [email protected]

Discussion

23.	Triangle abc is similar to triangle pqr and ar(abc)/ar(pqr)=196/361 then ab/ pq is
Answer» Step-by-step EXPLANATION: $Given: \triangle ABC \: similar \: \: \triangle PQR \: \\ hence, by \: area \: of \\ similar \: triangle \: theorem, \: we\: have: \: \\ \frac{A(\triangle ABC)}{A(\triangle PQR)} = ( { \frac{AB}{PQ} })^{2} \: \\ \implies \: \frac{196}{361} = ( { \frac{AB}{PQ} })^{2} \\ \implies \: \sqrt{ \frac{196}{361} } = { \frac{AB}{PQ} } \\ \implies { \frac{AB}{PQ} } = \frac{14}{19}$

23.

Triangle abc is similar to triangle pqr and ar(abc)/ar(pqr)=196/361 then ab/ pq is

Answer»

Step-by-step EXPLANATION:

$Given: \triangle ABC \: similar \: \: \triangle PQR \: \\ hence, by \: area \: of \\ similar \: triangle \: theorem, \: we\: have: \: \\ \frac{A(\triangle ABC)}{A(\triangle PQR)} = ( { \frac{AB}{PQ} })^{2} \: \\ \implies \: \frac{196}{361} = ( { \frac{AB}{PQ} })^{2} \\ \implies \: \sqrt{ \frac{196}{361} } = { \frac{AB}{PQ} } \\ \implies { \frac{AB}{PQ} } = \frac{14}{19}$

Discussion

24.	[\|x\|] =4 then interval of X is
Answer» Step-by-step explanation: If the square bracket is REPRESENTING greatest INTEGER FUNCTION then the interval of X WOULD be [4,5) and if square bracket is just a bracket then the X will lie in interval {-4, 4} where curly bracket represents single element.

24.

[|x|] =4 then interval of X is

Answer»

Step-by-step explanation:

If the square bracket is REPRESENTING greatest INTEGER FUNCTION then the interval of X WOULD be

[4,5)

and if square bracket is just a bracket then the X will lie in interval

{-4, 4} where curly bracket represents single element.

Discussion

25.	Q4. Divide the sum of 3 upon 11and 2upon5 by their product.
Answer» ANSWER: 6/37 Step-by-step explanation: 3/11 + 2/5 = 37/55 3/11 * 2/5 = 6/55 6/55 ÷ 37/55 = 6/37 Answer

25.

Q4. Divide the sum of 3 upon 11and 2upon5 by their product.

Answer»

ANSWER:

6/37

Step-by-step explanation:

3/11 + 2/5 = 37/55

3/11 * 2/5 = 6/55

6/55 ÷ 37/55 = 6/37 Answer

Discussion

26.	1/2=X/4 then X =. (rule of cross multiplication
Answer» Answer: 2 Step-by-step explanation: 1/2=x/4 cross multiplying 2x=4 X=2

26.

1/2=X/4 then X =. (rule of cross multiplication

Answer»

Answer:

2

Step-by-step explanation:

1/2=x/4

cross multiplying

2x=4

X=2

Discussion

27.	Two numbers are in the ratio 3:4. If 4 is added toeach of the numbers, the ratio becomes 4:5. Findthe product of numbers.
Answer» Step-by-step explanation: 3x+4/4x+4=4/5 5(3x+4)=4(4x+4) 15x+20=16x+16 16x-15x=20-16 x=4 The PRODUCT of TWO NUMBERS = 3x×4x =3×4×4×4=192

27.

Two numbers are in the ratio 3:4. If 4 is added toeach of the numbers, the ratio becomes 4:5. Findthe product of numbers.

Answer»

Step-by-step explanation:

3x+4/4x+4=4/5

5(3x+4)=4(4x+4)

15x+20=16x+16

16x-15x=20-16

x=4

The PRODUCT of TWO NUMBERS = 3x×4x

=3×4×4×4=192

Discussion

28.	The sum of 2 consecutive multiples of 3 is 69. find the numbers
Answer» Step-by-step EXPLANATION: NUMBERS are 33 and 3 .........

28.

The sum of 2 consecutive multiples of 3 is 69. find the numbers

Answer»

Step-by-step EXPLANATION:

NUMBERS are 33 and 3 .........

