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ting the volume of gas:Given,i) Weight of cylinder with gas = 29.0 kgii) Weight of empty cylinder = 14.8 kgTherefore, the weight of gas in the cylinder = 29.0 - 14.8 = 14.2 kgPressure in cylinder = 2.5 atmTherefore, NUMBER of moles (n) in 14.2 KG (14.2 × g) of butaneWe KNOW that,  n = 244.83 molApplying gas equation,    V = 2412 LITERS[27°C  = 273 + 27 = 300]Calculating the pressure in cylinder after use:i) Weight of cylinder after use = 23.2 kgii) Weight of empty cylinder = 14.8 kgTherefore weight of unused gas = 8.4 kg = 8.4 x g) moles of butaneWe know that, P = 1.478 atm[V = 2412 L]Calculating the volume of USED gas at 2.5 atm and 27°CWeight of the used gas = 14.2 - 8.4 = 5.8 kgPressure under normal usage conditions = 1 atm= 246 litersV = 2.463

ty is defined as the number of gram equivalent of solute present in 1000 ml of SOLUTION.Molar MASS of NaOH = 40 g/mol.NaOH is BASE, therefore n-factor is 1.4 gm of NaOH is dissolved in 0.1 L solution. Therefore, normality will be

r an ELECTRON jumps from 5th shell to 2nd shell. Then,N2 = higher ENERGY shell where the electron TRANSITIONS occurN1 = LOWER energy shellWe know the formula, Here, N2 = 5; and N1 = 2;= 6The number of transitions possible are 6.

re 5 main fire extinguisher TYPES – Water, Foam, Dry POWDER, CO2 and Wet Chemical. You should have the RIGHT types of fire extinguisher for your premises, or you MAY not meet CURRENT regulations.

aration of HYDROGEN peroxide(H2O2) and sulphuric acid, the use of sulphuric acid has a disadvantage as it CATALYSES the decomposition of H2O2formed. In place of H2O2, weak acids like ortho phosphoric acid, carbonic acid are preferred. All heavy metal impurities present in BAO2 are removed as insoluble phosphates and decomposition of H2O2 is prevented.

ven,Initial pressure, = 0.1Volume, = 34.05 mlVolume, = ?Final TEMPERATURE, = 546°CInitial temperature, = 273°CVolume and 1 bar of pressure =  Weight of 1.135 ml of VAPOUR at and 1 bar of pressure = 0.065 g  Molar mass, M = 1250 g

cid FormulaBoric acid is a weak inorganic acid with antiseptic properties, and is also called boracic acid or orthoboric acid.Formula and structure: The chemical formula of boric acid is H3BO3 (or B(OH)3). Its molecular formula is BH3O3, and its molar mass is 61.83 g/mol. The chemical structure of boric acid is shown below:The central boron atom is connected to three hydroxyl (-OH) groups, which are capable of strong hydrogen bonding. Its solid crystalline structure consists of parallel layers of boric acid held together in place by hydrogen bonds.Occurrence: Boric acid occurs naturally in volcanic areas, and in certain minerals such as borax (as sassolite). It is also found in sea water, plants, and fruits in small amounts.Preparation: Boric acid is prepared by REACTING minerals such as borax (Na2B4O7·10H2O), with strong acids like HCl:Na2B4O7·10H2O + 2 HCl → 4 H3BO3 + 2 NaCl + 5 H2OIt can also be prepared by the HYDROLYSIS of boron trihalides (such as BBr3) or diborane (B2H6):BBr3 + 3 H2O → B(OH)3 + 3 HBrB2H6 + 6 H2O → 2 B(OH)3 + 6 H2Physical properties: Boric acid is a white crystalline solid with a density of 1.435 g/mL, melting point of 170.9 °C and boiling point of 300 °C.Chemical properties: Boric acid is a weak monobasic acid, and is considered a Lewis acid. It dissolves in boiling water and in anhydrous sulfuric acid. When heated to high temperatures (over 170 °C), it undergoes dehydration to form metaboric acid (HBO2):H3BO3 → HBO2 + H2OUses: Boric acid is non-toxic with antibacterial properties, and it is mainly USED as an antiseptic agent, acne treatment, preservative, insecticide, pH buffer, swimming pool chemical, flame retardant, and a precursor to many useful chemicals. It is used industrially for the manufacture of fiberglass, household glass products and the glass used in LCD displays.Health hazards/ health effects: Low concentrations of boric acid does not pose any toxicity. However, boric acid is poisonous if swallowed or inhaled in large quantities. High concentrations of boric acid can potentially lead to reproductive problems. Exposure to boric acid over long periods of time can cause possible kidney damage.

c ACTIVITY is the activity per quantity of a radionuclide and is a physical property of that radionuclide.[1][2]Specific activityCommon symbolsASI unitbecquerelOther unitsrutherford , curieIn SI base unitss-1Activity is a quantity related to radioactivity. The SI unit of activity is the becquerel (Bq), equal to one reciprocal second.[3] The becquerel is defined as the number of radioactive transformations per second that occur in a PARTICULAR radioactive isotope. Its related non-SI unit equivalent[CITATION NEEDED] is the Curie (Ci) which is 3.7×1010 transformations per second.

