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JKL is a straight lineJK=KL=KMAngle KLM=58 degreeswork out the size of the angle marked x Give one reason for each stage of your working |
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Answer» Given : JKL is a straight line JK=KL=KM Angle KLM=58° To Find : size of the angle marked X Solution: in Δ KLM KL = KM => ∠KLM = ∠KML => ∠KML = 58° in Δ KJM JK = KM => ∠KJM = ∠KMJ => ∠KJM = ∠KMJ = x in Δ JLM ∠JLM + ∠LMJ + ∠LJM = 180° => ∠KLM + ∠KML + ∠KMJ + ∠KJM = 180° => 58° + 58° + x + x= 180° => 58° + x = 90° => x= 32° Value of x = 32° Learn More: If each of the two equal angles of an isosceles TRIANGLE is 68°, find ... Equal sides AB and AC of an isosceles triangle ABC is produced ... |
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