Find area of triangle whose vertices are (t,t-2),(t+2,t+2) and (t+3,t)

1.	Find area of triangle whose vertices are (t,t-2),(t+2,t+2) and (t+3,t).
Answer» Answer: 2t+8 Step-by-step explanation: AREA of a TRIANGLE is GIVEN by 1/2 × \|x1(y2-y3)-X2(y3-y1)+x3(y1-y2)\| =1/2 ×\|t(t+2-t)-(t+2)(t-t+2)+(t+3)(t-2-t-2)\| =1/2×\|2t-2t-4-4t-12\| =1/2×\|-4t-16\| =2t+8

Find area of triangle whose vertices are (t,t-2),(t+2,t+2) and (t+3,t).

Answer»

Answer:

2t+8

Step-by-step explanation:

AREA of a TRIANGLE is GIVEN by

1/2 × |x1(y2-y3)-X2(y3-y1)+x3(y1-y2)|

=1/2 ×|t(t+2-t)-(t+2)(t-t+2)+(t+3)(t-2-t-2)|

=1/2×|2t-2t-4-4t-12|

=1/2×|-4t-16|

=2t+8

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Find area of triangle whose vertices are (t,t-2),(t+2,t+2) and (t+3,t).

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