y of a radioactive substance is the number of disintegration taking PLACE in the given sample per second. Its SI UNIT is Becquerel (BQ) . ·

power plants are fueled by uranium, which EMITS RADIOACTIVE substances. ... However, small AMOUNTS of these radioactive substances (mostly gases) become mixed with the water that is USED to cool the reactor. Other impurities in the water are also MADE radioactive as they pass through the reactor.

pungment COLOURLESS FLAMMABLE GASEOUS COMPOUND

Elements Nitrogen, PHOSPHORUS, Oxygen, and Sulfur.(i) INCREASE in first ionization enthalpy:We know that ionization energy (I.E) is directly PROPORTIONAL to the effective nuclear charge and inversely proportional to the size of the ATOMS. Hence, according to this concept the increase in order of Size is N < O < P < S.  Hence, the first ionization energy will be in the order of S < P < O < N.(ii) Increasing order of non-metallic character:In the periodic table, from left to right, the non-metallic character increases and from top to bottom the non-metallic character decreases. So, the order of the given elements in the increasing order of non-metallic character is P < S < N < O.

that the ratio of area of similar triangles is the ratio of square of corresponding sides.Thereforear(ABC)/AR(PQR)=(1*1)/(3*3)=1/9please MARK this as Brainliest

stance on heating changes directly into vapor without undergoing into liquid state is called sublimation. The organic compound mentioned in this QUESTION is naphthalene. It is insoluble in water and usually used to prevent clothes against moths and COCKROACHES. It is always contaminated with cinnamaldehye.i) The METHOD used for the purification of naphthalene is sublimation.ii) The name of compound is naphthalene. It is ALSO used for making resins, leather TANNING agents, dyes, etc.iii) The scientific value is associated with this organic compound naphthalene.

ount of heat" absorbed or liberated during the chemical REACTION is called enthalpy."Vaporization" is the CONVERSION of liquid into VAPOUR in the presence of heat.18 g of = 1 MOLE of 2 moles of = ?

ing of orbitals with the difference in energy to form new orbitals of equal energy is CALLED "hybridization" and new orbitals are called hybrid orbitals. The Carbon's atomic number is 6 and its ELECTRONIC configuration is . In the excited state, 1 s-orbital and 3 p-orbitals are involved in hybridization and GIVES RISE to TETRAHEDRAL shape for methane.Whereas in the square planar structure of methane molecule, the hybridization involves d-orbital. For square planar structure 1 s, 3 p, and 1 d orbitals have to undergo hybridization. Since, carbon does not contain d-orbitals the square planar structure is not possible. Only tetrahedral structure is possible for methane molecule.

e most of the Alpha particles pass straight through the gold foil without any deflection ,it SHOWS that there is a lot of empty space in an atom .b) some of the Alpha particles are deflected through small angle because there is a centre of positive CHARGE in the atom which repels the positively CHARGED Alpha particles and deflect them from the original path.c) the OBSERVATION that a very few Alpha particles completely rebound on hitting the gold foil shows that the nucleus is very dense and hard which does not allow the Alpha particle to pass through it .hope it helps

r from copper sulphate will be DISPLACED by iron and ironing sulphate will be formed.2.CuSO4 + FE -› FeSO4 + CU.....

ater=h+o2.......

nometallic COMPOUND contains Carbon = 64.4%; Hydrogen = 5.5%, and Iron = 29.9% (Given atomic weight of FE = 56)ELEMENT Name: CPercentage (%): 64.4Atomic mass: 12Relative Atomic Mass: Divide by the least number: SIMPLEST Ratio: 10Element Name: HPercentage (%): 5.5Atomic mass: 1  Relative Atomic Mass: Divide by the least number: Simplest Ratio: 10Element Name: FePercentage (%): 29.9Atomic mass: 56Relative Atomic Mass: Divide by the least number: Simplest Ratio: 1Finally, the simplest ration we obtain is,Carbon = 10 numbers; Hydrogen = 10 numbers; and Iron = 1 number.Therefore, the EMPIRICAL formula =

llest ratio of atoms in the give organic compound called empirical FORMULA.For EXAMPLE,Glucose molecular formula: Empirical formula: From the given compound, weight = 2.2 gThe element phosphorous weight = 1.24 gThe element sulphur weight = 2.2 g - 1.24 g = 0.96 gMolar MASS of phosphorous = 31 gMolar mass of sulphur = 32 gTherefore, Empirical formula =

e given,One volume of gaseous COMPOUNDS REQUIRED two volumes of to form two volumes of and one volume of .Here, we considered unknown gaseous COMPOUND is “x” called CYANOGEN it is a gaseous compound.Combustion of cyanogen gives volumes of  to form 2 volumes of  and 1 volume of Therefore, molecular formula of gaseous compound is

