in a rectangle ABCD BM and CN are perpendicular from B and D respectiv

1.	in a rectangle ABCD BM and CN are perpendicular from B and D respectively on AC . Show that triangle BMC congurent to triangle DNA
Answer» GIVEN : ABCD is a rectangle and BM ⊥AC and DN⊥AC To prove: $\bigtriangleup BMC \cong \bigtriangleup DNA$ Solution : we know that ABCD is a rectangle and BM ⊥AC and DN⊥AC then $\angle BMC = 90^\circ \\\\\angle DNA = 90^\circ$ (angles of the rectangle ) in triangle BMC and DNA BC = AD (opposite side of rectangle are EQUAL ) $\angle DAN = \angle BCM$ $\angle ADN = 180^\circ - (\angle DAN)- (\angle DNA)\\\\\angle ADN = 180^\circ - (\angle BCM)- (\angle BMC)\\\\\angle ADN =\angle CBM$ thus , $\bigtriangleup BMC \cong \bigtriangleup DNA$ by (ASA property) Hence proved #LEARN more : brainly.in/question/6053411