Discussion

29.	Find the value of 'a' so that the point(3,9) lies on the line represented by 2ax-3y=5
Answer» ANSWER: I HOPE it WOULD HELP you

29.

Find the value of 'a' so that the point(3,9) lies on the line represented by 2ax-3y=5

Answer»

ANSWER:

I HOPE it WOULD HELP you

Discussion

30.	Peove that:1+sin2A=(cos A+sin A)^2pls guys do itt..❤️❤️ you will get 15 points
Answer» Answer: 1+sin2a = 1+ 2sinAcosA expanding RHS you GET 1+2cosAsinA Hence proved I don't want 15 points I want you ahhhaa sorry

30.

Peove that:1+sin2A=(cos A+sin A)^2pls guys do itt..❤️❤️ you will get 15 points

Answer»

Answer:

1+sin2a = 1+ 2sinAcosA

expanding RHS you GET

1+2cosAsinA

Hence proved

I don't want 15 points

I want you ahhhaa

sorry

Discussion

31.	Thrice a number when increased by 5give 44.Find the number.?
Answer» Answer: 3x+5=44 Step-by-step explanation: 3x=44-5 x=39÷3=13

31.

Thrice a number when increased by 5give 44.Find the number.?

Answer»

Answer:

3x+5=44

Step-by-step explanation:

3x=44-5

x=39÷3=13

Discussion

32.	A current of 1A flows through a copper wire.Number of electrons will pass a given in each second are?NEED SUPER FAST ANSWER PLS
Answer» Answer: i THINK it HELP u Step-by-step EXPLANATION: plzz MARK as BRAINLIST

32.

A current of 1A flows through a copper wire.Number of electrons will pass a given in each second are?NEED SUPER FAST ANSWER PLS

Answer»

Answer:

i THINK it HELP u

Step-by-step EXPLANATION:

plzz MARK as BRAINLIST

Discussion

33.	Distance between moon and sun in standard form
Answer» ANSWER: The DISTANCE b/w MOON & Sun RANGES between 1.47×10^8 KM to 1.52×10^8 km. *Answer*

33.

Distance between moon and sun in standard form

Answer»

ANSWER:

The DISTANCE b/w MOON & Sun RANGES between 1.47×10^8 KM to 1.52×10^8 km. Answer

Discussion

34.	LCM of two number 160and 352 is 1760 find HCF?
Answer» ANSWER: Step-by-step EXPLANATION: Lcm×hcf= product of 2 no. S 1760hcf=160352 Hcf=(160*352)/1760 Hcf=32 Mark as brainliest if it HELPS

34.

LCM of two number 160and 352 is 1760 find HCF?

Answer»

ANSWER:

Step-by-step EXPLANATION:

Lcm×hcf= product of 2 no. S

1760*hcf=160*352

Hcf=(160*352)/1760

Hcf=32

Mark as brainliest if it HELPS

Discussion

35.	If P(x)=x power2 -4x+4,then find the value of P(2)+P(-2)+P(1)
Answer» <P>ANSWER: P(2)=2^2-4×2+4 =4-8+4 =0 Similarly, P(-2)=16 P(1)=1 Therefore, =P(2)+P(-2)+P(1) =0+16+1 =17

35.

If P(x)=x power2 -4x+4,then find the value of P(2)+P(-2)+P(1)

Answer»

<P>ANSWER:

P(2)=2^2-4×2+4

=4-8+4

=0

Similarly,

P(-2)=16

P(1)=1

Therefore,

=P(2)+P(-2)+P(1)

=0+16+1

=17

Discussion

36.	A fractions becomes 2/3 if numerator is increased and denominator are increased by 2.if they are refuced by 1,the fraction becomes 1/2
Answer» Step-by-step explanation: LET the NUMERATOR be x and denominator be y, ACCORDING to given conditions: $\frac{x + 2}{y + 2} = \frac{2}{3} \\ 3(x + 2) = 2(y + 2) \\ 3x + 6 = 2y + 4 \\ 3x - 2y = - 2 \: ......(1) \\ next \\ \frac{x - 1}{y - 1} = \frac{1}{2} \\ 2x - 2 = y - 1 \\ 2x - 2 + 1 = y \\ y = 2x - 1 \: .......(2) \\ from \: (1) \: and \: (2) \\ 3x - 2(2x - 1) = - 2 \\ 3x - 4x + 2 = - 2 \\ - x = - 4 \\ x = 4 \\ y = 2 \times 4 - 1 \\ y = 7 \\ hence \: the \: required \: fraction \: is \: \\ \frac{4}{7} .$

36.

