332354 + Interview Questions in Secondary School in Math

1.	(3/5)^2x=1 answerrrrrrrrrrr
Answer» ANSWER: X = 0 Step-by-step explanation: (3/5)^2X = 1 1 can ALSO be written as (3/5)^0. (3/5)^2x = (3/5)^0 Now we can equate. 2x = 0 x = 0/2 x=0

1.

(3/5)^2x=1 answerrrrrrrrrrr

Answer»

ANSWER:

X = 0

Step-by-step explanation:

(3/5)^2X = 1

1 can ALSO be written as (3/5)^0.

(3/5)^2x = (3/5)^0

Now we can equate.

2x = 0

x = 0/2

x=0

Discussion

2.	Solve 3x + 2y = 11/3 and -7x + 5y = 31/3 solve by elimination method
Answer» Answer: ok if ANS is not CORRECT so U can do 45-42 INSTEAD of 45+42

2.

Solve 3x + 2y = 11/3 and -7x + 5y = 31/3 solve by elimination method

Answer»

Answer:

ok if ANS is not CORRECT so U can do 45-42 INSTEAD of 45+42

Discussion

3.	Plz guys give correct answer. .....n2-1 is divisible by 8, if n is(a) an integer (b) a natural number (c) an odd integer (d) an even integer
Answer» I THINK c NATURAL no. because it doesn't MEAN that the no. is odd or EVEN

3.

Plz guys give correct answer. .....n2-1 is divisible by 8, if n is(a) an integer (b) a natural number (c) an odd integer (d) an even integer

Answer»

I THINK c NATURAL no. because it doesn't MEAN that the no. is odd or EVEN

Discussion

4.	Simplify :D -C +M -(L/XXV)
Answer» ANSWER: D-C+M-(L/XXV) 500-100+1000-(50/25) 1500-100-2 1500-102 1498. Answer

4.

Simplify :D -C +M -(L/XXV)

Answer»

ANSWER:

D-C+M-(L/XXV)

500-100+1000-(50/25)

1500-100-2

1500-102

1498. Answer

Discussion

5.	Vinay bought a pen and some pencils for ₹ 25.50 If the cost of each pen is ₹ 10.50 and cost of each pencil is ₹ 1.50 ,find the number of pencils purchased by him.
Answer» Step-by-step EXPLANATION: No. of PENCILS PURCHASED by him= 25.50/1.50=17

5.

Vinay bought a pen and some pencils for ₹ 25.50 If the cost of each pen is ₹ 10.50 and cost of each pencil is ₹ 1.50 ,find the number of pencils purchased by him.

Answer»

Step-by-step EXPLANATION:

No. of PENCILS PURCHASED by him= 25.50/1.50=17

Discussion

6.	26Find the zeros of the following quadratic polynomialsand verify the relationship between the zeros andtheir co-efficients.@7y2 - 117-239-3m 2s2 - (1 + 212) 5+ 12
Answer» ANSWER: eags Step-by-step EXPLANATION: sbhhxhxhhsjszjxfxjxd

6.

26Find the zeros of the following quadratic polynomialsand verify the relationship between the zeros andtheir co-efficients.@7y2 - 117-239-3m 2s2 - (1 + 212) 5+ 12

Answer»

ANSWER:

eags

Step-by-step EXPLANATION:

sbhhxhxhhsjszjxfxjxd

Discussion

7.	P/q form of 1.63bar ,bar only for 3
Answer» SOLUTION : LET x be = 1.633333...... ___(i) Multiplying 10 to both sides of equation (i), we get, 10x = 16.333..... ___(ii) Multiplying 10 to both sides if equation (ii), we get, 100x = 163.3333........ ___(iii) Now, Subtracting equation (ii) from equation (iii), we get 100x = 163.333..... - 10x = 16.333..... _______________ 90x = 147.000.... _______________ ⇒ 90x = 147 ⇒ x = 147 ÷ 90 $\bf x=\frac{147}{90}$

7.

P/q form of 1.63bar ,bar only for 3

Answer»

SOLUTION :

LET x be = 1.633333...... ___(i)

Multiplying 10 to both sides of equation (i), we get,

10x = 16.333..... ___(ii)

Multiplying 10 to both sides if equation (ii), we get,

100x = 163.3333........ ___(iii)

Now,

Subtracting equation (ii) from equation (iii), we get

100x = 163.333.....

- 10x = 16.333.....

_______________

90x = 147.000....

_______________

⇒ 90x = 147

⇒ x = 147 ÷ 90

$\bf x=\frac{147}{90}$

Discussion

8.	EvaluateCos^2 20° + Cos^2 70° / 3 (Sin^2 59° + Sin^2 31°)full explanation. ..
Answer» ANSWER: Step-by-step explanation: COS2 20°+cos2(90-20)/3(SIN2 59°+sin2 (90-59) ) =Cos2 20°+sin2 20°/3(sin2 59°+cos2 59°) =1/3(1) =1/3

8.

EvaluateCos^2 20° + Cos^2 70° / 3 (Sin^2 59° + Sin^2 31°)full explanation. ..

