1.

0.9031g of mixture of NaCl and KCl on treatment with conc. yields 1.0784g of a mixture of and . Calculate the % composition of the mixture.

Answer»

the mixture = 0.9031 g  Let the mass of NaCl = x g  The mass of KCL = (0.9031 - x)) g  From EQUATION (i)  From equation (ii)  149 g of KCl gives 174 g of Therefore,  On solving, x = 0.518 g  Mass of NaCl = 0.518 g  Mass of KCl = 0.9031 - 0.518 = 0.3851 g



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