A fractions becomes 2/3 if numerator is increased and denominator are increased by 2.if they are refuced by 1,the fraction becomes 1/2

Answer»

Step-by-step explanation:

LET the NUMERATOR be x and denominator be y, ACCORDING to given conditions:

$\frac{x + 2}{y + 2} = \frac{2}{3} \\ 3(x + 2) = 2(y + 2) \\ 3x + 6 = 2y + 4 \\ 3x - 2y = - 2 \: ......(1) \\ next \\ \frac{x - 1}{y - 1} = \frac{1}{2} \\ 2x - 2 = y - 1 \\ 2x - 2 + 1 = y \\ y = 2x - 1 \: .......(2) \\ from \: (1) \: and \: (2) \\ 3x - 2(2x - 1) = - 2 \\ 3x - 4x + 2 = - 2 \\ - x = - 4 \\ x = 4 \\ y = 2 \times 4 - 1 \\ y = 7 \\ hence \: the \: required \: fraction \: is \: \\ \frac{4}{7} .$

Discussion

37.	If the HCF (210,55)is expressible in the form 210×5-55y, find y
Answer» Answer: 19 Step-by-step EXPLANATION: USING EUCLID'S DIVISION LEMMA 210=55×3+45 55=45×1+10 45=10×4+5 10=5×2+0 Thus, HCF(210,55)=5 Now, ATQ HCF(210,55)=210×5-55y 5=1050-55y 55y=1045 y=19 *Answer*

37.

If the HCF (210,55)is expressible in the form 210×5-55y, find y

Answer»

Answer:

19

Step-by-step EXPLANATION:

USING EUCLID'S DIVISION LEMMA

210=55×3+45

55=45×1+10

45=10×4+5

10=5×2+0

Thus, HCF(210,55)=5

Now, ATQ

HCF(210,55)=210×5-55y

5=1050-55y

55y=1045

y=19 Answer

Discussion

38.	Find root 2+3 root-5 +root 2-3 root-5
Answer» ANSWER: Step-by-step EXPLANATION: √2+3√5+√2-3√5 =2√2

38.

Find root 2+3 root-5 +root 2-3 root-5

Answer»

ANSWER:

Step-by-step EXPLANATION:

√2+3√5+√2-3√5

=2√2

Discussion

39.	Sin a. Cot a + sin a. Cosec a = 1 + cos a
Answer» ANSWER: SIN acot a+sin aCOSEC a=1+cos a LHS: sin acos a /sin a +sin a1/sin a cos a+1(RHS) LHS=RHS(proved)

39.

Sin a. Cot a + sin a. Cosec a = 1 + cos a

Answer»

ANSWER:

SIN a*cot a+sin a*COSEC a=1+cos a

LHS:

sin a*cos a /sin a +sin a*1/sin a

cos a+1(RHS)

LHS=RHS(proved)

Discussion

40.	Banks are digital today” is written as “Zi Li Ki Ti”, “Money transfer through banks” is written as “Di Ki Si Fi”, “Digital money easy today” is written as “Si Zi Ti Bi” and “Today we have leave” is written as “Gi Xi Vi Zi”. What is the possible code for “Easy for transfer”?
Answer» Answer: Step-by-step explanation: Banks are digital today” is written as “Zi LI Ki Ti” Money TRANSFER through banks” is written as “Di Ki Si Fi” Banks is common in both so Ki - common in both = Banks Digital money EASY today” is written as “Si Zi Ti Bi” “Today we have leave” is written as “GI Xi Vi Zi” Today is common in both so Zi common in both = Today Banks are digital today” is written as “Zi Li Ki Ti” Digital money easy today” is written as “Si Zi Ti Bi” common digital & today & Zi & Ti Common Today = Zi Digital = Ti Are = Li Money transfer through banks” is written as “Di Ki Si Fi” Digital money easy today” is written as “Si Zi Ti Bi” Money = Si Easy = Bi transfer through - Di & Fi Easy for Transfer Bi ( Di / Fi) xxx if options are given then we can choose based on this information.

40.

Banks are digital today” is written as “Zi Li Ki Ti”, “Money transfer through banks” is written as “Di Ki Si Fi”, “Digital money easy today” is written as “Si Zi Ti Bi” and “Today we have leave” is written as “Gi Xi Vi Zi”. What is the possible code for “Easy for transfer”?

