332354 + Interview Questions in Secondary School in Math

1.	1)the length of tangents drawn from point (3,-4) to the circle 2x2 + 2y2 - 7x - 9y - 13 = 0 is1)root 262)53)root 284)root 30
Answer» ANSWER: ROOT 26 is the answer please SAY I am brainleta

1.

1)the length of tangents drawn from point (3,-4) to the circle 2x2 + 2y2 - 7x - 9y - 13 = 0 is1)root 262)53)root 284)root 30

Answer»

ANSWER:

ROOT 26 is the answer

please SAY I am brainleta

Discussion

2.	A) If m=2, n=3 then find 4m2 - 372 +mn.b) 25x5* = 58 then find 'r' value?Please tell me 2 answer
Answer» ANSWER: not SURE about the ANS....

2.

A) If m=2, n=3 then find 4m2 - 372 +mn.b) 25x5* = 58 then find 'r' value?Please tell me 2 answer

Answer»

ANSWER:

not SURE about the ANS....

Discussion

3.	Weightage of 5 members of a team measured seriallyand calculate their average weight, calculated aftereach member was attended. If every time, his averageweight is increased by 1 kg then the weight of lastplayer is how much more than the first player ?
Answer» Answer: Assume a PERSON is STANDING in FRONT of a PLANE MIRROR. The distance between the mirror and his image is 6m. If the person moves 2m towards the plane mirror

3.

Weightage of 5 members of a team measured seriallyand calculate their average weight, calculated aftereach member was attended. If every time, his averageweight is increased by 1 kg then the weight of lastplayer is how much more than the first player ?

Answer»

Answer:

Assume a PERSON is STANDING in FRONT of a PLANE MIRROR. The distance between the mirror and his image is 6m. If the person moves 2m towards the plane mirror

Discussion

4.	Karan went to the Lab near to his home for COVID 19 test along with his familymembers. The seats in the waiting area were as per the norms of distancing during this pandemic (as shown in the above figure). His family member took their seats surrounded by red circular area. (i) Considering A as the origin, what are the coordinates of A? a) (0,1) b) (1,0) c) (0,0) d)(-1,-1) (ii) What is the distance between Neena and Karan ?a) 10 b) 2√5 c)√10 d)√8 (iii) What are the coordinates of seat of Akash ? a) (2,3) b) (3,2) c) (0,3) d) (2,0) (iv) What will be the coordinates of a point exactly between Akash and Binu where a person can be seated? a) (3.5,2.5) b) (2.5,5) c) (10,5) d) (1.5,0.5) (v) Determine the shape of the figure we get on joining the points where Karan’s family members are seated. a) Rectangle b ) Square c) Parallelogram d) Rhombusplease tell me fast
Answer» SOLUTION TO DETERMINE Karan went to the Lab near to his home for COVID 19 test along with his family members. The seats in the waiting area were as PER the norms of distancing during this pandemic (as shown in the above figure). His family member took their seats surrounded by red circular area. (i) Considering A as the origin, what are the coordinates of A? a) (0,1) b) (1,0) c) (0,0) d)(-1,-1) (ii) What is the distance between Neena and Karan a) 10 b) 2√5 c)√10 d)√8 (iii) What are the coordinates of seat of Akash a) (2,3) b) (3,2) c) (0,3) d) (2,0) (iv) What will be the coordinates of a point EXACTLY between Akash and BINU where a person can be seated? a) (3.5,2.5) b) (2.5,5) c) (10,5) d) (1.5,0.5) (V) Determine the SHAPE of the figure we get on joining the points where Karan’s family members are seated. a) Rectangle b ) Square c) Parallelogram d) Rhombus EVALUATION (i) Here A is origin So the coordinates of A is (0,0) Hence the correct option is c) (0,0) (ii) In the figure : Coordinates of Neena is (3,6) Coordinates of Karan is (6,5) ∴ The distance between Neena and Karan $\sf{ = \sqrt{ {(6 - 3)}^{2} + {(5 - 6)}^{2} } }$ $\sf{ = \sqrt{9 + 1} }$ $\sf{ = \sqrt{10} }$ Hence the correct option is c) √10 (iii) From the figure the coordinates of seat of Akash is (2,3) Hence the correct option is a) (2,3) (iv) The coordinates of seat of Akash is (2,3) The coordinates of Binu is (5,2) Midpoint of the line joining the points (2,3) & (5,2) is $\displaystyle \sf{ = \bigg( \: \frac{2 + 5}{2} \: ,\: \frac{3 + 2}{2} \: \bigg)}$ $\displaystyle \sf{ = \bigg( \: \frac{7}{2} \: ,\: \frac{5}{2} \: \bigg)}$ $\displaystyle \sf{ = ( \: 3.5 \: ,\: 2.5 \: )}$ So the coordinates of a point exactly between Akash and Binu where a person can be seated is (3.5,2.5) Hence the correct option is a) (3.5,2.5) (v) From the figure it is clear that shape of the figure we get on joining the points where Karan’s family members are seated is Parallelogram Hence the correct option is c) Parallelogram ━━━━━━━━━━━━━━━━ Learn more from Brainly :- 1. Layana’s house is located at (2 and two-thirds, 7 and one-third) on a map. The store where she works is located at (–1 a... brainly.in/question/33307352 2. locate the following points on the cartesian plane(aEr) (0,a),(a,0),(-a, 0),(0,-a)... brainly.in/question/26822338

4.

Karan went to the Lab near to his home for COVID 19 test along with his familymembers. The seats in the waiting area were as per the norms of distancing during this pandemic (as shown in the above figure). His family member took their seats surrounded by red circular area. (i) Considering A as the origin, what are the coordinates of A? a) (0,1) b) (1,0) c) (0,0) d)(-1,-1) (ii) What is the distance between Neena and Karan ?a) 10 b) 2√5 c)√10 d)√8 (iii) What are the coordinates of seat of Akash ? a) (2,3) b) (3,2) c) (0,3) d) (2,0) (iv) What will be the coordinates of a point exactly between Akash and Binu where a person can be seated? a) (3.5,2.5) b) (2.5,5) c) (10,5) d) (1.5,0.5) (v) Determine the shape of the figure we get on joining the points where Karan’s family members are seated. a) Rectangle b ) Square c) Parallelogram d) Rhombusplease tell me fast

Answer»

SOLUTION

TO DETERMINE

Karan went to the Lab near to his home for COVID 19 test along with his family members.

The seats in the waiting area were as PER the norms of distancing during this pandemic (as shown in the above figure).

His family member took their seats surrounded by red circular area.

(i) Considering A as the origin, what are the coordinates of A?

a) (0,1) b) (1,0) c) (0,0) d)(-1,-1)

(ii) What is the distance between Neena and Karan

a) 10 b) 2√5 c)√10 d)√8

(iii) What are the coordinates of seat of Akash

a) (2,3) b) (3,2) c) (0,3) d) (2,0)

(iv) What will be the coordinates of a point EXACTLY between Akash and BINU where a person can be seated?

a) (3.5,2.5) b) (2.5,5) c) (10,5) d) (1.5,0.5)

(V) Determine the SHAPE of the figure we get on joining the points where Karan’s family members are seated.

a) Rectangle b ) Square c) Parallelogram d) Rhombus

EVALUATION

(i) Here A is origin

So the coordinates of A is (0,0)

Hence the correct option is c) (0,0)

(ii) In the figure : Coordinates of Neena is (3,6)

Coordinates of Karan is (6,5)

∴ The distance between Neena and Karan

$\sf{ = \sqrt{ {(6 - 3)}^{2} + {(5 - 6)}^{2} } }$

$\sf{ = \sqrt{9 + 1} }$

$\sf{ = \sqrt{10} }$

Hence the correct option is c) √10

(iii) From the figure the coordinates of seat of Akash is (2,3)