Answer»

ANSWER:

Step-by-step explanation:

COS2 20°+cos2(90-20)/3(SIN2 59°+sin2 (90-59) )

=Cos2 20°+sin2 20°/3(sin2 59°+cos2 59°)

=1/3(1)

=1/3

Discussion

9.	81km 549m ÷9 what is the answer
Answer» ANSWER: 549÷9=61 is the answer

9.

81km 549m ÷9 what is the answer

Answer»

ANSWER:

549÷9=61 is the answer

Discussion

10.	Super market saleDiscriptionon the supermarket thereع هگونوکوکومکہوطہعلاطمطوE shop Reeper A sell in 2/3 aproduct in aday B sell 317aproduct in a day sell 4,50produce in adăd sell 516product in a day and E seu 7180للتكهنلهننممتنعميبنمطهر ومعجمQUE 5eachegual circles and representfraction on the airdeعععععععععع لفصحthe circle and find largestfraction and the smallestFraction
Answer» ANSWER: Step-by-step EXPLANATION: U U

10.

Super market saleDiscriptionon the supermarket thereع هگونوکوکومکہوطہعلاطمطوE shop Reeper A sell in 2/3 aproduct in aday B sell 317aproduct in a day sell 4,50produce in adăd sell 516product in a day and E seu 7180للتكهنلهننممتنعميبنمطهر ومعجمQUE 5eachegual circles and representfraction on the airdeعععععععععع لفصحthe circle and find largestfraction and the smallestFraction

Answer»

ANSWER:

Step-by-step EXPLANATION:

U U

Discussion

11.	Solve it fast pls it is very imp
Answer» ANSWER: that is answer of your QUESTION

11.

Solve it fast pls it is very imp

Answer»

ANSWER:

that is answer of your QUESTION

Discussion

12.	a sum of money is lent at 8% per annum compound interest if the interest for the second year exceeds for the first year by rupees 96 find the sum of money
Answer» Answer: For 1st YEAR p=rupees x .Rate=8% TIME =1year interest =x81/100 =0.08x and amount =x+0.08x=1.08x For 2nd year P=1.08x rupees Rate=8% Time= 1 year Interest =1.08x81/100 =0.0864x Amount =1.08x+0.0864x =1.8864 x 0.0864x-0.08x=96 x=15000 Step-by-step EXPLANATION: FOLLOW me

12.

a sum of money is lent at 8% per annum compound interest if the interest for the second year exceeds for the first year by rupees 96 find the sum of money

Answer»

Answer:

For 1st YEAR p=rupees x .Rate=8% TIME =1year

interest =x*8*1/100

=0.08x

and amount =x+0.08x=1.08x

For 2nd year P=1.08x rupees Rate=8% Time= 1 year

Interest =1.08x*8*1/100

=0.0864x

Amount =1.08x+0.0864x

=1.8864 x

0.0864x-0.08x=96

x=15000

Step-by-step EXPLANATION:

FOLLOW me

Discussion

13.	1)The surface area of a solid metallic sphere is 616 cm2. It is melted and recast into smallerspheres of diameter 3.5 cm. How many such spheres can be obtained?2)The surface area of a solid metallic sphere is 1256 cm2. It is melted and recast into solidright circular cones of radius 2.5 cm and height 8 cm. Calculate:(i) the radius of the solid sphere.(ii) the number of cones recast. (Use π= 3.14).
Answer» Answer:Hope this is help full Step-by-step EXPLANATION: Solution:- Surface area of the sphere = 4πr² 616 = 422/7r² r² = (6167)/88 r² = 4312/88 r² = 49 r = 7 cm Radius of the sphere is 7 cm As sphere is melted and recast into a cone then, Volume of the sphere = Volume of the cone 4/3πr³ = 1/3πr²h 4/322/777 = 1/322/7r²28 4/3777 = 1/3r²28 r² = 49 r = 7 cm So, radius of the cone is 7 cm and DIAMETER = 7*2 = 14 cm Answer.

13.

1)The surface area of a solid metallic sphere is 616 cm2. It is melted and recast into smallerspheres of diameter 3.5 cm. How many such spheres can be obtained?2)The surface area of a solid metallic sphere is 1256 cm2. It is melted and recast into solidright circular cones of radius 2.5 cm and height 8 cm. Calculate:(i) the radius of the solid sphere.(ii) the number of cones recast. (Use π= 3.14).

Answer»

Answer:Hope this is help full

Step-by-step EXPLANATION:

Solution:-

Surface area of the sphere = 4πr²

616 = 4*22/7*r²

r² = (616*7)/88

r² = 4312/88

r² = 49

r = 7 cm

Radius of the sphere is 7 cm

As sphere is melted and recast into a cone then,

Volume of the sphere = Volume of the cone

4/3πr³ = 1/3πr²h

4/3*22/7*7*7 = 1/3*22/7*r²*28

4/3*7*7*7 = 1/3*r²*28

r² = 49

r = 7 cm

So, radius of the cone is 7 cm and DIAMETER = 7*2 = 14 cm

Answer.

Discussion

14.	Give 1 reson why a person should be vaccinated against influenza?
Answer» ANSWER: to be alearted and SAFEGUARDED from that DISEASE

14.

Give 1 reson why a person should be vaccinated against influenza?