Answer»

Answer:

Step-by-step explanation:

Banks are digital today” is written as “Zi LI Ki Ti”

Money TRANSFER through banks” is written as “Di Ki Si Fi”

Banks is common in both so Ki - common in both = Banks

Digital money EASY today” is written as “Si Zi Ti Bi”

“Today we have leave” is written as “GI Xi Vi Zi”

Today is common in both so Zi common in both = Today

Banks are digital today” is written as “Zi Li Ki Ti”

Digital money easy today” is written as “Si Zi Ti Bi”

common digital & today & Zi & Ti Common

Today = Zi

Digital = Ti

Are = Li

Money transfer through banks” is written as “Di Ki Si Fi”

Digital money easy today” is written as “Si Zi Ti Bi”

Money = Si

Easy = Bi

transfer through - Di & Fi

Easy for Transfer

Bi ( Di / Fi) xxx

if options are given then we can choose based on this information.

Discussion

41.	Use the reminder theorem to completely factor p(x) = x³ + 7x² + 11x + 5
Answer» ANSWER: GIVE me the DIVISOR FIRST

41.

Use the reminder theorem to completely factor p(x) = x³ + 7x² + 11x + 5

Answer»

ANSWER:

GIVE me the DIVISOR FIRST

Discussion

42.	The additive inverse of minus -13÷7=
Answer» ANSWER: =13/7 Step-by-step EXPLANATION: -13/7+13/7= 0..........

42.

The additive inverse of minus -13÷7=

Answer»

ANSWER:

=13/7

Step-by-step EXPLANATION:

-13/7+13/7= 0..........

Discussion

43.	chek whether the g(x) is a factor of the p(x) by applying p(x) = 2x^5 -4x^3 + 2x^2+ 5x + 1 , g (x) = x^3 - 4x + 1
Answer» Step-by-step EXPLANATION: the ANSWER is no CUZ a REMAINDER is LEFT

43.

chek whether the g(x) is a factor of the p(x) by applying p(x) = 2x^5 -4x^3 + 2x^2+ 5x + 1 , g (x) = x^3 - 4x + 1

Answer»

Step-by-step EXPLANATION:

the ANSWER is no CUZ a REMAINDER is LEFT

Discussion

44.	if manure is to added in the soil ,then it should be added to the soil before ploughing the soil.why?
Answer» ANSWER: Step-by-step explanation: There are several activities involved in the process of CULTIVATION of crops. in. The following are some of the process involved: (i) PREPARING soil (ii) Sowing (iii) Applying of FERTILIZERS and manure (iv) Proper Irrigation (v) Protection from weeds (vi) Harvesting of crops (vii) STORAGE of crops The first step in the process of cultivation of crop is preparation of soil. The most important activity in the process of agriculture is to turn and loosen the soil. This enables the root to go deep into the soil. The loosening of soil helps the roots to breathe with ease even if they are deep into the soil. Earthworms and microbes which are present in the loosened soil thrives well in such conditions. These organisms helps in turning and loosening of the soil and add even add humus . Dead plants and animals which gets decomposed through soil organisms released their nutrients back into the soil which are absorbed by plants. With the help of the process of turning and loosening of soil it brings the soil(containing nutrients) to the top to be used by the plants. Ploughing or Tilling is a process of loosening and turning of the soil which is done through a plough. In some cases manure is added to the soil before the process of tilling as it helps in mixing of manure with soil in a proper manner. Hope this helps.

44.

if manure is to added in the soil ,then it should be added to the soil before ploughing the soil.why?

Answer»

ANSWER:

Step-by-step explanation:

There are several activities involved in the process of CULTIVATION of crops. in. The following are some of the process involved:

(i) PREPARING soil

(ii) Sowing

(iii) Applying of FERTILIZERS and manure

(iv) Proper Irrigation

(v) Protection from weeds

(vi) Harvesting of crops

(vii) STORAGE of crops

The first step in the process of cultivation of crop is preparation of soil. The most important activity in the process of agriculture is to turn and loosen the soil. This enables the root to go deep into the soil.

The loosening of soil helps the roots to breathe with ease even if they are deep into the soil. Earthworms and microbes which are present in the loosened soil thrives well in such conditions. These organisms helps in turning and loosening of the soil and add even add humus .