Hence the correct option is a) (2,3)

(iv) The coordinates of seat of Akash is (2,3)

The coordinates of Binu is (5,2)

Midpoint of the line joining the points (2,3) & (5,2) is

$\displaystyle \sf{ = \bigg( \: \frac{2 + 5}{2} \: ,\: \frac{3 + 2}{2} \: \bigg)}$

$\displaystyle \sf{ = \bigg( \: \frac{7}{2} \: ,\: \frac{5}{2} \: \bigg)}$

$\displaystyle \sf{ = ( \: 3.5 \: ,\: 2.5 \: )}$

So the coordinates of a point exactly between Akash and Binu where a person can be seated is (3.5,2.5)

Hence the correct option is a) (3.5,2.5)

(v) From the figure it is clear that shape of the figure we get on joining the points where Karan’s family members are seated is Parallelogram

Hence the correct option is

c) Parallelogram

━━━━━━━━━━━━━━━━

Learn more from Brainly :-

1. Layana’s house is located at (2 and two-thirds, 7 and one-third) on a map. The store where she works is located at (–1 a...

brainly.in/question/33307352

2. locate the following points on the cartesian plane(aEr) (0,a),(a,0),(-a, 0),(0,-a)...

brainly.in/question/26822338

Discussion

5.	a merchant gets 2 pens as gain when he selles 10 pens the percent of profit is option a-30 b-20 c-25 d-18
Answer» ANSWER: B)20 hope it HELPS you✨

5.

a merchant gets 2 pens as gain when he selles 10 pens the percent of profit is option a-30 b-20 c-25 d-18

Answer»

ANSWER:

B)20

hope it HELPS you✨

Discussion

6.	Determine whether the following system of linear equations is consistent or inconsistent 1) x+y=3, 3x-2y=42)3x+y+1=9 ; 2x-3y+8=03)x-2y=6 ; 3x-6y=04)2x+3y=9 ; x-y=2
Answer» ANSWER: haiJjzzbjzjbzizjjzjizjzj Step-by-step EXPLANATION: cHBzbnJ

6.

Determine whether the following system of linear equations is consistent or inconsistent 1) x+y=3, 3x-2y=42)3x+y+1=9 ; 2x-3y+8=03)x-2y=6 ; 3x-6y=04)2x+3y=9 ; x-y=2

Answer»

ANSWER:

haiJjzzbjzjbzizjjzjizjzj

Step-by-step EXPLANATION:

cHBzbnJ

Discussion

7.	Represent-3/7, 5/7, 9/7 on number with neat diagram.
Answer» ANSWER: -3/7, 5/7, 9/7 Step-by-step EXPLANATION:

7.

Represent-3/7, 5/7, 9/7 on number with neat diagram.

Answer»

ANSWER:

-3/7, 5/7, 9/7

Step-by-step EXPLANATION:

Discussion

8.	Area of figure formed by the lines x = 0, y = 0, x = 5 and y = 7 is
Answer» Answer: figure FORMED is a rectangle area is 35 square UNITS

8.

Area of figure formed by the lines x = 0, y = 0, x = 5 and y = 7 is

Answer»

Answer:

figure FORMED is a rectangle

area is 35 square UNITS

Discussion

9.	एका आयताकृती बाग॓ची लांबी ही रूंदी 5\|4पट असून त्या बागेला चार पदरी कुंपण घालण्यासाठी दर मिटर 36 रु प्रमाणे रु1,29,600 खर्च येतो तर त्या बागेचिं रुंदी किती? दोन पर्याय
Answer» Given :- The LENGTH of a rectangular garden is 5/4 times its breadth. The expenditure for four layered wiring around the garden at Rs.36 per meter is Rs.1,29,600. What is the breadth of the garden ? SOLUTION :- Let us assume that, Breadth of the rectangular garden is x m . so, → Length of rectangular garden = (5/4) of x = (5x/4) m . then, → Perimeter of rectangular garden = 2(Length + Breadth) = 2{(5x/4) + x} = 2{(5x + 4X)/4} = 2(9x/4) = (9x/2) m. therefore, → Perimeter od layering wire 4 times = 4 * (9x/2) = 18x m. hence, → 18x = (Total cost/Rate) → 18x = (129600/36) → 18x * 36 = 129600 → 648x = 129600 → x = 200 m (Ans.) Learn more :- The cost of sunflower oil is increased by 30 % due to which CONSUMPTION is decreased by 20%. Percentage change in the ex... brainly.in/question/35132516

9.

एका आयताकृती बाग॓ची लांबी ही रूंदी 5|4पट असून त्या बागेला चार पदरी कुंपण घालण्यासाठी दर मिटर 36 रु प्रमाणे रु1,29,600 खर्च येतो तर त्या बागेचिं रुंदी किती? दोन पर्याय

Answer»

Given :- The LENGTH of a rectangular garden is 5/4 times its breadth. The expenditure for four layered wiring around the garden at Rs.36 per meter is Rs.1,29,600. What is the breadth of the garden ?

SOLUTION :-

Let us assume that, Breadth of the rectangular garden is x m .

so,

→ Length of rectangular garden = (5/4) of x = (5x/4) m .

then,

→ Perimeter of rectangular garden = 2(Length + Breadth) = 2{(5x/4) + x} = 2{(5x + 4X)/4} = 2(9x/4) = (9x/2) m.

therefore,

→ Perimeter od layering wire 4 times = 4 * (9x/2) = 18x m.

hence,

→ 18x = (Total cost/Rate)

→ 18x = (129600/36)

→ 18x * 36 = 129600

→ 648x = 129600

→ x = 200 m (Ans.)

Learn more :-

The cost of sunflower oil is increased by 30 % due to which CONSUMPTION is decreased by 20%. Percentage

change in the ex...

brainly.in/question/35132516

Discussion

10.	L is LCM of 36 30,90G is GCD of 90,30,36Find L/G
Answer» ANSWER: it is 180/180=1 SO 1 IS THE ANSWER MARK IT AS BRAINLIEST IF SATISFIED

10.

L is LCM of 36 30,90G is GCD of 90,30,36Find L/G

Answer»

ANSWER:

it is

180/180=1

SO 1 IS THE ANSWER

MARK IT AS BRAINLIEST IF SATISFIED

Discussion

11.	वॉटर इन ए कैनल 6 मीटर वाइड एंड 1.5 मीटर टेप पोयम विद स्पीड ऑफ 10 किलोमीटर पर आर हाउ मच एरिया विल ई गेट इन 30 सेकंड
Answer» ANSWER: Can U TYPE in ENGLISH?

11.

वॉटर इन ए कैनल 6 मीटर वाइड एंड 1.5 मीटर टेप पोयम विद स्पीड ऑफ 10 किलोमीटर पर आर हाउ मच एरिया विल ई गेट इन 30 सेकंड

Answer»

ANSWER:

Can U TYPE in ENGLISH?

Discussion

12.	Find the value of y in the below figure.
Answer» ANSWER: y =15 Step-by-step explanation: angle DOF = 4y (vertically opp ANGLES) 5y + 4y +3Y = 180(angles in a line) 12Y= 180 y=15

12.

Find the value of y in the below figure.

Answer»

ANSWER:

y =15

Step-by-step explanation:

angle DOF = 4y (vertically opp ANGLES)

5y + 4y +3Y = 180(angles in a line)

12Y= 180

y=15

Discussion

13.	A) The marked price of a book is Rs. 250 & discount is 15% thenfind amount to be paid.b)The selling price of a gift is Rs. 550, cost price is Rs. 400.Find profit or Loss percentage.Please tell me 2 answer
Answer» ANSWER: A = MARKED PRICE = 250 discount =15% 250×15/100 =37.5 actual price =237.5 B = SELLING price -cost price =profit 550-400 =150 profit

13.