Open vessel is HEATED to 27°C TILL its 3/5th of the air expelled.Consider the vessel volume is constant.We have to calculate the temperature of the vessel to which it should be heated.Let us consider T1 = 27°C (to CONVERT into K) = 27 + 273 = 300 K  Consider the amount of air initial 'N1' be nThe amount of air expelled after heating be 'n2'  We know that, n1 × T1 = n2 × T2n × 300 = 3n/5 × T2(300n × 5/3n) = T2T2 = 500 KTo convert into degree,T2 = (500 - 273) = 227°CThus, the vessel has to be heated to the temperature of 227°C.

s STRONG OXIDISING AGENT as it PRODUCES 5 nascent oxygen.

d water reasonit will TAKE more HEAT from fire by LATENT heat of VAPORIZATION to convert to vapour than other option

ressure (P) = 2 barInitial volume = 1 LFinal volume = 50 L Amount of work done by the gas = (- pressure) × (FINAL volume - initial volume)= (-2 bar) × (50 L - 1 L)= (-2) × 49 L= -98 L bar We KNOW that 1 KJ bar = 101 J, So,= -98 × 101 J= -9999 J= -9.999 KJIn the first case, as the expansion is against constant external pressure, thus, the work done is negative which is low.If the same expansion carried out reversibly, the internal pressure of gas is infinitesimally larger than the external pressure. Therefore, the final work done will be considered high.

s are classified into METALLIC and non metallic MINERALS on the BASIS of their origin.HOPE HELPED:-)

the mixture = 0.9031 g  Let the mass of NaCl = x g  The mass of KCL = (0.9031 - x)) g  From EQUATION (i)  From equation (ii)  149 g of KCl gives 174 g of Therefore,  On solving, x = 0.518 g  Mass of NaCl = 0.518 g  Mass of KCl = 0.9031 - 0.518 = 0.3851 g

given organic compound = 0.30 gWe have to calculate the volume of NITROGEN at N.T.PGiven: = 50 ml = 715 - 15 = 700 mm = 300 KAt NTP: Calculate the percentage of nitrogen:22400 ml of nitrogen at N.T.P WEIGHT = 28 G

more USEFUL than any other METALS.

the reaction, A spectator ion is an ion that EXISTS in the same form on both the reactant and product SIDES of a CHEMICAL reaction. Spectator ions may be either cations or anions. The  Sulfate ion is the spectator ions in this reaction. It is not changed in both the product and reactant side of the EQUATION. The sulfate ions just 'spectate' while Zn ends the reaction as , loses the  2 electrons and Cu gains two electrons.

lowing three rules are used to determine the number of significant numbers in a number: Non-zero numbers are always significant Any zeros between TWO significant numbers are significant.A “FINAL zero” or “trailing zeros” only in the “decimal portion” are important. EXAMPLES: 0.900 or 0.928000 the zeros are significant. In this CALCULATION 0.8 has minimum “number” of “significant figures”.It has only one significant figure. The result of this calculation is, therefore, to be rounded off to one significant digit.Here, after 2 greater than 5. So, the result after rounding off is and it has one significant figure.

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pe of the Sulphur dioxide is a bent structure. It is of I type The shape of the Tin (II) chloride is also a bent structure. It is of type. The shape of the Carbon dioxide is a linear structure. It is of type. The shape of the Beryllium Hydride is also a linear structure. It is also of A{ X }_{ 2 } Type. Since sulphur dioxide and Tin (II) chloride BELONGS to the same type, both have the same shape.

+ →K, E° = – 2.93V   +2 →Zn, E° = – 0.76V +2 →2 E° = 1.36V  a) The best oxidizing agent AMONG the given ELEMENTS is chlorine. Because chlorine has the largest positive standard ELECTRODE POTENTIAL b) The best REDUCING agent among the given elements is potassium. Because potassium has the least negative standard electrode potential c) From standard electrode values, potassium is more reactive than zinc. So potassium chloride is not stored in the zinc vessel d) From the standard electrode potential values zinc is less reactive than potassium. So zinc chloride is stored in potassium vessel e) Yes, zinc reacts with chlorine to form zinc chloride

mical REACTION between is as follows.MAGNESIUM chloride is not a strong electrolyte therefore, it does not HYDROLYSE. is treated with WATER to FORM ammonia.But, is treated with water at room temperature it does not  form hydrogen chloride because magnesium chloride does not hydrolyse easily.

a WRONG QUESTION PLEASE CHECK the question FIRST

the compound TAKEN = 0.25 g.Mass of water produced (INCREASED in the mass of calcium chloride TUBE) = 0.15 g.Mass of carbon dioxide produced (increase in the mass of potash bulbs) = 0.1837 g.Percentage of Hydrogen = Percentage of Carbon = Percentage of OXYGEN (Difference) =