Dead plants and animals which gets decomposed through soil organisms released their nutrients back into the soil which are absorbed by plants. With the help of the process of turning and loosening of soil it brings the soil(containing nutrients) to the top to be used by the plants.

Ploughing or Tilling is a process of loosening and turning of the soil which is done through a plough.

In some cases manure is added to the soil before the process of tilling as it helps in mixing of manure with soil in a proper manner.

Hope this helps.

Discussion

45.	Ans it fast pls very imp
Answer» Answer: -1IS the ZERO of the POLYNOMIAL substitute that value

45.

Ans it fast pls very imp

Answer»

Answer:

-1IS the ZERO of the POLYNOMIAL substitute that value

Discussion

46.	3. Arrange in columns and add.(a) 1825 + 5172(c) 2538 + 3847(e) 1886 + 2432 + 4337(g) 1852 + 2156 +265 + 12(i) 1832 + 2031 + 3156 + 1204
Answer» ANSWER: [TEX]1825 + 5172 + 2538 + 3847 + 1886 + 2432 + 4337 + 1852 + 2156 + 3156 + 265 + 1 + 1832 + 2031 + 1204= [34534]

46.

3. Arrange in columns and add.(a) 1825 + 5172(c) 2538 + 3847(e) 1886 + 2432 + 4337(g) 1852 + 2156 +265 + 12(i) 1832 + 2031 + 3156 + 1204

Answer»

ANSWER:

[TEX]1825 + 5172 + 2538 + 3847 + 1886 + 2432 + 4337 + 1852 + 2156 + 3156 + 265 + 1 + 1832 + 2031 + 1204= [34534]

Discussion

47.	How to make a place value chart
Answer» Answer: Place value is the basis of our entire number system. A place value system is one in which the position of a digit in a number determines its value. ... In standard form, the number MODELED above is 233. A place-value chart is a way to make sure digits are in the correct placeIn math, every digit in a number has a place value. Place value can be defined as the value represented by a digit in a number on the basis of its position in the number. Here's an example showing the relationship between the place or position and the place value of the digits in a number.s. What is place value? In math, every digit in a number has a place value. Place value can be defined as the value represented by a digit in a number on the basis of its position in the number. Here’s an example showing the relationship between the place or position and the place value of the digits in a number. Place Value of digits in NUMBERS and decimal numbers – Ones to ten thousands In 13548, 1 is in ten thousands place and its place value is 10,000, 3 is in thousands place and its place value is 3,000, 5 is in hundreds place and its place value is 500, 4 is in tens place and its place value is 40, 8 is in ones place and its place value is 8. Understanding the place value of digits in numbers helps in writing numbers in their . For instance, the expanded form of the number above, 13548 is 10,000 + 3,000 + 500 + 40 + 8. A place value chart can help us in finding and comparing the place value of the digits in numbers through millions. The place value of a digit increases by ten times as we move left on the place value chart and decreases by ten times as we move right. place value chart Here’s an example of how drawing the place value chart can help in finding the place value of a number in millions. Place Value of digits in numbers and decimal numbers – Ones, tens, hundreds, thousands, through millions In 3287263, 3 is in millions place and its place value is 3000000, 2 is hundred thousands place and its place value is 200000, 8 is in ten thousands place and its place value is 80000, 7 is in thousands place and its place value is 7000, 2 is in hundreds place and its place value is 200, 6 is in ten place and its place value is 60, 3 is in ones place and its place value is 3. The place value of digits in numbers can also be represented using base-ten blocks and can help us write numbers in their expanded form. Here’s how the number 13548 can be represented using base-ten blocks. Place Value of digits in numbers using base-ten blocks Decimal Place Value Decimal numbers are or mixed numbers with denominators of powers of ten. In a decimal number, the digits to the left of the decimal point represent a whole number. The digits to the right of the decimal represent the PARTS. The place value of the digits becomes 10 times smaller. The first digit on the right of the decimal point means tenths i.e. image 1 . Place Value Chart of Decimal Numbers – Decrease left to right In 27.356, 27 is the whole number part, 2 is in tens place and its place value is 20, 7 is in ones place, and its place value is 7. There are three digits to the right of the decimal point, 3 is in the tenths place, and its place value is 0.3 or image 2 , 5 is in the hundredths place, and its place value is 0.05 or image 3 , 6 is in the thousandths place, and its place value is 0.006 or image 4 .