A) The marked price of a book is Rs. 250 & discount is 15% thenfind amount to be paid.b)The selling price of a gift is Rs. 550, cost price is Rs. 400.Find profit or Loss percentage.Please tell me 2 answer

Answer»

ANSWER:

A = MARKED PRICE = 250

discount =15%

250×15/100

=37.5

actual price =237.5

B = SELLING price -cost price =profit

550-400

=150 profit

Discussion

14.	In figure sides QP and RQ of ∆PQR are produced to points S and T respectively.If ∠SPR = 135° and ∠PQT = 110°, find ∠PRQ.
Answer» ∠PQT+∠PQR=180°. (STRAIGHT ANGLE MADE on LINE TR at point Q) 110° +∠PQR=180° ∠PQR = 180° − 110° = 70° In △PQR ∠PSR=∠PQR+∠PRQ (Exterior angle of triangle is eqal to sum of two interior angles) 135° = 70° +∠PRQ ∠PRQ = 135° −70° = 65°

14.

In figure sides QP and RQ of ∆PQR are produced to points S and T respectively.If ∠SPR = 135° and ∠PQT = 110°, find ∠PRQ.

Answer»

∠PQT+∠PQR=180°. (STRAIGHT ANGLE MADE on LINE TR at point Q)

110° +∠PQR=180°

∠PQR = 180° − 110° = 70°

In △PQR

∠PSR=∠PQR+∠PRQ (Exterior angle of triangle is eqal to sum of two interior angles)

135° = 70° +∠PRQ

∠PRQ = 135° −70° = 65°

Discussion

15.	If A(1 , 5) , B(6 , -1) and C( -2,-3) are the vertices of a triangle , then the slope of its median through A is :
Answer» Answer: as U WANT median it connects to MIDPOINT of BC Step-by-step explanation: refer to attachment hope it helps you

15.

If A(1 , 5) , B(6 , -1) and C( -2,-3) are the vertices of a triangle , then the slope of its median through A is :

Answer»

Answer:

as U WANT median it connects to MIDPOINT of BC

Step-by-step explanation:

refer to attachment

hope it helps you

Discussion

16.	9. In a cricket match. Karan faces 50 balls. He hits 10 fours, 5 sixes and remainingsingles in his score of 82 runs. Find the probability that on playing next ball hewill:(i) hit a four(ii) make a single run.(iii) not be able to score.
Answer» Answer: 23/50 Step-by-step explanation: Total number of balls FACED = 50 Total number of possible outcomes = 50 It is given that he HITS 10 boundaries and 5 sixes. Number of balls in which he score boundaries = 10 Number of balls in which he scores six = 5 Total runs in boundaries and sixes = 10×4+5×6 = 40+30 = 70 Total runs SCORED = 82So, runs scored in SINGLES = 82 − 70 = 12 Number of balls faced for singles = 12(1). Number of balls in which he score boundaries = 10 Number of favourable outcomes = 10 P(hitting 4) = Number of favourable outcomes Total number of possible outcomes = 1050 = 15(2). Number of balls in which he scores sixes=5 Number of favourable outcomes = 5 P(hitting 6) = Number of favourable outcomes Total number of possible outcomes = 550 = 110(3). Number of balls in which he does not score run = 50 − (10+5+12) = 50 − 27 = 23 Number of favourable outcomes = 23P(no run) = Number of favourable outcomes. Total number of possible outcomes = 23/50

16.

9. In a cricket match. Karan faces 50 balls. He hits 10 fours, 5 sixes and remainingsingles in his score of 82 runs. Find the probability that on playing next ball hewill:(i) hit a four(ii) make a single run.(iii) not be able to score.

Answer»

Answer:

23/50

Step-by-step explanation:

Total number of balls FACED = 50

Total number of possible outcomes = 50

It is given that he HITS 10 boundaries and 5 sixes.

Number of balls in which he score boundaries = 10

Number of balls in which he scores six = 5

Total runs in boundaries and sixes = 10×4+5×6

= 40+30

= 70

Total runs SCORED = 82So,

runs scored in SINGLES

= 82 − 70

= 12

Number of balls faced for singles = 12(1).

Number of balls in which he score boundaries = 10

Number of favourable outcomes = 10

P(hitting 4) = Number of favourable outcomes

Total number of possible outcomes = 1050 = 15(2).

Number of balls in which he scores sixes=5

Number of favourable outcomes = 5

P(hitting 6) = Number of favourable outcomes

Total number of possible outcomes = 550 = 110(3).

Number of balls in which he does not score run

= 50 − (10+5+12)

= 50 − 27

= 23

Number of favourable outcomes

= 23P(no run)

= Number of favourable outcomes.

Total number of possible outcomes = 23/50

Discussion

17.	Plot the following rational number on number line.
Answer» Step-by-step explanation: An ecosystem is a geographic area where PLANTS, animals, and other organisms, as well as weather and landscape, work together to form a BUBBLE of life. Ecosystems contain BIOTIC or living, parts, as well as abiotic factors, or NONLIVING parts. ... Ecosystems can be very LARGE or very small. ꉣ꒒ꇙꇙ ꊰ꒒ꅐ ꂵꏂ ꓄ꁝꏂꋊ ꒐ '꒒꒒ ꍌꋬ꒦ꏂ ꌦꄲ꒤ 10 ꓄ꁝꋬꋊꀘꇙ ❤.. ✌☺

17.

Plot the following rational number on number line.

Answer»

Step-by-step explanation:

An ecosystem is a geographic area where PLANTS, animals, and other organisms, as well as weather and landscape, work together to form a BUBBLE of life. Ecosystems contain BIOTIC or living, parts, as well as abiotic factors, or NONLIVING parts. ... Ecosystems can be very LARGE or very small.

ꉣ꒒ꇙꇙ ꊰ꒒ꅐ ꂵꏂ ꓄ꁝꏂꋊ ꒐ '꒒꒒ ꍌꋬ꒦ꏂ ꌦꄲ꒤ 10 ꓄ꁝꋬꋊꀘꇙ ❤.. ✌☺

Discussion

18.	Perform the operation 25x²y² ÷ 5xyz.
Answer» Answer: 5xy/z Step-by-step EXPLANATION: the answer hope it will HEPL

18.

Perform the operation 25x²y² ÷ 5xyz.

Answer»

Answer:

5xy/z

Step-by-step EXPLANATION:

