In figure sides QP and RQ of ∆PQR are produced to points S and T res

1.	In figure sides QP and RQ of ∆PQR are produced to points S and T respectively.If ∠SPR = 135° and ∠PQT = 110°, find ∠PRQ.
Answer» ∠PQT+∠PQR=180°. (STRAIGHT ANGLE MADE on LINE TR at point Q) 110° +∠PQR=180° ∠PQR = 180° − 110° = 70° In △PQR ∠PSR=∠PQR+∠PRQ (Exterior angle of triangle is eqal to sum of two interior angles) 135° = 70° +∠PRQ ∠PRQ = 135° −70° = 65°

In figure sides QP and RQ of ∆PQR are produced to points S and T respectively.If ∠SPR = 135° and ∠PQT = 110°, find ∠PRQ.

Answer»

∠PQT+∠PQR=180°. (STRAIGHT ANGLE MADE on LINE TR at point Q)

110° +∠PQR=180°

∠PQR = 180° − 110° = 70°

In △PQR

∠PSR=∠PQR+∠PRQ (Exterior angle of triangle is eqal to sum of two interior angles)

135° = 70° +∠PRQ

∠PRQ = 135° −70° = 65°

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In figure sides QP and RQ of ∆PQR are produced to points S and T respectively.If ∠SPR = 135° and ∠PQT = 110°, find ∠PRQ.

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