47.

How to make a place value chart

Answer»

Answer:

Place value is the basis of our entire number system. A place value system is one in which the position of a digit in a number determines its value. ... In standard form, the number MODELED above is 233.

A place-value chart is a way to make sure digits are in the correct placeIn math, every digit in a number has a place value. Place value can be defined as the value represented by a digit in a number on the basis of its position in the number. Here's an example showing the relationship between the place or position and the place value of the digits in a number.s.

What is place value?

In math, every digit in a number has a place value.

Place value can be defined as the value represented by a digit in a number on the basis of its position in the number.

Here’s an example showing the relationship between the place or position and the place value of the digits in a number.

Place Value of digits in NUMBERS and decimal numbers – Ones to ten thousands

In 13548, 1 is in ten thousands place and its place value is 10,000,

3 is in thousands place and its place value is 3,000,

5 is in hundreds place and its place value is 500,

4 is in tens place and its place value is 40,

8 is in ones place and its place value is 8.

Understanding the place value of digits in numbers helps in writing numbers in their . For instance, the expanded form of the number above, 13548 is 10,000 + 3,000 + 500 + 40 + 8.

A place value chart can help us in finding and comparing the place value of the digits in numbers through millions. The place value of a digit increases by ten times as we move left on the place value chart and decreases by ten times as we move right.

place value chart

Here’s an example of how drawing the place value chart can help in finding the place value of a number in millions.

Place Value of digits in numbers and decimal numbers – Ones, tens, hundreds, thousands, through millions

In 3287263, 3 is in millions place and its place value is 3000000,

2 is hundred thousands place and its place value is 200000,

8 is in ten thousands place and its place value is 80000,

7 is in thousands place and its place value is 7000,

2 is in hundreds place and its place value is 200,

6 is in ten place and its place value is 60,

3 is in ones place and its place value is 3.

The place value of digits in numbers can also be represented using base-ten blocks and can help us write numbers in their expanded form.

Here’s how the number 13548 can be represented using base-ten blocks.

Place Value of digits in numbers using base-ten blocks

Decimal Place Value

Decimal numbers are or mixed numbers with denominators of powers of ten. In a decimal number, the digits to the left of the decimal point represent a whole number. The digits to the right of the decimal represent the PARTS. The place value of the digits becomes 10 times smaller.

The first digit on the right of the decimal point means tenths i.e. image 1 .

Place Value Chart of Decimal Numbers – Decrease left to right

In 27.356, 27 is the whole number part,

2 is in tens place and its place value is 20,

7 is in ones place, and its place value is 7.

There are three digits to the right of the decimal point,

3 is in the tenths place, and its place value is 0.3 or image 2 ,

5 is in the hundredths place, and its place value is 0.05 or image 3 ,

6 is in the thousandths place, and its place value is 0.006 or image 4 .

Discussion

48.	Find tan θ if sec θ = square root of ten divided by three and sin θ < 0.-33negative one divided by threenegative square root of ten
Answer» ANSWER: -1/3 Step-by-step EXPLANATION: PLEASE SEE the ATTACHED explanation

48.

Find tan θ if sec θ = square root of ten divided by three and sin θ < 0.-33negative one divided by threenegative square root of ten

Answer»

ANSWER:

-1/3

Step-by-step EXPLANATION:

PLEASE SEE the ATTACHED explanation

Discussion

49.	Five years hence,a man's age will be three times the age of his son.Five years ago, the man was seven times as old as his son.Find their present ages.
Answer» Answer: Step-by-step explanation: GIVEN :- Five years hence, a man's age will be three times the age of his son. Five years ago, the man was seven times as old as his son. To Find :- Their Present ages Solution :- Let the present age of the man be x years And His son's be y years. 1st EQUATION :- After 5 years man’s age = x + 5 After 5 years ago son’s age = y + 5 As PER the question ⇒ x + 5 = 3(y + 5) ⇒ x – 3Y = 10 ……………(i) 2nd Equation 5 years ago man’s age = x – 5 5 years ago son’s age = y – 5 As per the question ⇒ x – 5 = 7(y – 5) ⇒ x – 7y = -30 …….(ii) Subtracting (ii) from (i), we have ⇒ 4y = 40 ⇒ y = 10 Putting y value in Eq (i) ⇒ x – 3y = 10 ⇒ x – 3 × 10 = 10 ⇒ x = 10 + 30 ⇒ x = 40 Hence, man’s present age = 40 years and son’s present age = 10 years.