Answer»

ANSWER:

to be alearted and SAFEGUARDED from that DISEASE

Discussion

15.	Given that A = 2 2 3.-2 21.-13 and that Cb = D.L1 -1 3 11 19Solve the matrix equation Axb.LLet A-and C =C-63 2039 be s piven mutrices.be 3 given matrices.0(r-DCompute the value ofwhere tr.(A) denotes trace of matrix A)To 1 17Let X be the solution set of the equation A=I, where A = 4 -3 4 and I is the corresponding13 3 4unit matrix and x N then find the minimum value of (cos' 0+ sin"0),0 € R.57
Answer» Answer: plradgjkko B d i don't KNOW ur you have a good DAY at work and I don't know what to do it in my room for me too BABY and I don't know what to do it in

15.

Given that A = 2 2 3.-2 21.-13 and that Cb = D.L1 -1 3 11 19Solve the matrix equation Axb.LLet A-and C =C-63 2039 be s piven mutrices.be 3 given matrices.0(r-DCompute the value ofwhere tr.(A) denotes trace of matrix A)To 1 17Let X be the solution set of the equation A=I, where A = 4 -3 4 and I is the corresponding13 3 4unit matrix and x N then find the minimum value of (cos' 0+ sin"0),0 € R.57

Answer»

Answer:

plradgjkko B d i don't KNOW ur you have a good DAY at work and I don't know what to do it in my room for me too BABY and I don't know what to do it in

Discussion

16.	in a rectangle ABCD BM and DN are perpendiculars from B and D respectively on AC shows that triangle B and C congruent to triangle DNA
Answer» In triangle BMC and triangle DNA BC =AD(opposite sides of RECTANGLE are equal) Angle BCM=Angle MAD(Alternate angles) Angle BMC =Angle DNA (BM and DN perpendicular to AC) THEREFORE triangle BMC congruent to triangle DNA Therefore BM =DN (CPCT)

16.

in a rectangle ABCD BM and DN are perpendiculars from B and D respectively on AC shows that triangle B and C congruent to triangle DNA

Answer»

In triangle BMC and triangle DNA

BC =AD(opposite sides of RECTANGLE are equal)

Angle BCM=Angle MAD(Alternate angles)

Angle BMC =Angle DNA (BM and DN perpendicular to AC)

THEREFORE triangle BMC congruent to triangle DNA

Therefore BM =DN (CPCT)

Discussion

17.	M.p ki sabse badi nadi konsi h
Answer» ANSWER: *HEYA* *NARMADA* IS *THE* *ANSWE*R ❤❤

17.

M.p ki sabse badi nadi konsi h

Answer»

ANSWER:

NARMADA IS THE ANSWER ❤❤

Discussion

18.	A monkey climbs 90 cm up a slippery pole every second and slips down 60cm over the next second. How many second will the monkey take to reach a banana tied 450 cm up the slippery pole
Answer» Answer: 15 Explanation :Monkey CLIMB 90cm in a SECOND and slip 60cm The distance TRAVELLED by monkey in one second =90cm - 60cm=30cm Number of second require to climb 450CM =450/30=15second

18.

A monkey climbs 90 cm up a slippery pole every second and slips down 60cm over the next second. How many second will the monkey take to reach a banana tied 450 cm up the slippery pole

Answer»

Answer:

15

Explanation :Monkey CLIMB 90cm in a SECOND and slip 60cm

The distance TRAVELLED by monkey in one second =90cm - 60cm=30cm

Number of second require to climb 450CM =450/30=15second

Discussion

19.	When you divide a certain number by 13 the quotient is (-18)and the remainder is 7 find the number.
Answer» ANSWER: - 227 Step-by-step explanation: 13 × (-18) + 7 = - 227

19.

When you divide a certain number by 13 the quotient is (-18)and the remainder is 7 find the number.

Answer»

ANSWER:

- 227

Step-by-step explanation:

13 × (-18) + 7

= - 227

Discussion

20.	(56)2=(62)5 What property of multiplication it is called? Options Commutative property of multiplication,Distributive property of multiplication and associative property of multiplication
Answer» ASSOCIATIVE PROPERTY of MULTIPLICATION it is

20.

(56)2=(62)5 What property of multiplication it is called? Options Commutative property of multiplication,Distributive property of multiplication and associative property of multiplication

Answer»

ASSOCIATIVE PROPERTY of MULTIPLICATION it is

Discussion

21.	For what value of m one zero of the polynomial 2x square - 8 x + M + 1 is double the other
Answer» ANSWER: I HOPE it WOULD HELP you

21.

For what value of m one zero of the polynomial 2x square - 8 x + M + 1 is double the other

Answer»

ANSWER:

I HOPE it WOULD HELP you

Discussion

22.	Hello Guys ________#Question #MathsFactorise : Best answer to be marked as Brainliest ✌️
Answer» ANSWER: <P> to find zeroes of the polynomial p(x)=x³+3x²+5x+6 METHOD: in the attachment BRIEF EXPLANATION: →There are three zeroes of a cubic polynomial →so,LET us assume one ZERO as -2 →p(-2)=0 →so,(x+2) is a factor of the poynomial →so when we divide the polynomial by (x+2),we get a quadratic equation →when we FACTORISE we are going to get other two zeroes

22.