the answer

hope it will HEPL

Discussion

19.	The height of a cone is 16cm and its base radius is 12cm. Find the curved surface area and the total surface area of the cone (Use π = 3.14).Note:-Wrong answer will reported on spot..!!!Correct answer with quality explanation will appreciated and mark as brainliest...!!!
Answer» ★ Concept:- Here the concept of CSA and TSA of the conce has been used. We see that we are given the height and radius of the cone. So firstly we can find its slant height. After FINDING this, we can apply required values and THUS find the answer. Let's Do It!!! ★FormulaUsed:: $\begin{gathered}\\\;\boxed{\sf{\purple{L^{2}\;=\;\bf{H^{2}\;+\;<klux>R</klux>^{2}}}}}\end{gathered}$ $\begin{gathered}\\\;\boxed{\sf{\pink{CSA\;of\;Cone\;=\;\bf{\pi rL}}}}\end{gathered}$ $\begin{gathered}\\\;\boxed{\sf{\purple{TSA\;of\;Cone\;=\;\bf{\pi rL\;+\;\pi r^{2}}}}}\end{gathered}$ Given, solution:- » Height of Cone = H = 16 cm » Radius of Cone = r = 12 cm » Value of π = 3.14 ~ For the slant Height of the Cone :: Let the Slant Height of the cone be L By relationship of Slant Height, we know that $\begin{gathered}\\\;\sf{\rightarrow\;\;L^{2}\;=\;\bf{H^{2}\;+\;r^{2}}}\end{gathered}$ By APPLYING values, we get $\begin{gathered}\\\;\sf{\rightarrow\;\;L^{2}\;=\;\bf{(16)^{2}\;+\;(12)^{2}}}\end{gathered}$ $\begin{gathered}\\\;\sf{\rightarrow\;\;L^{2}\;=\;\bf{256\;+\;144}}\end{gathered}$ $\begin{gathered}\\\;\sf{\rightarrow\;\;L^{2}\;=\;\bf{400}}\end{gathered}$ $\begin{gathered}\\\;\sf{\rightarrow\;\;L\;=\;\bf{\sqrt{400}}}\end{gathered}$ $\begin{gathered}\\\;\bf{\rightarrow\;\;Slant\;Height,\;L\;=\;\bf{\purple{20\;\;cm}}}\end{gathered}$ ~ For the CSA of Cone:: We know that, $\begin{gathered}\\\;\sf{\Longrightarrow\;\;CSA\;of\;Cone\;=\;\bf{\pi rL}}\end{gathered}$ By applying values, we get $\begin{gathered}\\\;\sf{\Longrightarrow\;\;CSA\;of\;Cone\;=\;\bf{3.14\:\times\:12\:\times\:20}}\end{gathered}$ $\begin{gathered}\\\;\bf{\Longrightarrow\;\;CSA\;of\;Cone\;=\;\bf{\red{753.6\;\;cm^{2}}}}\end{gathered}$ $\begin{gathered}\\\;\underline{\boxed{\tt{CSA\;\:of\;\:Cone\;=\;\bf{\pink{753.6\;\;cm^{2}}}}}}\end{gathered}$ ______________________________ ★More to know:- $\begin{gathered}\\\;\sf{\leadsto\;\;Volume\;of\;Cone\;=\;\dfrac{1}{3}\pi r^{2}H}\end{gathered}$ $\begin{gathered}\\\;\sf{\leadsto\;\;Volume\;of\;Cylinder\;=\;\pi r^{2}H}\end{gathered}$ $\begin{gathered}\\\;\sf{\leadsto\;\;TSA\;of\;Cylinder\;=\;2\pi rH\;+\;2\pi r^{2}}\end{gathered}$ $\begin{gathered}\\\;\sf{\leadsto\;\;CSA\;of\;Cylinder\;=\;2\pi rH}\end{gathered}$ $\begin{gathered}\\\;\sf{\leadsto\;\;Volume\;of\;Hollow\;Cone\;=\;\dfrac{1}{3}\pi (R^{2}\;-\;r^{2})H}\end{gathered}$

19.

The height of a cone is 16cm and its base radius is 12cm. Find the curved surface area and the total surface area of the cone (Use π = 3.14).Note:-Wrong answer will reported on spot..!!!Correct answer with quality explanation will appreciated and mark as brainliest...!!!

Answer»

★ Concept:-

Here the concept of CSA and TSA of the conce has been used. We see that we are given the height and radius of the cone. So firstly we can find its slant height. After FINDING this, we can apply required values and THUS find the answer.

Let's Do It!!!

★FormulaUsed::

$\begin{gathered}\\\;\boxed{\sf{\purple{L^{2}\;=\;\bf{H^{2}\;+\;<klux>R</klux>^{2}}}}}\end{gathered}$

$\begin{gathered}\\\;\boxed{\sf{\pink{CSA\;of\;Cone\;=\;\bf{\pi rL}}}}\end{gathered}$

$\begin{gathered}\\\;\boxed{\sf{\purple{TSA\;of\;Cone\;=\;\bf{\pi rL\;+\;\pi r^{2}}}}}\end{gathered}$

Given,

solution:-

» Height of Cone = H = 16 cm

» Radius of Cone = r = 12 cm

» Value of π = 3.14

~ For the slant Height of the Cone ::

Let the Slant Height of the cone be L

By relationship of Slant Height, we know that

$\begin{gathered}\\\;\sf{\rightarrow\;\;L^{2}\;=\;\bf{H^{2}\;+\;r^{2}}}\end{gathered}$

By APPLYING values, we get

$\begin{gathered}\\\;\sf{\rightarrow\;\;L^{2}\;=\;\bf{(16)^{2}\;+\;(12)^{2}}}\end{gathered}$

$\begin{gathered}\\\;\sf{\rightarrow\;\;L^{2}\;=\;\bf{256\;+\;144}}\end{gathered}$

$\begin{gathered}\\\;\sf{\rightarrow\;\;L^{2}\;=\;\bf{400}}\end{gathered}$

$\begin{gathered}\\\;\sf{\rightarrow\;\;L\;=\;\bf{\sqrt{400}}}\end{gathered}$

$\begin{gathered}\\\;\bf{\rightarrow\;\;Slant\;Height,\;L\;=\;\bf{\purple{20\;\;cm}}}\end{gathered}$

~ For the CSA of Cone::

We know that,

$\begin{gathered}\\\;\sf{\Longrightarrow\;\;CSA\;of\;Cone\;=\;\bf{\pi rL}}\end{gathered}$

By applying values, we get

$\begin{gathered}\\\;\sf{\Longrightarrow\;\;CSA\;of\;Cone\;=\;\bf{3.14\:\times\:12\:\times\:20}}\end{gathered}$

$\begin{gathered}\\\;\bf{\Longrightarrow\;\;CSA\;of\;Cone\;=\;\bf{\red{753.6\;\;cm^{2}}}}\end{gathered}$

$\begin{gathered}\\\;\underline{\boxed{\tt{CSA\;\:of\;\:Cone\;=\;\bf{\pink{753.6\;\;cm^{2}}}}}}\end{gathered}$

______________________________

★More to know:-

$\begin{gathered}\\\;\sf{\leadsto\;\;Volume\;of\;Cone\;=\;\dfrac{1}{3}\pi r^{2}H}\end{gathered}$

$\begin{gathered}\\\;\sf{\leadsto\;\;Volume\;of\;Cylinder\;=\;\pi r^{2}H}\end{gathered}$

$\begin{gathered}\\\;\sf{\leadsto\;\;TSA\;of\;Cylinder\;=\;2\pi rH\;+\;2\pi r^{2}}\end{gathered}$

$\begin{gathered}\\\;\sf{\leadsto\;\;CSA\;of\;Cylinder\;=\;2\pi rH}\end{gathered}$

$\begin{gathered}\\\;\sf{\leadsto\;\;Volume\;of\;Hollow\;Cone\;=\;\dfrac{1}{3}\pi (R^{2}\;-\;r^{2})H}\end{gathered}$

Discussion

20.	Two ratios are equivalent, if the ________ corresponding to them are equivalent
Answer» Answer: TWO ANGLES are equivalent, if the angles CORRESPONDING to them are equivalent. If it helps please MARK me brainliest.

20.

Two ratios are equivalent, if the ________ corresponding to them are equivalent

Answer»

Answer:

TWO ANGLES are equivalent, if the angles CORRESPONDING to them are equivalent.

If it helps please MARK me brainliest.