49.

Five years hence,a man's age will be three times the age of his son.Five years ago, the man was seven times as old as his son.Find their present ages.

Answer»

Answer:

Step-by-step explanation:

GIVEN :-

Five years hence, a man's age will be three times the age of his son.

Five years ago, the man was seven times as old as his son.

To Find :-

Their Present ages

Solution :-

Let the present age of the man be x years

And His son's be y years.

1st EQUATION :-

After 5 years man’s age = x + 5

After 5 years ago son’s age = y + 5

As PER the question

⇒ x + 5 = 3(y + 5)

⇒ x – 3Y = 10 ……………(i)

2nd Equation

5 years ago man’s age = x – 5

5 years ago son’s age = y – 5

As per the question

⇒ x – 5 = 7(y – 5)

⇒ x – 7y = -30 …….(ii)

Subtracting (ii) from (i), we have

⇒ 4y = 40

⇒ y = 10

Putting y value in Eq (i)

⇒ x – 3y = 10

⇒ x – 3 × 10 = 10

⇒ x = 10 + 30

⇒ x = 40

Hence, man’s present age = 40 years and son’s present age = 10 years.

Discussion

50.	Find the general solution of 4cos x - 3sec x=tan x............ Plz help
Answer» SOLUTION:-- 4 cosx − 3 secx = tanx 4 cosx − 3/cosx = SINX/cosx MULTIPLY both sides by cosx 4 cos²x − 3 = sinx 4 (1−sin²x) − 3 = sinx 1 − 4 sin²x = sinx 4 sin²x + sinx − 1 = 0 sinx = (−1±√(1²−44−1))/(2*4) sinx = (−1±√17)/8 sinx = (√17−1)/8 x = sin⁻¹((√17−1)/8) + 2πn ≈ 2πn + 0.401053217 x = π−sin⁻¹((√17−1)/8) + 2πn ≈ 2πn + 2.740539437 sinx = −(√17+1)/8 x = −sin⁻¹((√17+1)/8) + 2πn ≈ 2πn − 0.695003598 x = π+sin⁻¹((√17+1)/8) + 2πn ≈ 2πn + 3.836596252 hope HELPED

50.

Find the general solution of 4cos x - 3sec x=tan x............ Plz help

Answer»

SOLUTION:--

4 cosx − 3 secx = tanx

4 cosx − 3/cosx = SINX/cosx

MULTIPLY both sides by cosx

4 cos²x − 3 = sinx

4 (1−sin²x) − 3 = sinx

1 − 4 sin²x = sinx

4 sin²x + sinx − 1 = 0

sinx = (−1±√(1²−4*4*−1))/(2*4)

sinx = (−1±√17)/8

sinx = (√17−1)/8

x = sin⁻¹((√17−1)/8) + 2πn ≈ 2πn + 0.401053217

x = π−sin⁻¹((√17−1)/8) + 2πn ≈ 2πn + 2.740539437

sinx = −(√17+1)/8

x = −sin⁻¹((√17+1)/8) + 2πn ≈ 2πn − 0.695003598

x = π+sin⁻¹((√17+1)/8) + 2πn ≈ 2πn + 3.836596252

hope HELPED

Discussion

Explore topic-wise InterviewSolutions in Current Affairs.

If we add 1 to the numerator and subtract one from the denominator, of a fraction reduces to one. it becomes half if we add 1 to the denominator what is the fraction?plz guys want quick answers ​

Verify the property(-3)^m+1×(-3)^5=(-3)^7

The ratio of income of two person is 9: 7 and the ratio of their expenditure is 4 : 3 if each of them manage to save RS 2000 per month find their monthly income

Iffind ​

The function f(X) = √25-9x2

What should be added to -7/3 to get 3/7

Solve 156 by 44 multiply by 7 by 4

12 subtract from twice a no. Gives 3

Hcf of 27,36,25,75,12,16,24,25,50,100,72

2 ka power 2x+2 = 4 ka power 2x-1 find value of x

LCM of 999 and 1000 LCM

2+2-3+6÷22×67÷4-7+314×888-465×4+2=?

You need to return a product you purchased 3 days ago. The total cost of the item was $50.00. The store charges a 25% restocking fee. How much money will you get once the restocking fee is paid?