Hello Guys ________#Question #MathsFactorise : Best answer to be marked as Brainliest ✌️

Answer»

ANSWER:

<P>

to find zeroes of the polynomial

p(x)=x³+3x²+5x+6

METHOD:

in the attachment

BRIEF EXPLANATION:

→There are three zeroes of a cubic polynomial

→so,LET us assume one ZERO as -2

→p(-2)=0

→so,(x+2) is a factor of the poynomial

→so when we divide the polynomial by (x+2),we get a quadratic equation

→when we FACTORISE we are going to get other two zeroes

Discussion

23.	Prepare a project on different types of pollution levels of metropolitan cities in india draw a piechart
Answer» ANSWER: HOPE these HELPS you... If you are satisfied mark it as brainliest answer...

23.

Prepare a project on different types of pollution levels of metropolitan cities in india draw a piechart

Answer»

ANSWER:

HOPE these HELPS you...

If you are satisfied mark it as brainliest answer...

Discussion

24.	Five persons went for a breakfast. four of them spent rupees 120 each over there meals and 5th person spent rupees 24 more than the the average expenditure of all the five what was the total money spent by them.
Answer» Step-by-step EXPLANATION: (120×4)+120+24 480+144 624 Mark it as BRAINLIEST plz follow me

24.

Five persons went for a breakfast. four of them spent rupees 120 each over there meals and 5th person spent rupees 24 more than the the average expenditure of all the five what was the total money spent by them.

Answer»

Step-by-step EXPLANATION:

(120×4)+120+24

480+144

624

Mark it as BRAINLIEST plz

follow me

Discussion

25.	Simplify (64/125)^2×(4/5)^4×(16/25)^2x+1=(256/625)^3x
Answer» $\displaystyle\huge\red{\underline{\underline{Solution}}}$ FORMULA TO BE IMPLEMENTED $1. \: \: \: \sf{ {a}^{m} \times {a}^{n} = {a}^{m + n} \: }$ $2. \: \: \sf{{ ({a}^{m})}^{n} = {a}^{m n} \: }$ TO DETERMINE The VALUE of X when $\displaystyle \sf{ { \bigg( \frac{64}{125} \bigg)}^{2} \times { \bigg( \frac{4}{5} \bigg)}^{4} \times { \bigg( \frac{16}{25} \bigg)}^{2x + 1}\: ={ \bigg( \frac{256}{625} \bigg)}^{3x} }$ CALCULATION $\displaystyle \implies \: \sf{ { \bigg[ {\bigg( \frac{4}{5} \bigg)}^{3} \bigg]}^{2} \times { \bigg( \frac{4}{5} \bigg)}^{4} \times { { \bigg[ {\bigg( \frac{4}{5} \bigg)}^{2} \bigg]}}^{2x + 1}\: ={ { \bigg[ {\bigg( \frac{4}{5} \bigg)}^{4} \bigg]}}^{3x} }$ $\implies \: \displaystyle \sf{ { \bigg( \frac{4}{5} \bigg)}^{6} \times { \bigg( \frac{4}{5} \bigg)}^{4} \times { \bigg( \frac{4}{5} \bigg)}^{4x + 2}\: ={ \bigg( \frac{4}{5} \bigg)}^{12x} }$ $\implies \: \displaystyle \sf{ { \bigg( \frac{4}{5} \bigg)}^{4x + 12} ={ \bigg( \frac{4}{5} \bigg)}^{12x} }$ $\implies \: \displaystyle \sf{ 4x +1 2 = 12x}$ $\implies \: \displaystyle \sf{8x = 12}$ $\implies \: \displaystyle \sf{ x = \frac{3}{2} }$ RESULT The ANSWER is $\boxed{ \: \displaystyle \sf{ \: x = \frac{3}{2} \: \: \: }}$

25.

Simplify (64/125)^2×(4/5)^4×(16/25)^2x+1=(256/625)^3x

Answer»

$\displaystyle\huge\red{\underline{\underline{Solution}}}$

FORMULA TO BE IMPLEMENTED

$1. \: \: \: \sf{ {a}^{m} \times {a}^{n} = {a}^{m + n} \: }$

$2. \: \: \sf{{ ({a}^{m})}^{n} = {a}^{m n} \: }$

TO DETERMINE

The VALUE of X when

$\displaystyle \sf{ { \bigg( \frac{64}{125} \bigg)}^{2} \times { \bigg( \frac{4}{5} \bigg)}^{4} \times { \bigg( \frac{16}{25} \bigg)}^{2x + 1}\: ={ \bigg( \frac{256}{625} \bigg)}^{3x} }$

CALCULATION

$\displaystyle \implies \: \sf{ { \bigg[ {\bigg( \frac{4}{5} \bigg)}^{3} \bigg]}^{2} \times { \bigg( \frac{4}{5} \bigg)}^{4} \times { { \bigg[ {\bigg( \frac{4}{5} \bigg)}^{2} \bigg]}}^{2x + 1}\: ={ { \bigg[ {\bigg( \frac{4}{5} \bigg)}^{4} \bigg]}}^{3x} }$

$\implies \: \displaystyle \sf{ { \bigg( \frac{4}{5} \bigg)}^{6} \times { \bigg( \frac{4}{5} \bigg)}^{4} \times { \bigg( \frac{4}{5} \bigg)}^{4x + 2}\: ={ \bigg( \frac{4}{5} \bigg)}^{12x} }$

