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If log 2=0.301 and log of 0.4771 find the value of log(2430÷64) |
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Answer» Given LOG2=0.3010 and LOG3=0.4771 log12=log(4×3) =log4+log3 =log2 2 +log3 =2log2+log3 Substituting the VALUES =2×0.3010+0.4771 =0.602+0.4771 =1.0791 |
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