Discussion

21.	a cylinder is open at both ends and us made of 1.5 cm thick metal. it's external diameter is 12 cm and height is 84 cm. what is the volume of metal used in making the cylinder? also find the weight of the cylinder if 1 cm³ of the metal weighs 7.5 g
Answer» Answer: 11576.25 g = 11.57625 kg Step-by-step explanation: We have, external diameter =12 CM so, external radius R = 6 cm area of its external base = r² * 3.5 = 36 cm² 3.5= 126 cm² And height = 84 cm so, volume of the cylinder including the volume of the metal =area of it's external base height = 126 cm² * 84 cm = 10584 cm³ Now, INTERNAL diameter of the cylinder = 12 cm - 1.5 cm = 10.5 cm internal radius r = 10.5 cm /2 = 5.25 cm area of the internal base = r² * 3.5 = 5.25 cm * 3.5 = 18.375 cm² so, volume of the cylinder excluding the volume of the metal = area of the internal base * height =18.375 cm² * 84 cm =1543.5 cm³ Now, we have, weight of 1 cm³ = 7.5 g so, weight of 1543.5 cm³ = 7.5 g * 1543.5 = 11576.25 g = 11.57625 kg

21.

a cylinder is open at both ends and us made of 1.5 cm thick metal. it's external diameter is 12 cm and height is 84 cm. what is the volume of metal used in making the cylinder? also find the weight of the cylinder if 1 cm³ of the metal weighs 7.5 g

Answer»

Answer: 11576.25 g = 11.57625 kg

Step-by-step explanation:

We have,

external diameter =12 CM

so, external radius R = 6 cm

area of its external base = r² * 3.5 = 36 cm² *3.5= 126 cm²

And height = 84 cm

so, volume of the cylinder including the volume of the metal =area of it's external base * height = 126 cm² * 84 cm

= 10584 cm³

Now,

INTERNAL diameter of the cylinder = 12 cm - 1.5 cm = 10.5 cm

internal radius r = 10.5 cm /2 = 5.25 cm

area of the internal base = r² * 3.5 = 5.25 cm * 3.5 = 18.375 cm²

so, volume of the cylinder excluding the volume of the metal = area of the internal base * height

=18.375 cm² * 84 cm

=1543.5 cm³

Now, we have,

weight of 1 cm³ = 7.5 g

so, weight of 1543.5 cm³ = 7.5 g * 1543.5

= 11576.25 g

= 11.57625 kg

Discussion

22.	1. Evaluate the following:3(i) 7 x52Find
Answer» Step-by-step explanation: Answer ∫ 7x−2 − 7x−5 3 .dx ∫ 7x−2 − 7x−5 3 × 7x−2 − 7x−5 7x−2 + 7x+5 .dx =∫ (7x−2)−(7x−5) 3( 7x−2 + 7x−5 ) .dx =∫( 7x−2 + 7x−5 ).dx =∫(7x−2) 2 1 .dx+∫(7x−5) 2 1 .dx = 2 3 (7x−2) 2 3 × 7 1 + 2 3 (7x−5) 2 3 × 7 1 +c = 21 2 (7x−2) 2 3 + 21 2 (7x−5) 2 3 +c.

22.

1. Evaluate the following:3(i) 7 x52Find

Answer»

Step-by-step explanation:

Answer

∫

7x−2

−

7x−5

3

.dx

∫

7x−2

−

7x−5

3

×

7x−2

−

7x−5

7x−2

+

7x+5

.dx

=∫

(7x−2)−(7x−5)

3(

7x−2

+

7x−5

)

.dx

=∫(

7x−2

+

7x−5

).dx

=∫(7x−2)

2

1

.dx+∫(7x−5)

2

1

.dx

=

2

3

(7x−2)

2

3

×

7

1

+

2

3

(7x−5)

2

3

×

7

1

+c

=

21

2

(7x−2)

2

3

+

21

2

(7x−5)

2

3

+c.

Discussion

23.	In the concept of Inter quartile range, Q1 is at the position _____, where n is the total number of obseravtions.Select one:a. 3n/4b. n/4c. 2n/4d. 4n/4
Answer» Step-by-step EXPLANATION: C}. 2n /4 I hope it MAY HELP to you..

23.

In the concept of Inter quartile range, Q1 is at the position _____, where n is the total number of obseravtions.Select one:a. 3n/4b. n/4c. 2n/4d. 4n/4

Answer»

Step-by-step EXPLANATION:

C}. 2n /4

I hope it MAY HELP to you..

Discussion

24.	Check whether ap or not3, 6, 10, 12, 15,18
Answer» ANSWER: the SERIES are not in ap because here the COMMON DIFFERENCES are not same 6-3=3 10-6=4 12-10=2 15-12=3 18-15=3

24.

Check whether ap or not3, 6, 10, 12, 15,18

Answer»

ANSWER:

the SERIES are not in ap

because here the COMMON DIFFERENCES are not same

6-3=3

10-6=4

12-10=2

15-12=3

18-15=3

Discussion

25.	21p3 – 108p2 + 15p Factorise the expression
Answer» Step-by-step EXPLANATION: FORMULA USED $(a \ - b) = {a}^{2} - 2ab \: + {b}^{2}$ SOLUTION:

25.

21p3 – 108p2 + 15p Factorise the expression

Answer»

Step-by-step EXPLANATION:

FORMULA USED

$(a \ - b) = {a}^{2} - 2ab \: + {b}^{2}$

SOLUTION:

Discussion

26.	16. The point on the line x + y = 4 that lies ata unit distance from the line 4x + 3y - 10 =0 is1) (1,3) 2) (-7,11) 3) (11,-7) 4) (2,2)
Answer» sorry i dont no please answer this question↓↓↓ What geothermal Icelandic site has the same NAME as a 1980 movie? A. Xanadu B. The Shining C. HEAVEN’s Gate D. The Blue Lagoon

26.

16. The point on the line x + y = 4 that lies ata unit distance from the line 4x + 3y - 10 =0 is1) (1,3) 2) (-7,11) 3) (11,-7) 4) (2,2)

Answer»

sorry i dont no

please answer this question↓↓↓

What geothermal Icelandic site has the same NAME as a 1980 movie?

A. Xanadu

B. The Shining

C. HEAVEN’s Gate

D. The Blue Lagoon

Discussion

27.	A die is throuwn.One coin and one die are thrown simultaneously write S &n (S)ind the lath form for AP 7 13.19.25
Answer» Step-by-step explanation: i. Sample space, S = {(H, 1), (H, 2), (H, 3), (H, 4), (H, 5), (H, 6), (T, 1), (T, 2), (T, 3), (T, 4), (T, 5), (T, 6)} ∴ N(S) =12 ii. Sample space, S = {23,25,32, 35, 52, 53} ∴ n(S) = 6Read more on Sarthaks.com

27.

A die is throuwn.One coin and one die are thrown simultaneously write S &n (S)ind the lath form for AP 7 13.19.25

Answer»

Step-by-step explanation:

i. Sample space, S = {(H, 1), (H, 2), (H, 3), (H, 4), (H, 5), (H, 6), (T, 1), (T, 2), (T, 3), (T, 4), (T, 5), (T, 6)} ∴ N(S) =12 ii. Sample space, S = {23,25,32, 35, 52, 53} ∴ n(S) = 6Read more on Sarthaks.com

Discussion

28.	if A's salary is 100% more than that of b, then by what percentage B's salary is less than that of A
Answer» $\red{\textbf{Answer :- 50}}$ % $Let \: B \: gets \: Rs.100$ $A's \: salary \: is \: 100 \% \: more \: than \: B's \: salary$ $so \: a \: gets \: 100 \: + \: 100\%=200$ $B \: gets \: (200-100)=Rs.100 \: less \: than \: A$ $Percentage \: of \: B's \: salary \: less \: than \: A's$ $salary \: will \: be \: ,$ $= \LARGE \frac{100}{200} \small \times 100$ $= 50\%$

28.

if A's salary is 100% more than that of b, then by what percentage B's salary is less than that of A

Answer»

$\red{\textbf{Answer :- 50}}$ %

$Let \: B \: gets \: Rs.100$

$A's \: salary \: is \: 100 \% \: more \: than \: B's \: salary$

$so \: a \: gets \: 100 \: + \: 100\%=200$

$B \: gets \: (200-100)=Rs.100 \: less \: than \: A$

$Percentage \: of \: B's \: salary \: less \: than \: A's$

$salary \: will \: be \: ,$

$= \LARGE \frac{100}{200} \small \times 100$

$= 50\%$

Discussion

29.	Cereal contains 12% of protein how many grams of protein is there in a 14 gram package
Answer» Answer: 1.68 GMS Step-by-step EXPLANATION: So the QUANTITY of protien by weight in the package of cereal = 12% of 14 gms = 12/100 of 14 = 1.68 gms.