$\implies \: \displaystyle \sf{ { \bigg( \frac{4}{5} \bigg)}^{4x + 12} ={ \bigg( \frac{4}{5} \bigg)}^{12x} }$

$\implies \: \displaystyle \sf{ 4x +1 2 = 12x}$

$\implies \: \displaystyle \sf{8x = 12}$

$\implies \: \displaystyle \sf{ x = \frac{3}{2} }$

RESULT

The ANSWER is

$\boxed{ \: \displaystyle \sf{ \: x = \frac{3}{2} \: \: \: }}$

Discussion

26.	Simply the following -5/8+8/9+-11/12
Answer» ANSWER: Step-by-step EXPLANATION:

26.

Simply the following -5/8+8/9+-11/12

Answer»

ANSWER:

Step-by-step EXPLANATION:

Discussion

27.	If+a=log+3+5+and+b=log+17+25+then+which+one+is+greater
Answer» Answer: the QUESTION is not correctly written then only I will HELP you mark it as BRAINLIEST plz follow me

27.

If+a=log+3+5+and+b=log+17+25+then+which+one+is+greater

Answer»

Answer:

the QUESTION is not correctly written

then only I will HELP you

mark it as BRAINLIEST plz

follow me

Discussion

28.	Find the sum of all 2 digital natural number that are divisible by 5
Answer» GIVEN : 2 digital natural NUMBER divisible by 5 To Find : the sum Solution: 2 digits natural numbers 10 , 11 , 12 ___________________98 , 99 Divisible by 5 10 , 15 , 20 __________________90 , 95 95 = 10 + (n - 1) 5 => n = 18 Sum = (18/2)(10 + 95) = 9 * 105 = 945 sum of 2 digital natural number which are divisible by 5 is 945 Learn More: The sum of all integers between 200 and 800, which is divisible by 9 ... brainly.in/question/12590445 find the sum of all integers from 100 to 400, which are divisible by ... brainly.in/question/12947068

28.

Find the sum of all 2 digital natural number that are divisible by 5

Answer»

GIVEN : 2 digital natural NUMBER divisible by 5

To Find : the sum

Solution:

2 digits natural numbers

10 , 11 , 12 ___________________98 , 99

Divisible by 5

10 , 15 , 20 __________________90 , 95

95 = 10 + (n - 1) 5

=> n = 18

Sum = (18/2)(10 + 95)

= 9 * 105

= 945

sum of 2 digital natural number which are divisible by 5 is 945

Learn More:

The sum of all integers between 200 and 800, which is divisible by 9 ...

brainly.in/question/12590445

find the sum of all integers from 100 to 400, which are divisible by ...

brainly.in/question/12947068

Discussion

29.	Find the value of √U^-1 ×V √v^-1 × W√W^-1 × .
Answer» Step-by-step EXPLANATION: INCOMPLETE QUESTION COMPLETE the question FIRST

29.

Find the value of √U^-1 ×V √v^-1 × W√W^-1 × .

Answer»

Step-by-step EXPLANATION:

INCOMPLETE QUESTION COMPLETE the question FIRST

Discussion

30.	Today is varuns birthday one year from today he will be twice as old as he was 12 years ago. How old is varun today?
Answer» Step-by-step explanation: let the PRESENT age of varun be X YEARS According to the GIVEN condition x+1=2(x-12) x+1=2x-24 2x-x=24+1 x=25 ANS: The present age of varun is 25 years

30.

Today is varuns birthday one year from today he will be twice as old as he was 12 years ago. How old is varun today?

Answer»

Step-by-step explanation:

let the PRESENT age of varun be X YEARS

According to the GIVEN condition

x+1=2(x-12)

x+1=2x-24

2x-x=24+1

x=25

ANS: The present age of varun is 25 years

Discussion

31.	When two chords intersect inside a circle prove that there is rectangle?
Answer» Answer: when two chords intersect in a circle then angle between them is 90because it BISECTS so if one angle is 90 DEGREES then it becomes a rectangle

31.

When two chords intersect inside a circle prove that there is rectangle?

Answer»

Answer:

when two chords intersect in a circle then angle between them is 90because it BISECTS so if one angle is 90 DEGREES then it becomes a rectangle

Discussion

32.	(a+b+c)2 + (a-b-c)2
Answer» ANSWER: 4a Step-by-step explanation: 2a + 2B + 2C +(2a-2b-2c) = 2a Pls MARK as BRAINLIEST

32.

