1.

Simplify (64/125)^2×(4/5)^4×(16/25)^2x+1=(256/625)^3x

Answer»

\displaystyle\huge\red{\underline{\underline{Solution}}}

FORMULA TO BE IMPLEMENTED

1. \:  \:  \:  \sf{ {a}^{m}  \times  {a}^{n}  = {a}^{m + n}  \: }

2. \:  \: \sf{{ ({a}^{m})}^{n}  = {a}^{m n}  \: }

TO DETERMINE

The VALUE of X when

\displaystyle \sf{  { \bigg(  \frac{64}{125} \bigg)}^{2}  \times { \bigg(  \frac{4}{5} \bigg)}^{4} \times  { \bigg(  \frac{16}{25} \bigg)}^{2x + 1}\: ={ \bigg(  \frac{256}{625} \bigg)}^{3x}  }

CALCULATION

\displaystyle \implies \:  \sf{  { \bigg[  {\bigg(  \frac{4}{5} \bigg)}^{3} \bigg]}^{2}  \times { \bigg(  \frac{4}{5} \bigg)}^{4} \times  { { \bigg[  {\bigg(  \frac{4}{5} \bigg)}^{2} \bigg]}}^{2x + 1}\: ={ { \bigg[  {\bigg(  \frac{4}{5} \bigg)}^{4} \bigg]}}^{3x}  }

\implies \: \displaystyle \sf{  { \bigg(  \frac{4}{5} \bigg)}^{6}  \times { \bigg(  \frac{4}{5} \bigg)}^{4} \times  { \bigg(  \frac{4}{5} \bigg)}^{4x + 2}\: ={ \bigg(  \frac{4}{5} \bigg)}^{12x}  }

\implies \: \displaystyle \sf{  { \bigg(  \frac{4}{5} \bigg)}^{4x + 12}   ={ \bigg(  \frac{4}{5} \bigg)}^{12x}  }

\implies \: \displaystyle \sf{ 4x +1 2 = 12x}

\implies \: \displaystyle \sf{8x =  12}

\implies \: \displaystyle \sf{ x =   \frac{3}{2} }

RESULT

The ANSWER is

\boxed{ \: \displaystyle \sf{ \:   x =   \frac{3}{2}  \:  \:  \: }}



Discussion

No Comment Found

Related InterviewSolutions