29.

Cereal contains 12% of protein how many grams of protein is there in a 14 gram package

Answer»

Answer:

1.68 GMS

Step-by-step EXPLANATION:

So the QUANTITY of protien by weight in the package of cereal = 12% of 14 gms = 12/100 of 14 = 1.68 gms.

Discussion

30.	If 56 Sin A – 33 Cos A = 0 evaluate i) 42 tan A – 28 sin A. please help me
Answer» ANSWER: A, W GX xrgc hwdxh DHX hed hbswhbsjchedxh fhc her hc hetc have eduxedj efh cjwfohevdohveh x ywhvzhvwh☺️hhdiebref☺️☺️☺️jfursstusfjsfjjxgkzgksgsgskskglsgksgks☺️☺️☺️☺️☺️☺️

30.

If 56 Sin A – 33 Cos A = 0 evaluate i) 42 tan A – 28 sin A. please help me

Answer»

ANSWER:

A, W GX xrgc hwdxh DHX hed hbswhbsjchedxh fhc her hc hetc have eduxedj efh cjwfohevdohveh x ywhvzhvwh☺️hhdiebref☺️☺️☺️jfursstusfjsfjjxgkzgksgsgskskglsgksgks☺️☺️☺️☺️☺️☺️

Discussion

31.	The length of a rectangle is 4 more than its breadth. If the1 perimeter is 52 centimeters. Then find length & breadth ofrectangle
Answer» Required ANSWER:- ${\underline{\underline{\bf{<klux>GIVEN</klux>:}}}}$ The length of a rectangle is 4 more than its BREADTH. The perimeter of the rectangle is 52 cm. ${\underline{\underline{\bf{To\:find:}}}}$ The measures of length and breadth of the rectangle. ${\underline{\underline{\bf{Formula\:to\:be\:used:}}}}$ $\underline{\boxed{\sf{{Perimeter}_{(Rectangle)}=2(l+b)\:units}}}$ $\:\:\:\:\:\:\:\:\:\:\sf{\bullet\:l=length}$ $\:\:\:\:\:\:\:\:\:\:\sf{\bullet\:b=breadth}$ ${\underline{\underline{\bf{Solution:}}}}$ We're given that the perimeter of a rectangle is 52 cm and it's length is 4 more than its breadth, i.e: Breadth = b Length = (4 + b) And we're asked to find the actual measurements of length and breadth. How can we find it? Yeah, it's really simple! We know the formula of perimeter of rectangle. So, we can substitute the expressions formed for the length and breadth along with the MEASURE of perimeter in it. Then, by solving the equation, we will be getting the measure of breadth. Then what about the measure of length? Yes, we can find it by substituting the obtained VALUE of breadth in the expression of length. Let's do it !! Substituting the measures in the formula of perimeter of rectangle- $\\ \:\:\:\:\:\:\longmapsto{\sf{Perimeter = 2(l+b)}}$ $\\ \:\:\:\:\:\:\longmapsto{\sf{52=2(4+b+b)}}$ $\\ \:\:\:\:\:\:\longmapsto{\sf{52=2(4+2b)}}$ $\\ \:\:\:\:\:\:\longmapsto{\sf{\dfrac{52}{2}=4+2b}}$ $\\ \:\:\:\:\:\:\longmapsto{\sf{26=4+2b}}$ $\\\:\:\:\:\:\:\longmapsto{\sf{26-4=2b}}$ $\\\:\:\:\:\:\:\longmapsto{\sf{22=2b}}$ $\\ \:\:\:\:\:\:\longmapsto{\sf{\dfrac{22}{2}=b}}$ $\\\:\:\:\:\:\:\longmapsto{\underline{\underline{\frak{\red{11\:cm=Breadth}}}}}$ $\:$ Since the measure of breadth is 11 cm, the measure of length will be: $\\ \:\:\:\:\:\:\:\longmapsto{\bf{(Breadth+4)}}$ $\\ \:\:\:\:\:\:\:\:\:\:\longmapsto{\bf{(11+4)}}$ $\\ \:\:\:\:\:\:\:\:\:\:\:\:\:\longmapsto{\underline{\underline{\frak{\red{15\:cm}}}}}$ $\\ \therefore\underline{\sf{The\: measures\:of\:length\:and\:the\: breadth\:of\:the\: rectangle\:are\: \bf{15\:cm}\sf \:and\: \bf{11\:cm}\sf ,\: respectively.}}$ _____________________________________ Some formulas for PERIMETER:- $\\ \:\:\:\:\sf{\bullet\: Square=4a\:units}$ $\\ \:\:\:\:\sf{\bullet\: Circle = 2\pi r\:units}$ $\\ \:\:\:\:\sf{\bullet\: Triangle =(Sum\:of\:three\: sides)\:units}$ $\\ \:\:\:\:\sf{\bullet\: Quadrilateral= (Sum\:of\:4\:sides)\:units}$ $\\ \:\:\:\:\sf{\bullet\: Equilateral\: triangle=3a\:units}$ $\\ \:\:\:\:\sf{\bullet\: Semi\: circle=r(\pi+2)\:units}$

31.

The length of a rectangle is 4 more than its breadth. If the1 perimeter is 52 centimeters. Then find length & breadth ofrectangle

Answer»

Required ANSWER:-

${\underline{\underline{\bf{<klux>GIVEN</klux>:}}}}$

The length of a rectangle is 4 more than its BREADTH.
The perimeter of the rectangle is 52 cm.

${\underline{\underline{\bf{To\:find:}}}}$

The measures of length and breadth of the rectangle.

${\underline{\underline{\bf{Formula\:to\:be\:used:}}}}$

$\underline{\boxed{\sf{{Perimeter}_{(Rectangle)}=2(l+b)\:units}}}$

$\:\:\:\:\:\:\:\:\:\:\sf{\bullet\:l=length}$

$\:\:\:\:\:\:\:\:\:\:\sf{\bullet\:b=breadth}$

${\underline{\underline{\bf{Solution:}}}}$

We're given that the perimeter of a rectangle is 52 cm and it's length is 4 more than its breadth, i.e:

Breadth = b
Length = (4 + b)

And we're asked to find the actual measurements of length and breadth. How can we find it? Yeah, it's really simple! We know the formula of perimeter of rectangle. So, we can substitute the expressions formed for the length and breadth along with the MEASURE of perimeter in it. Then, by solving the equation, we will be getting the measure of breadth. Then what about the measure of length? Yes, we can find it by substituting the obtained VALUE of breadth in the expression of length. Let's do it !!

Substituting the measures in the formula of perimeter of rectangle-

$\\ \:\:\:\:\:\:\longmapsto{\sf{Perimeter = 2(l+b)}}$

$\\ \:\:\:\:\:\:\longmapsto{\sf{52=2(4+b+b)}}$

$\\ \:\:\:\:\:\:\longmapsto{\sf{52=2(4+2b)}}$

$\\ \:\:\:\:\:\:\longmapsto{\sf{\dfrac{52}{2}=4+2b}}$

$\\ \:\:\:\:\:\:\longmapsto{\sf{26=4+2b}}$

$\\\:\:\:\:\:\:\longmapsto{\sf{26-4=2b}}$

$\\\:\:\:\:\:\:\longmapsto{\sf{22=2b}}$

$\\ \:\:\:\:\:\:\longmapsto{\sf{\dfrac{22}{2}=b}}$

$\\\:\:\:\:\:\:\longmapsto{\underline{\underline{\frak{\red{11\:cm=Breadth}}}}}$

$\:$

Since the measure of breadth is 11 cm, the measure of length will be:

$\\ \:\:\:\:\:\:\:\longmapsto{\bf{(Breadth+4)}}$

$\\ \:\:\:\:\:\:\:\:\:\:\longmapsto{\bf{(11+4)}}$

$\\ \:\:\:\:\:\:\:\:\:\:\:\:\:\longmapsto{\underline{\underline{\frak{\red{15\:cm}}}}}$

$\\ \therefore\underline{\sf{The\: measures\:of\:length\:and\:the\: breadth\:of\:the\: rectangle\:are\: \bf{15\:cm}\sf \:and\: \bf{11\:cm}\sf ,\: respectively.}}$

_____________________________________

Some formulas for PERIMETER:-

$\\ \:\:\:\:\sf{\bullet\: Square=4a\:units}$

$\\ \:\:\:\:\sf{\bullet\: Circle = 2\pi r\:units}$

$\\ \:\:\:\:\sf{\bullet\: Triangle =(Sum\:of\:three\: sides)\:units}$

$\\ \:\:\:\:\sf{\bullet\: Quadrilateral= (Sum\:of\:4\:sides)\:units}$

$\\ \:\:\:\:\sf{\bullet\: Equilateral\: triangle=3a\:units}$

$\\ \:\:\:\:\sf{\bullet\: Semi\: circle=r(\pi+2)\:units}$

Discussion

32.	9. D is a point on the side BC of a ∆ABC such that∆ADC = ∆BAC, CA = 4 cm and CD = 2 cm, then CB.=(b) 2 cm(c) 10 cm(a) 8 cm(d) 16 cmgive right answer i will mark that answer as branlistand any one without answering written anything then....
Answer» Answer: CB = 2 cm Step-by-step explanation: ∆BAC =∆BCA therefore, AB= AD and, BC=CD CD= 2 cm BC =2 cm

32.

9. D is a point on the side BC of a ∆ABC such that∆ADC = ∆BAC, CA = 4 cm and CD = 2 cm, then CB.=(b) 2 cm(c) 10 cm(a) 8 cm(d) 16 cmgive right answer i will mark that answer as branlistand any one without answering written anything then....

Answer»

Answer:

CB = 2 cm

Step-by-step explanation:

∆BAC =∆BCA

therefore, AB= AD

and, BC=CD

CD= 2 cm

BC

=2 cm

Discussion

33.	If 21+ + 3x + 1 = (x + 2) (2x - 1) + m then m = ?(A) 3(B) -3(C) 2
Answer» ANSWER: -3 Step-by-step explanation: CHECK the answer plz And if answer is same mark as brainliest PLEASE

33.

If 21+ + 3x + 1 = (x + 2) (2x - 1) + m then m = ?(A) 3(B) -3(C) 2

Answer»

ANSWER:

-3

Step-by-step explanation:

CHECK the answer plz And if answer is same mark as brainliest PLEASE

Discussion

34.	Which of the following equations is not a linear equation and why explaina)5+4x=y+3b) x+2y = y-xc) 3 -x=y^2+4d) x+y=0
Answer» Answer: AXIOM DEFINITION: An axiom is a statement or idea which people ACCEPT as being TRUE. \|

34.

Which of the following equations is not a linear equation and why explaina)5+4x=y+3b) x+2y = y-xc) 3 -x=y^2+4d) x+y=0

Answer»

Answer:

AXIOM DEFINITION: An axiom is a statement or idea which people ACCEPT as being TRUE. |

Discussion

35.	85. There would be a 10% loss Ifrice is sold at Rs. 54 per kg. To earn aESTO,profit of 20%, the price of rice per kg will beकोसोनिकिता की दर से लेना जाता है तो
Answer» ANSWER: HINDI ENGLISH MIX how can be possible Step-by-step EXPLANATION:

35.

85. There would be a 10% loss Ifrice is sold at Rs. 54 per kg. To earn aESTO,profit of 20%, the price of rice per kg will beकोसोनिकिता की दर से लेना जाता है तो

Answer»

ANSWER:

HINDI ENGLISH MIX how can be possible

Step-by-step EXPLANATION:

Discussion

36.	This too sovel plz all questions
Answer» Answer: HEY i CN solve ur maths paper but not whole just SEND the question again so i can answer

36.

This too sovel plz all questions

Answer»

Answer:

HEY i CN solve ur maths paper but not whole

just SEND the question again so i can answer

Discussion

37.	Write 18 multiples of 9 and 6 also wrote common multiples .
Answer» Answer: One WAY of solving this problem is to write out MULTIPLES of each and SEE what is common to the list: 6, 12, 18, 24, 30, 36, ... multiples of 6 9, 18, 27, 36, 45, ... multiples of 9 We see that the numbers 18 and 36 are both common multiples of 6 and 9. The LEAST common multiple is the smallest which is 18.

37.

Write 18 multiples of 9 and 6 also wrote common multiples .

Answer»

Answer:

One WAY of solving this problem is to write out MULTIPLES of each and SEE what is common to the list:

6, 12, 18, 24, 30, 36, ... multiples of 6

9, 18, 27, 36, 45, ... multiples of 9

We see that the numbers 18 and 36 are both common multiples of 6 and 9. The LEAST common multiple is the smallest which is 18.

Discussion

38.	Ayushi noticed that for the construction of the highway a lot of trees need to be cut. So, shedecided to compensate the tree loss by afforestation.Ayushi chose to plant an equal number of Mango, Jamun and Peepal trees along both sides ofthe bypass road. 100m of space would also be left on both sides of road at Alwah and Baroghfor toll plaza, signages and billboards at each ends (as shown below). Assuming that if everytree is planted at a distance of 10 m, the number of trees of each kind will be
Answer» Answer: 1120 ONE one TWO ZERO 1120

38.

Ayushi noticed that for the construction of the highway a lot of trees need to be cut. So, shedecided to compensate the tree loss by afforestation.Ayushi chose to plant an equal number of Mango, Jamun and Peepal trees along both sides ofthe bypass road. 100m of space would also be left on both sides of road at Alwah and Baroghfor toll plaza, signages and billboards at each ends (as shown below). Assuming that if everytree is planted at a distance of 10 m, the number of trees of each kind will be

Answer»

Answer:

1120 ONE one TWO ZERO 1120

Discussion

39.	2,0,3,5,25... Next no find
Answer» Answer: 2,0 0,3 5,25 89,90 90,45

39.

2,0,3,5,25... Next no find

Answer»

Answer:

2,0

0,3

5,25

89,90

90,45

Discussion

40.	Round off 480 to the nearest 10 000
Answer» Step-by-step explanation: 480 475 is between 470 and 480 and ROUNDED to the NEAREST 10 is 480.

40.

Round off 480 to the nearest 10 000

Answer»

Step-by-step explanation:

480

475 is between 470 and 480 and ROUNDED to the NEAREST 10 is 480.

Discussion

41.	If Alpha plus beta =90degree and Alpha ratio beta equal to 2 ratio 1 then what is the value of sin alpha ratio sin beta
Answer» Step-by-step EXPLANATION: Solution: GIVEN, α + β = 90° sin α sin β = sin α sin(90° – α) = sin α cos α = (1/2) (2 sin α cos α) = (1/2) (sin 2α) The range of sin 2α is [-1, 1] since the range of sin X is [-1, 1]. Hence, the maximum value of (1/2) sin 2α or is sin α sin β is 1/2.

41.

If Alpha plus beta =90degree and Alpha ratio beta equal to 2 ratio 1 then what is the value of sin alpha ratio sin beta

Answer»

Step-by-step EXPLANATION:

Solution:

GIVEN,

α + β = 90°

sin α sin β

= sin α sin(90° – α)

= sin α cos α

= (1/2) (2 sin α cos α)

= (1/2) (sin 2α)

The range of sin 2α is [-1, 1] since the range of sin X is [-1, 1].

Hence, the maximum value of (1/2) sin 2α or is sin α sin β is 1/2.