(a+b+c)2 + (a-b-c)2

Answer»

ANSWER:

4a

Step-by-step explanation:

2a + 2B + 2C +(2a-2b-2c) = 2a

Pls MARK as BRAINLIEST

Discussion

33.	in a rectangle ABCD BM and CN are perpendicular from B and D respectively on AC . Show that triangle BMC congurent to triangle DNA
Answer» GIVEN : ABCD is a rectangle and BM ⊥AC and DN⊥AC To prove: $\bigtriangleup BMC \cong \bigtriangleup DNA$ Solution : we know that ABCD is a rectangle and BM ⊥AC and DN⊥AC then $\angle BMC = 90^\circ \\\\\angle DNA = 90^\circ$ (angles of the rectangle ) in triangle BMC and DNA BC = AD (opposite side of rectangle are EQUAL ) $\angle DAN = \angle BCM$ $\angle ADN = 180^\circ - (\angle DAN)- (\angle DNA)\\\\\angle ADN = 180^\circ - (\angle BCM)- (\angle BMC)\\\\\angle ADN =\angle CBM$ thus , $\bigtriangleup BMC \cong \bigtriangleup DNA$ by (ASA property) Hence proved #LEARN more : brainly.in/question/6053411

33.

in a rectangle ABCD BM and CN are perpendicular from B and D respectively on AC . Show that triangle BMC congurent to triangle DNA

Answer»

GIVEN : ABCD is a rectangle and BM ⊥AC and DN⊥AC

To prove: $\bigtriangleup BMC \cong \bigtriangleup DNA$

Solution :

we know that ABCD is a rectangle

and

BM ⊥AC and

DN⊥AC

then

$\angle BMC = 90^\circ \\\\\angle DNA = 90^\circ$

(angles of the rectangle )

in triangle BMC and DNA

BC = AD (opposite side of rectangle are EQUAL )

$\angle DAN = \angle BCM$

$\angle ADN = 180^\circ - (\angle DAN)- (\angle DNA)\\\\\angle ADN = 180^\circ - (\angle BCM)- (\angle BMC)\\\\\angle ADN =\angle CBM$

thus ,

$\bigtriangleup BMC \cong \bigtriangleup DNA$

by (ASA property)

Hence proved

#LEARN more :

brainly.in/question/6053411

Discussion

34.	Find the least square number which is exactly divisible by each of the following 20, 15, 6 and 9
Answer» the LEAST NUMBER is 2 and 3

Discussion

35.	According to a study, hair grows about half a millimetre each day. How much time does it take for Tina hair to grow 1 meter( 1000 millimetres) longer?A) 9 yearsB) 3 yearsC) 6 yearsD) 1 years
Answer» Answer: It TAKES nearly 1 YEAR to 1year HALF .

35.

According to a study, hair grows about half a millimetre each day. How much time does it take for Tina hair to grow 1 meter( 1000 millimetres) longer?A) 9 yearsB) 3 yearsC) 6 yearsD) 1 years

Answer»

Answer:

It TAKES nearly 1 YEAR to 1year HALF .

Discussion

36.	(2.5×10^10)×(31.25×10^-5)
Answer» ANSWER: $\mathrm{Simplify}\:\left(2.5\times \:10^{10}\right)\times \left(31.25\times \:10^{-5}\right):\quad 7812500$ Step-by-step EXPLANATION: $\left(2.5\times \:10^{10}\right)\left(31.25\times \:10^{-5}\right)$ $\gray{\mathrm{Apply\:exponent\:rule}:\quad \:a^b\times \:a^c=a^{b+c}}$ $\gray{10^{10}\times \:10^{-5}=\:10^{10-5}}$ $=2.5\times \:31.25\times \:10^{10-5}$ $\gray{\mathrm{Subtract\:the\:numbers:}\:10-5=5}$ $=2.5\times \:31.25\times \:10^5$ $\gray{\mathrm{Multiply\:the\:numbers:}\:2.5\times \:31.25=78.125}$ $=10^5\times \:78.125$ $\gray{10^5=100000}$ $=100000\times \:78.125$ $\gray{\mathrm{Multiply\:the\:numbers:}\:78.125\times \:100000=7812500}$ $=7812500$

36.

(2.5×10^10)×(31.25×10^-5)

Answer»

ANSWER:

$\mathrm{Simplify}\:\left(2.5\times \:10^{10}\right)\times \left(31.25\times \:10^{-5}\right):\quad 7812500$

Step-by-step EXPLANATION:

$\left(2.5\times \:10^{10}\right)\left(31.25\times \:10^{-5}\right)$

$\gray{\mathrm{Apply\:exponent\:rule}:\quad \:a^b\times \:a^c=a^{b+c}}$

$\gray{10^{10}\times \:10^{-5}=\:10^{10-5}}$

$=2.5\times \:31.25\times \:10^{10-5}$

$\gray{\mathrm{Subtract\:the\:numbers:}\:10-5=5}$

$=2.5\times \:31.25\times \:10^5$

$\gray{\mathrm{Multiply\:the\:numbers:}\:2.5\times \:31.25=78.125}$

$=10^5\times \:78.125$

$\gray{10^5=100000}$

$=100000\times \:78.125$

$\gray{\mathrm{Multiply\:the\:numbers:}\:78.125\times \:100000=7812500}$

$=7812500$

Discussion

37.	X-a/x-3+x-4/x-5=10/3 solv the x
Answer» ANSWER: X*===45 is the BEST answer for the QUESTION

37.

