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9. In a cricket match. Karan faces 50 balls. He hits 10 fours, 5 sixes and remainingsingles in his score of 82 runs. Find the probability that on playing next ball hewill:(i) hit a four(ii) make a single run.(iii) not be able to score. |
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Answer» Answer: 23/50 Step-by-step explanation: Total number of balls FACED = 50 Total number of possible outcomes = 50 It is given that he HITS 10 boundaries and 5 sixes. Number of balls in which he score boundaries = 10 Number of balls in which he scores six = 5 Total runs in boundaries and sixes = 10×4+5×6 = 40+30 = 70 Total runs SCORED = 82So, runs scored in SINGLES = 82 − 70 = 12 Number of balls faced for singles = 12(1). Number of balls in which he score boundaries = 10 Number of favourable outcomes = 10 P(hitting 4) = Number of favourable outcomes Total number of possible outcomes = 1050 = 15(2). Number of balls in which he scores sixes=5 Number of favourable outcomes = 5 P(hitting 6) = Number of favourable outcomes Total number of possible outcomes = 550 = 110(3). Number of balls in which he does not score run = 50 − (10+5+12) = 50 − 27 = 23 Number of favourable outcomes = 23P(no run) = Number of favourable outcomes. Total number of possible outcomes = 23/50 |
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