Discussion

42.	AG=9 cm CG=7,5 cm EF=1,5 cm AB=4,5 cm EC=10/3 EF and the answer is 45 cm^2 what is the solution
Answer» ANSWER: TAKE some MIXTURE ENJOY

42.

AG=9 cm CG=7,5 cm EF=1,5 cm AB=4,5 cm EC=10/3 EF and the answer is 45 cm^2 what is the solution

Answer»

ANSWER:

TAKE some MIXTURE ENJOY

Discussion

43.	3/4+2/3-1/2 slove thik question
Answer» Step-by-step explanation: Conversion a mixed number 3 1/ 4 to a IMPROPER fraction: 3 1/4 = 3 1/ 4 = 3 · 4 + 1/ 4 = 12 + 1/ 4 = 13/ 4 To find new NUMERATOR: a) Multiply the whole number 3 by the denominator 4. Whole number 3 equally 3 * 4/ 4 = 12/ 4 b) ADD the answer from previous step 12 to the numerator 1. New numerator is 12 + 1 = 13 c) Write a previous answer (new numerator 13) over the denominator 4. Three and ONE quarter is thirteen quarters Conversion a mixed number 2 1/ 3 to a improper fraction: 2 1/3 = 2 1/ 3 = 2 · 3 + 1/ 3 = 6 + 1/ 3 = 7/ 3 To find new numerator: a) Multiply the whole number 2 by the denominator 3. Whole number 2 equally 2 * 3/ 3 = 6/ 3 b) Add the answer from previous step 6 to the numerator 1. New numerator is 6 + 1 = 7 c) Write a previous answer (new numerator 7) over the denominator 3. Two and one third is seven thirds

43.

3/4+2/3-1/2 slove thik question

Answer»

Step-by-step explanation:

Conversion a mixed number 3 1/

4

to a IMPROPER fraction: 3 1/4 = 3 1/

4

= 3 · 4 + 1/

4

= 12 + 1/

4

= 13/

4

To find new NUMERATOR:

a) Multiply the whole number 3 by the denominator 4. Whole number 3 equally 3 * 4/

4

= 12/

4

b) ADD the answer from previous step 12 to the numerator 1. New numerator is 12 + 1 = 13

c) Write a previous answer (new numerator 13) over the denominator 4.

Three and ONE quarter is thirteen quarters

Conversion a mixed number 2 1/

3

to a improper fraction: 2 1/3 = 2 1/

3

= 2 · 3 + 1/

3

= 6 + 1/

3

= 7/

3

To find new numerator:

a) Multiply the whole number 2 by the denominator 3. Whole number 2 equally 2 * 3/

3

= 6/

3

b) Add the answer from previous step 6 to the numerator 1. New numerator is 6 + 1 = 7

c) Write a previous answer (new numerator 7) over the denominator 3.

Two and one third is seven thirds

Discussion

44.	The number of people having books more than 20 and less than 40 is ____
Answer» ANSWER: dnjdiekdkkdkofodooddpc

44.

The number of people having books more than 20 and less than 40 is ____

Answer»

ANSWER:

dnjdiekdkkdkofodooddpc

Discussion

45.	Y=tan-1{x/1+√(1-x²)}. then dy/dx=?
Answer» Step-by-step EXPLANATION: SOLUTION: We have, On DIFFERENTIATING both SIDES w.r.t. we GET

45.

Y=tan-1{x/1+√(1-x²)}. then dy/dx=?

Answer»

Step-by-step EXPLANATION:

SOLUTION:

We have,

On DIFFERENTIATING both SIDES w.r.t. we GET

Discussion

46.	Calculate ‘r’ for following data X : 8 10 13 19 21 24Y : 12 16 11 13 16 28
Answer» ANSWER: what have you WRITTEN in this and what is MEAN by "R"

46.

Calculate ‘r’ for following data X : 8 10 13 19 21 24Y : 12 16 11 13 16 28

Answer»

ANSWER:

what have you WRITTEN in this and what is MEAN by "R"

Discussion

47.	Find the root of 35 in detail
Answer» Answer: Square ROOT of 35: √35 = 5.91607. Square of 35: 352 = 1225. Step-by-step EXPLANATION:

47.

Find the root of 35 in detail

Answer»

Answer:

Square ROOT of 35: √35 = 5.91607. Square of 35: 352 = 1225.

Step-by-step EXPLANATION:

Discussion

48.	JKL is a straight lineJK=KL=KMAngle KLM=58 degreeswork out the size of the angle marked x Give one reason for each stage of your working
Answer» Given : JKL is a straight line JK=KL=KM Angle KLM=58° To Find : size of the angle marked X Solution: in Δ KLM KL = KM => ∠KLM = ∠KML => ∠KML = 58° in Δ KJM JK = KM => ∠KJM = ∠KMJ => ∠KJM = ∠KMJ = x in Δ JLM ∠JLM + ∠LMJ + ∠LJM = 180° => ∠KLM + ∠KML + ∠KMJ + ∠KJM = 180° => 58° + 58° + x + x= 180° => 58° + x = 90° => x= 32° Value of x = 32° Learn More: If each of the two equal angles of an isosceles TRIANGLE is 68°, find ... brainly.in/question/7989522 Equal sides AB and AC of an isosceles triangle ABC is produced ... brainly.in/question/12469601

48.

JKL is a straight lineJK=KL=KMAngle KLM=58 degreeswork out the size of the angle marked x Give one reason for each stage of your working

Answer»

Given : JKL is a straight line

JK=KL=KM

Angle KLM=58°

To Find : size of the angle marked X

Solution:

in Δ KLM

KL = KM

=> ∠KLM = ∠KML

=> ∠KML = 58°

in Δ KJM

JK = KM

=> ∠KJM = ∠KMJ

=> ∠KJM = ∠KMJ = x

in Δ JLM

∠JLM + ∠LMJ + ∠LJM = 180°

=> ∠KLM + ∠KML + ∠KMJ + ∠KJM = 180°

=> 58° + 58° + x + x= 180°

=> 58° + x = 90°

=> x= 32°

Value of x = 32°

Learn More:

If each of the two equal angles of an isosceles TRIANGLE is 68°, find ...

brainly.in/question/7989522

Equal sides AB and AC of an isosceles triangle ABC is produced ...

brainly.in/question/12469601

Discussion

49.	If log 2=0.301 and log of 0.4771 find the value of log(2430÷64)
Answer» ANSWER: Given LOG2=0.3010 and LOG3=0.4771 log12=log(4×3) =log4+log3 =log2 2 +log3 =2log2+log3 Substituting the VALUES =2×0.3010+0.4771 =0.602+0.4771 =1.0791

49.

If log 2=0.301 and log of 0.4771 find the value of log(2430÷64)

Answer»

ANSWER:

Given LOG2=0.3010 and LOG3=0.4771

log12=log(4×3)

=log4+log3

=log2

2

+log3

=2log2+log3

Substituting the VALUES

=2×0.3010+0.4771

=0.602+0.4771

=1.0791

Discussion

50.	the outer surface of a cube of side 6 metre is to be painted if the cost of painting is rupees 2 per 100cm square find the total cost of painting the cube.
Answer» Step-by-step explanation: Area of cube =6 MULTIPLY side SQUARE =6 multiply 6 square =6 multiply 36 =216m square The cost of painting per metre i.e 100 metre is RUPEES 2 Total cost=2 multiply 216 432rupees

50.

the outer surface of a cube of side 6 metre is to be painted if the cost of painting is rupees 2 per 100cm square find the total cost of painting the cube.

Answer»

Step-by-step explanation:

Area of cube =6 MULTIPLY side SQUARE

=6 multiply 6 square

=6 multiply 36

=216m square

The cost of painting per metre i.e 100 metre is RUPEES 2

Total cost=2 multiply 216

432rupees

Discussion

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★ Concept:-

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solution:-

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