X-a/x-3+x-4/x-5=10/3 solv the x

Answer»

ANSWER:

X*===45 is the BEST answer for the QUESTION

Discussion

38.	The area of a rectangle is 70 in² and the length of the rectangle is 3 in. longer than the width.The area of a rectangle is found by multiplying the length times the width.During the Set Up step of the five-step problem-solving plan, which equation would you set up to solve for the width?a) w + 3w = 70b) w(w+3)=70c) 3w = 70d) w + 3 = 70
Answer» ANSWER: w+3 = 70 (option d) Step-by-step explanation: Given Problem: The area of a rectangle is 70 in² and the length of the rectangle is 3 in. longer than the width. The area of a rectangle is found by multiplying the length TIMES the width. During the Set Up step of the five-step problem-solving PLAN, which equation would you set up to solve for the width? a) w + 3W = 70 b) w(w+3)=70 c) 3w = 70 d) w + 3 = 70 Solution: Rectangle Formula: W.L = rectangle area W.(w+3) = 70 Hence, Answer is (Option D)

38.

The area of a rectangle is 70 in² and the length of the rectangle is 3 in. longer than the width.The area of a rectangle is found by multiplying the length times the width.During the Set Up step of the five-step problem-solving plan, which equation would you set up to solve for the width?a) w + 3w = 70b) w(w+3)=70c) 3w = 70d) w + 3 = 70

Answer»

ANSWER:

w+3 = 70 (option d)

Step-by-step explanation:

Given Problem:

The area of a rectangle is 70 in² and the length of the rectangle is 3 in. longer than the width.

The area of a rectangle is found by multiplying the length TIMES the width.

During the Set Up step of the five-step problem-solving PLAN, which equation would you set up to solve for the width?

a) w + 3W = 70

b) w(w+3)=70

c) 3w = 70

d) w + 3 = 70

Solution:

Rectangle Formula:

W.L = rectangle area

W.(w+3) = 70

Hence,

Answer is (Option D)

Discussion

39.	Change the following sentences into interrogative sentences:i Sheeba takes part in sports activities.ii.iii.iv.The school will close for summer holidays tomorrowThe recess is over.We exercise everyday in the morning.I knew what she wanted.n helow to frame four different types of
Answer» Answer: ●Here is your answer ● Did seeba takes PART in SPORT activity? Did SCHOOL close for summer holiday? Did the RECESS over?

39.

Change the following sentences into interrogative sentences:i Sheeba takes part in sports activities.ii.iii.iv.The school will close for summer holidays tomorrowThe recess is over.We exercise everyday in the morning.I knew what she wanted.n helow to frame four different types of

Answer»

Answer:

●Here is your answer ●

Did seeba takes PART in SPORT activity?
Did SCHOOL close for summer holiday?
Did the RECESS over?

Discussion

40.	what three numbers have the same answer when added together and multiplied together. Best will get brainlest, follower and thanks
Answer» Answer: 1,2,3 Step-by-step explanation: 1+2+3= 6 1×2×3= 6

40.

what three numbers have the same answer when added together and multiplied together. Best will get brainlest, follower and thanks

Answer»

Answer:

1,2,3

Step-by-step explanation:

1+2+3= 6

1×2×3= 6

Discussion

41.	in which quadrant or on which Axis to each of the following points (- 2, 4,) (3, - 1, )(- 4, 0, )(2, 3) lie?
Answer» ANSWER: (-2, 4) lies on the SECOND QUADRANT (3, -1) lies on the fourth quadrant (-4, 0) lies on the x axis (2, 3) lies on the FIRST quadrant

41.

in which quadrant or on which Axis to each of the following points (- 2, 4,) (3, - 1, )(- 4, 0, )(2, 3) lie?

Answer»

ANSWER:

(-2, 4) lies on the SECOND QUADRANT

(3, -1) lies on the fourth quadrant

(-4, 0) lies on the x axis

(2, 3) lies on the FIRST quadrant

Discussion

42.	L. Construct a quadrilateral ABCD, given thatAB = 4 cm, BC = 5 cm, angleA = 50°, angleB = 110° and angleC = 70°.
Answer» Step-by-step explanation: steps for construction 1. draw line AB = 4 cm. 2. on A draw ANGLE 50° same on B draw angle 110°. 3. Now on the angle B cut an ARC of 5 cm and mark that arc as POINT C. 4. on C draw angle 70°. 5. Now EXTEND the line of angle A and angle C and join them. 6. mark it point D.

42.

L. Construct a quadrilateral ABCD, given thatAB = 4 cm, BC = 5 cm, angleA = 50°, angleB = 110° and angleC = 70°.

Answer»

Step-by-step explanation:

steps for construction

1. draw line AB = 4 cm.

2. on A draw ANGLE 50° same on B draw angle 110°.

3. Now on the angle B cut an ARC of 5 cm and mark that arc as POINT C.

4. on C draw angle 70°.

5. Now EXTEND the line of angle A and angle C and join them.

6. mark it point D.

Discussion

43.	How many different ways can $50 and be made using only $5 and $10 bills?(A) 4(B) 5C) 6D) 7
Answer» ANSWER: there are 5DIFFERENCE

43.