If tan theta = cot theta then value of( tan theta + cot theta)square is

A = 9+4√5 & b= 1/a, then find the value of a2+b2

Log 1 to the base 2​

What is addition deffination​

Help me please............​

Verify the property2/2+15=4/9

in a gruop of 52 persons, 16 drink tea but not coffee and 33 drink tea. find how many drink coffee but not tea.

Please solve this que please provide solution of this question​

Triangle abc is similar to triangle pqr and ar(abc)/ar(pqr)=196/361 then ab/ pq is

[|x|] =4 then interval of X is​

Q4. Divide the sum of 3 upon 11and 2upon5 by their product.​

1/2=X/4 then X =. (rule of cross multiplication​

Two numbers are in the ratio 3:4. If 4 is added toeach of the numbers, the ratio becomes 4:5. Findthe product of numbers.​

The sum of 2 consecutive multiples of 3 is 69. find the numbers

Find the value of 'a' so that the point(3,9) lies on the line represented by 2ax-3y=5​

Peove that:1+sin2A=(cos A+sin A)^2pls guys do itt..❤️❤️ you will get 15 points​

Thrice a number when increased by 5give 44.Find the number.?

A current of 1A flows through a copper wire.Number of electrons will pass a given in each second are?NEED SUPER FAST ANSWER PLS​

Distance between moon and sun in standard form

LCM of two number 160and 352 is 1760 find HCF?

If P(x)=x power2 -4x+4,then find the value of P(2)+P(-2)+P(1)

A fractions becomes 2/3 if numerator is increased and denominator are increased by 2.if they are refuced by 1,the fraction becomes 1/2

If the HCF (210,55)is expressible in the form 210×5-55y, find y

Find root 2+3 root-5 +root 2-3 root-5

Sin a. Cot a + sin a. Cosec a = 1 + cos a

Use the reminder theorem to completely factor p(x) = x³ + 7x² + 11x + 5

The additive inverse of minus -13÷7=

chek whether the g(x) is a factor of the p(x) by applying p(x) = 2x^5 -4x^3 + 2x^2+ 5x + 1 , g (x) = x^3 - 4x + 1​

if manure is to added in the soil ,then it should be added to the soil before ploughing the soil.why?​

Ans it fast pls very imp​

3. Arrange in columns and add.(a) 1825 + 5172(c) 2538 + 3847(e) 1886 + 2432 + 4337(g) 1852 + 2156 +265 + 12(i) 1832 + 2031 + 3156 + 1204​

How to make a place value chart ​

Find tan θ if sec θ = square root of ten divided by three and sin θ < 0.-33negative one divided by threenegative square root of ten

Five years hence,a man's age will be three times the age of his son.Five years ago, the man was seven times as old as his son.Find their present ages.

Find the general solution of 4cos x - 3sec x=tan x............ Plz help

If we add 1 to the numerator and subtract one from the denominator, of a fraction reduces to one. it becomes half if we add 1 to the denominator what is the fraction?plz guys want quick answers

Iffind

Log 1 to the base 2

What is addition deffination

Help me please............

Please solve this que please provide solution of this question

[|x|] =4 then interval of X is

Q4. Divide the sum of 3 upon 11and 2upon5 by their product.

1/2=X/4 then X =. (rule of cross multiplication

Two numbers are in the ratio 3:4. If 4 is added toeach of the numbers, the ratio becomes 4:5. Findthe product of numbers.

Find the value of 'a' so that the point(3,9) lies on the line represented by 2ax-3y=5

Peove that:1+sin2A=(cos A+sin A)^2pls guys do itt..❤️❤️ you will get 15 points

A current of 1A flows through a copper wire.Number of electrons will pass a given in each second are?NEED SUPER FAST ANSWER PLS

chek whether the g(x) is a factor of the p(x) by applying p(x) = 2x^5 -4x^3 + 2x^2+ 5x + 1 , g (x) = x^3 - 4x + 1

if manure is to added in the soil ,then it should be added to the soil before ploughing the soil.why?

Ans it fast pls very imp

3. Arrange in columns and add.(a) 1825 + 5172(c) 2538 + 3847(e) 1886 + 2432 + 4337(g) 1852 + 2156 +265 + 12(i) 1832 + 2031 + 3156 + 1204

How to make a place value chart