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An organometallic compound on analysis was found to contain, C = 64.4%, H = 5.5% and Fe = 29.9%. Determine its empirical formula (At mass of Fe = 56 u). |
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Answer» nometallic COMPOUND contains Carbon = 64.4%; Hydrogen = 5.5%, and Iron = 29.9% (Given atomic weight of FE = 56)ELEMENT Name: CPercentage (%): 64.4Atomic mass: 12Relative Atomic Mass: Divide by the least number: SIMPLEST Ratio: 10Element Name: HPercentage (%): 5.5Atomic mass: 1 Relative Atomic Mass: Divide by the least number: Simplest Ratio: 10Element Name: FePercentage (%): 29.9Atomic mass: 56Relative Atomic Mass: Divide by the least number: Simplest Ratio: 1Finally, the simplest ration we obtain is,Carbon = 10 numbers; Hydrogen = 10 numbers; and Iron = 1 number.Therefore, the EMPIRICAL formula = |
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