How many different ways can $50 and be made using only $5 and $10 bills?(A) 4(B) 5C) 6D) 7

Answer»

ANSWER:

there are 5DIFFERENCE

Discussion

44.	If a =2 +under root 3 ,find the value of a power 3 - 1 by a power 3
Answer» Step-by-step EXPLANATION: a =2+√3 1/a = 1/2+√3 = (2-√3)/(2+√3)(2-√3) = (2-√3)/(4-3) = (2-√3) a+ 1/a = 4 SQUARING on both sides we get ${(a + \frac{1}{a})}^{2} = 16 = > {a}^{2} + \frac{1}{{a}^{2}} + 2 = 16$ $= > {a}^{2} + \frac{1}{ {a}^{2}} = 14$ a -1/a =>(2+√3)-(2-√3) =>2√3. ${a}^{3} - \frac{1}{{a}^3} = (a - \frac{1}{a})({a}^{2} + \frac{1}{ {a}^{2}} + 1) = >$ ${a}^{3} - \frac{1}{ {a}^{3}} = 2 \sqrt{3}(14 + 1) = 30 \sqrt{3}$ Hope it helps you.

44.

If a =2 +under root 3 ,find the value of a power 3 - 1 by a power 3

Answer»

Step-by-step EXPLANATION:

a =2+√3

1/a = 1/2+√3 = (2-√3)/(2+√3)(2-√3) =

(2-√3)/(4-3) = (2-√3)

a+ 1/a = 4 SQUARING on both sides we get

${(a + \frac{1}{a})}^{2} = 16 = > {a}^{2} + \frac{1}{{a}^{2}} + 2 = 16$

$= > {a}^{2} + \frac{1}{ {a}^{2}} = 14$

a -1/a =>(2+√3)-(2-√3) =>2√3.

${a}^{3} - \frac{1}{{a}^3} = (a - \frac{1}{a})({a}^{2} + \frac{1}{ {a}^{2}} + 1) = >$

${a}^{3} - \frac{1}{ {a}^{3}} = 2 \sqrt{3}(14 + 1) = 30 \sqrt{3}$

Hope it helps you.

Discussion

45.	(3k-4r-2m)^2-(3k+4r-2m)^2Simplify this sum:
Answer» Answer: 9k²+16k²+4m²-24kr +16rm -12mk-9k²-16r²-4m²-24kr+16 RM +12mk

45.

(3k-4r-2m)^2-(3k+4r-2m)^2Simplify this sum:

Answer»

Answer:

9k²+16k²+4m²-24kr +16rm -12mk-9k²-16r²-4m²-24kr+16 RM +12mk

Discussion

46.	Examples of Vedic maths with examples
Answer» Step-by-step EXPLANATION: Bro Vedic MATHS also has topics we cannot tell them just by GIVING any examples and also it is a methodology not any number like RATIONAL number etc

46.

Examples of Vedic maths with examples

Answer»

Step-by-step EXPLANATION:

Bro Vedic MATHS also has topics we cannot tell them just by GIVING any examples and also it is a methodology not any number like RATIONAL number etc

Discussion

47.	P, Q, R and S go for a picnic. When P stands on a weighingmachine, Q also climbs on, and the weight shown was 132 kg.When Q stands, R also climbs on, and the machine shows 130kg. Similarly the weight of Rand S is found as 102 kg and thatof Q and S is 116 kg. What is Q weight?(A) 58kg(B) 78 kg(C) 67 kg(D) 44 Kg
Answer» ANSWER: c67 is the answer of your QUESTION

47.

P, Q, R and S go for a picnic. When P stands on a weighingmachine, Q also climbs on, and the weight shown was 132 kg.When Q stands, R also climbs on, and the machine shows 130kg. Similarly the weight of Rand S is found as 102 kg and thatof Q and S is 116 kg. What is Q weight?(A) 58kg(B) 78 kg(C) 67 kg(D) 44 Kg

Answer»

ANSWER:

c67 is the answer of your QUESTION

Discussion

48.	If the cost of 56 apples are 120 then what is the cost of an apple?
Answer» Cost of 56 apple is =RS. 120 so, cost of ONE apple is = rs. 56÷120 = rs. 2.14

48.

If the cost of 56 apples are 120 then what is the cost of an apple?

Answer»

Cost of 56 apple is =RS. 120

so, cost of ONE apple is = rs. 56÷120

= rs. 2.14

Discussion

49.	Nia is 3 years younger than Jordan. Jordan is 36 years old.After correctly carrying out the Solve step of the five-step problem-solving plan, which solution should you arrive at to find Nia’s age?a) 30b) 33c) 36d) 39
Answer» Answer: 33 Step-by-step explanation: because Nia is 3 years YOUNGER than JORDAN If Jordan is 36 then Nia is (36-3) = 33 years old

49.

Nia is 3 years younger than Jordan. Jordan is 36 years old.After correctly carrying out the Solve step of the five-step problem-solving plan, which solution should you arrive at to find Nia’s age?a) 30b) 33c) 36d) 39

Answer»

Answer:

33

Step-by-step explanation:

because Nia is 3 years YOUNGER than JORDAN

If Jordan is 36

then Nia is (36-3)

= 33 years old

Discussion

50.	Expand and siimplify (x-2) (x-1)
Answer» ANSWER: X^2-3x+2 Step-by-step EXPLANATION: (x-2)(x-1) x^2-x(1)-2(x)+2 x^2-x-2x+2 x^-3x+2

50.

Expand and siimplify (x-2) (x-1)

Answer»

ANSWER:

X^2-3x+2

Step-by-step EXPLANATION:

(x-2)(x-1)

x^2-x(1)-2(x)+2

x^2-x-2x+2

x^-3x+2

Discussion

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